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JEE • MATHEMATICS • DEFINITE INTEGRATION

Definite integration practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 571-596 of 596 questions
571 Medium
571 of 596
Application +4 | -1
If the orthogonal trajectories of the family of curves en−1x=yne^{n-1} x=y^n always passes through (1,e)(1, e) and (0,0)(0,0), then value of n\boldsymbol{n} is
View answer and explanation
Correct option: D
−e2-e^2
Option D (−e2-e^2) is correct because substituting the given points into the orthogonal trajectory equation allows us to solve for n, resulting in n = -e2.
572 Medium
572 of 596
Application +4 | -1
Area inside the parabola y2=4axy^2=4 a x, between the lines x=ax=a and x=4ax=4 a is equal to
View answer and explanation
Correct option: C
28a2328 \frac{a^2}{3}
Option C (28a2328 \frac{a^2}{3}) is correct because the area inside the parabola y2=4axy^2=4ax between the lines x=ax=a and x=4ax=4a is found by integrating 2ax2\sqrt{ax} from aa to 4a4a, which results in 283a2\frac{28}{3}a^2.
573 Medium
573 of 596
Application +4 | -1
If [x]\left[ x \right] is the greatest integer ≤x\le x then π2∫02(sin⁡πx2)(x−∣x∣)[x]dx{\pi ^2}\int\limits_0^2 {\left( {\sin \frac{{\pi x}}{2}} \right)(x - \left| x \right|} {)^{\left[ x \right]}}dx is equal to
View answer and explanation
Correct option: B
4(π−1)4\left( {\pi - 1} \right)
Option B (4(π−1)4(\pi - 1)) is correct because the integral is evaluated by splitting the integration range and using the greatest integer function.
574 Medium
574 of 596
Application +4 | -1
The value of the integral ∫01xα−1ln⁡xdx\int\limits_{0}^1 \frac{x^\alpha-1}{\ln x} d x, is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the correct result of the integral is ln(α\alpha+1), which is not among the options.
575 Medium
575 of 596
Analyzing +4 | -1
If ∫01  cot⁡−1  (1  −  x  +  x2)  dx=k ∫01tan⁡−1  x dx\int \limits_0^1 \,\,{\cot ^{ - 1}}\,\,\left( {1\,\, - \,\,x\,\, + \,\,{x^2}} \right)\,\,dx = k\,\int \limits_0^1 {\tan ^{ - 1}}\,\,x\,dx, then k=k =
View answer and explanation
Correct option: B
2\mathrm{2}
Option B is correct because after applying properties of inverse trigonometric functions and simplifying, k=2k = 2.
576 Medium
576 of 596
Application +4 | -1
∫−π/2π/2  sin⁡  ∣ x ∣  dx\int \nolimits_{ - \pi /2}^{\pi /2} \,\,\sin \,\,\left| {\,x\,} \right|\,\,dxis equal to
View answer and explanation
Correct option: C
2\mathrm{2}
Option C (2) is correct because the integral of sin|x| from -π\pi/2 to π\pi/2 is twice the integral of sin(x) from 0 to π\pi/2.
577 Medium
577 of 596
Application +4 | -1
Find the value of ∫−13/2∣xsin⁡πx∣dx\int\limits_{{-1}}^{3 / 2}|x \sin \pi x| d x.
View answer and explanation
Correct option: A
3π+1π2\frac{3}{\pi}+\frac{1}{\pi^2}
Option A (3π+1π2\frac{{3}}{{\pi}} + \frac{{1}}{{\pi^2}}) is correct because the integral is evaluated by splitting it into intervals where the sine function has different signs and then integrating by parts.
578 Medium
578 of 596
Application +4 | -1
The value of ∫35  x2x2−  4  dx\int \limits_3^5 \,\,\frac{{{x^2}}}{{{x^2} - \,\,4}}\,\,dx, is
View answer and explanation
Correct option: B
2  +  log⁡e(157)2\,\, + \,\,{\log _e}\left( {\frac{{15}}{7}} \right)
Option B (2  +  log⁡e(157)2\,\, + \,\,{\log _e}\left( {\frac{{15}}{7}} \right)) is correct because evaluating the definite integral using partial fractions yields this result.
