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JEE • MATHEMATICS • MULTIPLE AND SUBMULTIPLE ANGLES

Multiple and submultiple angles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 122 questions
61 Easy
61 of 122
Application +4 | -1
If   x  cos⁡  θ=y  cos⁡(θ+2π3)=z  cos⁡(θ+4π3)  \;x\,\,\cos \,\,\mathrm{\theta } = y\,\,\cos \left( {\mathrm{\theta } + \frac{{2\pi }}{3}} \right) = \mathrm{z}\,\,\cos \left( {\mathrm{\theta } + \frac{{4\pi }}{3}} \right)\;, then the value of 1x+1y+1z\frac{1}{x} + \frac{1}{y} + \frac{1}{\mathrm{z}} is equal to
View answer and explanation
Correct option: C
0
Option C (0) is correct because the sum of the cosines with the given phase shifts equals zero, leading to the result 1/x + 1/y + 1/z = 0.
62 Easy
62 of 122
Application +4 | -1
If cosec    θ=p+qp−q\mathrm{cosec}\;\,\,\theta = \frac{{p + q}}{{p - q}}, then cot⁡  (π/4+θ/2)=\cot \,\,\left( {\pi /4 + \theta /2} \right) =
View answer and explanation
Correct option: B
qp\sqrt {\frac{q}{p}}
Option B, qp\sqrt {\frac{q}{p}}, is correct because it is the simplified form of cot⁡(π/4+θ/2)\cot \left( {\pi /4 + \theta /2} \right) after substituting the given value of cosec   θ\mathrm{cosec}\;\,\theta and using trigonometric identities.
63 Medium
63 of 122
Analyzing +4 | -1
If x=y  cos⁡  2 π3=z  cos⁡4 π3x = y\,\,\cos \,\,\frac{{2\,\pi }}{3} = z\,\,\cos \frac{{4\,\pi }}{3}, then xy+yz+zx=xy + yz + zx =
View answer and explanation
Correct option: B
0
Option B (0) is correct because when x, y, and z are expressed in terms of a common variable, the expression xy + yz + zx simplifies to 0.
64 Medium
64 of 122
Analyzing +4 | -1
The value of 36(4cos⁡29∘−1)(4cos⁡227∘−1)36\left(4 \cos ^{2} 9^{\circ}-1\right)\left(4 \cos ^{2} 27^{\circ}-1\right) (4cos⁡281∘−1)(4cos⁡2243∘−1)\left(4 \cos ^{2} 81^{\circ}-1\right)\left(4 \cos ^{2} 243^{\circ}-1\right) is
View answer and explanation
Correct option: D
36
Option D, 36, is the correct value of the given expression. This is found by using trigonometric identities to simplify the expression.
65 Easy
65 of 122
Application +4 | -1
The value of the series

cos⁡  12∘+cos⁡  84∘+cos⁡  132∘+cos⁡  156∘\cos \,\,12^\circ + \cos \,\,84^\circ + \cos \,\,132^\circ + \cos \,\,156^\circ is
View answer and explanation
Correct option: D
−12- \frac{1}{2}
Option D is correct because the sum of the cosine series simplifies to -1/2 using trigonometric identities.
66 Medium
66 of 122
Application +4 | -1
If a2+12a=cos⁡  θ\frac{{{a^2} + 1}}{{2a}} = \cos \,\,\theta, then a6+12a3=\frac{{{a^6} + 1}}{{2{a^3}}} =
View answer and explanation
Correct option: D
cos⁡  3θ\cos \,\,3\theta
Option D (cos⁡ 3θ\cos \,3\theta) is correct because by manipulating the given equation and using trigonometric identities, we can find that a6+12a3=cos⁡ 3θ\frac{{a^6 + 1}}{{2{a^3}}} = \cos \,3\theta.
