Skip to main content
Back to MULTIPLE AND SUBMULTIPLE ANGLES

Your Progress

0 / 122 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • MULTIPLE AND SUBMULTIPLE ANGLES

Multiple and submultiple angles practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 121-122 of 122 questions
121 Easy
121 of 122
Application +4 | -1
If   cos⁡  (θ−α),  cos⁡  θ  and  cos⁡  (θ+α)\mathrm{\;}\cos \,\,\left( {\mathrm{\theta } - \mathrm{\alpha }} \right),\,\,\cos \,\,\mathrm{\theta }\,\,\mathrm{and}\,\,\cos \,\,\left( {\mathrm{\theta } + \mathrm{\alpha }} \right) are in HP, then cos⁡  θ  sec⁡  α2\cos \,\,\mathrm{\theta }\,\,\sec \,\,\frac{\mathrm{\alpha }}{2} is equal to
View answer and explanation
Correct option: A
± 2\pm \,\sqrt 2
Option A (±,2\pm \\,\sqrt 2) is correct because the expression simplifies to ±,2\pm \\,\sqrt 2 when the given cosines are in Harmonic Progression.
122 Easy
122 of 122
Application +4 | -1
If cos⁡  2α=3cos⁡  2β−13−cos⁡  2β\cos \,\,2\alpha = \frac{{3\cos \,\,2\beta - 1}}{{3 - \cos \,\,2\beta }}, then tan⁡α\tan \alpha is equal to
View answer and explanation
Correct option: A
2  tan⁡  β\sqrt 2 \,\,\tan \,\,\beta
Option A (2  tan⁡  β\sqrt 2 \,\,\tan \,\,\beta) is correct because by applying componendo and dividendo, tan⁡α\tan \alpha can be expressed in terms of tan⁡β\tan \beta.
Revision notes and key takeaways

Review MULTIPLE AND SUBMULTIPLE ANGLES in your textbook or class notes, then use this set to check your understanding.

Showing 121-122 of 122 questions
0 /122
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.