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JEE • MATHEMATICS • HYPERBOLA
Hyperbola practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 271-298 of 298 questions
271
Easy
271 of 298
Application
+4 | -1
Equation of the chord of the hyperbola which is bisected at the point , is
View answer and explanation
Correct option: B
Option B () is correct because the equation of the chord bisected at a given point can be found using the formula .
272
Easy
272 of 298
Application
+4 | -1
If the eccentricity of a hyperbola is , then the eccentricity of its conjugate hyperbola is
View answer and explanation
Correct option: C
Option C () is correct because it is calculated using the relationship between the eccentricities of a hyperbola and its conjugate hyperbola: .
273
Easy
273 of 298
Application
+4 | -1
The locus of the foot of the perpendicular drawn from the origin to any tangent to the hyperbola is
View answer and explanation
Correct option: A
Option A () is correct because eliminating 'm' from the tangent and perpendicular line equations gives this locus.
274
Easy
274 of 298
Application
+4 | -1
are respectively the eccentricities of the hyperbola and the ellipse . If and , then is equal to
View answer and explanation
Correct option: C
Option C () is correct because by finding the eccentricities and in terms of and using the given relation , we can solve for .
275
Easy
275 of 298
Application
+4 | -1
A hyperbola whose transverse axis is along the major axis of the conic and has vertices at the foci of the conic. If the eccentricity of the hyperbola is , then which of the following points does not lie on it?
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Correct option: B
Option B is correct because when substituted into the hyperbola equation, it does not satisfy the equation, indicating it does not lie on the hyperbola.
276
Easy
276 of 298
Understanding
+4 | -1
The difference in focal distances of any point on the hyperbola is
View answer and explanation
Correct option: A
8
Option A (8) is correct because the difference in focal distances of any point on a hyperbola is equal to the length of its transverse axis (2a).
277
Easy
277 of 298
Understanding
+4 | -1
A point on the curve is
View answer and explanation
Correct option: B
Option B () is correct because substituting and into the equation satisfies the equation.
278
Easy
278 of 298
Application
+4 | -1
The equation of the tangent to the hyperbola at the point (1,0), is
View answer and explanation
Correct option: A
Option A () is the correct answer because substituting the point (1,0) into the equation of the tangent yields .
279
Easy
279 of 298
Application
+4 | -1
If in a hyperbola, the distance between the foci is 10 and the transverse axis has length 8, then the length of its latusrectum is
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Correct option: B
Option B () is correct because using the given information to find 'a' and 'b' and then applying the latus rectum formula results in 9/2.
280
Easy
280 of 298
Application
+4 | -1
If the chords of contact of tangents from two points and to the hyperbola are at right angles, then is equal to
View answer and explanation
Correct option: D
Option D () is correct because the product of the slopes of the chords of contact is -1, leading to the given ratio.
281
Easy
281 of 298
Analyzing
+4 | -1
The line is tangent to the hyperbola . If this line passes through the point of intersection of the nearest directrix and the -axis, then the eccentricity of the hyperbola is
View answer and explanation
Correct option: B
2
Option B (2) is correct because by using the tangent condition and the fact that the line passes through the directrix intersection with the x-axis, we can solve for the eccentricity.
282
Easy
282 of 298
Understanding
+4 | -1
If and are the eccentricities of a hyperbola and its conjugate, then is equal to
View answer and explanation
Correct option: C
1
Option C (1) is correct because for a hyperbola and its conjugate.
283
Easy
283 of 298
Application
+4 | -1
The tangents to the hyperbola are parallel to the straight line at the following points:
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Correct option: B
Option B () is correct because these are the points where tangents parallel to the given line touch the hyperbola, calculated using the tangent's slope.
284
Easy
284 of 298
Application
+4 | -1
If represents the equation of a hyperbola and the joint equation of its asymptotes and the conjugate hyperbola respectively, then for any point in the plane, , and are in
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Correct option: A
A.P.
Option A (A.P.) is correct because the relationship between the hyperbola, its asymptotes, and the conjugate hyperbola results in an arithmetic progression.
285
Easy
285 of 298
Application
+4 | -1
The line touches the hyperbola at the point
View answer and explanation
Correct option: B
Option B () is correct because the point satisfies the equation of the tangent to the hyperbola at that point.
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286
Easy
286 of 298
Application
+4 | -1
The area of the triangle formed by the asymptotes and any tangent to the hyperbola is
View answer and explanation
Correct option: D
Option D is correct because the area of the triangle formed by the asymptotes and any tangent to the hyperbola is .
287
Easy
287 of 298
Application
+4 | -1
The line touches the hyperbola , if
View answer and explanation
Correct option: A
Option A () is correct because it represents the condition for the line to be tangent to the hyperbola.
288
Easy
288 of 298
Application
+4 | -1
If the chords of contact of the tangents from two points and to the hyperbola are at right angles. Then is equal to
View answer and explanation
Correct option: B
0
Option B (0) is correct because the condition for perpendicularity of the chords of contact leads to the equation .
289
Easy
289 of 298
Application
+4 | -1
The equation of the hyperbola referred to its axes as axes of coordinates whose distance between the foci is 16 and eccentricity , is
View answer and explanation
Correct option: B
Option B () is correct because given the distance between foci and eccentricity, the equation of the hyperbola can be derived as .
290
Easy
290 of 298
Application
+4 | -1
The equation to the hyperbola having its eccentricity 2 and the distance between its foci is 8, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the equation of a hyperbola with the given eccentricity and distance between foci.
291
Easy
291 of 298
Application
+4 | -1
The eccentricity of the hyperbola conjugate to is
View answer and explanation
Correct option: C
2
Option C (2) is correct because the eccentricity of the conjugate hyperbola is calculated after finding the equation of the conjugate hyperbola.
292
Easy
292 of 298
Remembering
+4 | -1
The curve is said to be
View answer and explanation
Correct option: B
A rectangular hyperbola
Option B (A rectangular hyperbola) is correct because the equation represents a rectangular hyperbola.
293
Easy
293 of 298
Application
+4 | -1
The distance between the foci of the conic is equal to
View answer and explanation
Correct option: A
8
Option A (8) is correct because it is the distance between the foci of the hyperbola, calculated using the formula 2ae.
294
Easy
294 of 298
Application
+4 | -1
The diameter of which is conjugate to is
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Correct option: B
Option B () is correct because it represents the diameter conjugate to the given diameter of the hyperbola.
295
Easy
295 of 298
Understanding
+4 | -1
The locus of the equation is
View answer and explanation
Correct option: B
a hyperbola
Option C (a pair of lines) is correct because the equation x² - y² = 0 can be factored into (x - y)(x + y) = 0, representing two straight lines.
296
Easy
296 of 298
Understanding
+4 | -1
The locus of a point which moves such that the difference of its distances from two fixed points is always a constant, is
View answer and explanation
Correct option: C
a hyperbola
Option D (Centre and vertices only) is correct because both the ellipse and hyperbola share the same center (0,0) and vertices (+-5, 0).
297
Easy
297 of 298
Analyzing
+4 | -1
If tangent to any member of family of hyperbolas is not a normal to any member of family of circles , where is any real parameter, then belongs to
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the given condition holds true for all the specified intervals of .
298
Easy
298 of 298
Application
+4 | -1
The equation of the diameter which is conjugate to w.r.t. the hyperbola , is
View answer and explanation
Correct option: A
Option A is correct because the equation of the conjugate diameter is found using the relation .
Revision notes and key takeaways
Review HYPERBOLA in your textbook or class notes, then use this set to check your understanding.
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