67 Easy
67 of 122
Application +4 | -1
The value of     (1+cos  π8)  (1+cos  3π8)  (1+cos  5π8)  (1+cos  7π8)  \mathrm{\;\;}\left( {1 + \mathrm{cos}\,\,\frac{\mathrm{\pi }}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{3\mathrm{\pi }}}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{5\mathrm{\pi }}}{8}} \right)\,\,\left( {1 + \mathrm{cos}\,\,\frac{{7\mathrm{\pi }}}{8}} \right)\mathrm{\;} is equal to
View answer and explanation
Correct option: C
18\frac{1}{8}
Option D (nπ+π4n\pi \\ + \\ \frac{\pi }{4}) is correct because by simplifying the equation, we get tan⁡θ=1\tan \theta = 1, which gives the general solution θ=nπ+π4\theta = n\pi + \frac{\pi}{4}.
68 Hard
68 of 122
Analyzing +4 | -1
If cos⁡  x2  .  cos⁡  x22…..cos⁡  x2n=sin⁡  x2n  sin⁡    x2n\cos \,\,\frac{x}{2}\,\,.\,\,\cos \,\,\frac{x}{{{2^2}}} \ldots ..\cos \,\,\frac{x}{{{2^n}}} = \frac{{\sin \,\,x}}{{{2^n}\,\,\sin \;\,\,\frac{x}{{{2^n}}}}} , then

12  tan⁡  x2+122  tan⁡  x22+...+12n  tan⁡  x2n\frac{1}{2}\,\,\tan \,\,\frac{x}{2} + \frac{1}{{{2^2}}}\,\,\tan \,\,\frac{x}{{{2^2}}} + ... + \frac{1}{{{2^n}}}\,\,\tan \,\,\frac{x}{{{2^n}}} is
View answer and explanation
Correct option: B
12n  cot⁡  (x2n)−cot⁡  x\frac{1}{{{2^n}}}\,\,\cot \,\,\left( {\frac{x}{{{2^n}}}} \right) - \cot \,\,x
Option B (1/2^n cot(x/2^n) - cot x) is correct because by repeatedly using the identity tan x/2 = cot x/2 - 2cot x, the expression simplifies to the given form.
69 Easy
69 of 122
Application +4 | -1
The value of
cos⁡2  π16+cos⁡2  3π16+cos⁡2  5π16+cos⁡2  7π16{\cos ^2}\,\,\frac{\pi }{{16}} + {\cos ^2}\,\,\frac{{3\pi }}{{16}} + {\cos ^2}\,\,\frac{{5\pi }}{{16}} + {\cos ^2}\,\,\frac{{7\pi }}{{16}}
View answer and explanation
Correct option: A
2
Option A (2) is correct because using trigonometric identities, the expression simplifies to 2.
70 Easy
70 of 122
Analyzing +4 | -1
(1+cos⁡  π8)  (1+cos⁡  3 π8)  (1+cos⁡  5 π8)  (1+cos⁡  7π8)\left( {1 + \cos \,\,\frac{\pi }{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{3\,\pi }}{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{5\,\pi }}{8}} \right)\,\,\left( {1 + \cos \,\,\frac{{7\pi }}{8}} \right) is equal to
View answer and explanation
Correct option: C
18\frac{1}{8}
Option C (18\frac{1}{8}) is correct because the given expression simplifies to 18\frac{1}{8} using trigonometric identities and properties of cosine.
71 Medium
71 of 122
Application +4 | -1
If tan⁡θ+tan⁡(π3+θ)+tan⁡(−π3+θ)=atan⁡3θ,\tan \mathrm{\theta } + \tan \left( {\frac{\pi }{3} + \mathrm{\theta }} \right) + \tan \left( { - \frac{\pi }{3} + \mathrm{\theta }} \right) = a\tan 3\mathrm{\theta }, then aa is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because by simplifying the given trigonometric expression, we find that a=3a = 3.
72 Medium
72 of 122
Application +4 | -1
If   0∘<θ<180∘,    then  2  +  2  +  2  +  ...+2  (1+cos⁡  θ),\;0^\circ < \mathrm{\theta } < 180^\circ ,\;\;\mathrm{then}\,\,\sqrt {2\,\, + \,\,\sqrt {2\,\, + \,\,\sqrt {2\,\, + \,\,... + \sqrt {2\,\,\left( {1 + \cos \,\,\mathrm{\theta }} \right),} } } } then being n number of 2′ s\mathrm{2'}\,\mathrm{s}, is equal to

View answer and explanation
Correct option: A
2  cos⁡  (θ2n)2\,\,\cos \,\,\left( {\frac{\mathrm{\theta }}{{{2^n}}}} \right)
Option A (2cos⁡(θ2n)2\cos \left( {\frac{\mathrm{\theta }}{{{{2^n}}}}} \right)) is correct because the nested square roots simplify using trigonometric identities to this expression.
