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JEE • MATHEMATICS • FUNCTIONS

Functions practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 353 questions

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211 Medium
211 of 353
Understanding +4 | -1
f  :[−4,0]→Rf\;:\left[ { - 4,0} \right] \to R is given byf(x)=ex+sin⁡x,f\left( x \right) = {e^x} + \sin x, its even extension to [−4,4],\left[ { - 4,4} \right], is
View answer and explanation
Correct option: B
e−∣x∣−sin⁡∣x∣{e^{ - \left| x \right|}} - \sin \left| x \right|
Option B (e−∣x∣−sin⁡∣x∣{e^{ - \left| x \right|}} - \sin \left| x \right|) is correct because it defines the even extension of the given function over the specified interval.
212 Medium
212 of 353
Application +4 | -1
If cos⁡2x−asin⁡x=2a−7\cos 2 x-a \sin x=2 a-7, then range of aa is
View answer and explanation
Correct option: B
2≤a≤62 \leq a \leq 6
Option B (2≤a≤62 \leq a \leq 6) is correct because it is derived from the condition −1≤sin⁡x≤1-1 \leq \sin x \leq 1 after simplifying the given trigonometric equation.
213 Medium
213 of 353
Application +4 | -1
Let A≡{1,2,3,4},B≡{a,b,c}A \equiv\{1,2,3,4\}, B \equiv\{a, b, c\}, then number of functions from A→BA \rightarrow B, which are not onto i
View answer and explanation
Correct option: C
45
Option C (45) is correct because it calculates the total number of functions from A to B and subtracts the number of onto functions.
214 Medium
214 of 353
Application +4 | -1
Let f(x)=αxx+1,x≠1f(x)=\frac{\alpha x}{x+1}, x \neq 1. Then for what value of α\alpha, is f(f(x))=x?f(f(x))=x ?
View answer and explanation
Correct option: D
−1-1
Option D (-1) is correct because when alpha is -1, f(f(x)) simplifies to x.
215 Medium
215 of 353
Application +4 | -1
The domain of the function f(x  )=log⁡2x−1(x−1)f\left( {x\;} \right) = {\log _{2x - 1}}\left( {x - 1} \right) is
View answer and explanation
Correct option: A
(1,  ∞)\left( {1,\;\infty } \right)
Option D (None of these) is incorrect. Option A (1,  ∞)\left( {1,\;\infty } \right) is correct because the argument of the logarithm and the base must be positive and the base cannot be 1.
216 Medium
216 of 353
Understanding +4 | -1
If f:R→R&g:R→Rf: \mathbb{R} \rightarrow \mathbb{R} \& \quad g: \mathbb{R} \rightarrow \mathbb{R} be two given functions, then 2min⁡{f(x)−g(x),0}2 \min \{f(x)-g(x), 0\} equals
View answer and explanation
Correct option: D
f(x)−g(x)−∣g(x)−f(x)∣f(x)-g(x)-|g(x)-f(x)|
Option D is correct because it uses the identity min(a, b) = (a+b-|a-b|)/2 and simplifies the expression.
217 Medium
217 of 353
Understanding +4 | -1
Which of the following statement is true (T)(\mathrm{T}) or false (F)(\mathrm{F}) for the function f:R→Rf: \mathrm{R} \rightarrow \mathrm{R} ?
(i) If ∣f(x)−f(y)∣≤30∣x−y∣,∀x,y∈R|f(x)-f(y)| \leq 30|x-y|, \forall x, y \in \mathrm{R}, then ff is a continuous function on R\mathrm{R}.
(ii) If ∣f(x)−f(y)∣≤30∣x−y∣,∀x,y∈R|f(x)-f(y)| \leq 30|x-y|, \forall x, y \in \mathrm{R}, then ff is differentiable on R\mathrm{R}.
(iii) If ∣f(x)−f(y)∣≤21∣x−y∣2,∀x,y∈R|f(x)-f(y)| \leq 21|x-y|^2, \forall x, y \in \mathbb{R}, then ff is differentiable on R\mathrm{R}.
