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JEE • MATHEMATICS • DIFFERENTIATION

Differentiation practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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391 Easy
391 of 500
Application +4 | -1
A value of xx in the interval (1,2) such that f′(x)=0f'\left( x \right) = 0, where
View answer and explanation
Correct option: A
3+33\frac{{3 + \sqrt 3 }}{3}
Option A (3+33\frac{{3 + \sqrt 3 }}{3}) is correct because it is the only root of the derivative that lies within the specified interval (1, 2).
392 Easy
392 of 500
Application +4 | -1
If f(x)=ax+a2axf\left( x \right) = \sqrt {ax} + \frac{{{a^2}}}{{\sqrt {ax} }}, then f′(a)f'\left( a \right) is equal to
View answer and explanation
Correct option: C
0
Option C (0) is correct because after differentiating the given function and substituting x = a, the expression simplifies to zero.
393 Easy
393 of 500
Analyzing +4 | -1
The number of values of xx at which f(x)=Sin⁡−1(2x1+x2)f(x)=\operatorname{Sin}^{-1}\left(\frac{2 x}{1+x^2}\right) is not differentiable is
View answer and explanation
Correct option: C
2
Option C (2) is correct because the function is not differentiable at x = 1 and x = -1 due to the absolute value in the derivative.
394 Easy
394 of 500
Application +4 | -1
If y=f(x)y=f(x) is an odd differentiable function defined on (−∞,∞)(-\infty, \infty) such that f′(3)=−2f^{\prime}(3)=-2, then f′(−3)f^{\prime}(-3) equals
View answer and explanation
Correct option: C
-2
Option C (-2) is correct because the derivative of an odd function is an even function, so f'(-3) = f'(3) = -2.
395 Easy
395 of 500
Application +4 | -1
Derivative of x6+6x{x^6} + {6^x} with respect to xx is
View answer and explanation
Correct option: C
6x5+6xlog⁡66{x^5} + {6^x}\log 6
Option C (6x5+6xlog⁡66{x^5} + {6^x}\log 6) is correct because it is the result of applying the power rule and the exponential derivative rule.
396 Easy
396 of 500
Application +4 | -1
If f(x)=∣cos⁡x−sin⁡x∣f(x)=|\cos x-\sin x|, then f′(π/4)f^{\prime}(\pi / 4) is equal to
View answer and explanation
Correct option: D
None of these
The correct answer is None of these because the left-hand derivative and right-hand derivative at x=π/4 are not equal, meaning the function is not differentiable at that point.
397 Easy
397 of 500
Analyzing +4 | -1
If y=(log⁡cos⁡xsin⁡x)(log⁡sin⁡xcos⁡x)+sin⁡−12x1+x2,y=\left(\log _{\cos x} \sin x\right)\left(\log _{\sin x} \cos x\right)+\sin ^{-1} \frac{2 x}{1+x^2}, then dydx\frac{d y}{d x} at x=π2x=\frac{\pi}{2} is equal to
View answer and explanation
Correct option: C
−8π2+4\frac{-8}{\pi^2+4}
Option C is correct because it involves simplifying the expression and then differentiating, evaluating the derivative at the specified point.
398 Easy
398 of 500
Application +4 | -1
If sin⁡y=xsin⁡(a+y),\sin y = x\sin \left( {a + y} \right), then dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: B
sin⁡2(a+y)sin⁡a\frac{{{{\sin }^2}\left( {a + y} \right)}}{{\sin a}}
Option B (sin⁡2(a+y)sin⁡a\frac{{{{\sin }^2}\left( {a + y} \right)}}{{\sin a}}) is correct because it is the result of differentiating the given equation and solving for dydx\frac{{dy}}{{dx}}.
399 Easy
399 of 500
Application +4 | -1
If y=sec⁡(tan⁡−1x),y = \sec ({\tan ^{ - 1}}x), then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: A
x1+x2\frac{x}{{\sqrt {1 + {x^2}} }}
Option A (x1+x2\frac{x}{{\sqrt {1 + {x^2}} }}) is correct because it is the result of simplifying the expression and then differentiating.
400 Easy
400 of 500
Analyzing +4 | -1
If f(x)=∣sec⁡θtan⁡2θ1θsec⁡xtan⁡xx1tan⁡x−tan⁡θ0∣f(x)=\left|\begin{array}{ccc}\sec \theta & \tan ^2 \theta & 1 \\ \theta \sec x & \tan x & x \\ 1 & \tan x-\tan \theta & 0\end{array}\right|, then f′(θ)f^{\prime}(\theta) is
View answer and explanation
Correct option: B
−1-1
Option B (-1) is correct because after differentiating the determinant and substituting x = θ\theta, the expression simplifies to -1.
