Skip to main content
Back to DIFFERENTIAL EQUATIONS

Your Progress

0 / 452 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 151-180 of 452 questions

Preparing practice and saved progress…

151 Medium
151 of 452
Application +4 | -1
If xdy=(2y+2x4+x2)dx,y(1)=0x d y=\left(2 y+2 x^4+x^2\right) d x, y(1)=0 then y(e)=y(e)=
View answer and explanation
Correct option: D
e4\mathrm{e}^4
Option D (e4e^4) is correct because it is the solution obtained after solving the given differential equation with the initial condition y(1)=0.
152 Medium
152 of 452
Application +4 | -1
Solution of differential equations (xcos⁡x−sin⁡x)dx=xysin⁡xdy(x \cos x-\sin x) d x=\frac{x}{y} \sin x d y is
View answer and explanation
Correct option: C
∣sin⁡xxy∣=c\left|\frac{\sin x}{x y}\right|=c
Option C (∣sin⁡xxy∣=c\left|\frac{{\sin x}}{{x y}}\right|=c) is correct because it represents the solution obtained after integrating the given differential equation and simplifying the result.
153 Medium
153 of 452
Application +4 | -1
Solution of equation dydx=3x−4y−23x−4y−3\frac{d y}{d x}=\frac{3 x-4 y-2}{3 x-4 y-3} is
View answer and explanation
Correct option: B
x−y+c=log⁡(3x−4y+1)x-y+c=\log (3 x-4 y+1)
Option B (x−y+c=log⁡(3x−4y+1)x-y+c=\log (3 x-4 y+1)) is correct because it is the solution obtained by substituting 3x−4y=z3x-4y=z and integrating the resulting differential equation.
154 Medium
154 of 452
Application +4 | -1
The solution of differential equation x dx+y dy=a(x2+y2)dyx \,d x+y \,d y=a\left(x^2+y^2\right) d y, is
View answer and explanation
Correct option: B
x2+y2=Ce2ayx^2+y^2=C e^{2 a y}
Option B (x2+y2=Ce2ayx^2+y^2=C e^{2 a y}) is correct because it is the solution obtained by integrating the given differential equation.
155 Medium
155 of 452
Analyzing +4 | -1
Solution to the differential equation x+x33!+x35!+⋯1+x22!+x44!+⋯=dx−dydx+dy\frac{x+\frac{x^3}{3 !}+\frac{x^3}{5 !}+\cdots}{1+\frac{x^2}{2 !}+\frac{x^4}{4 !}+\cdots}=\frac{d x-d y}{d x+d y} is
View answer and explanation
Correct option: D
2ye2x=ce2x−12 y e^{2 x}=c e^{2 x}-1
Option D (2ye2x=ce2x−12 y e^{2 x}=c e^{2 x}-1) is correct because it is the solution obtained by solving the given differential equation using componendo and dividendo and integrating.
156 Medium
156 of 452
Application +4 | -1
The solution of the differential equation ydx+(x+x2y)dy=0y d x+\left(x+x^2 y\right) d y=0 is
View answer and explanation
Correct option: B
−1xy+log⁡y=c-\frac{1}{x y}+\log y=c
Option B (−1xy+log⁡y=c-\frac{1}{x y}+\log y=c) is the correct solution, found by rearranging the equation and integrating.
157 Medium
157 of 452
Application +4 | -1
The solution curve of the differential equation

ydxdy=x(log⁡ex−log⁡ey+1),x>0,y>0 passing y \frac{d x}{d y}=x\left(\log _e x-\log _e y+1\right), x>0, y>0 \text { passing }

