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JEE • MATHEMATICS • HYPERBOLA
Hyperbola practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 91-118 of 118 questions
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91
Medium
91 of 118
Application
+4 | -1
If the equation of the hyperbola is , then
I. the coordinates of the foci are
II. the length of the latus rectum is 18 units
III. the eccentricity is
I. the coordinates of the foci are
II. the length of the latus rectum is 18 units
III. the eccentricity is
View answer and explanation
Correct option: C
Only I and II is true
Option C is correct because statements I and II are true. The foci and latus rectum are correctly calculated, while the eccentricity is incorrect.
92
Medium
92 of 118
Application
+4 | -1
Equations of the asymptotes of the hyperbola is
View answer and explanation
Correct option: D
Option D () is correct because the equation of the asymptotes differs from the hyperbola by a constant, which is found using the condition for a pair of straight lines.
93
Medium
93 of 118
Application
+4 | -1
The mid point of the chord of the hyperbola is
View answer and explanation
Correct option: B
Option B (2,1) is correct because it satisfies the condition T=S1, where T is the equation of the chord with the given midpoint and S1 is the hyperbola equation with the midpoint coordinates.
94
Medium
94 of 118
Analyzing
+4 | -1
For different values of , the locus of the point of intersection of the two straight lines is
View answer and explanation
Correct option: A
a hyperbola with eccentricity 2
Option A (a hyperbola with eccentricity 2) is correct because the locus of the intersection point is a hyperbola, and its eccentricity is calculated to be 2.
95
Medium
95 of 118
Application
+4 | -1
is a point on the hyperbola . The tangent at meets the transverse axis at is the foot of the perpendicular from to the transverse axis. If is the origin, then is equal to.
View answer and explanation
Correct option: A
81
Option A (81) is correct because the product of ON and OT is calculated using the parametric coordinates of a point on the hyperbola and the equation of the tangent.
96
Medium
96 of 118
Application
+4 | -1
Any point on the hyperbola is of the form
View answer and explanation
Correct option: D
Option D () is correct because it represents a general point on the given hyperbola.
97
Medium
97 of 118
Application
+4 | -1
The product of the perpendiculars from the foci on any tangent to the hyperbola is
View answer and explanation
Correct option: B
9
Option B (9) is correct because the product of the perpendiculars from the foci to any tangent of the hyperbola is equal to .
98
Medium
98 of 118
Analyzing
+4 | -1
The locus of the point of intersection of the lines and is
View answer and explanation
Correct option: C
A hyperbola
Option C (A hyperbola) is correct because eliminating theta from the given equations results in the equation of a hyperbola.
99
Medium
99 of 118
Application
+4 | -1
The normal at on the hyperbola meets the coordinate axes at and . If , is the origin and , the eccentricity of the hyperbola, then
View answer and explanation
Correct option: A
Option A () is correct because the x-intercept of the normal is , which represents the distance OA.
100
Medium
100 of 118
Application
+4 | -1
Any point on the hyperbola is of the form
View answer and explanation
Correct option: B
Option B () is correct because it represents a general point on the given hyperbola after considering the shift in the center.
101
Medium
101 of 118
Application
+4 | -1
The condition that the straight line may be a normal to the hyperbola is given by
View answer and explanation
Correct option: A
Option A () is correct because it is the condition derived by comparing the general normal equation to the hyperbola with the given line equation.
102
Medium
102 of 118
Application
+4 | -1
Length of the straight line intercepted by the hyperbola is
View answer and explanation
Correct option: B
Option B () is correct because it is the distance between the intersection points of the line and the hyperbola.
103
Medium
103 of 118
Application
+4 | -1
The value of , for which the line is a normal to the conic , is
View answer and explanation
Correct option: B
Option D () is correct because substituting the point (8, 3√3) into the equation satisfies it, and it is the normal to the hyperbola at that point.
104
Medium
104 of 118
Application
+4 | -1
The area of the triangle formed by any tangent to the hyperbola with its asymptotes is
View answer and explanation
Correct option: D
Option D () is correct because the area of the triangle formed by the tangent to the hyperbola and its asymptotes is constant and equal to .
