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JEE • MATHEMATICS • DIFFERENTIATION

Differentiation practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 932 questions

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391 Easy
391 of 932
Application +4 | -1
If y=cos⁡−19−x29+x2y=\cos ^{-1} \frac{9-x^2}{9+x^2} then y′(−1)y^{\prime}(-1) is equal to
View answer and explanation
Correct option: A
−3/5-3 / 5
Option A (-3/5) is correct because after simplifying the inverse cosine function and differentiating, substituting x=-1 yields -3/5.
392 Easy
392 of 932
Understanding +4 | -1
If y=sin⁡−1x2+cos⁡−1x2,y = {\sin ^{ - 1}}\frac{x}{2} + {\cos ^{ - 1}}\frac{x}{2}, then the value of dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the expression simplifies to a constant, and the derivative of a constant is zero.
393 Easy
393 of 932
Application +4 | -1
Let f(x)=x2+px+qf(x)=x^2+p x+q. The value of (p,q)(p, q) so that f(1)=3f(1)=3 is an extreme value of ff on [0,2][0,2] is
View answer and explanation
Correct option: C
(−2,4)(-2,4)
Option C ((-2,4)) is correct because the given conditions f(1)=3 and f'(1)=0 lead to p=-2 and q=4.
394 Medium
394 of 932
Application +4 | -1
If x=∫0y11+4t2dtx = \int \limits_0^y \frac{1}{{\sqrt {1 + 4{t^2}} }}dt, then d2ydx2\frac{{{d^2}y}}{{d{x^2}}} is
View answer and explanation
Correct option: B
4y4y
Option B (4y4y) is correct because it is the result of differentiating the given integral equation twice and simplifying.
395 Easy
395 of 932
Analyzing +4 | -1
If y(x)=∣sin⁡xcos⁡xsin⁡x+cos⁡x+1231713111∣,x∈Ry(x)=\left|\begin{array}{ccc}\sin x & \cos x & \sin x+\cos x+1 \\ 23 & 17 & 13 \\ 1 & 1 & 1\end{array}\right|, x \in R, then d2ydx2+y\frac{d^2 y}{d x^2}+y is equal to:
View answer and explanation
Correct option: A
6
Option A (6) is correct because after finding the first and second derivatives of y(x) and then adding y and the second derivative, the result is 6.
396 Easy
396 of 932
Application +4 | -1
If sin⁡2x+2cos⁡y+xy=0\sin ^{2} x+2 \cos y+x y=0, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: B
y+sin⁡2x2sin⁡y−x\frac{y+\sin 2 x}{2 \sin y-x}
Option B is correct because it is the result of implicit differentiation of the given equation and solving for dy/dx.
397 Medium
397 of 932
Application +4 | -1
If f(x)=(∣x∣)∣sin⁡ x∣,f(x) = {(|x|)^{|\sin \,x|}}, then f′(−π/4)f'( - \pi /4) is equal to
View answer and explanation
Correct option: A
(π4)1/2.(22log⁡ 4π−22π){\left( {\frac{\pi }{4}} \right)^{1/\sqrt 2 }}.\left( {\frac{{\sqrt 2 }}{2}\log \,\frac{4}{\pi } - \frac{{2\sqrt 2 }}{\pi }} \right)
Option A ((π4)1/2.(22log⁡4π−22π){\left( {\frac{\pi }{4}} \right)^{1/\sqrt 2 }}.{\left( {\frac{{\sqrt 2 }}{2}\log \frac{4}{\pi } - \frac{{2\sqrt 2 }}{\pi }} \right)}) is correct because it is the value of the derivative of the function f(x) at x = -π/4, calculated using logarithmic differentiation.
398 Easy
398 of 932
Analyzing +4 | -1
If f(x)={xe−(1∣x∣+1x),x≠00,x=0f(x)=\left\{\begin{array}{ll}x e^{-\left(\frac{1}{|x|}+\frac{1}{x}\right)} & , x \neq 0 \\ 0 & , x=0\end{array}\right. then f(x)\mathrm{f}(\mathrm{x}) is
View answer and explanation
Correct option: C
continuous for all xx but not differentiable at x=0x=0
Option C (continuous for all xx but not differentiable at x=0x=0) is correct because the left-hand limit, right-hand limit, and function value at x=0x=0 are all 0, but the left-hand derivative and right-hand derivative are not equal.