(iv) If ∣f(x)−f(y)∣≤21∣x−y∣2,∀x,y∈R|f(x)-f(y)| \leq 21|x-y|^2, \forall x, y \in \mathrm{R}, then ff is a constant function.
View answer and explanation
Correct option: B
TFTT
Option B (TFTT) is correct because statement (i) is true, statement (ii) is false, and statements (iii) and (iv) are true based on the given conditions.
218 Medium
218 of 353
Application +4 | -1
If f(x)={x}+{x+1}+{x+2}……..x+99}f(x)=\{x\}+\{x+1\}+\{x+2\} \ldots \ldots . . x+99\}, then the value of [f(2)][f(\sqrt{2})] is, where {\{.}\} denotes fractional part function & [.][.] denotes the greatest integer function

View answer and explanation
Correct option: C
41
Option B (41) is correct because the fractional part of 2\sqrt{2} is used to evaluate the function, and then the greatest integer function is applied.
219 Medium
219 of 353
Application +4 | -1
If f:R→Rf: R \rightarrow R is given by f(x)=3x−5f(x)=3 x-5, then f−1(x)f^{-1}(x) ?
View answer and explanation
Correct option: B
Is given by x+53\frac{x+5}{3}
Option B (x+53\frac{{x+5}}{{3}}) is correct because it represents the inverse function obtained by swapping xx and yy and solving for yy.
220 Medium
220 of 353
Application +4 | -1
Suppose that g(x)=1+xg(x)=1+\sqrt{x} and f(g(x))=3+2x+xf(g(x))=3+2 \sqrt{x}+x, then f(x)f(x) is:
View answer and explanation
Correct option: B
2+x22+x^2
The correct answer is B (2+x22+x^2). By substituting y=1+xy = 1 + \sqrt{x} into the given equation, we can find the expression for f(x)f(x).
221 Medium
221 of 353
Application +4 | -1
The range of the function f(x)=12−cos⁡3  x,f\left( x \right) = \frac{1}{{2 - \cos 3\;x}}, is
View answer and explanation
Correct option: C
[1/3,  1]\left[ {1/3,\;1} \right]
Option C ([1/3,  1]\left[ {1/3,\;1} \right]) is correct because the range is found by determining the minimum and maximum values of the function based on the cosine function's range.
222 Medium
222 of 353
Analyzing +4 | -1
The range of the function f(x)=x1+x2,x∈Rf(x)=\frac{x}{1+x^2}, x \in \mathbb{R} is
View answer and explanation
Correct option: A
[−12,12]\left[-\frac{1}{2}, \frac{1}{2}\right]
Option A ([-1/2, 1/2]) is correct because the range of the function is between -1/2 and 1/2, inclusive.
223 Medium
223 of 353
Application +4 | -1
The domain of the function f(x)=sin⁡−1(log⁡3(x/3))f\left( x \right) = {\sin ^{ - 1}}\left( {{{\log }_3}\left( {x/3} \right)} \right) is
View answer and explanation
Correct option: A
[1,  9]\left[ {1,\;9} \right]
Option A ([1, 9]) is correct because the argument of the arcsine function must be between -1 and 1, leading to the inequality -1 <= log_3(x/3) <= 1, which simplifies to 1 <= x <= 9.
224 Medium
224 of 353
Application +4 | -1
If f(2x+3y,2x−7y)=20xf(2 x+3 y, 2 x-7 y)=20 x, then f(x,y)f(x, y) equals
View answer and explanation
Correct option: B
7x+3y7 x+3 y
Option B (9C5{ }^9 {C}_5) is correct because it is the difference between the number of 5-digit numbers with digits in descending order and the number of 5-digit numbers with digits in ascending order.