401 Easy
401 of 500
Application +4 | -1
Let x=2sin⁡θ−sin⁡2θx=2 \sin \theta-\sin 2 \theta and y=2cos⁡θ−cos⁡2θy=2 \cos \theta-\cos 2 \theta, then (d2ydx2)θ=π=\left(\frac{d^2 y}{d x^2}\right)_{\theta=\pi}=
View answer and explanation
Correct option: A
38\frac{3}{8}
Option A (38\frac{3}{8}) is correct because it is the value of the second derivative of y with respect to x at the specified point.
402 Easy
402 of 500
Application +4 | -1
If y=cos⁡−1(x−1)y=\cos ^{-1}\left(x^{-1}\right) then y′(−2)y^{\prime}(-2) is equal to
View answer and explanation
Correct option: A
123\frac{1}{2 \sqrt{3}}
Option A (123\frac{1}{2 \sqrt{3}}) is correct because it is the value of the derivative of the given function at x = -2, calculated using the chain rule.
403 Easy
403 of 500
Application +4 | -1
The least value of g(t)=8t−t4g(t)=8 t-t^4 on [−2,1][-2,1] is
View answer and explanation
Correct option: C
-32
Option C (-32) is correct because it is the minimum value of the function g(t) on the interval [-2,1], found by evaluating the function at the endpoints and critical points.
404 Easy
404 of 500
Application +4 | -1
If f(x)=∣x−2∣f\left( x \right) = \left| {x - 2} \right| and g(x)=f(f(x))\mathrm{g}\left( x \right) = f\left( {f\left( x \right)} \right), then for x>20,g′(x)x > 20,\mathrm{g'}\left( x \right) is equal to
View answer and explanation
Correct option: C
1
Option C (1) is correct because for x>20x > 20, g(x)g(x) simplifies to x−4x - 4, and its derivative is 1.
405 Easy
405 of 500
Application +4 | -1
A ball is dropped from a platform 19.6 m19.6 \mathrm{~m} high. Its position function is
View answer and explanation
Correct option: B
x=−4.9t2+19.6(0≤t≤2)x=-4.9 t^2+19.6(0 \leq t \leq 2)
Option B (x=−4.9t2+19.6(0≤t≤2)x=-4.9 t^2+19.6(0 \leq t \leq 2)) is correct because it accurately describes the ball's position as a function of time under constant gravitational acceleration, with the correct initial height and time interval.
406 Easy
406 of 500
Analyzing +4 | -1
If f(x)=sin⁡(sin⁡x)f(x)=\sin (\sin x) and f′′(x)+tan⁡xf′(x)+g(x)=0f^{\prime \prime}(x)+\tan x f^{\prime}(x)+g(x)=0, then g(x)g(x) is :
View answer and explanation
Correct option: D
cos⁡2xsin⁡(sin⁡x)\cos ^{2} x \sin (\sin x)
Option D is correct. By differentiating f(x) twice and substituting into the given equation, we can solve for g(x) and find that it equals cos⁡2xsin⁡(sin⁡x)\cos ^{2} x \sin (\sin x).
407 Easy
407 of 500
Analyzing +4 | -1
If y=tan⁡−1(x−x1+x3/2),y = {\tan ^{ - 1}}\left( {\frac{{\sqrt x - x}}{{1 + {x^{3/2}}}}} \right), then y′(1)y'\left( 1 \right) is equal to
View answer and explanation
Correct option: D
−14- \frac{1}{4}
Option D (−14- \frac{1}{4}) is correct because after simplifying the expression using inverse trigonometric properties and then differentiating, y'(1) equals −14-\frac{1}{4}.
408 Easy
408 of 500
Application +4 | -1
If y=x+x+x,x>0y=\sqrt{x+\sqrt{x+\sqrt{x}}}, x>0, then dy/dxd y / d x at x=1x=1 is
View answer and explanation
Correct option: A
121+2(3+4242)\frac{1}{2 \sqrt{1+\sqrt{2}}}\left(\frac{3+4 \sqrt{2}}{4 \sqrt{2}}\right)
Option A (121+2(3+4242)\frac{1}{2 \sqrt{1+\sqrt{2}}}(\frac{3+4 \sqrt{2}}{4 \sqrt{2}})) is correct because it follows from applying the chain rule to find the derivative and then substituting x=1.
409 Easy
409 of 500
Application +4 | -1
The minimum value of the function f(x)=tan⁡x+cot⁡xf(x)=\tan x+\cot x in the interval (0,π/2)(0, \pi / 2) is
View answer and explanation
Correct option: C
2
Option C (2) is correct because the minimum value of the function occurs at x=π\pi/4, where the function value is 2.
410 Easy
410 of 500
Application +4 | -1
ddx[log⁡1−cos⁡x1+cos⁡x]\frac{d}{d x}\left[\log \sqrt{\frac{1-\cos x}{1+\cos x}}\right] is equal to
View answer and explanation
Correct option: B
cosec⁡x\operatorname{cosec} x
Option B is correct because the expression is simplified using trigonometric identities and then differentiated, resulting in cosec x.
