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JEE • MATHEMATICS • MULTIPLE AND SUBMULTIPLE ANGLES

Multiple and submultiple angles practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 66 questions
31 Easy
31 of 66
Application +4 | -1
The value of tan⁡  67  1∘2+cot⁡  67  1∘2\tan \,\,67\,\,\frac{{1^\circ }}{2} + \cot \,\,67\,\,\frac{{1^\circ }}{2} is
View answer and explanation
Correct option: C
2 22\,\sqrt 2
Option C (222\sqrt 2) is correct because simplifying the expression using trigonometric identities leads to the result 222\sqrt 2.
32 Easy
32 of 66
Application +4 | -1
If   x  cos⁡  θ=y  cos⁡(θ+2π3)=z  cos⁡(θ+4π3)  \;x\,\,\cos \,\,\mathrm{\theta } = y\,\,\cos \left( {\mathrm{\theta } + \frac{{2\pi }}{3}} \right) = \mathrm{z}\,\,\cos \left( {\mathrm{\theta } + \frac{{4\pi }}{3}} \right)\;, then the value of 1x+1y+1z\frac{1}{x} + \frac{1}{y} + \frac{1}{\mathrm{z}} is equal to
View answer and explanation
Correct option: C
0
Option C (0) is correct because the sum of the cosines with the given phase shifts equals zero, leading to the result 1/x + 1/y + 1/z = 0.
33 Easy
33 of 66
Application +4 | -1
If cosec    θ=p+qp−q\mathrm{cosec}\;\,\,\theta = \frac{{p + q}}{{p - q}}, then cot⁡  (π/4+θ/2)=\cot \,\,\left( {\pi /4 + \theta /2} \right) =
View answer and explanation
Correct option: B
qp\sqrt {\frac{q}{p}}
Option B, qp\sqrt {\frac{q}{p}}, is correct because it is the simplified form of cot⁡(π/4+θ/2)\cot \left( {\pi /4 + \theta /2} \right) after substituting the given value of cosec   θ\mathrm{cosec}\;\,\theta and using trigonometric identities.
34 Easy
34 of 66
Application +4 | -1
The value of the series

cos⁡  12∘+cos⁡  84∘+cos⁡  132∘+cos⁡  156∘\cos \,\,12^\circ + \cos \,\,84^\circ + \cos \,\,132^\circ + \cos \,\,156^\circ is
View answer and explanation
Correct option: D
−12- \frac{1}{2}
Option D is correct because the sum of the cosine series simplifies to -1/2 using trigonometric identities.
35 Easy
35 of 66
Application +4 | -1
The value of     (1+cos  π8)  (1+cos  3π8)  (1+cos  5π8)  (1+cos  7π8)  \mathrm{\;\;}\left( {1 + \mathrm{cos}\,\,\frac{\mathrm{\pi }}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{3\mathrm{\pi }}}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{5\mathrm{\pi }}}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{7\mathrm{\pi }}}{8}} \right)\mathrm{\;} is equal to
View answer and explanation
Correct option: C
18\frac{1}{8}
Option D (nπ+π4n\pi \\ + \\ \frac{\pi }{4}) is correct because by simplifying the equation, we get tan⁡θ=1\tan \theta = 1, which gives the general solution θ=nπ+π4\theta = n\pi + \frac{\pi}{4}.
36 Easy
36 of 66
Application +4 | -1
The value of
cos⁡2  π16+cos⁡2  3π16+cos⁡2  5π16+cos⁡2  7π16{\cos ^2}\,\,\frac{\pi }{{16}} + {\cos ^2}\,\,\frac{{3\pi }}{{16}} + {\cos ^2}\,\,\frac{{5\pi }}{{16}} + {\cos ^2}\,\,\frac{{7\pi }}{{16}}
View answer and explanation
Correct option: A
2
Option A (2) is correct because using trigonometric identities, the expression simplifies to 2.