225 Medium
225 of 353
Application +4 | -1
The value of the function f(x)=3sin⁡(π216−x2)f\left( x \right) = 3\sin \left( {\sqrt {\frac{{{\pi ^2}}}{{16}} - {x^2}} } \right) lies in the interval
View answer and explanation
Correct option: B
[0,  3/2]\left[ {0,\;3/\sqrt 2 } \right]
Option B ([0, 3/√(2)]) is correct because it represents the range of the function, considering the domain restriction and the sine function's properties.
226 Medium
226 of 353
Application +4 | -1
If f(x)=xf(x)=x and g(x)=∣x∣g(x)=|x|, then (f+g)(x)(f+g)(x) is equal to
View answer and explanation
Correct option: C
{2x, for x≥00, for x<0\left\{\begin{array}{l}2 x, \text { for } x \geq 0 \\ 0, \text { for } x < 0\end{array}\right.
Option C ({2x, for x≥00, for x<0\left\{\begin{array}{l}2 x, \text { for } x \geq 0 \\ 0, \text { for } x < 0\end{array}\right.) is correct because it correctly defines the sum of the functions f(x) = x and g(x) = |x| for all real x.
227 Medium
227 of 353
Application +4 | -1
∣2x−3∣<∣x+5∣,\left| {2x - 3} \right| < \left| {x + 5} \right|, then xx belongs to
View answer and explanation
Correct option: C
(−23,8)\left( { - \frac{2}{3},8} \right)
Option C (−23,8)\left( { - \frac{2}{3},8} \right) is correct because it represents the solution set of the inequality after considering different cases based on the absolute values.
228 Medium
228 of 353
Understanding +4 | -1
Let A={1,2,3,4}A=\{1,2,3,4\} and RR be the relation on AA defined by {(a,b):a,b∈A,a×b\{(a, b): a, b \in A, a \times b is an even number }\}, then the range of RR is
View answer and explanation
Correct option: B
{2,4}\{2,4\}
Option B ({2,4}\{2,4\}) is correct because the range of the relation R consists of the second elements of the ordered pairs (a, b) where a * b is even.
229 Medium
229 of 353
Analyzing +4 | -1
The range of the function [4x−2x+1+1]\left[4^x-2^{x+1}+1\right] is, where [.] represents the greatest integer function is
View answer and explanation
Correct option: B
Whole numbers
Option B (Whole numbers) is correct because the function simplifies to the square of a real number inside the greatest integer function, which always results in a non-negative integer.
230 Medium
230 of 353
Application +4 | -1
If f(x)f\left( x \right) is defined on [0,  1],\left[ {0,\;1} \right], then the domain of definition of f(tan⁡x)f\left( {\tan x} \right) is
View answer and explanation
Correct option: A
[n  π,n  π+π/4],  n∈Z\left[ {n\;\pi ,n\;\pi + \pi /4} \right],\;n \in Z
Option A ([nπ,nπ+π/4],  n∈Z[n \pi ,n \pi + \pi /4],\;n \in Z) is correct because it defines the interval where 0≤tan⁡x≤10 \le \tan x \le 1.
231 Medium
231 of 353
Application +4 | -1
A real valued function f(x)f(x) satisfies the function equation f(x−y)=f(x)f(y)−f(a−x)f(a+y)f(x-y)=f(x) f(y)-f(a-x) f(a+y) where aa is a given constant and f(0)=1,f(2a−x)f(0)=1, f(2 a-x) is equal to
View answer and explanation
Correct option: C
−f(x)-f(x)
Option C (−f(x)-f(x)) is correct because substituting f(0)=1f(0)=1 and f(a)=0f(a)=0 into the given functional equation leads to f(2a−x)=−f(x)f(2a-x) = -f(x).
232 Medium
232 of 353
Application +4 | -1
If f(x)=sin⁡log⁡xf(x)=\sin \log x, then the value of f(xy)+f(xy)−2f(x)⋅cos⁡log⁡yf(x y)+f\left(\frac{x}{y}\right)-2 f(x) \cdot \cos \log y is equal to
View answer and explanation
Correct option: B
0
Option B (0) is correct because the expression simplifies to 0 after applying trigonometric identities and the properties of logarithms.