411 Easy
411 of 500
Application +4 | -1
If x2+y2=1x^2+y^2=1, then
View answer and explanation
Correct option: B
yy′′+(y′)2+1=0y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0
Option B (yy′′+(y′)2+1=0y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0) is correct because it is the result of differentiating the given equation x2+y2=1x^2 + y^2 = 1 twice with respect to x.
412 Easy
412 of 500
Analyzing +4 | -1
If sin⁡(x+y)+cos⁡(x+y)=log⁡(x+y)\sin \left( {x + y} \right) + \cos \left( {x + y} \right) = \log \left( {x + y} \right), then d2ydx2\frac{{{d^2}y}}{{d{x^2}}} is
View answer and explanation
Correct option: B
0
Option B (0) is correct because after differentiating the given equation with respect to x, it simplifies to 1 + dy/dx = 0, and the second derivative is therefore 0.
413 Easy
413 of 500
Application +4 | -1
If y=sec⁡(tan⁡−1x)y=\sec \left(\tan ^{-1} x\right), then dydx\frac{d y}{d x} at x=1x=1 is equal to
View answer and explanation
Correct option: A
12\frac{1}{\sqrt{2}}
Option A (12\frac{1}{\sqrt{2}}) is correct because it is the value of the derivative of the given function evaluated at x=1.
414 Easy
414 of 500
Application +4 | -1
If x=cos⁡θ,y=sin⁡5θx = \cos \theta ,y = \sin 5\theta, then (1−x2)d2ydx2−xdydx=\left( {1 - {x^2}} \right)\frac{{{d^2}y}}{{d{x^2}}} - x\frac{{dy}}{{dx}} =
View answer and explanation
Correct option: D
−25y- 25y
Option D (-25y) is correct because after differentiating the given equations and substituting, the expression simplifies to -25y.
415 Easy
415 of 500
Application +4 | -1
For x1+y+y1+x=0,dydx=…….(x≠0,−1)x \sqrt{1+y}+y \sqrt{1+x}=0, \frac{d y}{d x}=\ldots \ldots . \quad(x \neq 0,-1)
View answer and explanation
Correct option: B
−1(1+x)2\frac{-1}{(1+x)^2}
Option B (−1(1+x)2\frac{-1}{(1+x)^2}) is correct because simplifying the given equation and then differentiating yields dy/dx = −1(1+x)2\frac{-1}{(1+x)^2}.
416 Easy
416 of 500
Application +4 | -1
If xy=ex−yx^{y}=e^{x-y}, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: A
log⁡x⋅[log⁡(ex)]−2\log x \cdot[\log (e x)]^{-2}
Option A is correct because it is the result of logarithmic differentiation and simplification.
417 Easy
417 of 500
Application +4 | -1
Find the derivative of yy with respect to xx if ex+ey=ex+y{e^x} + {e^y} = {e^{x + y}}
View answer and explanation
Correct option: C
−ey−x- {e^{y - x}}
Option C (−ey−x- {e^{y - x}}) is correct because it is the derivative of y with respect to x after implicit differentiation and simplification.
418 Easy
418 of 500
Application +4 | -1
If x1+y+y1+x=0,x\sqrt {1 + y} + y\sqrt {1 + x} = 0, dydx\frac{{dy}}{{dx}} equals
View answer and explanation
Correct option: B
−1(1+x)2\frac{{ - 1}}{{{{(1 + x)}^2}}}
Option B (−1(1+x)2\frac{{ - 1}}{{{{(1 + x)}^2}}}) is correct because it is the result of differentiating the simplified equation after eliminating y.
419 Easy
419 of 500
Application +4 | -1
The derivative of F[f{ϕ(x)}]F\left[ {f\left\{ {\phi \left( x \right)} \right\}} \right] is
View answer and explanation
Correct option: D
F′[f{ϕ(x)}]f′{ϕ(x)}ϕ′(x)F'\left[ {f\left\{ {\phi \left( x \right)} \right\}} \right]f'\left\{ {\phi \left( x \right)} \right\}\phi '\left( x \right)
Option D (F′[f{ϕ(x)}]f′{ϕ(x)}ϕ′(x)F'\left[ {f\left\{ {\phi \left( x \right)} \right\}} \right]f'\left\{ {\phi \left( x \right)} \right\}\phi '\left( x \right)) is correct because it correctly applies the chain rule multiple times.
420 Easy
420 of 500
Application +4 | -1
d2xdy2\frac{d^{2} x}{d y^{2}} is equal to
View answer and explanation
Correct option: D
(−d2y/dx2)(dy/dx)2\frac{\left(-d^{2} y / d x^{2}\right)}{(d y / d x)^{2}}
Option D ((−d2y/dx2)(dy/dx)2\frac{{(-d^{2} y / d x^{2})}}{{(d y / d x)^{2}}}) is correct because it represents the second derivative of x with respect to y, which is the negative of the second derivative of y with respect to x divided by the square of the first derivative of y with respect to x.
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