37 Easy
37 of 66
Analyzing +4 | -1
(1+cos⁡  π8)  (1+cos⁡  3 π8)  (1+cos⁡  5 π8)  (1+cos⁡  7π8)\left( {1 + \cos \,\,\frac{\pi }{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{3\,\pi }}{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{5\,\pi }}{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{7\pi }}{8}} \right) is equal to
View answer and explanation
Correct option: C
18\frac{1}{8}
Option C (18\frac{1}{8}) is correct because the given expression simplifies to 18\frac{1}{8} using trigonometric identities and properties of cosine.
38 Easy
38 of 66
Application +4 | -1
If tan⁡x=ba\tan x=\frac{b}{a}, then a+ba−b+a−ba+b=\sqrt{\frac{a+b}{a-b}}+\sqrt{\frac{a-b}{a+b}}=
View answer and explanation
Correct option: B
2cos⁡xcos⁡2x\frac{2 \cos x}{\sqrt{\cos 2 x}}
Option B (2cos⁡xcos⁡2x\frac{{2 \cos x}}{{\sqrt{{\cos 2 x}}}}) is correct because, after using componendo and dividendo and simplifying, the expression equals 2cos⁡xcos⁡2x\frac{{2 \cos x}}{{\sqrt{{\cos 2 x}}}}.
39 Easy
39 of 66
Application +4 | -1
The value of   tan  20∘  tan⁡  40∘  tan⁡  60∘  tan⁡  80∘  \mathrm{\;tan}\,\,20^\circ \,\,\tan \,\,40^\circ \,\,\tan \,\,60^\circ \,\,\tan \,\,80^\circ \mathrm{\;} is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because the product of the tangent values simplifies to 3 using trigonometric identities.
40 Easy
40 of 66
Analyzing +4 | -1
If tan⁡  x=2ba−c,   a≠c\tan \,\,x = \frac{{2b}}{{a - c}},\,\;a \ne c and y=a  cos⁡2 x  +  2b  sin⁡  x  cos⁡  x  +  c  sin⁡2 xy = a\,\,{\cos ^2}\,x\,\, + \,\,2b\,\,\sin \,\,x\,\,\cos \,\,x\,\, + \,\,c\,\,{\sin ^2}\,x

z=a  sin⁡2 x  −  2b  sin⁡  x  cos⁡  x  +  c  cos⁡2 xz = a\,\,{\sin ^2}\,x\,\, - \,\,2b\,\,\sin \,\,x\,\,\cos \,\,x\,\, + \,\,c\,\,{\cos ^2}\,x, then
View answer and explanation
Correct option: C
y−z=a−cy - z = a - c
Option C (y−z=a−cy - z = a - c) is correct because simplifying the expression y−zy - z using trigonometric identities and the given condition tan⁡x=2ba−c\tan x = \frac{{2b}}{{a - c}} leads to the result a−ca - c.
41 Easy
41 of 66
Understanding +4 | -1
1+cos⁡22A1+\cos ^2 2 A is equal to
View answer and explanation
Correct option: C
2(cos⁡4 A+sin⁡4 A)2\left(\cos ^4 \mathrm{~A}+\sin ^4 \mathrm{~A}\right)
Option C (2(cos⁡4A+sin⁡4A)2(\cos ^4 A+\sin ^4 A)) is correct because it is the simplified form of the given expression using trigonometric identities.
42 Easy
42 of 66
Application +4 | -1
If cos⁡A=3/4\cos A=3 / 4 then value of 32sin⁡(A/2)sin⁡(5 A/2)32 \sin (A / 2) \sin (5 \mathrm{~A} / 2) is equal to
View answer and explanation
Correct option: C
11
Option C (11) is correct because it is the result of applying the product-to-sum trigonometric identity and simplifying using the given value of cos⁡A\cos A.