233 Medium
233 of 353
Understanding +4 | -1
The domain of F(x)=log⁡2(x+3)x2+3x+2F(x)=\frac{\log _2(x+3)}{x^2+3 x+2} is
View answer and explanation
Correct option: D
(−3,∞)−{−1,−2}(-3, \infty)-\{-1,-2\}
Option D ((−3,∞)−{−1,−2}(-3, \infty)-\{-1,-2\}) is correct because the argument of the logarithm must be positive, and the denominator cannot be zero.
234 Medium
234 of 353
Analyzing +4 | -1
The number of functions f:{1,2,3,4}→{a∈:Z∣α∣≤8}f:\{1,2,3,4\} \rightarrow\{a \in: \mathbb{Z}|\alpha| \leq 8\} satisfying f(n)+1nf(n+1)=1,∀n∈{1,2,3}f(n)+\frac{1}{n} f(n+1)=1, \forall n \in\{1,2,3\} is
View answer and explanation
Correct option: B
2
Option B (2) is correct because only two functions satisfy the given conditions and constraints.
235 Medium
235 of 353
Application +4 | -1
The range of the function 7−xPx−3{ }^{7-x} P_{x-3} is
View answer and explanation
Correct option: A
{1,2,3}\{1,2,3\}
Option A is correct because the range of the function is {1, 2, 3} by evaluating the permutation for valid x values.
236 Medium
236 of 353
Application +4 | -1
The least integer satisfying 49.4−(27−x10)<47.4−(27−9x10),49.4 - \left( {\frac{{27 - x}}{{10}}} \right) < 47.4 - \left( {\frac{{27 - 9x}}{{10}}} \right), is
View answer and explanation
Correct option: B
3
The correct answer is B (3) because solving the inequality results in x > 2.5, and the least integer satisfying this is 3.
237 Medium
237 of 353
Application +4 | -1
If f(x)=x−1x+1f(x)=\frac{x-1}{x+1}, then f(f(ax))f(f(a x)) is equal to
View answer and explanation
Correct option: C
f(x)−1a(f(x)+1)\frac{f(x)-1}{a(f(x)+1)}
The correct answer is C (f(x)−1a(f(x)+1)\frac{{f(x)-1}}{{a(f(x)+1)}}) because it is the result of correctly substituting f(x)f(x) into the composite function f(f(ax))f(f(ax)).
238 Medium
238 of 353
Application +4 | -1
The domain of the function f(x)=sin⁡−1{log⁡2(12x2)}f(x)=\sin ^{-1}\left\{\log _2\left(\frac{1}{2} x^2\right)\right\} is
View answer and explanation
Correct option: C
[−2,−1]∪[1,2][-2,-1] \cup[1,2]
Option C ([-2,-1]∪\cup[1,2]) is correct because it represents the domain for which the function is defined, considering the logarithmic and inverse sine functions.
239 Medium
239 of 353
Analyzing +4 | -1
If x,y ∈{1,2,3,4},x,y\, \in \left\{ {1,2,3,4} \right\}, then which ofthe following is/are function(s) in the given set?
View answer and explanation
Correct option: D
f4={(x,y):x+y=5}f_4=\{(x, y): x+y=5\}
Option D (f4={(x,y):x+y=5}f_4=\{(x, y): x+y=5\}) is the correct answer because it represents a function where each element in the domain maps to a unique element in the codomain.
240 Medium
240 of 353
Analyzing +4 | -1
The set of all values of ' aa 'for which the roots of the equation (a+1)x2−3ax+4a=0(a≠−1)(a+1) x^2-3 a x+4 a=0(a \neq-1) are real and greater than 1 is
View answer and explanation
Correct option: C
[−167,−1)\left[\frac{-16}{7},-1\right)
Option C ([−167,−1)\left[\frac{{-16}}{{7}},-1\right)) is correct because it satisfies the conditions for the roots to be real and greater than 1, considering the discriminant and the vertex of the quadratic.
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