Skip to main content
Back to DIFFERENTIATION

Your Progress

0 / 500 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • DIFFERENTIATION

Differentiation practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 181-210 of 500 questions

Preparing practice and saved progress…

181 Easy
181 of 500
Application +4 | -1
A particle is moving along the parabola y2=4(x+2)y^2=4(x+2). As it passes through the point (7,6)(7,6) its yy-coordinate is increasing at the rate of 3 units per second. The rate at which xx-coordinate change at this instant is (in units/sec)
View answer and explanation
Correct option: D
9
Option D (9) is correct because it's the rate of change of the x-coordinate, calculated using implicit differentiation.
182 Easy
182 of 500
Application +4 | -1
The derivative of f(x)=3∣2+x∣f(x)=3|2+x| at the point x0=−3x_{0}=-3 is
View answer and explanation
Correct option: B
-3
Option B (-3) is correct because the derivative of the function at x=-3 is calculated considering the absolute value function.
183 Easy
183 of 500
Application +4 | -1
Let ff be a bijection satisfying f′(x)=f(x)f^{\prime}(x)=f(x). Then, (f−1)′′(x)\left(f^{-1}\right)^{\prime \prime}(x) is equal to
View answer and explanation
Correct option: B
−1x2-\frac{1}{x^2}
Option B is correct because it correctly applies the derivative rules for inverse functions and uses the given condition f'(x) = f(x).
184 Easy
184 of 500
Application +4 | -1
Let f:R→Rf: R \rightarrow R be a function given by f(x+y)=f(x)f(y)f(x+y)=f(x) f(y) for all x,y∈Rx, y \in R

If f(x)≠0f(x) \neq 0 for all x∈Rx \in R and f′(0)f^{\prime}(0) exists, then f′(x)f^{\prime}(x) equals
View answer and explanation
Correct option: B
f(x)f′(0)f(x) f^{\prime}(0) for all x∈Rx \in R
Option B is correct because differentiating f(x+y)=f(x)f(y)f(x+y)=f(x)f(y) leads to f′(x)=f(x)f′(0)f'(x) = f(x)f'(0) for all x∈Rx \in R.
185 Easy
185 of 500
Application +4 | -1
If f(x+y)=f(x)⋅f(y)∀x⋅yf(x+y)=f(x) \cdot f(y) \forall x \cdot y and f(5)=2f(5)=2, f′(0)=3f^{\prime}(0)=3, then f′(5)f^{\prime}(5) is
View answer and explanation
Correct option: C
6
Option C (6) is correct because f′(5)f'(5) is calculated to be 6 using the given functional equation and derivative at 0.
186 Easy
186 of 500
Application +4 | -1
If f(x)=log⁡∣2x∣,x≠0f(x)=\log |2 x|, x \neq 0 then f′(x)f^{\prime}(x) is equal to
View answer and explanation
Correct option: A
11\frac{1}{1}
The correct answer is D (None of these). The derivative of f(x)=log⁡∣2x∣f(x) = \log |2x| is 1x\frac{{1}}{{x}} for all x≠0x \neq 0. However, the provided option A is also 1x\frac{{1}}{{x}}, so there is a typo in the options.
187 Easy
187 of 500
Application +4 | -1
ddxcos⁡−1x−x−1x+x−1\frac{d}{d x} \cos ^{-1} \frac{x-x^{-1}}{x+x^{-1}} is equal to
View answer and explanation
Correct option: D
−21+x2\frac{-2}{1+x^{2}}
Option D (−21+x2\frac{{-2}}{{1+x^{2}}}) is correct because by substituting x=cot⁡θx = \cot \theta, the expression simplifies to 2θ2\theta, and its derivative is −21+x2\frac{{-2}}{{1+x^{2}}}.
188 Easy
188 of 500
Analyzing +4 | -1
If f(x)=xn,f\left( x \right) = {x^n}, then the value of f(1)−f′(1)1!+f′′(1)2!−f′′′(1)3!+…+(−1)nfn(1)n!f\left( 1 \right) - \frac{{f'\left( 1 \right)}}{{1!}} + \frac{{f''\left( 1 \right)}}{{2!}} - \frac{{f'''\left( 1 \right)}}{{3!}} + \ldots + \frac{{{{\left( { - 1} \right)}^n}{f^n}\left( 1 \right)}}{{n!}} is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the expression is equivalent to the binomial expansion of (1-1)^n which equals 0.
189 Easy
189 of 500
Analyzing +4 | -1
Let ff be a twice differentiable function such that f′′(x)=−f(x)f''\left( x \right) = - f\left( x \right) and f′(x)=g(x).f'\left( x \right) = \mathrm{g}\left( x \right). If h′(x)=[f(x)2+g(x)2]h(1)=8h'\left( x \right) = \left[ {f{{\left( x \right)}^2} + \mathrm{g}{{\left( x \right)}^2}} \right]h\left( 1 \right) = 8 and h(0)=2,h\left( 0 \right) = 2, then h(2)h\left( 2 \right) is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because after solving the differential equation and using the given conditions, we find that h(2)=14h(2) = 14, which is not among the provided options.
190 Easy
190 of 500
Understanding +4 | -1
Which of the following is/are true?