43 Easy
43 of 66
Application +4 | -1
If sin    (x+y)sin⁡    (x−y)=a+ba−b\frac{{\mathrm{sin}\,\,\mathrm{\;}\left( {x + y} \right)}}{{\sin \,\,\;\left( {x - y} \right)}} = \frac{{a + b}}{{a - b}}, then tan⁡  xtan⁡  y\frac{{\tan \,\,x}}{{\tan \,\,y}} is equal to
View answer and explanation
Correct option: B
ab\frac{a}{b}
Option B (ab\frac{a}{b}) is correct because by applying the componendo and dividendo rule and trigonometric identities, the ratio of tangents simplifies to ab\frac{a}{b}.
44 Easy
44 of 66
Application +4 | -1
If 5cos⁡  2θ+2cos⁡2θ2+1=0,  −π<θ<π5\cos \,\,2\theta + 2{\cos ^2}\frac{\theta }{2} + 1 = 0,\; - \pi < \theta < \pi, then θ\theta is equal to

View answer and explanation
Correct option: D
π3,   π−cos⁡−1(35)\frac{\pi }{3},\;\,\pi - {\cos ^{ - 1}}\left( {\frac{3}{5}} \right)
Option D (π3,   π−cos⁡−1(35)\frac{\pi }{3},\;\,\pi - {\cos ^{ - 1}}\left( {\frac{3}{5}} \right)) is correct because it represents the solutions obtained by solving the given trigonometric equation within the specified interval.
45 Easy
45 of 66
Analyzing +4 | -1
If 2  cos⁡  A2=1+sin⁡  A+1−sin⁡  A2\,\,\cos \,\,\frac{A}{2} = \sqrt {1 + \sin \,\,A} + \sqrt {1 - \sin \,\,A}, then A2\frac{A}{2} lies between, (n∈Z)\left( {n \in Z} \right)
View answer and explanation
Correct option: B
2n  π−π42n\;\pi - \frac{\pi }{4} and 2n  π+π42n\;\pi + \frac{\pi }{4}
Option C (cot⁡B\cot B) is correct because simplifying the given expression using trigonometric identities leads to this result.
46 Easy
46 of 66
Application +4 | -1
The value of 2+2+2+2cos⁡8θ\sqrt{2+\sqrt{2+\sqrt{2+2 \cos 8 \theta}}}, where 0<θ<π80 < \theta < \frac{\pi}{8}, is
View answer and explanation
Correct option: A
2cos⁡θ2 \cos \theta
Option A (2cos⁡θ2 \cos \theta) is correct because the nested square roots simplify to 2cos⁡θ2 \cos \theta using the double angle formula for cosine.
47 Easy
47 of 66
Application +4 | -1
The value of cos⁡  π15  cos⁡  2 π15  cos⁡  3 π15  cos⁡  4 π15  cos⁡  5 π15  cos⁡  6 π15  cos⁡  7π15\cos \,\,\frac{\pi }{{15}}\,\,\cos \,\,\frac{{2\,\pi }}{{15}}\,\,\cos \,\,\frac{{3\,\pi }}{{15}}\,\,\cos \,\,\frac{{4\,\pi }}{{15}}\,\,\cos \,\,\frac{{5\,\pi }}{{15}}\,\,\cos \,\,\frac{{6\,\pi }}{{15}}\,\,\cos \,\,\frac{{7\pi }}{{15}}, is
View answer and explanation
Correct option: A
1/1281/128
Option A (1/1281/128) is correct because the expression can be simplified using the identity ∏k=1n−1cos⁡(kπ2n)=n2n−1\prod_{k=1}^{n-1} \cos(\frac{k\pi}{2n}) = \frac{\sqrt{n}}{2^{n-1}}.
