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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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571 Medium
571 of 975
Application +4 | -1
If dx+dy=(x+y)(dx−dy)dx + dy = \left( {x + y} \right)\left( {dx - dy} \right), then log⁡(x+y)\log \left( {x + y} \right) is equal to
View answer and explanation
Correct option: C
x−y+cx - y + c
Option C (x−y+cx - y + c) is the correct solution because it is obtained by solving the given differential equation using substitution and integration.
572 Easy
572 of 975
Application +4 | -1
y=4sin⁡3xy=4 \sin 3 x is a solution of the differential equation
View answer and explanation
Correct option: C
d2ydx2+9y=0\frac{d^2 y}{d x^2}+9 y=0
Option C (d2ydx2+9y=0\frac{{d^2 y}}{{d x^2}}+9 y=0) is correct because the second derivative of y=4sin⁡3xy=4 \sin 3x satisfies this differential equation.
573 Easy
573 of 975
Application +4 | -1
I.F. for yln⁡ydxdy+x−ln⁡y=0y \ln y \frac{d x}{d y}+x-\ln y=0 is
View answer and explanation
Correct option: B
ln⁡y\ln y
Option B (ln⁡y\ln y) is correct because the integrating factor is calculated as e∫Pdye^{\int P dy} where PP is the coefficient of xx after rewriting the equation in the standard form.
574 Medium
574 of 975
Application +4 | -1
The equation of the curve satisfying the equation (xy−x2)dydx=y2\left( {xy - {x^2}} \right)\frac{{dy}}{{dx}} = {y^2} and passing through the point (−1,1)\left( { - 1,1} \right) is
View answer and explanation
Correct option: A
y=(log⁡y−1)xy = \left( {\log y - 1} \right)x
Option A (y=(log⁡y−1)xy = \left( {\log y - 1} \right)x) is the correct solution because it satisfies the given differential equation and passes through the point (-1, 1).
575 Easy
575 of 975
Understanding +4 | -1
The order and degree of the differential equation d2ydx2+(dydx)14+x15=0\frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^{\frac{1}{4}}+x^{\frac{1}{5}}=0, respectively, are
View answer and explanation
Correct option: A
2 and not defined
Option A (2 and not defined) is correct because the order is the highest derivative (2), but the degree is not defined due to the fractional exponent on the first derivative.
576 Easy
576 of 975
Understanding +4 | -1
The differential equation of displacement of all "Simple harmonic motions" of given period 2π/n2 \pi / n, is
View answer and explanation
Correct option: B
d2xdt2+n2x=0\frac{d^2 x}{d t^2}+n^2 x=0
Option B (d2xdt2+n2x=0\frac{{d^2 x}}{{d t^2}}+n^2 x=0) is correct because it represents the standard differential equation for simple harmonic motion with angular frequency n.
577 Easy
577 of 975
Analyzing +4 | -1
If f(x)f(x) is differentiable function in the interoal (0,∞)(0, \infty) such that f(1)=1f(1)=1 and lim⁡t→xt2f(x)−x2f(t)t−x=1\lim\limits _{t \rightarrow x} \frac{t^2 f(x)-x^2 f(t)}{t-x}=1 for each x>0x>0, then f(32)f\left(\frac{3}{2}\right) is equal to
View answer and explanation
Correct option: D
3118\frac{31}{18}
Option D is correct because it is the value of f(3/2) obtained after solving the differential equation and applying the initial condition f(1)=1.
578 Easy
578 of 975
Application +4 | -1
If y=y(x)y=y(x) is the solution of the differential equation, ey=exe^y=e^x such that y(0)=0y(0)=0, then y(1)y(1) is equal to:
View answer and explanation
Correct option: A
1+log⁡e21+\log _e 2
Option A (1+log⁡e21+\log _e 2) is correct because it is the value of y(1) obtained after solving the given differential equation and applying the initial condition y(0) = 0.