579 Medium
579 of 596
Analyzing +4 | -1
The value of ∫0π/2 cosec    (x−π/3)  cosec  (x  −  π/6)dx\int \limits_0^{\pi /2} \,\mathrm{cosec}\;\,\,\left( {x - \pi /3} \right)\,\,\mathrm{cosec}\,\,\left( {x\,\, - \,\,\pi /6} \right)dx, is
View answer and explanation
Correct option: B
− 2  log⁡  3- \,2\,\,\log \,\,3
Option B (-2 log 3) is correct because the integral simplifies using trigonometric identities and evaluates to -2 log 3 after applying the limits.
580 Medium
580 of 596
Application +4 | -1
The value of the integral ∫0x(1−∣sin⁡8x∣)dx\int\limits_{0}^x(1-|\sin 8 x|) d x is
View answer and explanation
Correct option: C
π−2\pi-2
Option C (π−2\pi-2) is correct because the integral is evaluated by splitting the integral and using the periodicity of the sine function.
581 Medium
581 of 596
Application +4 | -1
If y=f(x)y=f(x) makes positive intercepts of 2 and 1 unit on xx and yy coordinate axes and encloses an area of 3/43 / 4 square unit with the axes, then ∫02xf′(x)dx\int\limits_{0}^2 x f^{\prime}(x) d x, is
View answer and explanation
Correct option: D
−34-\frac{3}{4}
Option D (−34-\frac{3}{4}) is correct because it is the result of integration by parts, using the given information about the function's intercepts and area.
582 Medium
582 of 596
Application +4 | -1
The value of ∫127  1x  (2x7  +  1)  dx\int \limits_1^{\sqrt[7]{2}} \,\,\frac{1}{{x\,\,\left( {2{x^7}\,\, + \,\,1} \right)}}\,\,dx, is
View answer and explanation
Correct option: C
(1/7)  log⁡  (6/5)\left( {1/7} \right)\,\,\log \,\,\left( {6/5} \right)
Option C ((1/7)log⁡(6/5)\left( {1/7} \right)\log \left( {6/5} \right)) is correct because the integral is solved by using a substitution to simplify the expression.
583 Medium
583 of 596
Analyzing +4 | -1
The value of integral ∫3π43π4x1+sin⁡xdx\int\limits_ {\frac{3 \pi}{4}}^{\frac{3 \pi}{4}} \frac{x}{1+\sin x} d x is
View answer and explanation
Correct option: A
π2(2+1)\frac{\pi}{2}(\sqrt{2}+1)
Option A (π2(2+1)\frac{\pi}{2}(\sqrt{2}+1)) is correct because the integral is solved by multiplying the numerator and denominator by (1-sin x) and then integrating by parts.
584 Medium
584 of 596
Analyzing +4 | -1
Let f(x)=ex1+exf(x) =\frac{e^x}{1+e^x} I1=∫f(−a)f(a)xg(x(1−x))dxI_1 =\int\limits_{{f(-a)}}^{f(a)} x g(x(1-x)) d x I2=∫f(−a)f(a)g(x(1−x))dxI_2 =\int\limits_{{f(-a)}}^{f(a)} g(x(1-x)) d x then I2/I1I_2 / I_1 is
View answer and explanation
Correct option: D
2
The correct answer is D (2) because using the property f(a) + f(-a) = 1 and substituting (1-x) for x in the integral allows us to relate I1 and I2.