73 Easy
73 of 122
Application +4 | -1
If tan⁡x=ba\tan x=\frac{b}{a}, then a+ba−b+a−ba+b=\sqrt{\frac{a+b}{a-b}}+\sqrt{\frac{a-b}{a+b}}=
View answer and explanation
Correct option: B
2cos⁡xcos⁡2x\frac{2 \cos x}{\sqrt{\cos 2 x}}
Option B (2cos⁡xcos⁡2x\frac{{2 \cos x}}{{\sqrt{{\cos 2 x}}}}) is correct because, after using componendo and dividendo and simplifying, the expression equals 2cos⁡xcos⁡2x\frac{{2 \cos x}}{{\sqrt{{\cos 2 x}}}}.
74 Easy
74 of 122
Application +4 | -1
The value of   tan  20∘  tan⁡  40∘  tan⁡  60∘  tan⁡  80∘  \mathrm{\;tan}\,\,20^\circ \,\,\tan \,\,40^\circ \,\,\tan \,\,60^\circ \,\,\tan \,\,80^\circ \mathrm{\;} is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because the product of the tangent values simplifies to 3 using trigonometric identities.
75 Easy
75 of 122
Analyzing +4 | -1
If tan⁡  x=2ba−c,   a≠c\tan \,\,x = \frac{{2b}}{{a - c}},\,\;a \ne c and y=a  cos⁡2 x  +  2b  sin⁡  x  cos⁡  x  +  c  sin⁡2 xy = a\,\,{\cos ^2}\,x\,\, + \,\,2b\,\,\sin \,\,x\,\,\cos \,\,x\,\, + \,\,c\,\,{\sin ^2}\,x

z=a  sin⁡2 x  −  2b  sin⁡  x  cos⁡  x  +  c  cos⁡2 xz = a\,\,{\sin ^2}\,x\,\, - \,\,2b\,\,\sin \,\,x\,\,\cos \,\,x\,\, + \,\,c\,\,{\cos ^2}\,x, then
View answer and explanation
Correct option: C
y−z=a−cy - z = a - c
Option C (y−z=a−cy - z = a - c) is correct because simplifying the expression y−zy - z using trigonometric identities and the given condition tan⁡x=2ba−c\tan x = \frac{{2b}}{{a - c}} leads to the result a−ca - c.
76 Easy
76 of 122
Understanding +4 | -1
1+cos⁡22A1+\cos ^2 2 A is equal to
View answer and explanation
Correct option: C
2(cos⁡4 A+sin⁡4 A)2\left(\cos ^4 \mathrm{~A}+\sin ^4 \mathrm{~A}\right)
Option C (2(cos⁡4A+sin⁡4A)2(\cos ^4 A+\sin ^4 A)) is correct because it is the simplified form of the given expression using trigonometric identities.
77 Easy
77 of 122
Application +4 | -1
If cos⁡A=3/4\cos A=3 / 4 then value of 32sin⁡(A/2)sin⁡(5 A/2)32 \sin (A / 2) \sin (5 \mathrm{~A} / 2) is equal to
View answer and explanation
Correct option: C
11
Option C (11) is correct because it is the result of applying the product-to-sum trigonometric identity and simplifying using the given value of cos⁡A\cos A.
78 Medium
78 of 122
Application +4 | -1
The value of cos⁡4(π8)+cos⁡4(3π8)+\cos ^4\left(\frac{\pi}{8}\right)+\cos ^4\left(\frac{3 \pi}{8}\right)+ cos⁡4(5π8)+cos⁡4(7π8)\cos ^4\left(\frac{5 \pi}{8}\right)+\cos ^4\left(\frac{7 \pi}{8}\right) is equal to
View answer and explanation
Correct option: C
3/23 / 2
Option C (3/23/2) is the correct answer. The expression simplifies using trigonometric identities and the property that cos⁡(π−x)=−cos⁡(x)\cos(\pi - x) = -\cos(x) and cos⁡(π2−x)=sin⁡(x)\cos(\frac{\pi}{2} - x) = \sin(x).