579 Easy
579 of 975
Application +4 | -1
The differential equation for which y=acos⁡x+bsin⁡xy=a \cos x+b \sin x is a solution, is
View answer and explanation
Correct option: A
d2ydx2+y=0\frac{d^2 y}{d x^2}+y=0
Option A (d2ydx2+y=0\frac{d^2 y}{d x^2}+y=0) is correct because it is the differential equation that results from differentiating the given function twice.
580 Easy
580 of 975
Understanding +4 | -1
Degree of differential equation edy/dx=x{e^{dy/dx}} = x is
View answer and explanation
Correct option: A
1
Option A (1) is correct because after taking the natural logarithm, the highest order derivative is 1 and its power is 1.
581 Easy
581 of 975
Application +4 | -1
The differential equation of all circles passing through the origin and having their centres on xx-axis
View answer and explanation
Correct option: C
(x2−y2)+2xydydx=0\left(x^2-y^2\right)+2 x y \frac{d y}{d x}=0
Option C, (x2−y2)+2xydydx=0\left(x^2-y^2\right)+2 x y \frac{d y}{d x}=0, is the correct differential equation representing the family of circles passing through the origin and having their centers on the x-axis.
582 Medium
582 of 975
Application +4 | -1
The integrating factor of the differential equation xlog⁡xdydx+y=2log⁡xx\log x\frac{{dy}}{{dx}} + y = 2\log x is given by
View answer and explanation
Correct option: B
log⁡x\log x
Option B (log⁡x\log x) is correct because it is the integrating factor obtained by rewriting the differential equation in standard form and then applying the integrating factor formula.
583 Medium
583 of 975
Application +4 | -1
For solution of dydx+ytan⁡x=sec⁡x,y(0)=1\frac{d y}{d x}+y \tan x=\sec x, y(0)=1, then y(π6)y\left(\frac{\pi}{6}\right) is equal to:
View answer and explanation
Correct option: B
1+32\frac{1+\sqrt{3}}{2}
Option B (1+32\frac{{1+\sqrt{{3}}}}{{2}}) is correct because it is the value of y(π6)y(\frac{{\pi}}{{6}}) obtained by solving the given differential equation with the initial condition.
584 Easy
584 of 975
Understanding +4 | -1
Assertion: The differential equation x2=y2+xydydxx^2=y^2+x y \frac{d y}{d x} is an ordinary differential equation.

Reason: An ordinary differential equation involves derivatives of the dependent variable with respect to only one dependent variable.
View answer and explanation
Correct option: A
Assertion is correct, Reason is correct; Reason is a correct explanation for assertion.
Assertion is correct, Reason is correct; Reason is a correct explanation for assertion because the given equation involves derivatives of the dependent variable with respect to only one independent variable.
585 Easy
585 of 975
Understanding +4 | -1
The order of the differential equation (d2ydx2)3=(1+dydx)1/2\left(\frac{d^2 y}{d x^2}\right)^3=\left(1+\frac{d y}{d x}\right)^{1 / 2}
View answer and explanation
Correct option: A
2
Option A is correct because after squaring both sides to eliminate the fractional exponent, the highest order derivative is d2y/dx2, making the order 2.
586 Easy
586 of 975
Application +4 | -1
If the solution curve f(x,y)=0f(x, y)=0 of the differential equation (1+log⁡ex)dxdy−xlog⁡ex=ey,x>0\left(1+\log _{e} x\right) \frac{d x}{d y}-x \log _{e} x=e^{y}, x > 0, passes through the points (1,0)(1,0) and (α,2)(\alpha, 2), then aaa^{a} is equal to
View answer and explanation
Correct option: A
e2e2e^{2 e^{2}}
Option A (e2e2e^{2 e^{2}}) is correct because after solving the differential equation and applying the given conditions, we find aa=e2e2a^a = e^{2e^2}.
