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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 931-960 of 975 questions

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931 Easy
931 of 975
Application +4 | -1
If y=y(x)y = y(x) is the solution of the differential equation 2x2dydx−2xy+3y2=02{x^2}\frac{{dy}}{{dx}} - 2xy + 3{y^2} = 0 such that y(e)=e3,y(e) = \frac{e}{3}, then y(1)y(1) is equal to
View answer and explanation
Correct option: B
02-Mar
Option B (02-Mar) which is equivalent to 2/3 is correct because it is the value of y(1) obtained by solving the given differential equation with the specified initial condition.
932 Medium
932 of 975
Application +4 | -1
A differential equation representing the family of parabolas with axis parallel to yy-axis and whose length of latusrectum is the distance from the point origin to the line 4x−3y+5=04 x-3 y+5=0 is given by
View answer and explanation
Correct option: B
d2ydx2=2\frac{\mathrm{d}^2 y}{\mathrm{dx}^2}=2
Option B, d2ydx2=2\frac{\mathrm{d}^2 y}{\mathrm{dx}^2}=2, is the correct differential equation representing the family of parabolas with the given conditions.
933 Easy
933 of 975
Understanding +4 | -1
The degree of the differential equation d3y dx2+5(d2y dx2)2=x3log⁡d2y dx2\frac{\mathrm{d}^3 y}{\mathrm{~d} x^2}+5\left(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}\right)^2=x^3 \log \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2} is
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because the degree of the differential equation is not defined since the equation is not a polynomial in all the differential coefficients.
934 Easy
934 of 975
Application +4 | -1
The differential equation corresponding to the family of curves y=ex(acos⁡x+bsin⁡x),ay=e^x(a \cos x+b \sin x), a and bb being arbitrary constants is
View answer and explanation
Correct option: B
y2−2y1+2y=0y_2-2 y_1+2 y=0
Option B (y2−2y1+2y=0y_2-2 y_1+2 y=0) is correct because it is the differential equation obtained by differentiating the given family of curves twice and eliminating the arbitrary constants a and b.
935 Easy
935 of 975
Application +4 | -1
If y(x)y(x) is the solution of the differential equation (x+2)dydx=x2+4x−9,x≠−2(x+2) \frac{d y}{d x}=x^2+4 x-9, x \neq-2 and y(0)=0y(0)=0, then y(−4)y(-4) is equal to:0
View answer and explanation
Correct option: A
0
Option A (0) is correct because it is the value of y(-4) obtained after solving the given differential equation and applying the initial condition y(0) = 0.
936 Easy
936 of 975
Application +4 | -1
The equation of a curve passing through the origin and satisfying the differential equation dydx=(x−y)2\frac{d y}{d x}=(x-y)^2, is
View answer and explanation
Correct option: A
e2x(1−x+y)=1+x−ye^{2 x}(1-x+y)=1+x-y
Option A (e2x(1−x+y)=1+x−ye^{2 x}(1-x+y)=1+x-y) is correct because it is the solution obtained by solving the given differential equation with the initial condition.
937 Easy
937 of 975
Analyzing +4 | -1
The differential equation representing the family of curves y2=2c(x+c)y^2=2 c(x+\sqrt{c}), where cc is a positive parameter, is of
View answer and explanation
Correct option: A
Order 1 and degree 3
Option A (Order 1 and degree 3) is correct because after eliminating the arbitrary constant, the resulting differential equation has order 1 and degree 3.
938 Easy
938 of 975
Application +4 | -1
If d2ydx2+sin⁡x=0\frac{d^2 y}{d x^2}+\sin x=0, then solution of the differential equation is.
View answer and explanation
Correct option: A
sin⁡x+c1x+c2\sin x+c_1 x+c_2
Option A (sin⁡x+c1x+c2\sin x+c_1 x+c_2) is correct because it is the general solution obtained by integrating the given second-order differential equation twice.