585 Medium
585 of 596
Application +4 | -1
If f(x)    and    g(x),    x ∈ Rf\left( x \right)\mathrm{\;}\,\,\mathrm{and}\,\,\;g\left( x \right),\,\,\;x\, \in \,R are continuous functions, then value of integral

∫−π/2π/2  [{ f(x)  +  f(−x)}  {g(x)  −  g(−x)}]  dx\int \nolimits_{ - \pi /2}^{\pi /2} \,\,\left[ {\left\{ {\,f\left( x \right)\,\, + \,\,f\left( { - x} \right)} \right\}\,\,\left\{ {g\left( x \right)\,\, - \,\,g\left( { - x} \right)} \right\}} \right]\;dx is
View answer and explanation
Correct option: D
0\mathrm{0}
Option D (0\mathrm{0}) is correct because the integrand is an odd function integrated over a symmetric interval.
586 Medium
586 of 596
Analyzing +4 | -1
If F(x)=1x2  ∫4x  [4t2  −  2 F′  (t)] dtF\left( x \right) = \frac{1}{{{x^2}}}\,\,\int \limits_4^x \,\,\left[ {4{t^2}\,\, - \,\,2\,F'\,\,\left( t \right)} \right]\,dt, then F′  (4)F'\,\,\left( 4 \right) equals
View answer and explanation
Correct option: C
32 / 9\mathrm{32}\,\mathrm{/}\,\mathrm{9}
Option C (329\frac{\mathrm{32}}{\mathrm{9}}) is correct because after differentiating and substituting, the value of F′(4)F'(4) is found to be 329\frac{\mathrm{32}}{\mathrm{9}}.
587 Medium
587 of 596
Analyzing +4 | -1
Let In=∫0π/2sin⁡(2n−1)xsin⁡xdx,Fn=∫0π/2sin⁡2nxsin⁡2x,n∈NI_n=\int_0^{\pi / 2} \frac{\sin (2 n-1) x}{\sin x} d x, \mathcal{F}_n=\int_0^{\pi / 2} \frac{\sin ^2 n x}{\sin ^2 x}, n \in N, then
View answer and explanation
Correct option: B
Fn+1−Fn=In+1\mathcal{F}_{n+1}-\mathcal{F}_n=I_{n+1}
Option B (Fn+1−Fn=In+1\mathcal{F}_{n+1}-\mathcal{F}_n=I_{n+1}) is correct because it follows from the derivation of the difference between consecutive terms of F\mathcal{F} and its relation to II.
588 Medium
588 of 596
Application +4 | -1
The value of integral ∫01  1  −  x1  +  x    dx\int \nolimits_0^1 \,\,\sqrt {\frac{{1\,\, - \,\,x}}{{1\,\, + \,\,x}}} \;\,\,dx is
View answer and explanation
Correct option: B
π2−1\frac{\mathrm{\pi }}{2} - 1
Option B (π2−1\frac{\mathrm{\pi }}{2} - 1) is correct because the integral is solved by simplifying the expression and using trigonometric substitution.
589 Medium
589 of 596
Analyzing +4 | -1
Let nn be the number of integral values of xx, which satisfy the equation

tan⁡−1x−sin⁡−1x=cos⁡−1x−cot⁡−1x\tan ^{-1} x-\sin ^{-1} x=\cos ^{-1} x-\cot ^{-1} x.

Let c⃗=∣a⃗×b⃗∣a⃗+(a⃗⋅b⃗)b⃗\vec{c}=|\vec{a} \times \vec{b}| \vec{a}+(\vec{a} \cdot \vec{b}) \vec{b} \quad where a⃗\vec{a} and b⃗\vec{b} are unit vectors and angle between a⃗\vec{a} and b⃗\vec{b} is π6\frac{\pi}{6}

Let the value of definite integral ∫−π2π2ln⁡(sec⁡x)(2013)sin⁡x+1dx\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} \frac{\ln (\sec x)}{(2013)^{\sin x}+1} d x equals π2ln⁡k\frac{\pi}{2} \ln k, then the value of (n+2∣c→∣2+k)\left(\mathrm{n}+2|\overrightarrow{\mathrm{c}}|^2+\mathrm{k}\right) is equal to
View answer and explanation
Correct option: C
172\frac{17}{2}
The correct answer is C (17/2). This value is obtained by solving trigonometric equations, vector algebra, and definite integrals, then summing the results.
