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JEE • MATHEMATICS • DIFFERENTIATION

Differentiation practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Easy
91 of 500
Application +4 | -1
If 2f(x)=f′(x)2f\left( x \right) = f'\left( x \right) and f(0)=3,f\left( 0 \right) = 3, then f(2)f\left( 2 \right) is equal to
View answer and explanation
Correct option: A
3e43{e^4}
Option A (3e43{e^4}) is correct because it satisfies the given differential equation and initial condition.
92 Easy
92 of 500
Application +4 | -1
If y=xxxxx...y=x^{x^{x^{x^{x^{...}}}}}, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: C
yx(1+ylog⁡x)\frac{y}{x(1+y \log x)}
Option B is correct because it is derived by taking the logarithm of both sides and then differentiating implicitly.
93 Easy
93 of 500
Application +4 | -1
If y=x+x+x,x>0y=\sqrt{x+\sqrt{x+\sqrt{x}}}, x > 0, then dy/dxd y / d x at x=1x=1 is
View answer and explanation
Correct option: A
121+2(3+4242)\frac{1}{2 \sqrt{1+\sqrt{2}}}\left(\frac{3+4 \sqrt{2}}{4 \sqrt{2}}\right)
Option A is correct because it is the result of applying the chain rule multiple times and evaluating the derivative at x=1.
94 Easy
94 of 500
Application +4 | -1
If y=cot⁡−1(x2)y=\cot ^{-1}\left(x^2\right), then dydx\frac{d y}{d x} is equal to :
View answer and explanation
Correct option: C
−2x1+x4\frac{-2 x}{1+x^4}
Option C (−2x1+x4\frac{{-2 x}}{{1+x^4}}) is correct because it is the derivative of arccot(x2) using the chain rule.
95 Easy
95 of 500
Application +4 | -1
ddxlog⁡(log⁡x)\frac{d}{d x} \log (\log x) is equal to
View answer and explanation
Correct option: C
(xlog⁡x)−1(x \log x)^{-1}
Option C ((xlog⁡x)−1(x \log x)^{-1}) is correct because the derivative of log⁡(log⁡x)\log(\log x) is 1log⁡x⋅1x\frac{1}{\log x} \cdot \frac{1}{x}, which simplifies to (xlog⁡x)−1(x \log x)^{-1}.
96 Easy
96 of 500
Application +4 | -1
If y=sin⁡−1(sin⁡αsin⁡x1−cos⁡αsin⁡x)y=\sin ^{-1}\left(\frac{\sin \alpha \sin x}{1-\cos \alpha \sin x}\right), then y′(0)y^{\prime}(0) is
View answer and explanation
Correct option: D
sin⁡α\sin \alpha.
Option D (sin⁡α\sin \alpha) is correct because it is the value of the derivative of yy with respect to xx evaluated at x=0x=0.
97 Easy
97 of 500
Application +4 | -1
Let f(x)=118−x2f\left( x \right) = \frac{1}{{\sqrt {18 - {x^2}} }}. The value of lim⁡x→3f(x)−f(3)x−3\lim\limits_{x \to 3} \frac{{f\left( x \right) - f\left( 3 \right)}}{{x - 3}}, is
View answer and explanation
Correct option: D
19\frac{1}{9}
Option D (19\frac{1}{9}) is correct because the limit is the derivative of f(x)f(x) evaluated at x=3x=3, which equals 19\frac{1}{9}.
98 Easy
98 of 500
Application +4 | -1
If f(x)=1+cos⁡2(x2),f\left( x \right) = \sqrt {1 + {{\cos }^2}\left( {{x^2}} \right)} , then f′(π2)f'\left( {\frac{{\sqrt \pi }}{2}} \right) is
View answer and explanation
Correct option: B
−π6- \sqrt {\frac{\pi }{6}}
Option B (−π6- \sqrt {\frac{\pi }{6}}) is correct because it's the result of applying the chain rule and evaluating the derivative at the given point.
99 Easy
99 of 500
Application +4 | -1
If a function is represented parametrically by the equations
x=1+tt3,y=32t2+2tx=\frac{1+t}{t^3}, \quad y=\frac{3}{2 t^2}+\frac{2}{t} then
View answer and explanation
Correct option: B
x(dydx)3=1+dydxx\left(\frac{d y}{d x}\right)^3=1+\frac{d y}{d x}
Option B (x(dydx)3=1+dydxx(\frac{{d y}}{{d x}})^3=1+\frac{{d y}}{{d x}}) is correct because after finding dydx\frac{{dy}}{{dx}} and substituting in the given equation, it satisfies the equation.
100 Easy
100 of 500
Application +4 | -1
If 2x+2y=2x+y2^x+2^y=2^{x+y}, then the value of dydx\frac{d y}{d x} at x=yx=y =1=1 is
View answer and explanation
Correct option: B
-1
Option B (-1) is correct because after differentiating the given equation and substituting x=y=1, the value of dy/dx is -1.