939 Easy
939 of 975
Application +4 | -1
The solution of the differential equation (x+2y3)dydx=y\left( {x + 2{y^3}} \right)\frac{{dy}}{{dx}} = y, is
View answer and explanation
Correct option: C
x=y(y2+C)x = y\left( {{y^2} + C} \right)
Option C (x=y(y2+C)x = y\left( {{y^2} + C} \right)) is correct because it is the solution obtained by rewriting the differential equation, finding the integrating factor, and integrating.
940 Medium
940 of 975
Application +4 | -1
The general solution of the differential equation sec⁡2xtan⁡ydx+sec⁡2ytan⁡xdy=0\sec ^2 x \tan y d x+\sec ^2 y \tan x d y=0 is x,y∈(0,π4)x, y \in\left(0, \frac{\pi}{4}\right).
View answer and explanation
Correct option: B
cot⁡xcot⁡y=c\cot x \cot y=c
Option C (cot⁡xcot⁡y=c\cot x \cot y = c) is incorrect. The correct answer is tan⁡xtan⁡y=c\tan x \tan y = c because it is the general solution obtained by separating variables and integrating the given differential equation.
941 Medium
941 of 975
Application +4 | -1
The solution yn−1(ay′+y)=xy^{n-1}\left(a y^{\prime}+y\right)=x is
View answer and explanation
Correct option: C
nyn=Ce−nxa+nx−an y^n=C e^{-\frac{n x}{a}}+n x-a
Option C (nyn=Ce−nxa+nx−an y^n=C e^{-\frac{{n x}}{{a}}}+n x-a) is correct because it is the solution obtained by making the substitution u=ynu = y^n and solving the resulting linear differential equation.
942 Easy
942 of 975
Application +4 | -1
y+x2=dydxy + {x^2} = \frac{{dy}}{{dx}} has the solution
View answer and explanation
Correct option: A
y+x2+2x+2=cexy + {x^2} + 2x + 2 = c{e^x}
Option A (y+x2+2x+2=cexy + {x^2} + 2x + 2 = c{e^x}) is correct because it is the solution obtained by solving the linear differential equation using an integrating factor.
943 Medium
943 of 975
Application +4 | -1
Solution of the differential equation y(axy+ex)dx−exdy=0y\left(a x y+e^x\right) d x-e^x d y=0 where y(0)=1y(0)=1 is
View answer and explanation
Correct option: A
y(2−ax2)=2exy\left(2-a x^2\right)=2 e^x
Option A (y(2−ax2)=2exy(2-ax^2)=2e^x) is correct because it represents the solution to the given differential equation with the specified initial condition.
944 Medium
944 of 975
Application +4 | -1
The solution of dydx+y3=1\frac{d y}{d x}+\frac{y}{3}=1 is
View answer and explanation
Correct option: B
y=3+ce−x/3y=3+c e^{-x / 3}
Option B (y=3+ce−x/3y=3+c e^{-x / 3}) is correct because it is the solution obtained by solving the given first-order linear differential equation using the integrating factor method.
945 Medium
945 of 975
Application +4 | -1
The solution of differential equation (1+x)ydx+(1−y)xdy=0\left( {1 + x} \right)y\mathrm{ }dx + \left( {1 - y} \right)x\mathrm{ }dy = 0 is
View answer and explanation
Correct option: A
log⁡e(xy)+x−y=c{\log _e}\left( {xy} \right) + x - y = c
Option A (log⁡e(xy)+x−y=c{\log _e}\left( {xy} \right) + x - y = c) is correct because it is the solution obtained by separating variables and integrating the given differential equation.
946 Medium
946 of 975
Application +4 | -1
A function y=f(x)y = f\left( x \right) has a second order derivative f′′=6(x−1)f'' = 6\left( {x - 1} \right). If its graph passes through the point (2,1) and at point the tangent to the graph is y=3x−5y = 3x - 5 then the function is
View answer and explanation
Correct option: B
(x−1)3{\left( {x - 1} \right)^3}
Option B ((x−1)3{(x - 1)^3}) is correct because it satisfies the given conditions for the second derivative, the point (2,1), and the tangent line y=3x−5y = 3x - 5.