48 Easy
48 of 66
Application +4 | -1
If cos⁡  (θ−α),  cos⁡  θ,  cos⁡  (θ+α)\cos \,\,\left( {\theta - \alpha } \right),\,\,\cos \,\,\theta ,\,\,\cos \,\,\left( {\theta + \alpha } \right) are in H.P., then cos⁡  θ  sec⁡  (α2)\cos \,\,\theta \,\,\sec \,\,\left( {\frac{\alpha }{2}} \right) is equal to
View answer and explanation
Correct option: B
±   2\pm \;\,\sqrt 2
Option B (±   2\pm \;\,\sqrt 2) is correct because by using the harmonic progression property and trigonometric identities, the expression cos⁡ θ  sec⁡ (α2)\cos \,\theta \,\,\sec \,\left( {\frac{\alpha }{2}} \right) simplifies to ±   2\pm \;\,\sqrt 2.
49 Easy
49 of 66
Analyzing +4 | -1
If sin⁡x+sin⁡y=3(cos⁡y−cos⁡x)\sin x + \sin y = 3\left( {\cos y - \cos x} \right), then the value of sin⁡3xsin⁡3y\frac{{\sin 3x}}{{\sin 3y}} is
View answer and explanation
Correct option: B
−1- 1
Option B (-1) is correct because by simplifying the given equation, we find a relationship between x and y, allowing us to evaluate the expression.
50 Easy
50 of 66
Analyzing +4 | -1
The value of sin⁡  15 π32  sin⁡  7π16  sin⁡  3 π8\sin \,\,\frac{{15\,\pi }}{{32}}\,\,\sin \,\,\frac{{7\pi }}{{16}}\,\,\sin \,\,\frac{{3\,\pi }}{8} is
View answer and explanation
Correct option: A
18 2  cos⁡  (15π32)\frac{1}{{8\,\sqrt 2 \,\,\cos \,\,\left( {\frac{{15\pi }}{{32}}} \right)}}
Option A (182cos⁡(15π32)\frac{1}{{8\sqrt 2 \cos \left( {\frac{{15\pi }}{{32}}} \right)}}) is correct because it is derived by repeatedly applying the double angle formula for sine.
51 Easy
51 of 66
Analyzing +4 | -1
tan⁡  α+2  tan⁡  2α+4  tan⁡  4α+8  cot⁡  8α\tan \,\,\alpha + 2\,\,\tan \,\,2\alpha + 4\,\,\tan \,\,4\alpha + 8\,\,\cot \,\,8\alpha is equal to
View answer and explanation
Correct option: C
cot⁡  α\cot \,\,\alpha
Option C (cot⁡α\cot \alpha) is correct because the given expression simplifies to cot⁡α\cot \alpha using the identity cot⁡2x=cot⁡x−tan⁡x2\cot 2x = \frac{{\cot x - \tan x}}{2}.
52 Easy
52 of 66
Application +4 | -1
Suppose 0<t<π0 < t < \pi and sin⁡  t+cos⁡  t=15\sin \,\,t + \cos \,\,t = \frac{1}{5}. Then, tan⁡  t2\tan \,\,\frac{t}{2} is equal to
View answer and explanation
Correct option: A
2
Option A, 2, is correct because it is the value of tan⁡t2\tan \frac{t}{2} obtained by substituting the given expression into the trigonometric identity and solving the resulting quadratic equation.
53 Easy
53 of 66
Application +4 | -1
sin⁡4  π8+sin⁡4  3 π8+sin⁡4  5 π8+sin⁡4  7π8  {\sin ^4}\,\,\frac{\pi }{8} + {\sin ^4}\,\,\frac{{3\,\pi }}{8} + {\sin ^4}\,\,\frac{{5\,\pi }}{8} + {\sin ^4}\,\,\frac{{7\pi }}{8}\; is equal to
View answer and explanation
Correct option: B
3 / 2\mathrm{3}\,\mathrm{/}\,\mathrm{2}
Option B (3/2) is correct because the given trigonometric expression simplifies to 3/2 using trigonometric identities and properties.