399 Easy
399 of 932
Application +4 | -1
If F(x)=∣xx2x312x3x2026x∣F(x)=\left|\begin{array}{ccc}x & x^2 & x^3 \\ 1 & 2 x & 3 x^2 \\ 0 & 2 & 6 x\end{array}\right| then F′(x)F^{\prime}(x) is equal to
View answer and explanation
Correct option: D
6x26 x^2
Option D (6x26 x^2) is correct because it is the derivative of the determinant function F(x), calculated by differentiating each row separately.
400 Easy
400 of 932
Application +4 | -1
If f(x)=xtan⁡−1xf(x)=x \tan ^{-1} x, then f′(1)f^{\prime}(1) is equal to
View answer and explanation
Correct option: B
12+π4\frac{1}{2}+\frac{\pi}{4}
The correct answer is B (12+π4\frac{1}{2}+\frac{\pi}{4}) because it is the value of the derivative of the given function evaluated at x=1, using the product rule and the derivative of the inverse tangent function.
401 Medium
401 of 932
Application +4 | -1
If f(x)=3ex2f\left( x \right) = 3{e^{{x^2}}}, then f′(x)−2xf(x)+13f(0)−f′(0)f'\left( x \right) - 2x\mathrm{ }f\left( x \right) + \frac{1}{3}f\left( 0 \right) - f'\left( 0 \right) is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because when the given expression is simplified using the derivative of the function, all terms cancel out except for a constant which evaluates to 1.
402 Easy
402 of 932
Application +4 | -1
Let ff be a differentiable function satisfying [f(x)]n=f(nx)[f(x)]^n=f(n x) for all x∈Rx \in R.
Then, f′(x)f(nx)f^{\prime}(x) f(n x) equals
View answer and explanation
Correct option: C
f(x)f′(nx)f(x) f^{\prime}(n x)
Option C (f(x)f′(nx)f(x) f^{\prime}(n x)) is correct because, after differentiating the given equation and manipulating the result, we find that f′(x)f(nx)=f(x)f′(nx)f^{\prime}(x) f(n x) = f(x) f^{\prime}(n x).
403 Easy
403 of 932
Application +4 | -1
If sin⁡−1x+sin⁡−1y=π2{\sin ^{ - 1}}x + {\sin ^{ - 1}}y = \frac{\pi }{2}, then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: B
−xy- \frac{x}{y}
Option B (−xy- \frac{x}{y}) is correct because it is the derivative of y with respect to x, obtained by implicitly differentiating the given equation and using trigonometric identities.
404 Easy
404 of 932
Analyzing +4 | -1
Let x(t)=22cos⁡tsin⁡2tx(t)=2 \sqrt{2} \cos t \sqrt{\sin 2 t} and y(t)=22sin⁡ty(t)=2 \sqrt{2} \sin t sin⁡2t,t∈(0,π2)\sqrt{\sin 2 t}, t \in\left(0, \frac{\pi}{2}\right). Then 1+(dydx)2d2ydx2\frac{1+\left(\frac{d y}{d x}\right)^2}{\frac{d^2 y}{d x^2}} at t=π4t=\frac{\pi}{4} is equal to
View answer and explanation
Correct option: D
−23\frac{-2}{3}
Option D (−23\frac{-2}{3}) is correct because after finding the first and second derivatives and substituting t=π4t = \frac{\pi}{4}, the expression evaluates to −23\frac{-2}{3}.
405 Easy
405 of 932
Analyzing +4 | -1
If f(x)=[x]∣x∣,x≠0f(x)=\frac{[x]}{|x|}, x \neq 0, where [.] denotes the greatest integer function, then f′(1)f^{\prime}(1) is
View answer and explanation
Correct option: C
non-existent
Option C (non-existent) is correct because the left-hand derivative and right-hand derivative at x=1 are not equal, so the derivative does not exist.