947 Easy
947 of 975
Analyzing +4 | -1
The differential equation representing the family of curves y2=2c(x+c23){y^2} = 2c\left( {x + {c^{\frac{2}{3}}}} \right), where cc is a positive parameter, is of
View answer and explanation
Correct option: C
Order 1, degree 5
Option C (Order 1, degree 5) is correct because after eliminating the parameter cc, the resulting differential equation is of order 1 and degree 5.
948 Easy
948 of 975
Application +4 | -1
If xdy=y(dx+ydy),y>0x d y=y(d x+y d y), y > 0 and y(1)=1y(1)=1, then y(−3)y(-3) is equal to
View answer and explanation
Correct option: B
3
Option B (3) is the correct value of y(−3)y(-3) because after solving the differential equation and applying the initial condition y(1)=1y(1)=1, we find the solution and substitute x=−3x=-3.
949 Medium
949 of 975
Analyzing +4 | -1
The solution to the differential equation dydx=yf′(x)−y2f(x)\frac{{dy}}{{dx}} = \frac{{yf'\left( x \right) - {y^2}}}{{f\left( x \right)}} where f(x)f\left( x \right) is a given function is
View answer and explanation
Correct option: A
f(x)=y(x+c)f\left( x \right) = y\left( {x + c} \right)
Option A is correct. The solution to the differential equation is found by recognizing it as a Bernoulli equation and solving accordingly.
950 Medium
950 of 975
Application +4 | -1
The general solution of the differential equation (x+y)dx+xdy=0(x+y) d x+x d y=0 is
View answer and explanation
Correct option: C
x2+2xy=cx^2+2 x y=c
Option C (x2+2xy=cx^2+2 x y=c) is the correct general solution of the given differential equation, obtained by recognizing it as a homogeneous equation and applying the substitution y=vxy=vx.
951 Easy
951 of 975
Application +4 | -1
The solution of the equation dydx=x+yx−y\frac{{dy}}{{dx}} = \frac{{x + y}}{{x - y}} is
View answer and explanation
Correct option: B
c(x2+y2)12=etan⁡−1(yx)c{\left( {{x^2} + {y^2}} \right)^{\frac{1}{2}}} = {e^{{{\tan }^{ - 1}}\left( {\frac{y}{x}} \right)}}
Option B (c(x2+y2)12=etan⁡−1(yx)c{\left( {{x^2} + {y^2}} \right)^{\frac{1}{2}}} = {e^{{{\tan }^{ - 1}}\left( {\frac{y}{x}} \right)}}) is correct because it is the solution obtained by solving the homogeneous differential equation using the substitution y = vx.
952 Easy
952 of 975
Application +4 | -1
The integrating factor of differential equation dydx(1+x)−xy=1−x\frac{d y}{d x}(1+x)-x y=1-x is
View answer and explanation
Correct option: B
(1+x)e−x(1+x) e^{-x}
Option B ((1+x)e−x(1+x)e^{-x}) is correct because it is the integrating factor of the given differential equation after rewriting it in standard form.
953 Medium
953 of 975
Application +4 | -1
The solution of the differential equation dydx−tan⁡yx=tan⁡ysin⁡yx2\frac{{dy}}{{dx}} - \frac{{\tan y}}{x} = \frac{{\tan y\sin y}}{{{x^2}}} is
View answer and explanation
Correct option: A
xsin⁡y+log⁡x=c\frac{x}{{\sin y}} + \log x = c
Option A (xsin⁡y+log⁡x=c\frac{x}{{\sin y}} + \log x = c) is correct because it is the solution of the given differential equation after applying appropriate substitutions and integrating factors.