105
Medium
105 of 118
Application
+4 | -1
A common tangent to and , is
View answer and explanation
Correct option: B
Option B () is correct because it represents a line that is tangent to both the hyperbola and the circle.
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106
Medium
106 of 118
Analyzing
+4 | -1
Two conics and intersect, if
View answer and explanation
Correct option: B
Option A () is correct because the condition for intersection requires the discriminant of the resulting quadratic equation to be positive, leading to the inequality .
107
Medium
107 of 118
Analyzing
+4 | -1
The circle drawn on the line segment joining the foci of the hyperbola as diameter cuts the asymptotes at
View answer and explanation
Correct option: D
Option C () is correct because the circle intersects the asymptotes at these points.
108
Medium
108 of 118
Application
+4 | -1
The locus of point of intersection of straight lines and where is variable, is a
View answer and explanation
Correct option: C
Hyperbola
The correct answer is Hyperbola because multiplying the two given equations eliminates and results in the standard form of a hyperbola.
109
Medium
109 of 118
Application
+4 | -1
Find the equation of the hyperbola whose foci are and and eccentricity is 2 .
View answer and explanation
Correct option: A
Option A () is correct because it represents the equation of the hyperbola derived from the given foci and eccentricity.
110
Medium
110 of 118
Application
+4 | -1
The centre of the hyperbola is
View answer and explanation
Correct option: B
Option B ((-1,1)) is correct because it is the center of the hyperbola found by completing the square and rewriting the equation in standard form.
111
Medium
111 of 118
Application
+4 | -1
The product of perpendiculars drawn from any point of a hyperbola to its asymptotes is
View answer and explanation
Correct option: A
Option A () is correct because the product of the perpendiculars from any point on a hyperbola to its asymptotes is a constant value, which is given by the formula .
112
Medium
112 of 118
Application
+4 | -1
Locus of the mid-point of the chords of the hyperbola , that touch the parabola , is
View answer and explanation
Correct option: B
Option B () is correct because it represents the locus of the mid-point of the chords of the hyperbola that touch the parabola.
113
Medium
113 of 118
Application
+4 | -1
The equation of the tangents to the conic perpendicular to the line is
View answer and explanation
Correct option: A
Option A () is correct because it represents the tangent lines with a slope perpendicular to the given line, derived from the hyperbola equation.
114
Medium
114 of 118
Analyzing
+4 | -1
The curve with parametric equation and is
View answer and explanation
Correct option: C
A hyperbola
Option C is correct because eliminating the parameter 't' results in the equation of a hyperbola.
115
Medium
115 of 118
Application
+4 | -1
If a hyperbola passing through the origin has and as its assumptions, then the equation of the transverse axis of the hyperbola is
View answer and explanation
Correct option: B
Option B () is correct because the transverse axis is the bisector of the angle between the asymptotes that contains the origin.
116
Medium
116 of 118
Analyzing
+4 | -1
If a variable straight line which is a chord of hyperbola subtends a right angle at the centre of the hyperbola, then it always touches a fixed circle whose radius, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the radius of the circle that the variable straight line always touches when it subtends a right angle at the center of the hyperbola.
117
Medium
117 of 118
Application
+4 | -1
The equation of the chord of the hyperbola that is bisected at point is:
View answer and explanation
Correct option: B
Option B () is correct because it is the equation of the chord of the hyperbola bisected at the point (5,3), found using the formula T=S1.
118
Medium
118 of 118
Application
+4 | -1
If the tangent at the point to the hyperbola passes through the point where a directrix of the hyperbola meets the positive side of the transverse axis, then is equal to
Where is the eccentricity of the hyperbola.
Where is the eccentricity of the hyperbola.
View answer and explanation
Correct option: A
Option A () is correct because substituting the directrix point into the tangent equation and solving for gives .
Revision notes and key takeaways
Review HYPERBOLA in your textbook or class notes, then use this set to check your understanding.
Showing 91-118 of 118 questions