through the point (e,1)(e, 1) is
View answer and explanation
Correct option: A
∣log⁡exy∣=y\left|\log _e \frac{x}{y}\right|=y
Option A (∣log⁡exy∣=y\left|\log _e \frac{x}{y}\right|=y) is correct because it involves solving the given differential equation and applying the initial condition to find the particular solution.
158 Medium
158 of 452
Application +4 | -1
The solution of differential equation yexydx=(xexy+y2)dyy e^{\frac{x}{y}} d x=\left(x e^{\frac{x}{y}}+y^2\right) d y is
View answer and explanation
Correct option: A
y=exy+Cy=e^{\frac{x}{y}}+C
Option A (y=exy+Cy=e^{\frac{x}{y}}+C) is correct because it is the solution obtained after solving the given homogeneous differential equation by substitution and integration.
159 Medium
159 of 452
Application +4 | -1
The curve satisfying the differential equation dydx=y(x+y3)x(y3−x)\frac{d y}{d x}=\frac{y\left(x+y^3\right)}{x\left(y^3-x\right)} and passing through (4,−2)(4,-2) is
View answer and explanation
Correct option: B
y=−2xy=-2 x
Option C, y3=−2xy^3=-2 x, is the correct curve obtained by solving the given differential equation and applying the given condition (4,-2).
160 Medium
160 of 452
Application +4 | -1
General solution of the differential equation (cos⁡2x)dydx+y=tan⁡x   (0≤x<π2)\left(\cos ^2 x\right) \frac{d y}{d x}+y=\tan x \,\,\,\left(0 \leq x < \frac{\pi}{2}\right) is
View answer and explanation
Correct option: A
y+1=tan⁡x+ce−tan⁡xy+1=\tan x+c e^{-\tan x}
Option A (y+1=tan⁡x+ce−tan⁡xy+1=\tan x+c e^{-\tan x}) is correct because it is the solution obtained after solving the given linear differential equation.
161 Medium
161 of 452
Application +4 | -1
The solution of y5x+y−xdy dx=0y^5 x+y-x \frac{\mathrm{d} y}{\mathrm{~d} x}=0 is
View answer and explanation
Correct option: B
x5/5+(1/4)(x/y)4=Cx^5 / 5+(1 / 4)(x / y)^4=C
Option B (x5/5+(1/4)(x/y)4=Cx^5 / 5+(1 / 4)(x / y)^4=C) is correct because it is the solution obtained by multiplying the given differential equation by an appropriate integrating factor and then integrating.
162 Medium
162 of 452
Understanding +4 | -1
The order and degree of the differential equation (1+3dydx)23=4d3ydx3{\left( {1 + 3\frac{{dy}}{{dx}}} \right)^{\frac{2}{3}}} = 4\frac{{{d^3}y}}{{d{x^3}}} are
View answer and explanation
Correct option: C
(3,3)\left( {3,3} \right)
Option C (3,33,3) is correct because after raising both sides to the power of 3/2, the highest order derivative is d3ydx3\frac{{{d^3}y}}{{d{x^3}}} (order 3) and its power is 3 (degree 3).
163 Medium
163 of 452
Analyzing +4 | -1
The differential equation representing the family of ellipse having foci either on the xx-axis or on the yy-axis centre at the origin and passing through the point (0,3)(0,3) is
View answer and explanation
Correct option: C
xyy′′+x(y′)2−yy′=0x y y^{\prime \prime}+x\left(y^{\prime}\right)^2-y y^{\prime}=0
Option C (xyy′′+x(y′)2−yy′=0x y y^{\prime\prime}+x(y^{\prime})^2-y y^{\prime}=0) is correct because it represents the differential equation of the family of ellipses centered at the origin, passing through (0,3), and having foci on either the x-axis or y-axis.
164 Medium
164 of 452
Application +4 | -1
A curve having the condition that the slope of tangent at some point is two times the slope of the straight line joining the same point to the origin of coordinates, is a/an
View answer and explanation
Correct option: C
Parabola
The correct answer is C (Parabola) because the given condition leads to a differential equation whose solution is of the form y = cx², which represents a parabola.
165 Medium
165 of 452
Application +4 | -1
General solution of the equation (1+x2)dydx+xy=x3y3\left(1+x^2\right) \frac{d y}{d x}+x y=x^3 y^3 is