79 Easy
79 of 122
Application +4 | -1
If sin    (x+y)sin⁡    (x−y)=a+ba−b\frac{{\mathrm{sin}\,\,\mathrm{\;}\left( {x + y} \right)}}{{\sin \,\,\;\left( {x - y} \right)}} = \frac{{a + b}}{{a - b}}, then tan⁡  xtan⁡  y\frac{{\tan \,\,x}}{{\tan \,\,y}} is equal to
View answer and explanation
Correct option: B
ab\frac{a}{b}
Option B (ab\frac{a}{b}) is correct because by applying the componendo and dividendo rule and trigonometric identities, the ratio of tangents simplifies to ab\frac{a}{b}.
80 Medium
80 of 122
Analyzing +4 | -1
The number of all possible ordered pairs (x, y),   x,  y∈R\left( {x,\,y} \right),\;\,x,\,\,y \in R satisfying the system of equations
x+y=2  π3,  cos⁡  x+cos⁡  y=32,   isx + y = \frac{{2\;\pi }}{3},\,\,\cos \,\,x + \cos \,\,y = \frac{3}{2},\;\,\mathrm{is}
View answer and explanation
Correct option: A
0
Option A (0) is correct because the given system of equations has no solution, as the second equation leads to an impossible value for cosine.
81 Medium
81 of 122
Application +4 | -1
If tan⁡x=ba\tan x = \frac{b}{a}, then the value of a  cos⁡  2x+b  sin⁡  2xa\,\,\cos \,\,2x + b\,\,\sin \,\,2x is
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Correct option: A
aa
Option A (aa) is correct because substituting the given value of tan⁡x\tan x and simplifying the expression results in aa.
82 Easy
82 of 122
Application +4 | -1
If 5cos⁡  2θ+2cos⁡2θ2+1=0,  −π<θ<π5\cos \,\,2\theta + 2{\cos ^2}\frac{\theta }{2} + 1 = 0,\; - \pi < \theta < \pi, then θ\theta is equal to

View answer and explanation
Correct option: D
π3,   π−cos⁡−1(35)\frac{\pi }{3},\;\,\pi - {\cos ^{ - 1}}\left( {\frac{3}{5}} \right)
Option D (π3,   π−cos⁡−1(35)\frac{\pi }{3},\;\,\pi - {\cos ^{ - 1}}\left( {\frac{3}{5}} \right)) is correct because it represents the solutions obtained by solving the given trigonometric equation within the specified interval.
83 Easy
83 of 122
Analyzing +4 | -1
If 2  cos⁡  A2=1+sin⁡  A+1−sin⁡  A2\,\,\cos \,\,\frac{A}{2} = \sqrt {1 + \sin \,\,A} + \sqrt {1 - \sin \,\,A}, then A2\frac{A}{2} lies between, (n∈Z)\left( {n \in Z} \right)
View answer and explanation
Correct option: B
2n  π−π42n\;\pi - \frac{\pi }{4} and 2n  π+π42n\;\pi + \frac{\pi }{4}
Option C (cot⁡B\cot B) is correct because simplifying the given expression using trigonometric identities leads to this result.
84 Medium
84 of 122
Application +4 | -1
The value of cos⁡210∘−cos⁡10∘cos⁡50∘+cos⁡250∘{\cos ^2}10^\circ - \cos 10^\circ \cos 50^\circ + {\cos ^2}50^\circ is
View answer and explanation
Correct option: D
34\frac{3}{4}
Option D (34\frac{{3}}{{4}}) is correct because the expression simplifies to this value using trigonometric identities.
