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JEE • MATHEMATICS • FUNCTIONS

Functions practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Easy
91 of 478
Analyzing +4 | -1
Let f:R−{3}→R−{1}f:R - \{ 3\} \to R - \{ 1\} be defined by f(x)=x−2x−3f(x) = \frac{{x - 2}}{{x - 3}}. Let g:R→Rg:R \to R be given as g(x)=2x−3g(x) = 2x - 3. Then, the sum of all the values of xx for which f−1(x)+g−1(x)=132{f^{ - 1}}(x) + {g^{ - 1}}(x) = \frac{{13}}{2} is equal to
View answer and explanation
Correct option: C
5
Option C (5) is correct because by finding the inverse functions and solving the given equation, the sum of the solutions is 5.
92 Easy
92 of 478
Analyzing +4 | -1
If f:(0,π)→Rf:(0, \pi) \rightarrow \mathbf{R} is given by f(x)=∑k=1n[1+sin⁡kx],[x]f(x)=\sum\limits_{{k=1}}^n[1+\sin k x],[x] denotes the greatest integer function, then the range of f(x)f(x) is
View answer and explanation
Correct option: C
{n,n+1}\{n, n+1\}
Option C ({n,n+1}\left\{n, n+1\right\}) is correct because the function f(x) can take two values, n when all [sin⁡kx]=0[\sin kx] = 0, and n+1 when one of the [sin⁡kx]=1[\sin kx] = 1 and the rest are 0.
93 Easy
93 of 478
Application +4 | -1
The range of f(x)=cos⁡x−sin⁡xf(x)=\cos x-\sin x is
View answer and explanation
Correct option: D
[−2,2][-\sqrt{2}, \sqrt{2}]
Option D ([-2\sqrt{2}, 2\sqrt{2}]) is correct because the range of f(x) = cos(x) - sin(x) is between -√2 and √2.
94 Easy
94 of 478
Application +4 | -1
If f(x)=2x+13x−2f(x)=\frac{2 x+1}{3 x-2}, then (f∘f)(2)(f \circ f)(2) is equal to
View answer and explanation
Correct option: D
2
Option D (2) is correct because when you evaluate the composite function f(f(x))f(f(x)) at x=2x = 2, the result is 2.
95 Easy
95 of 478
Application +4 | -1
Let the function ff be defined by f(x)=2x+11−3xf(x)=\frac{2 x+1}{1-3 x}, then f−1(x)f^{-1}(x) is
View answer and explanation
Correct option: A
x−13x+2\frac{x-1}{3 x+2}
Option A is correct because solving for x in terms of y and swapping x and y gives f−1(x)=x−13x+2f^{-1}(x) = \frac{x-1}{3x+2}.
96 Easy
96 of 478
Application +4 | -1
If f(x)=x−1x,x≠0,f\left( x \right) = x - \frac{1}{x},x \ne 0, then f(x2)f\left( {{x^2}} \right) equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because f(x2)f(x^2) does not equal any of the given expressions.
97 Easy
97 of 478
Application +4 | -1
If f(x)f\left( x \right) is an odd periodic function with period 2, then f(4)f\left( 4 \right) equals
View answer and explanation
Correct option: A
0
The correct answer is A (0) because an odd periodic function with period 2 has the property f(0) = 0, and f(4) = f(0) due to periodicity.
98 Easy
98 of 478
Application +4 | -1
The domain of the function
f(x)=sin⁡1(x−3)9−x2f\left( x \right) = \frac{{{{\sin }^1}\left( {x - 3} \right)}}{{\sqrt {9 - {x^2}} }} is
View answer and explanation
Correct option: B
[2,3)\left[ {2,\mathrm{ }3} \right)
Option B ([2, 3)) is correct because it satisfies both the domain of the arcsine function and the square root function.
99 Easy
99 of 478
Application +4 | -1
Let n(A)=4 and n(B)=6n\left( A \right) = 4\,and\,n\left( B \right) = 6. The number of one to one functions from A to B is
View answer and explanation
Correct option: D
360
Option D (360) is correct because it is the number of ways to choose 4 elements from 6 and arrange them.
100 Easy
100 of 478
Application +4 | -1
If a function F is such that F(0)=2,  F(1)=3,  F(n+2)=2F(n)−F(n+1)  for  n≠0F\left( 0 \right) = 2,\;F\left( 1 \right) = 3,\;F\left( {n + 2} \right) = 2F\left( n \right) - F\left( {n + 1} \right)\;for\;n \ne 0, then F(5)F\left( 5 \right) is equal to
View answer and explanation
Correct option: D
13
Option D (13) is correct because by iteratively applying the given recurrence relation, we find that F(5) equals 13.
101 Easy
101 of 478
Application +4 | -1
If g(x)=1+x  and  f(g(x))=3+2x+xg\left( x \right) = 1 + \sqrt x \;and\;f\left( {g\left( x \right)} \right) = 3 + 2\sqrt x + x then, f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: B
2+x22 + {x^2}
Option B is correct because by substituting g(x) into f(g(x)), we can solve for f(x) to find it equals 2 + x².
102 Easy
102 of 478
Application +4 | -1
If af(x+1)+bf(1x+1)=x,x≠−1,a≠ba f(x+1)+b f\left(\frac{1}{x+1}\right)=x, x \neq-1, a \neq b, then f(2)f(2) is equal to
View answer and explanation
Correct option: A
2a+b2(a2−b2)\frac{2 a+b}{2\left(a^2-b^2\right)}
Option A (2a+b2(a2−b2)\frac{{2a+b}}{{2(a^2-b^2)}}) is correct because it is the value of f(2)f(2) obtained by solving the given functional equation.
103 Easy
103 of 478
Understanding +4 | -1
Assertion: The function f:R→Rf: R \rightarrow R given by f(x)=x3f(x)=x^3 is injective.