590 Medium
590 of 596
Application +4 | -1
If f(x)={ecos⁡xsin⁡x for ∣x∣≤22 otherwisef(x)=\left\{\begin{array}{l}e^{\cos x} \sin x \text { for }|x| \leq 2 \\ 2 \text { otherwise}\end{array}\right., then ∫−23f(x)dx=\int\limits_{{-2}}^3 f(x) d x=
View answer and explanation
Correct option: C
2
Option C (2) is correct. The integral is evaluated by splitting the integral and recognizing that one part is an odd function.
591 Medium
591 of 596
Application +4 | -1
The area bounded by the curve y=4x−x2y=4 x-x^2 and the xx-axis, is
View answer and explanation
Correct option: C
323\frac{32}{3} sq. unit
Option C (323\frac{32}{3} sq. unit) is correct because the area bounded by the curve y=4x−x2y = 4x - x^2 and the x-axis is found by integrating the function from 0 to 4, which results in 323\frac{32}{3}.
592 Medium
592 of 596
Application +4 | -1
The value of the definite integral ∫01xdx(x3+16)\int\limits_{0}^1 \frac{x d x}{\left(x^3+16\right)} lies in the interval [a,b][a, b]. Then smallest such interval is
View answer and explanation
Correct option: A
[0,117]\left[0, \frac{1}{17}\right]
Option A ([0, 117\frac{{1}}{{17}}]) is correct because the integral's value lies within this interval, determined by bounding the integrand.
593 Medium
593 of 596
Analyzing +4 | -1
3(e−1)e∫12x2e[x]+[x2]dx\frac{3(e-1)}{e} \int\limits_{1}^2 x^2 e^{[x]+\left[x^2\right]} dx equals:
View answer and explanation
Correct option: C
e8−ee^8-e
Option C (e8−ee^8-e) is correct because after evaluating the integral by splitting the interval and using the greatest integer function, the result simplifies to e8−ee^8-e.
594 Medium
594 of 596
Application +4 | -1
∫05[x]{x}dx\int\limits_{0}^5[x]\{x\} d x (where [.] denotes greatest integer function and {\{.}\} denotes fractional part of function) is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the integral of [x]{x} from 0 to 5 can be broken down into intervals where [x] is constant, and the sum of these integrals equals 5.
595 Medium
595 of 596
Analyzing +4 | -1
If ϕ(x)=cos⁡   x −∫0x  (x−t)  ϕ  (t)  dt\phi \left( x \right) = \cos \,\,\,x\, - \int \nolimits_0^x \,\,\left( {x - t} \right)\,\,\phi \,\,\left( t \right)\,\,dt, then ϕ′′  (x)  +  ϕ  (x)\phi ''\,\,\left( x \right)\,\, + \,\,\phi \,\,\left( x \right) is equal to

View answer and explanation
Correct option: A
−  cos⁡  x- \,\,\cos \,\,x
Option A is correct because after differentiating the given equation twice and simplifying, ϕ′′  (x)  +  ϕ  (x)\phi ''\,\,\left( x \right)\,\,+ \,\,\phi \,\,\left( x \right) is equal to −  cos⁡  x- \,\,\cos \,\,x.
596 Medium
596 of 596
Application +4 | -1
If ∫sin⁡xsin⁡(x−α)dx=Ax+Blog⁡sin⁡(x−α),+C\int \frac{\sin x}{\sin (x-\alpha)} d x=A x+B \log \sin (x-\alpha),+C, then value of (A,B)(A, B) is
View answer and explanation
Correct option: B
(cos⁡α,sin⁡α)(\cos \alpha, \sin \alpha)
Option B (cos⁡α,sin⁡α\cos \alpha, \sin \alpha) is correct because after expanding and integrating, the coefficients of x and the logarithm term match these values.
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