View answer and explanation
Correct option: B
1x2+1(1y2+1)=−1log⁡(1+x2)+c\frac{1}{x^2+1}\left(\frac{1}{y^2}+1\right)=-1 \log \left(1+x^2\right)+c
Option B (1x2+1(1y2+1)=−1log⁡(1+x2)+c\frac{1}{x^2+1}(\frac{1}{y^2}+1)=-1 \log (1+x^2)+c) is the correct general solution obtained by solving the Bernoulli differential equation.
166 Medium
166 of 452
Application +4 | -1
The solution of dυdt+kmυ=−g\frac{{d\upsilon }}{{dt}} + \frac{k}{m}\upsilon = - g is
View answer and explanation
Correct option: A
υ=ce−kmt−mgk\upsilon = c{e^{ - \frac{k}{m}t}} - \frac{{mg}}{k}
Option A (υ=ce−kmt−mgk\upsilon = c{e^{ - \frac{k}{m}t}} - \frac{{mg}}{k}) is correct because it is the solution to the given first-order linear differential equation.
167 Medium
167 of 452
Analyzing +4 | -1
If y=(x+1+x)ny = {\left( {x + \sqrt {1 + x} } \right)^n}, then (1+x2)d2ydx2+xdydx\left( {1 + {x^2}} \right)\frac{{{d^2}y}}{{d{x^2}}} + x\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: A
n2y{n^2}y
Option A (n2y{n^2}y) is correct because after differentiating the given equation twice and simplifying, we obtain the expression equal to n2y{n^2}y.
168 Medium
168 of 452
Analyzing +4 | -1
If x=sec⁡θ−cos⁡θx=\sec \theta-\cos \theta and y=sec⁡nθ−cos⁡nθy=\sec ^n \theta-\cos ^n \theta, then (x2+4)(dydx)2\left(x^2+4\right)\left(\frac{d y}{d x}\right)^2 is equal to
View answer and explanation
Correct option: C
n2(y2+4)n^2\left(y^2+4\right)
The correct answer is C (n2(y2+4)n^2\left(y^2+4\right)) because it is the simplified expression obtained after differentiating xx and yy with respect to θ\theta and substituting into the given equation.
169 Medium
169 of 452
Application +4 | -1
The solution of the differential equation dydx=x−2y+12x−4y\frac{{dy}}{{dx}} = \frac{{x - 2y + 1}}{{2x - 4y}} is
View answer and explanation
Correct option: A
(x−2y)2+2x=c{\left( {x - 2y} \right)^2} + 2x = c
Option A ((x−2y)2+2x=c{\left( {x - 2y} \right)^2} + 2x = c) is correct because it is the solution to the differential equation obtained by using a suitable substitution.
170 Medium
170 of 452
Application +4 | -1
The solution of differential equation dtdx=t(ddx(g(x)))−t2g(x)\frac{{dt}}{{dx}} = \frac{{t\left( {\frac{d}{{dx}}\left( {\mathrm{g}\left( x \right)} \right)} \right) - {t^2}}}{{\mathrm{g}\left( x \right)}} is
View answer and explanation
Correct option: C
t=g(x)x+ct = \frac{{\mathrm{g}\left( x \right)}}{{x + c}}
Option D (t=g(x)x+ct = \frac{{\mathrm{g}\left( x \right)}}{{x + c}}) is correct because it is the solution to the given differential equation after applying a suitable substitution and integrating factor.
171 Medium
171 of 452
Application +4 | -1
The solution of differential equation (xy2−ex13)dx−x2ydy=0\left(x y^2-e^{x^{\frac{1}{3}}}\right) d x-x^2 y d y=0 is
View answer and explanation
Correct option: B
3y2=2x2ex13+Cx23 y^2=2 x^2 e^{x^{\frac{1}{3}}}+C x^2
Option B (3y2=2x2ex13+Cx23 y^2=2 x^2 e^{x^{\frac{1}{3}}}+C x^2) is correct as it represents the solution to the given differential equation after using an integrating factor.
172 Medium
172 of 452
Application +4 | -1
The solution of 2(y+3)−xydydx=02\left( {y + 3} \right) - xy\frac{{dy}}{{dx}} = 0 with y=−2y = - 2, where x=1x = 1, is
View answer and explanation
Correct option: D
x2(y+3)3=ey+2{x^2}{\left( {y + 3} \right)^3} = {e^{y + 2}}
The correct answer is D (x2(y+3)3=ey+2{x^2}{\left( {y + 3} \right)^3} = {e^{y + 2}}) because it is the solution to the given differential equation 2(y+3)−xydydx=02\left( {y + 3} \right) - xy\frac{{dy}}{{dx}} = 0 with the initial condition y=−2y = -2 when x=1x = 1.
173 Medium
173 of 452
Application +4 | -1
By a suitable substitution, the equation y3dydx+x+y2=0y^3 \frac{d y}{d x}+x+y^2=0 can be transformed to