101 Easy
101 of 500
Analyzing +4 | -1
If y=x+y+x+y+…∞y=\sqrt{x+\sqrt{y+\sqrt{x+\sqrt{y+\ldots \infty}}}}, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: D
None of these
The correct answer is D (None of these) because the derivative calculated does not match any of the given options.
102 Easy
102 of 500
Analyzing +4 | -1
Let f(x)=log⁡e(sin⁡x),(0<x<π)f(x) = {\log _e}(\sin x),(0 < x < \pi ) and g(x)=sin⁡−1(e−x),(x≥0)g(x) = {\sin ^{ - 1}}({e^{ - x}}),(x \ge 0). If α\alpha is positive real number
such that a=(fog)′(α)a = (fog)'(\alpha ) and b=(fog)(α)b = (fog)(\alpha ), then
View answer and explanation
Correct option: B
aα2−bα−a=1a{\alpha ^2} - b\alpha - a = 1
Option B (aα2−bα−a=1a{\alpha ^2} - b\alpha - a = 1) is correct because the given functions are composed and simplified, then differentiated and evaluated at α\alpha to satisfy the equation.
103 Easy
103 of 500
Application +4 | -1
ddx(sin⁡x1+cos⁡x)=\frac{d}{d x}\left(\frac{\sin x}{1+\cos x}\right)=
View answer and explanation
Correct option: A
12sec⁡2x2\frac{1}{2} \sec ^{2} \frac{x}{2}
Option A (1/2 sec2(x/2)) is correct because the derivative of sin(x)/(1+cos(x)) simplifies to tan(x/2), and the derivative of tan(x/2) is 1/2 sec2(x/2).
104 Easy
104 of 500
Analyzing +4 | -1
The derivative of tan⁡−1(1+x2−1x){\tan ^{ - 1}}\left( {\frac{{\sqrt {1 + {x^2}} - 1}}{x}} \right) with respect to tan⁡−1(2x1−x21−2x2){\tan ^{ - 1}}\left( {\frac{{2x\sqrt {1 - {x^2}} }}{{1 - 2{x^2}}}} \right) at x=12x = \frac{1}{2} is
View answer and explanation
Correct option: D
310 \frac{{\sqrt 3 }}{{10}}\,
Option D is correct because after simplification using trigonometric substitutions and differentiation, the derivative evaluates to 310\frac{{\sqrt 3 }}{{{{10}}}} at x=12x = \frac{1}{2}.
105 Easy
105 of 500
Application +4 | -1
If f(x)=log⁡x{ln⁡(x)}f(x)=\log _x\{\ln (x)\}, then f′(x)f^{\prime}(x) at x=ex=e, is
View answer and explanation
Correct option: D
e−1e^{-1}
Option D (e−1e^{-1}) is correct because after applying the change of base formula and differentiating, the value of the derivative at x=e is 1/e.
106 Easy
106 of 500
Application +4 | -1
If f(x)=cot⁡−1(xx−x−x2)f(x)=\cot ^{-1}\left(\frac{x^x-x^{-x}}{2}\right), then f′(1)f^{\prime}(1) equals
View answer and explanation
Correct option: A
−1-1
Option A (-1) is correct because it is the value of the derivative of the given function, evaluated at x=1.
107 Easy
107 of 500
Application +4 | -1
If x=a[cos⁡θ+log⁡tan⁡θ2],x=a\left[\cos \theta+\log \tan \frac{\theta}{2}\right], y=asin⁡θy=a \sin \theta then dydx=\frac{d y}{d x}=
View answer and explanation
Correct option: C
tan⁡θ\tan \theta
Option C (tan⁡θ\tan \theta) is correct because it is the result of calculating dydx\frac{{dy}}{{dx}} using parametric differentiation.
108 Easy
108 of 500
Application +4 | -1
If f(x)=log⁡a(log⁡ax)f\left( x \right) = {\log _a}\left( {{{\log }_a}x} \right), then f′(x)f'\left( x \right) is
View answer and explanation
Correct option: A
log⁡aexlog⁡ex\frac{{{{\log }_a}e}}{{x{{\log }_e}x}}
Option A (log⁡aexlog⁡ex\frac{{{{\log }_a}e}}{{x{{\log }_e}x}}) is correct because it is the correct derivative of the given logarithmic function using the chain rule and change of base formula.
109 Easy
109 of 500
Application +4 | -1
If x2+y2=1x^2+y^2=1, then
View answer and explanation
Correct option: B
yy′′+(y′)2+1=0y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0
Option B (y y'' + (y')2 + 1 = 0) is correct because it is the result of differentiating the given equation twice and simplifying.
110 Easy
110 of 500
Application +4 | -1
If y=21/log⁡x4y=2^{1 / \log _{x} 4}, then xx is equal to
View answer and explanation
Correct option: C
y2y^{2}
Option C is correct because it is the result of simplifying the expression using properties of logarithms.