I. The derivative of sin⁡(x+a)\sin (x+a) is cos⁡(x+a)\cos (x+a), where aa is a fixed non-zero constant.

II. The derivative of cosec⁡xcot⁡x\operatorname{cosec} x \cot x is cosec⁡3x−cot⁡2xcosec⁡x\operatorname{cosec}^3 x-\cot ^2 x \operatorname{cosec} x
View answer and explanation
Correct option: B
Only I is true
Option B (Only I is true) is correct because the derivative of sin(x+a) is cos(x+a), while the derivative of cosec(x)cot(x) is -cosec3(x) - cot2(x)cosec(x).
191 Easy
191 of 500
Application +4 | -1
If y=5xx5,y = {5^x}{x^5},, then dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: D
5x(x5log⁡5+5x4){5^x}({x^5}\log 5 + 5{x^4})
Option D (5x(x5log⁡5+5x4)){5^x}({x^5}\log 5 + 5{x^4})) is correct because it is the result of applying the product rule and differentiating each term correctly.
192 Easy
192 of 500
Analyzing +4 | -1
If f(x)f\left( x \right) and g(x)g\left( x \right) are two functions with g(x)=x−1xg\left( x \right) = x - \frac{1}{x} and fog(x)=x3−1x3,fo\mathrm{g}\left( x \right) = {x^3} - \frac{1}{{{x^3}}}, then f′(x)f'\left( x \right) is
View answer and explanation
Correct option: A
3x2+33{x^2} + 3
Option A (3x2+33{x^2} + 3) is correct because by substituting g(x)g(x) into f(g(x))f(g(x)) and simplifying, we find f(x)=x3+3xf(x) = x^3 + 3x, and thus f′(x)=3x2+3f'(x) = 3x^2 + 3.
193 Easy
193 of 500
Application +4 | -1
If y=(sin⁡x)tan⁡xy=(\sin x)^{\tan x}, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: A
(sin⁡x)tan⁡x⋅(1+sec⁡2x⋅log⁡sin⁡x)(\sin x)^{\tan x} \cdot\left(1+\sec ^{2} x \cdot \log \sin x\right)
Option A is correct because it is the result of logarithmic differentiation and simplification.
194 Easy
194 of 500
Application +4 | -1
If y=sec⁡x−tan⁡xsec⁡x+tan⁡x,y = \frac{{\sec x - \tan x}}{{\sec x + \tan x}}, then dydx\frac{{dy}}{{dx}} equals
View answer and explanation
Correct option: B
−2sec⁡x(sec⁡x−tan⁡x)2- 2\sec x{(\sec x - \tan x)^2}
Option B (−2sec⁡x(sec⁡x−tan⁡x)2- 2\sec x{(\sec x - \tan x)^2}) is correct because it is the derivative of the given function y with respect to x, obtained after simplification and applying the chain rule.
195 Easy
195 of 500
Analyzing +4 | -1
If f(x)=sin⁡−1(2x1−x2),x∈[−1,1]f(x)=\sin ^{-1}\left(2 x \sqrt{1-x^2}\right), x \in[-1,1] Then,
View answer and explanation
Correct option: B
f′(x)={21−x2, if ∣x∣<12−21−x2, if 12<∣x∣<1f^{\prime}(x)=\left\{\begin{array}{l}\frac{2}{\sqrt{1-x^2}}, \text { if }|x|<\frac{1}{\sqrt{2}} \\ \frac{-2}{\sqrt{1-x^2}}, \text { if } \frac{1}{\sqrt{2}}<|x|<1\end{array}\right.
Option B is correct because the derivative of arcsin(2x*sqrt(1-x2)) is piecewise, being 2/sqrt(1-x2) for |x|<1/sqrt(2) and -2/sqrt(1-x2) for 1/sqrt(2)<|x|<1 due to the properties of arcsin.
196 Easy
196 of 500
Application +4 | -1
If G(x)=25−x2G\left( x \right) = \sqrt {25 - {x^2}}, then lim⁡x→1G(x)−G(1)x−1\lim\limits_{x \to 1} \frac{{G\left( x \right) - G\left( 1 \right)}}{{x - 1}} has the value
View answer and explanation
Correct option: A
124\frac{1}{{\sqrt {24} }}