954 Medium
954 of 975
Application +4 | -1
If y=0y=0 when x=1x=1, then a particular solution of the equation (1+x2)dydx+2xy=11+x2\left(1+x^2\right) \frac{d y}{d x}+2 x y=\frac{1}{1+x^2} is
View answer and explanation
Correct option: C
y(1+x2)=π4−Cot⁡−1xy\left(1+x^2\right)=\frac{\pi}{4}-\operatorname{Cot}^{-1} x
Option D (y(1+x2)=Tan⁡−1x+π4y(1+x^2)=\operatorname{{Tan}}^{-1} x+\frac{{\pi}}{{4}}) is incorrect. The correct answer is C (y(1+x2)=π4−Cot⁡−1xy(1+x^2)=\frac{{\pi}}{{4}}-\operatorname{{Cot}}^{-1} x). The error likely stems from incorrect handling of the initial condition or trigonometric identities.
955 Easy
955 of 975
Application +4 | -1
Solution of xdydx+y−x+xycot⁡x=0   (x≠0)x \frac{d y}{d x}+y-x+x y \cot x=0 \,\,\,(x \neq 0) is
View answer and explanation
Correct option: A
xy=csin⁡x+1−xcot⁡xx y=\frac{c}{\sin x}+1-x \cot x
Option A (xy=csin⁡x+1−xcot⁡xx y=\frac{{c}}{{\sin x}}+1-x \cot x) is correct because it represents the general solution of the given differential equation after finding the integrating factor and integrating.
956 Medium
956 of 975
Application +4 | -1
An integrating factor of the differential equation (1−x2)dydx−xy=1\left(1-x^2\right) \frac{d y}{d x}-x y=1, is
View answer and explanation
Correct option: C
(1−x2)\sqrt{\left(1-x^2\right)}
Option C ((1−x2)\sqrt{\left(1-x^2\right)}) is correct because it is the integrating factor obtained after rewriting the differential equation in standard form.
957 Medium
957 of 975
Application +4 | -1
The substitution y=zαy=z^\alpha transforms the differential equation (x2y2−1)dy+2xy3dx=0\left(x^2 y^2-1\right) d y+2 x y^3 d x=0 into a homogeneous differential equation for
View answer and explanation
Correct option: A
α=−1\alpha=-1
Option A is correct because the substitution transforms the given differential equation into a homogeneous equation when alpha is -1.
958 Medium
958 of 975
Application +4 | -1
The solution of the differential equation y(sin⁡2x)dy+(sin⁡xcos⁡x)y2dx=xdxy\left(\sin ^2 x\right) d y+(\sin x \cos x) y^2 d x=x d x is (where C{C} is the constant of integration)
View answer and explanation
Correct option: B
sin⁡2x⋅y2=x2+C\sin ^2 x \cdot y^2=x^2+C
Option B (sin⁡2x⋅y2=x2+C\sin ^2 x \cdot y^2=x^2+C) is correct because it is the solution obtained after rearranging and integrating the given differential equation.
959 Easy
959 of 975
Application +4 | -1
Solution of dydx+2xy2=y2\frac{d y}{d x}+2 x y^2=y^2 is
View answer and explanation
Correct option: A
1y=x2−x+C\frac{1}{y}=x^2-x+C
Option A (1y=x2−x+C\frac{1}{y}=x^2-x+C) is correct because the given differential equation is separable, and integrating both sides leads to this solution.
960 Easy
960 of 975
Understanding +4 | -1
The solution of dydx+p(x)y=0\frac{d y}{d x}+p(x) y=0 is
View answer and explanation
Correct option: C
y=ce−∫pdxy=c e^{-\int p d x}
Option C (y=ce−∫pdxy=c e^{-\int p d x}) is the correct solution to the given first-order linear homogeneous differential equation, derived by integrating factor method.
Revision notes and key takeaways

Review DIFFERENTIAL EQUATIONS in your textbook or class notes, then use this set to check your understanding.

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