406 Easy
406 of 932
Analyzing +4 | -1
If f(x)=2tan⁡−1x+cos⁡−1(1−x21+x2)f(x)=2 \tan ^{-1} x+\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right), then
View answer and explanation
Correct option: C
f′(x)=0f^{\prime}(x)=0 for all x<0x < 0
Option D (All the above) is correct because all three given statements are true based on the given functions and their derivatives.
407 Easy
407 of 932
Application +4 | -1
If x3+8xy+y3=64x^{3}+8 x y+y^{3}=64, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: A
−3x2+8y8x+3y2-\frac{3 x^{2}+8 y}{8 x+3 y^{2}}
Option A is correct because it is the result of implicit differentiation of the given equation and solving for dy/dx.
408 Medium
408 of 932
Analyzing +4 | -1
If for all x,y∈Rx,y \in R, the function ff is defined by f(x)+f(y)+f(x)f(y)=1f\left( x \right) + f\left( y \right) + f\left( x \right)f\left( y \right) = 1 and f(x)>0f\left( x \right) > 0. Then,
View answer and explanation
Correct option: A
f′(x)=0f'\left( x \right) = 0 for all x∈Rx \in R
Option A (f′(x)=0f'\left( x \right) = 0 for all x∈Rx \in R) is correct because the given functional equation implies that f(x)f(x) is a constant function, hence its derivative is zero.
409 Medium
409 of 932
Analyzing +4 | -1
Let g(x)=log⁡ef(x)g(x)=\log _e f(x), where f(x)f(x) is twice differentiable positive function on (0,∞)(0, \infty) such that f(x+1)=xf(x)f(x+1)=x f(x), for N=1,2,3,…N=1,2,3, \ldots, then g′′(N+12)−g′′(12)equalsg''\left( {N + \frac{1}{2}} \right) - g''\left( {\frac{1}{2}} \right)\mathrm{ equals }
View answer and explanation
Correct option: A
−4{1+19+125+…+1(2N−1)2}-4\left\{1+\frac{1}{9}+\frac{1}{25}+\ldots+\frac{1}{(2 N-1)^2}\right\}
Option A (−4{1+19+125+…+1(2N−1)2}-4\left\{1+\frac{1}{9}+ \frac{1}{25}+\ldots+\frac{1}{(2 N-1)^2}\right\}) is correct because it is the result obtained after differentiating the given logarithmic function and summing the series.
410 Medium
410 of 932
Analyzing +4 | -1
The value of ddx[(tan⁡22x−tan⁡2x1−tan⁡22xtan⁡2x)cot⁡3x]\frac{d}{{dx}}\left[ {\left( {\frac{{{{\tan }^2}2x - {{\tan }^2}x}}{{1 - {{\tan }^2}2x{{\tan }^2}x}}} \right)\cot 3x} \right] is
View answer and explanation
Correct option: C
sec⁡2x{\sec ^2}x
The correct answer is C (sec⁡2x{\sec ^2}x) because the expression simplifies to tan⁡x\tan x after applying trigonometric identities, and the derivative of tan⁡x\tan x is sec⁡2x{\sec ^2}x.
411 Medium
411 of 932
Application +4 | -1
If ln⁡((e−1)exy+x2)=x2+y2\ln \left(({e}-1){e}^{{xy}}+{x}^2\right)={x}^2+{y}^2, then (dydx)(1,0)\left(\frac{{dy}}{{dx}}\right)_{(1,0)} is given by
View answer and explanation
Correct option: A
2
Option A (2) is correct because by differentiating the given equation implicitly and substituting the point (1,0), we can find the value of dydx\frac{dy}{dx}.
412 Easy
412 of 932
Application +4 | -1
If y=12x−13+1(x2+2)34y=\frac{1}{\sqrt[3]{2 x-1}}+\frac{1}{\sqrt[4]{\left(x^2+2\right)^3}} then y′(0)y^{\prime}(0) is given by
View answer and explanation
Correct option: C
−23-\frac{2}{3}
Option C (-23\frac{2}{3}) is correct because it is the value of the derivative of the function evaluated at x=0.
413 Medium
413 of 932
Application +4 | -1
Differential coefficient of sec⁡−112x2−1{\sec ^{ - 1}}\frac{1}{{2{x^2} - 1}} with respect to 1−x2\sqrt {1 - {x^2}} at x=12x = \frac{1}{2} is equal to
View answer and explanation
Correct option: B
4
Option B (4) is correct because after substituting x=12x = \frac{1}{2}, the ratio of the derivatives simplifies to 4.