Option D (−1/5- 1/5) is correct because the limit represents the derivative of G(x) evaluated at x=1.
197 Easy
197 of 500
Analyzing +4 | -1
Let f(x)={sin⁡(x−[x])x−[x],x∈(−2,−1)max⁡   {2x,3[∣x∣]},∣x∣<11,other  wisef(x) = \left\{ {\begin{array}{cccccccccccccccccccc} {\frac{{\sin (x - [x])}}{{x - [x]}},}&{x \in ( - 2, - 1)} \\ {\max \,\,\,\left\{ {2x,3\left[ {\left| x \right|} \right]} \right\},}&{\left| x \right| < 1} \\ {1,}&{{\text{other}}\,\,{\text{wise}}} \end{array}} \right.
Where [t][t] denotes greatest integer ⩽t.\leqslant t. If mm is the number of points where ff is not continuous and nn is the number of points where ff is not differentiable, then the ordered pair (m,n)(m,n) is
View answer and explanation
Correct option: C
(2, 3)
Option C ((2, 3)) is correct because the function f(x) is discontinuous at two points and not differentiable at three points.
198 Easy
198 of 500
Analyzing +4 | -1
If y2=ax2+bx+c,{y^2} = a{x^2} + bx + c, where a,b,ca,b,c are constants,then y3d2ydx2{y^3}\frac{{{d^2}y}}{{d{x^2}}} is equal to
View answer and explanation
Correct option: A
a constant
Option A (a constant) is correct because after differentiating twice and simplifying, y3d2ydx2{y^3}\frac{{{d^2}y}}{{d{x^2}}} equals a constant value of 4ac−b24\frac{{4ac - {b^2}}}{4}.
199 Easy
199 of 500
Application +4 | -1
If ex−y=xye^{x-y}=x^y, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: C
log⁡x(1+log⁡x)2\frac{\log x}{(1+\log x)^2}
Option C (log⁡x(1+log⁡x)2\frac{\log x}{(1+\log x)^2}) is correct because taking the logarithm and differentiating leads to this result.
200 Easy
200 of 500
Analyzing +4 | -1
The set of all points where the function f(x)=x∣x∣f(x)=x|x| is twice differentiable is
View answer and explanation
Correct option: B
(−∞,0)∪(0,∞)(-\infty, 0) \cup(0, \infty)
Option B ((−∞,0)∪(0,∞)) is correct because the second derivative exists everywhere except at x=0, making the function twice differentiable on that interval.
201 Easy
201 of 500
Application +4 | -1
If the greatest value of x2−x+cx2+x+c\frac{x^2-x+c}{x^2+x+c} is 53\frac{5}{3}, then find the value of cc.
View answer and explanation
Correct option: A
4
Option A (4) is correct because solving the inequality derived from the given condition yields c = 4.
202 Easy
202 of 500
Application +4 | -1
If f(x)=sin⁡{π3[x]−x2}f(x)=\sin \left\{\frac{\pi}{3}[x]-x^2\right\} for 2<x<32 < x < 3 and [x][x] denotes the greatest integer less than or equal to xx, then f′(π/3)f^{\prime}(\sqrt{\pi / 3}) is equal to
View answer and explanation
Correct option: B
−π/3-\sqrt{\pi / 3}
Option B (−π/3-\sqrt{\pi / 3}) is correct because it is the value of the derivative of the function f(x)f(x) at x=π/3x = \sqrt{\pi / 3}.
203 Easy
203 of 500
Analyzing +4 | -1
f(x)=∣x3x43x21−64pp2p3∣f\left( x \right) = \left| {\begin{array}{cccccccccccccccccccc} {{x^3}}&{{x^4}}&{3{x^2}}\\ 1&{ - 6}&4\\ p&{{p^2}}&{{p^3}} \end{array}} \right|, here pp is a constant, then d4f(x)dx4\frac{{{d^4}f\left( x \right)}}{{d{x^4}}} is