View answer and explanation
Correct option: B
Homogeneous
Option B (Homogeneous) is correct because the given equation can be transformed into a homogeneous differential equation by using the substitution z=x+y2z = x + y^2.
174 Medium
174 of 452
Application +4 | -1
The general solution of ydx−xdy−3x2y2ex3dx=0ydx - xdy - 3{x^2}{y^2}{e^{{x^3}}}dx = 0, is equal to
View answer and explanation
Correct option: A
xy=ex3+C\frac{x}{y} = {e^{{x^3}}} + C
Option A (xy=ex3+C\frac{x}{y} = {e^{{x^3}}} + C) is correct because it is the general solution obtained by rearranging the given differential equation and integrating.
175 Medium
175 of 452
Application +4 | -1
The solution curve, of the differential equation 2ydydx+3=5dydx2 {y} \frac{{dy}}{{dx}}+3=5 \frac{{dy}}{{dx}}, passing through the point (0,1)(0,1) is a conic, whose vertex lies on the line:
View answer and explanation
Correct option: A
2x+3y=92 x+3 y=9
Option A (2x+3y=92 x+3 y=9) is correct because the vertex of the conic (parabola) lies on this line, after solving the differential equation and applying the given point.
176 Medium
176 of 452
Application +4 | -1
The equation of curve through point (1,0) which satisfies the differential equation (1+y2)dx−xydy=0\left( {1 + {y^2}} \right)dx - xy\mathrm{ }dy = 0 is
View answer and explanation
Correct option: B
x2−y2=1{x^2} - {y^2} = 1
Option B (x2−y2=1{x^2} - {y^2} = 1) is correct because it is the solution to the differential equation that passes through the point (1,0).
177 Medium
177 of 452
Application +4 | -1
General solution of the equation dydx+1x=eyx2\frac{d y}{d x}+\frac{1}{x}=\frac{e^y}{x^2} is
View answer and explanation
Correct option: A
2x=ey(2cx2+1)2 x=e^y\left(2 c x^2+1\right)
Option A (2x=ey(2cx2+1)2 x=e^y(2 c x^2+1)) is the correct general solution obtained by solving the differential equation.
178 Medium
178 of 452
Application +4 | -1
The solution of edydx=(x+1),y(0)=3{e^{\frac{{dy}}{{dx}}}} = \left( {x + 1} \right),y\left( 0 \right) = 3 is
View answer and explanation
Correct option: B
y=(x+1)log⁡∣x+1∣−x+3y = \left( {x + 1} \right)\log \left| {x + 1} \right| - x + 3
Option B, y=(x+1)log⁡∣x+1∣−x+3y = \left( {x + 1} \right)\log \left| {x + 1} \right| - x + 3 is the correct solution obtained by integrating the given differential equation and applying the initial condition.
179 Medium
179 of 452
Application +4 | -1
The solution of (y+x+5)dy=(y−x+(y+x+5) \mathrm{d} y=(y-x+ 1) dx\mathrm{d} x is
View answer and explanation
Correct option: C
log⁡((y+3)2+(x+2)2)+2tan⁡−1y+3x+2=C\log \left((y+3)^2+(x+2)^2\right)+2 \tan ^{-1} \frac{y+3}{x+2}=C
The correct answer is C (log⁡((y+3)2+(x+2)2)+2tan⁡−1y+3x+2=C\log \left((y+3)^2+(x+2)^2\right)+2 \tan ^{-1} \frac{{y+3}}{{x+2}}=C) because it is the solution to the homogeneous differential equation after substitution and integration.
180 Medium
180 of 452
Application +4 | -1
If y1(x)y_1(x) is a solution of the differential equation dydx−f(x)y=0\frac{d y}{d x}-f(x) y=0, then a solution of the differential equation dydx+f(x)y=r(x)\frac{d y}{d x}+f(x) y=r(x) can be y=y=
View answer and explanation
Correct option: A
1y1(x)∫r(x)y1(x)dx\frac{1}{y_1(x)} \int r(x) y_1(x) d x
Option A (1y1(x)∫r(x)y1(x)dx\frac{{1}}{{y_1(x)}} \int r(x) y_1(x) dx) is correct because it represents the solution obtained using the integrating factor method for a first-order linear differential equation.
Revision notes and key takeaways

Review DIFFERENTIAL EQUATIONS in your textbook or class notes, then use this set to check your understanding.

Showing 151-180 of 452 questions

Your practice

0 / 452 answered · 452 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.