85 Easy
85 of 122
Application +4 | -1
The value of 2+2+2+2cos⁡8θ\sqrt{2+\sqrt{2+\sqrt{2+2 \cos 8 \theta}}}, where 0<θ<π80 < \theta < \frac{\pi}{8}, is
View answer and explanation
Correct option: A
2cos⁡θ2 \cos \theta
Option A (2cos⁡θ2 \cos \theta) is correct because the nested square roots simplify to 2cos⁡θ2 \cos \theta using the double angle formula for cosine.
86 Easy
86 of 122
Application +4 | -1
The value of cos⁡  π15  cos⁡  2 π15  cos⁡  3 π15  cos⁡  4 π15  cos⁡  5 π15  cos⁡  6 π15  cos⁡  7π15\cos \,\,\frac{\pi }{{15}}\,\,\cos \,\,\frac{{2\,\pi }}{{15}}\,\,\cos \,\,\frac{{3\,\pi }}{{15}}\,\,\cos \,\,\frac{{4\,\pi }}{{15}}\,\,\cos \,\,\frac{{5\,\pi }}{{15}}\,\,\cos \,\,\frac{{6\,\pi }}{{15}}\,\,\cos \,\,\frac{{7\pi }}{{15}}, is
View answer and explanation
Correct option: A
1/1281/128
Option A (1/1281/128) is correct because the expression can be simplified using the identity ∏k=1n−1cos⁡(kπ2n)=n2n−1\prod_{k=1}^{n-1} \cos(\frac{k\pi}{2n}) = \frac{\sqrt{n}}{2^{n-1}}.
87 Easy
87 of 122
Application +4 | -1
If cos⁡  (θ−α),  cos⁡  θ,  cos⁡  (θ+α)\cos \,\,\left( {\theta - \alpha } \right),\,\,\cos \,\,\theta ,\,\,\cos \,\,\left( {\theta + \alpha } \right) are in H.P., then cos⁡  θ  sec⁡  (α2)\cos \,\,\theta \,\,\sec \,\,\left( {\frac{\alpha }{2}} \right) is equal to
View answer and explanation
Correct option: B
±   2\pm \;\,\sqrt 2
Option B (±   2\pm \;\,\sqrt 2) is correct because by using the harmonic progression property and trigonometric identities, the expression cos⁡ θ  sec⁡ (α2)\cos \,\theta \,\,\sec \,\left( {\frac{\alpha }{2}} \right) simplifies to ±   2\pm \;\,\sqrt 2.
88 Easy
88 of 122
Analyzing +4 | -1
If sin⁡x+sin⁡y=3(cos⁡y−cos⁡x)\sin x + \sin y = 3\left( {\cos y - \cos x} \right), then the value of sin⁡3xsin⁡3y\frac{{\sin 3x}}{{\sin 3y}} is
View answer and explanation
Correct option: B
−1- 1
Option B (-1) is correct because by simplifying the given equation, we find a relationship between x and y, allowing us to evaluate the expression.
89 Easy
89 of 122
Analyzing +4 | -1
The value of sin⁡  15 π32  sin⁡  7π16  sin⁡  3 π8\sin \,\,\frac{{15\,\pi }}{{32}}\,\,\sin \,\,\frac{{7\pi }}{{16}}\,\,\sin \,\,\frac{{3\,\pi }}{8} is
View answer and explanation
Correct option: A
18 2  cos⁡  (15π32)\frac{1}{{8\,\sqrt 2 \,\,\cos \,\,\left( {\frac{{15\pi }}{{32}}} \right)}}
Option A (182cos⁡(15π32)\frac{1}{{8\sqrt 2 \cos \left( {\frac{{15\pi }}{{32}}} \right)}}) is correct because it is derived by repeatedly applying the double angle formula for sine.
90 Medium
90 of 122
Application +4 | -1
If cot⁡θ=m+nm−n\cot \theta=\frac{\sqrt{m}+\sqrt{n}}{\sqrt{m}-\sqrt{n}}, then (m+n)cos⁡2θ(m+n) \cos 2 \theta is equal to
View answer and explanation
Correct option: A
2mn2 \sqrt{m n}
Option A (2mn2 \sqrt{mn}) is correct because by using the given equation and applying the double angle formula for cosine, the expression simplifies to 2mn2 \sqrt{mn}.
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