587 Easy
587 of 975
Application +4 | -1
An equation of the curve satisfying x dy−y dx=x2−y2 dxx \mathrm{~d} y-y \mathrm{~d} x=\sqrt{x^2-y^2} \mathrm{~d} x and y(1)=0y(1)=0 is
View answer and explanation
Correct option: B
y=xsin⁡(log⁡∣x∣)y=x \sin (\log |x|)
Option B (y=xsin⁡(log⁡∣x∣)y=x \sin (\log |x|)) is correct because it satisfies the given differential equation and the initial condition y(1)=0y(1)=0.
588 Easy
588 of 975
Application +4 | -1
A function y=f(x)y=f(x) satisfies the differential equation f(x)⋅sin⁡2x−cos⁡x+(1+sin⁡2x)f′(x)=0f(x) \cdot \sin 2 x-\cos x+\left(1+\sin ^2 x\right) f^{\prime}(x)=0 with initial condition y(0)=0y(0)=0. The value of f(π/6)f(\pi / 6) is equal to
View answer and explanation
Correct option: D
2/52 / 5
Option D, 2/52 / 5, is the correct value of f(π/6)f(\pi / 6) obtained by solving the given differential equation with the initial condition y(0)=0y(0)=0.
589 Easy
589 of 975
Application +4 | -1
If y=y(x)y=y(x) satisfies the differential equation 8x(9+x)dy=(4+9+x)−1dx,x>08 \sqrt{x}(\sqrt{9+\sqrt{x}}) d y=(\sqrt{4+\sqrt{9+\sqrt{x}}})^{-1} d x, x > 0 and y(0)=7y(0)=\sqrt{7}, then y(256)=y(256)=
View answer and explanation
Correct option: A
3
Option D ((x−C)ex+y+1=0(x-C)e^{x+y} + 1 = 0) is correct because it is the solution obtained by substituting x+y=vx+y=v and integrating the resulting equation.
590 Medium
590 of 975
Application +4 | -1
The solution of the differential equation e−x(y+1)dy+(cos⁡2x−sin⁡2x)ydx=0{e^{ - x}}\left( {y + 1} \right)dy + \left( {{{\cos }^2}x - \sin 2x} \right)y\mathrm{ }dx = 0 subjected to the condition that y=1y = 1 when x=0x = 0 is
View answer and explanation
Correct option: A
y+log⁡y+excos⁡2x=2y + \log y + {e^x}{\cos ^2}x = 2
Option A (y+log⁡y+excos⁡2x=2y + \log y + {e^x}{\cos ^2}x = 2) is correct because it is the solution of the given differential equation that satisfies the given initial condition.
591 Medium
591 of 975
Application +4 | -1
Solution of the differential equation {1x−y2(x−y)2}dx+{x2(x−y)2−1y}dy=0\left\{\frac{1}{x}-\frac{y^2}{(x-y)^2}\right\} d x+\left\{\frac{x^2}{(x-y)^2}-\frac{1}{y}\right\} d y=0 is
View answer and explanation
Correct option: A
ln⁡∣xy∣+xyx−y=c\ln \left|\frac{x}{y}\right|+\frac{x y}{x-y}=c
Option A (ln⁡∣xy∣+xyx−y=c\ln |\frac{{x}}{{y}}| + \frac{{xy}}{{x-y}} = c) is the correct solution obtained by separating variables and integrating the given differential equation.
592 Medium
592 of 975
Application +4 | -1
The differential equation of the family of circles with fixed radius 5 unit and centre on the line y=2y = 2, is
View answer and explanation
Correct option: D
(y−2)2y′2=25−(y−2)2{\left( {y - 2} \right)^2}{y'^2} = 25 - {\left( {y - 2} \right)^2}
Option D ((y−2)2y′2=25−(y−2)2{\left( {y - 2} \right)^2}{y'^2} = 25 - {\left( {y - 2} \right)^2}) is correct because it represents the differential equation derived from the family of circles with radius 5 and center on the line y=2.