414 Easy
414 of 932
Application +4 | -1
Let g(x)g\left( x \right) be the inverse of the function f(x)f\left( x \right) and f′(x)=11+x3f'\left( x \right) = \frac{1}{{1 + {x^3}}} then, g′(x)g'\left( x \right) is equal to
View answer and explanation
Correct option: C
1+(g(x))31 + {\left( {g\left( x \right)} \right)^3}
Option C (1+(g(x))31 + {\left( {g\left( x \right)} \right)^3}) is correct because it is derived from the inverse function differentiation rule, where g′(x)=1/f′(g(x))g'(x) = 1/f'(g(x)).
415 Medium
415 of 932
Analyzing +4 | -1
If x2+y2=t−1t{x^2} + {y^2} = t - \frac{1}{t} and x4+y4=t2+1t2{x^4} + {y^4} = {t^2} + \frac{1}{{{t^2}}}, then x3ydydx{x^3}y\frac{{dy}}{{dx}} equals
View answer and explanation
Correct option: B
1
The correct answer is 1 because after simplifying the given equations and differentiating, x3ydydx{x^3}y\frac{{dy}}{{dx}} equals 1.
416 Medium
416 of 932
Application +4 | -1
If y=log⁡x+log⁡x+log⁡x+log⁡x+...∞,y = \sqrt {\log x + \sqrt {\log x + \sqrt {\log x + \sqrt {\log x + ...\infty } } } ,} then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: C
1x(2y−1)\frac{1}{{x\left( {2y - 1} \right)}}
Option C (1x(2y−1)\frac{1}{{x\left( {2y - 1} \right)}}) is correct because it is the derivative of the given function after simplifying and differentiating implicitly.
417 Medium
417 of 932
Application +4 | -1
If y=1+tan⁡x1−tan⁡xy=\sqrt{\frac{1+\tan x}{1-\tan x}}, then dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: A
121−tan⁡x1+tan⁡x⋅sec⁡2(π4+x)\frac{1}{2} \sqrt{\frac{1-\tan x}{1+\tan x}} \cdot \sec ^{2}\left(\frac{\pi}{4}+x\right)
Option A is correct because the derivative is found using the chain rule and trigonometric identities to simplify the expression.
418 Hard
418 of 932
Analyzing +4 | -1
If f(x)=22x−1f\left( x \right) = {2^{2x - 1}} and ϕ(x)−2x+2xlog⁡2.\phi \left( x \right) - {2^x} + 2x\log 2. If f′(x)>ϕ′(x),f'\left( x \right) > \phi '\left( x \right), then
View answer and explanation
Correct option: C
x>0x > 0
Option C (x>0x > 0) is correct because solving the inequality f′(x)>ϕ′(x)f'(x) > \phi'(x) leads to the condition x>0x > 0.
419 Medium
419 of 932
Application +4 | -1
If f(x)=1+cos⁡2(x)2f\left( x \right) = \sqrt {1 + {{\cos }^2}{{\left( x \right)}^2}}, then the value of f′(π2)f'\left( {\frac{{\sqrt \mathrm{\pi } }}{2}} \right) is
View answer and explanation
Correct option: B
−π6- \sqrt {\frac{\mathrm{\pi }}{6}}
Option B (−π6- \sqrt {\frac{\mathrm{\pi }}{6}}) is correct because it is the value of the derivative of the given function evaluated at x=π2x = \frac{{\sqrt \mathrm{\pi } }}{2}.
420 Medium
420 of 932
Application +4 | -1
A continuous and differentiable function f(x)f(x) satisfy the functional equation f(x+y)=f(x)f(y)f(x)+f(y)f(x+y)=\frac{f(x) f(y)}{f(x)+f(y)}, f(1)=32f(1)=32 then f(4)=f(4)=
View answer and explanation
Correct option: A
8
Option A (8) is correct because by substituting the functional equation into a simpler form and using the given condition f(1)=32f(1)=32, we can find the value of f(4)f(4).
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