54 Easy
54 of 66
Application +4 | -1
The value of cos⁡π22⋅cos⁡π23.......cos⁡π210⋅sin⁡π210\cos \frac{\pi }{{{2^2}}} \cdot \cos \frac{\pi }{{{2^3}}}.......\cos \frac{\pi }{{{2^{10}}}} \cdot \sin \frac{\pi }{{{2^{10}}}} is
View answer and explanation
Correct option: C
1512\frac{1}{{512}}
Option C (1512\frac{1}{{512}}) is correct because it is the simplified result after applying the trigonometric identity for the product of cosines and sine.
55 Easy
55 of 66
Application +4 | -1
If cos⁡  (x−y),  cos⁡x\cos \,\,\left( {x - y} \right),\,\,\cos x and cos⁡  (x+y)\cos \,\,\left( {x + y} \right) are in H.P., then ∣ cos⁡x  sec⁡  y2 ∣\left| {\,\cos x\,\,\sec \,\,\frac{y}{2}\,} \right| equals
View answer and explanation
Correct option: C
2\sqrt 2
Option C (2\sqrt 2) is correct because after applying the properties of Harmonic Progression and trigonometric identities, the expression simplifies to 2\sqrt{2}.
56 Easy
56 of 66
Analyzing +4 | -1
sin⁡23 Asin⁡2 A−cos⁡23 Acos⁡2A=\frac{{{{\sin }^2}3\,A}}{{{{\sin }^2}\,A}} - \frac{{{{\cos }^2}3\,A}}{{{{\cos }^2}A}} =
View answer and explanation
Correct option: B
8  cos⁡  2A8\;\cos \,\,2A
Option B (8  cos⁡  2A8\;\cos \;2A) is correct because the expression simplifies to 8cos⁡2A8\cos 2A using trigonometric identities.
57 Easy
57 of 66
Application +4 | -1
If sin⁡A=336625\sin A = \frac{{336}}{{625}} where 450∘  <A<540∘450^\circ \,\, < A < 540^\circ, then sin⁡  A4=\sin \,\,\frac{A}{4} =
View answer and explanation
Correct option: C
45\frac{4}{5}
Option C (45\frac{4}{5}) is correct because given the range of A and the value of sin⁡A\sin A, we can find sin⁡A4\sin \frac{A}{4} using half-angle formulas.
58 Easy
58 of 66
Analyzing +4 | -1
If cos⁡  x=tan⁡y,  cos⁡  y=tan⁡  z,  cos⁡  z=tan⁡ x\cos \,\,x = \tan y,\,\,\cos \,\,y = \tan \,\,z,\,\,\cos \,\,z = \tan \,x, then the value of sin⁡x\sin x is
View answer and explanation
Correct option: D
2sin⁡ 18∘2\sin \,18^\circ
Option D (2sin⁡ 18∘2\sin \,18^\circ) is the correct answer because, after simplification and solving the trigonometric equations, the value of sin⁡x\sin x is found to be equal to 2sin⁡ 18∘2\sin \,18^\circ.
59 Easy
59 of 66
Application +4 | -1
2sin⁡(π22)sin⁡(3π22)sin⁡(5π22)sin⁡(7π22)sin⁡(9π22)2 \sin \left(\frac{\pi}{22}\right) \sin \left(\frac{3 \pi}{22}\right) \sin \left(\frac{5 \pi}{22}\right) \sin \left(\frac{7 \pi}{22}\right) \sin \left(\frac{9 \pi}{22}\right) is equal to:
View answer and explanation
Correct option: B
116\frac{1}{{16}}
Option B (5) is correct because setting up the integral for the area and solving for 'a' yields the odd natural number 5.
60 Easy
60 of 66
Application +4 | -1
The value of sin⁡  36∘  sin⁡  72∘  sin⁡  108∘  sin⁡144∘\sin \,\,36^\circ \,\,\sin \,\,72^\circ \,\,\sin \,\,108^\circ \,\,\sin 144^\circ is
View answer and explanation
Correct option: D
516\frac{5}{{16}}
Option D (5/16) is correct because it is the result of simplifying the given expression using trigonometric identities and known values of sine functions.
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