View answer and explanation
Correct option: D
A constant
The correct answer is 'A constant' because after taking the fourth derivative of the determinant, the resulting expression is a constant value.
204 Easy
204 of 500
Application +4 | -1
If xxyyzz=c{x^x}{y^y}{z^z} = c, then ∂z∂x\frac{{\partial z}}{{\partial x}} is equal to
View answer and explanation
Correct option: B
−(1+log⁡x1+log⁡z)- \left( {\frac{{1 + \log x}}{{1 + \log z}}} \right)
Option B (−(1+log⁡x1+log⁡z)-(\frac{{1 + \log x}}{{1 + \log z}})) is correct because it is the result of partially differentiating the given equation with respect to x and solving for ∂z∂x\frac{{\partial z}}{{\partial x}}.
205 Easy
205 of 500
Application +4 | -1
If f(x)=exg(x),g(0)=2,g′(0)=1f(x)=e^x g(x), g(0)=2, g^{\prime}(0)=1, then f′(0)f^{\prime}(0) is
View answer and explanation
Correct option: B
3
Option B (3) is correct because it is the value of the derivative of f(x) at x=0, calculated using the product rule and the given values of g(0) and g'(0).
206 Easy
206 of 500
Analyzing +4 | -1
If y=sin⁡[cos⁡−1{sin⁡(cos⁡−1x)}],y = \sin [{\cos ^{ - 1}}\{ \sin ({\cos ^{ - 1}}x)\} ], then dydx\frac{{dy}}{{dx}} at x=12x = \frac{1}{2} is equal to
View answer and explanation
Correct option: D
1
Option D (1) is correct because after simplifying the given expression, y becomes equal to x, hence its derivative is 1.
207 Easy
207 of 500
Understanding +4 | -1
Let ff be the function on [0,1][0,1] given by f(x)=f(x)= xsin⁡πxx \sin \frac{\pi}{x} for x≠0x \neq 0 and f(0)=0f(0)=0. Then ff is
View answer and explanation
Correct option: D
continuous and bounded
Option D (continuous and bounded) is correct because the function f(x)f(x) is continuous on the interval [0,1][0,1] and its absolute value is bounded by ∣x∣|x|.
208 Easy
208 of 500
Application +4 | -1
If y=cos⁡−19−x29+x2y=\cos ^{-1} \frac{9-x^2}{9+x^2} then y′(−1)y^{\prime}(-1) is equal to
View answer and explanation
Correct option: A
−3/5-3 / 5
Option A (-3/5) is correct because after simplifying the inverse cosine function and differentiating, substituting x=-1 yields -3/5.
209 Easy
209 of 500
Understanding +4 | -1
If y=sin⁡−1x2+cos⁡−1x2,y = {\sin ^{ - 1}}\frac{x}{2} + {\cos ^{ - 1}}\frac{x}{2}, then the value of dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the expression simplifies to a constant, and the derivative of a constant is zero.
210 Easy
210 of 500
Application +4 | -1
Let f(x)=x2+px+qf(x)=x^2+p x+q. The value of (p,q)(p, q) so that f(1)=3f(1)=3 is an extreme value of ff on [0,2][0,2] is
View answer and explanation
Correct option: C
(−2,4)(-2,4)
Option C ((-2,4)) is correct because the given conditions f(1)=3 and f'(1)=0 lead to p=-2 and q=4.
Revision notes and key takeaways

Review DIFFERENTIATION in your textbook or class notes, then use this set to check your understanding.

Showing 181-210 of 500 questions

Your practice

0 / 500 answered · 500 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.