Reason: The function f:X→Yf: X \rightarrow Y is injective, if f(x)=f(y)f(x)=f(y) ⇒x=y\Rightarrow {x}={y} for all x,y∈X{x},{y} \in {X}.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct
explanation for assertion
Option A is correct because the assertion is true, the reason is true, and the reason correctly explains why the function f(x) = x3 is injective.
104 Easy
104 of 478
Application +4 | -1
If 3<3t−18≤183 < 3t - 18 \le 18, then which one of the following is true?
View answer and explanation
Correct option: C
8≤t+1≤138 \le t + 1 \le 13
The correct answer is C (8≤t+1≤138 \le t + 1 \le 13) because it is derived by solving the given compound inequality and then adding 1 to each part.
105 Easy
105 of 478
Application +4 | -1
If f(x)=3x−5f(x)=3 x-5, then f−1(x)f^{-1}(x)
View answer and explanation
Correct option: B
Is given by x+53\frac{x+5}{3}
Option B is correct because it represents the inverse function f−1(x)f^{-1}(x) obtained by solving for x in terms of y and swapping x and y.
106 Easy
106 of 478
Application +4 | -1
Let f(x)f(x) is a monic polynomial of degree =5=5 such that f(1)=1,f(2)=2,f(3)=3f(1)=1, f(2)=2, f(3)=3, f(4)=4f(4)=4 and f(5)=5f(5)=5. If f(6)=5!+λf(6)=5 !+\lambda, then find the value of λ\lambda.
View answer and explanation
Correct option: A
6
Option A (6) is correct because the value of λ\lambda is found by constructing a polynomial that satisfies the given conditions and then evaluating it at x=6.
107 Easy
107 of 478
Understanding +4 | -1
If f  :R→Rf\;:R \to R is defined by f(x)=2x−2[x]f\left( x \right) = 2x - 2\left[ x \right] for all x∈R,x \in R, where [x]\left[ x \right] denotes the greatest integer less than or equal to xx, then range of ff, is
View answer and explanation
Correct option: B
{0,  1}\left\{ {0,\;1} \right\}
Option B (\{0, 1\}) is correct because the range of the function f(x)=2x−2[x]f(x) = 2x - 2[x] is \{0, 1\}.
108 Easy
108 of 478
Application +4 | -1
If f(x)=1(1−x),g(x)=f{f(x)}f(x)=\frac{1}{(1-x)}, g(x)=f\{f(x)\} and h(x)=f[f{f(x)}]h(x)=f[f\{f(x)\}]. Then the value of f(x)⋅g(x)⋅h(x)f(x) \cdot g(x) \cdot h(x) is
View answer and explanation
Correct option: B
-1
Option B (-1) is correct because by finding g(x) and h(x) in terms of f(x), the product f(x) * g(x) * h(x) simplifies to -1.
109 Easy
109 of 478
Application +4 | -1
The maximum value attained by the function y=10−∣x−10∣y=10-|x-10|, if −9≤x≤9-9 \leq x \leq 9, is
View answer and explanation
Correct option: B
9
Option B is correct because the maximum value of the function is attained when x is 9, resulting in y = 9.
110 Easy
110 of 478
Analyzing +4 | -1
The domain of definition of f(x)=log⁡1.7(2−ϕ′(x)x+1)1/2,f\left( x \right) = {\log _{1.7}}{\left( {\frac{{2 - \phi '\left( x \right)}}{{x + 1}}} \right)^{1/2}}, where ϕ(x)=x33−32x2−2x+32,\phi \left( x \right) = \frac{{{x^3}}}{3} - \frac{3}{2}{x^2} - 2x + \frac{3}{2}, is
View answer and explanation
Correct option: C
(−∞,−1)∪(−1,  4)\left( { - \infty , - 1} \right) \cup \left( { - 1,\;4} \right)
Option C is correct. The domain requires 2−ϕ′(x)x+1>0\frac{{2 - \phi'(x)}}{{x + 1}} > 0. After finding ϕ′(x)\phi'(x) and simplifying, we get (x−4)(x+1)x+1<0\frac{{(x - 4)(x + 1)}}{{x + 1}} < 0, which leads to x<4x < 4 and x≠−1x \neq -1.
111 Easy
111 of 478
Application +4 | -1
Let f(n)=[13+3n100]nf(n)=\left[\frac{1}{3}+\frac{3 n}{100}\right] n, where [n][\mathrm{n}] denotes the greatest integer less than or equal to nn. Then ∑n=156f(n)\sum_{n=1}^{56} f(n) is equal to:
View answer and explanation
Correct option: D
1399
Option D (1399) is correct because by evaluating the function for different ranges of n and summing the results, we arrive at the value 1399.
112 Easy
112 of 478
Understanding +4 | -1
The number of surjection from
A={1,2\mathrm{A}=\{1,2...., n},n≥2\mathrm{n}\}, \mathrm{n} \geq 2 onto B={a,b}\mathrm{B}=\{\mathrm{a}, \mathrm{b}\} is
View answer and explanation
Correct option: B
2n−22^{\mathrm{n}}-2
Option B (2n−22^{\mathrm{n}}-2) is correct because it represents the number of surjective mappings from a set A with n elements to a set B with 2 elements, calculated using the inclusion-exclusion principle.
113 Easy
113 of 478
Application +4 | -1
Given f(x)=log⁡(1+x1−x)  and  g(x)=3  x+x31+3  x2,f\left( x \right) = \log \left( {\frac{{1 + x}}{{1 - x}}} \right)\;and\;g\left( x \right) = \frac{{3\;x + {x^3}}}{{1 + 3\;{x^2}}}, then fog(x)fog\left( x \right) equals
View answer and explanation
Correct option: B
3  f(x)3\;f\left( x \right)
Option B (3f(x)3f(x)) is correct because the composition of the functions simplifies to 3log⁡(1+x1−x)3 \log \left( {\frac{{1 + x}}{{1 - x}}} \right).
114 Easy
114 of 478
Application +4 | -1
If f:IR→IRf: I R \rightarrow I R is defined by f(x)=3x−4f(x)=3 x-4, then f−1:IR→IRf^{-1}: I R \rightarrow I R is
View answer and explanation
Correct option: B
x+43\frac{x+4}{3}
Option B is correct because it represents the inverse function f−1(x)f^{-1}(x) obtained by solving for x in terms of y and swapping x and y.
115 Easy
115 of 478
Application +4 | -1
The number of surjections from A={1,2,…,n},n≥2A=\{1,2, \ldots, n\}, n \geq 2 onto B={a,b}B=\{a, b\} is
View answer and explanation
Correct option: B
2n−22^n-2
Option B (2n−22^n-2) is correct because it represents the total number of functions from A to B minus the functions that map all elements of A to a single element in B.
116 Easy
116 of 478
Application +4 | -1
If f(x)=ax+a−x2f(x)=\frac{a^x+a^{-x}}{2} and f(x+y)+f(x−y)=Kf(x)f(x+y)+f(x-y)=K f(x) f(y)f(y) then KK is equal to
View answer and explanation
Correct option: A
2
Option A (2) is correct because substituting the given function into the equation and simplifying leads to K = 2.
117 Easy
117 of 478
Understanding +4 | -1
Let f(x){f}({x}) be a differentiable even function. Consider the following statements:

(I) f′(x){f}^{\prime}({x}) is an even function.

(II) f′(x){f}^{\prime}({x}) is an odd function.

(III) f′(x){f}^{\prime}({x}) may be even or odd.

Which of the above statements is/are correct?
View answer and explanation
Correct option: B
Only II
Option B is correct because the derivative of an even function is always an odd function.
118 Easy
118 of 478
Application +4 | -1
If f(x)=cos⁡[π2]x+cos⁡[−π2]xf(x)=\cos \left[\pi^{2}\right] x+\cos \left[-\pi^{2}\right] x, then
View answer and explanation
Correct option: D
f(π2)=−1f\left(\frac{\pi}{2}\right)=-1
Option D (f(π2)=−1f(\frac{\pi}{2})=-1) is correct because substituting x=π2x = \frac{\pi}{2} into the simplified function yields -1.
119 Easy
119 of 478
Application +4 | -1
If f:R→Rf:R \to R be a mapping defined by f(x)=x3+5,f\left( x \right) = {x^3} + 5, then f−1(x){f^{ - 1}}\left( x \right) is equal to
View answer and explanation
Correct option: B
(x−5)1/3{\left( {x - 5} \right)^{1/3}}
The correct answer is B ((x−5)1/3(x - 5)^{1/3}) because it is the inverse function obtained by solving for x in terms of y and then swapping x and y.
120 Easy
120 of 478
Analyzing +4 | -1
Let f:R→R\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R} be defined by f(x)=∣x∣−1∣x∣+1f(x)=\frac{|\mathrm{x}|-1}{|\mathrm{x}|+1} then f\mathrm{f} is:
View answer and explanation
Correct option: C
onto but not one-one
Option C (onto but not one-one) is correct because the function is surjective (onto) but not injective (one-to-one).
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