111 Easy
111 of 500
Application +4 | -1
ddx(x+1x)2\frac{d}{d x}\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)^{2} is equal to
View answer and explanation
Correct option: A
1−1x21-\frac{1}{x^{2}}
The correct answer is A (1−1x21-\frac{1}{x^{2}}) because it is the result of differentiating the given expression after simplifying it.
112 Easy
112 of 500
Application +4 | -1
Let f(x)f(x) be a differentiable function such that f′(x)=sin⁡x+sin⁡4xcos⁡xf^{\prime}(x)=\sin x+\sin 4 x \cos x. Then, f′(2x2+π2)f^{\prime}\left(2 x^2+\frac{\pi}{2}\right) at x=π2x=\sqrt{\frac{\pi}{2}} is equal to
View answer and explanation
Correct option: C
−22π-2 \sqrt{2 \pi}
Option C is correct because it correctly applies the chain rule and trigonometric identities to find the derivative and evaluate it at the given point.
113 Easy
113 of 500
Analyzing +4 | -1
If y1/m=[x+1+x2]y^{1 / m}=\left[x+\sqrt{1+x^2}\right], then (1+x2)y2+xy1\left(1+x^2\right) y_2+x y_1 is equal to
View answer and explanation
Correct option: A
m2ym^2 y
Option A (m2ym^2 y) is correct because it is the result of differentiating the given equation twice and simplifying using the given relation.
114 Easy
114 of 500
Analyzing +4 | -1
If y=tan⁡−1(log⁡(ex2)log⁡(ex2))+tan⁡−1(3+2log⁡x1−6log⁡x)y = {\tan ^{ - 1}}\left( {\frac{{\log \left( {\frac{e}{{{x^2}}}} \right)}}{{\log \left( {e{x^2}} \right)}}} \right) + {\tan ^{ - 1}}\left( {\frac{{3 + 2\log x}}{{1 - 6\log x}}} \right), then d2ydx2\frac{{{d^2}y}}{{d{x^2}}} is
View answer and explanation
Correct option: C
0
Option C (0) is correct because after simplifying the expression for y, we find that y is a constant, and therefore its second derivative is 0.
115 Easy
115 of 500
Application +4 | -1
Differential coefficient of sec⁡x\sqrt {\sec \sqrt x } is
View answer and explanation
Correct option: B
14x(sec⁡x)32.sin⁡x\frac{1}{{4\sqrt x }}{\left( {\sec \sqrt x } \right)^{\frac{3}{2}}}.\sin \sqrt x
Option B (14x(sec⁡x)32.sin⁡x\frac{1}{{4\sqrt x }}{\left( {\sec \sqrt x } \right)^{\frac{3}{2}}}.\sin \sqrt x) is correct because it correctly applies the chain rule to find the derivative of the given function.
116 Easy
116 of 500
Application +4 | -1
If ff and gg are differentiable functions such that g′(a)=2g^{\prime}(a)=2 and g(a)=bg(a)=b and if f∘gf \circ g is an identity function, then f′(b)f^{\prime}(b) has the value equal to
View answer and explanation
Correct option: D
1/21 / 2
Option D (12\frac{1}{2}) is correct because it is the value of f'(b) calculated using the properties of inverse functions and the chain rule.
117 Easy
117 of 500
Application +4 | -1
If the parametric equation of a curve given by x=et  cost,  y=etsin⁡tx = {e^t}\;\mathrm{cost},\;y = {e^t}\sin t then the tangent to the curve at the point t=π/4t = \pi /4 makes with axis of xx the angle
View answer and explanation
Correct option: D
π2\frac{\pi }{2}
Option D (π2\frac{\pi}{2}) is correct because the tangent at t = π4\frac{\pi}{4} has an infinite slope, indicating a vertical line.
118 Easy
118 of 500
Application +4 | -1
If x=cos⁡θ,y=sin⁡3θx=\cos \theta, y=\sin ^3 \theta, then (dy dx)2+yd2y dx2\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)^2+y \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2} at θ=π/2\theta=\pi / 2 is
View answer and explanation
Correct option: D
-3
Option D (-3) is correct because after finding the first and second derivatives and substituting θ=π2\theta = \frac{{\pi}}{{2}}, the expression evaluates to -3.
119 Easy
119 of 500
Application +4 | -1
Let ff and gg be differentiable functions satisfying g′(a)=2,g(a)=bg'\left( a \right) = 2,g\left( a \right) = b and fog=Ifog = I (identify function). Then, f′(b)f'\left( b \right) is equal to
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A (1/2) is correct because, given fog = I, the derivative f'(b) can be found using the chain rule and the fact that g'(a) = 2 and g(a) = b.
120 Easy
120 of 500
Application +4 | -1
If yx−xy=1y^x-x^y=1, then the value of dydx\frac{d y}{d x} at x=1x=1 is
View answer and explanation
Correct option: A
2(1−log⁡2)2(1-\log 2)
Option A (2(1−log⁡2)2(1-\log 2)) is correct because it is the result of differentiating the given equation and substituting the given values.
Revision notes and key takeaways

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