593 Easy
593 of 975
Application +4 | -1
Solution of differential equation xdy+ydx=exy−ℓnx2(xdy−ydx)x d y+y d x=e^{x y-\ell n x^2}(x d y-y d x) is given by: (where C{C} is arbitrary constant)
View answer and explanation
Correct option: A
yx+e−xy=C\frac{y}{x}+e^{-x y}=C
Option A (yx+e−xy=C\frac{y}{x}+e^{-x y}=C) is the correct solution to the given differential equation, obtained by rearranging and integrating.
594 Easy
594 of 975
Application +4 | -1
A solution of the equation xdy dx=y(log⁡y−log⁡x+1)x \frac{\mathrm{d} y}{\mathrm{~d} x}=y(\log y-\log x+1) is
View answer and explanation
Correct option: A
y=xecty=x e^{c t}
Option A (y=xecxy=x e^{c x}) is correct because it satisfies the given differential equation after substituting y=vxy=vx and solving the resulting separable equation.
595 Medium
595 of 975
Application +4 | -1
The solution of the differential equation (1+y2)tan⁡−1xdx+y(1+x2)dy=0\left( {1 + {y^2}} \right){\tan ^{ - 1}}xdx + y\left( {1 + {x^2}} \right)dy = 0 is
View answer and explanation
Correct option: B
log⁡(1+y2)+(tan⁡−1x)2=c\log \left( {1 + {y^2}} \right) + {\left( {{{\tan }^{ - 1}}x} \right)^2} = c
Option B (log⁡(1+y2)+(tan⁡−1x)2=c\log (1 + {y^2}) + {({{\tan }^{ - 1}}x)^2} = c) is correct because it is the solution obtained after separating variables and integrating the differential equation.
596 Easy
596 of 975
Application +4 | -1
Solution of dydx=x−y+3x+y+7\frac{d y}{d x}=\frac{x-y+3}{x+y+7} is
View answer and explanation
Correct option: A
x2−y2−2xy+6x−14y=cx^2-y^2-2 x y+6 x-14 y=c
Option A, x2−y2−2xy+6x−14y=cx^2-y^2-2 x y+6 x-14 y=c, is the correct solution obtained by rearranging the equation and integrating.
597 Easy
597 of 975
Application +4 | -1
The differential equation xdydx−y=x2x \frac{d y}{d x}-y=x^2, has the general solution
View answer and explanation
Correct option: B
2y−x3=Cx2 y-x^3=C x
Option B (2y−x3=Cx2 y-x^3=C x) is correct because it represents the general solution obtained after solving the given differential equation using the integrating factor method.
598 Medium
598 of 975
Application +4 | -1
Let y=y(x),y>0y=y(x), y>0, be a solution curve of the differential equation (1+x2)dy=y(x−y)dx\left(1+x^{2}\right) d y=y(x-y) d x. If y(0)=1y(0)=1 and y(22)=βy(2 \sqrt{2})=\beta, then
View answer and explanation
Correct option: A
e3β−1=e(3+22)e^{3 \beta^{-1}}=e(3+2 \sqrt{2})
Option A (e3β−1=e(3+22)e^{3 \beta^{-1}}=e(3+2 \sqrt{{2}})) is correct because it represents the solution to the given differential equation with the specified initial condition and value at x=22x = 2\sqrt{2}.
599 Easy
599 of 975
Understanding +4 | -1
The degree of the differential equation (d2ydx2)2+(dydx)2=xsin⁡(dydx)\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^2=x \sin \left(\frac{d y}{d x}\right) is
View answer and explanation
Correct option: D
not defined
Option D (not defined) is correct because the presence of the derivative inside the sine function makes it impossible to express the equation as a polynomial in derivatives.
600 Easy
600 of 975
Application +4 | -1
Solution of the differential equation ln⁡(dydx)=ax+\ln \left(\frac{d y}{d x}\right)=a x+ by is
View answer and explanation
Correct option: A
−1be−by=1aeax+c-\frac{1}{b} e^{-b y}=\frac{1}{a} e^{a x}+c
Option D (−1be−by=1aeax+c-\frac{1}{b} e^{-b y}=\frac{1}{a} e^{a x}+c) is the correct solution to the differential equation, obtained by separating variables and integrating.
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