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JEE • MATHEMATICS • DEFINITE INTEGRATION
Definite integration practice · Medium
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Showing 571-596 of 596 questions
571
Medium
571 of 596
Application
+4 | -1
If the orthogonal trajectories of the family of curves always passes through and , then value of is
View answer and explanation
Correct option: D
Option D () is correct because substituting the given points into the orthogonal trajectory equation allows us to solve for n, resulting in n = -e2.
572
Medium
572 of 596
Application
+4 | -1
Area inside the parabola , between the lines and is equal to
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Correct option: C
Option C () is correct because the area inside the parabola between the lines and is found by integrating from to , which results in .
573
Medium
573 of 596
Application
+4 | -1
If is the greatest integer then is equal to
View answer and explanation
Correct option: B
Option B () is correct because the integral is evaluated by splitting the integration range and using the greatest integer function.
574
Medium
574 of 596
Application
+4 | -1
The value of the integral , is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the correct result of the integral is ln(+1), which is not among the options.
575
Medium
575 of 596
Analyzing
+4 | -1
If , then
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Correct option: B
Option B is correct because after applying properties of inverse trigonometric functions and simplifying, .
576
Medium
576 of 596
Application
+4 | -1
is equal to
View answer and explanation
Correct option: C
Option C (2) is correct because the integral of sin|x| from -/2 to /2 is twice the integral of sin(x) from 0 to /2.
577
Medium
577 of 596
Application
+4 | -1
Find the value of .
View answer and explanation
Correct option: A
Option A () is correct because the integral is evaluated by splitting it into intervals where the sine function has different signs and then integrating by parts.
578
Medium
578 of 596
Application
+4 | -1
The value of , is
View answer and explanation
Correct option: B
Option B () is correct because evaluating the definite integral using partial fractions yields this result.
579
Medium
579 of 596
Analyzing
+4 | -1
The value of , is
View answer and explanation
Correct option: B
Option B (-2 log 3) is correct because the integral simplifies using trigonometric identities and evaluates to -2 log 3 after applying the limits.
580
Medium
580 of 596
Application
+4 | -1
The value of the integral is
View answer and explanation
Correct option: C
Option C () is correct because the integral is evaluated by splitting the integral and using the periodicity of the sine function.
581
Medium
581 of 596
Application
+4 | -1
If makes positive intercepts of 2 and 1 unit on and coordinate axes and encloses an area of square unit with the axes, then , is
View answer and explanation
Correct option: D
Option D () is correct because it is the result of integration by parts, using the given information about the function's intercepts and area.
582
Medium
582 of 596
Application
+4 | -1
The value of , is
View answer and explanation
Correct option: C
Option C () is correct because the integral is solved by using a substitution to simplify the expression.
583
Medium
583 of 596
Analyzing
+4 | -1
The value of integral is
View answer and explanation
Correct option: A
Option A () is correct because the integral is solved by multiplying the numerator and denominator by (1-sin x) and then integrating by parts.
584
Medium
584 of 596
Analyzing
+4 | -1
Let then is
View answer and explanation
Correct option: D
2
The correct answer is D (2) because using the property f(a) + f(-a) = 1 and substituting (1-x) for x in the integral allows us to relate I1 and I2.
585
Medium
585 of 596
Application
+4 | -1
If are continuous functions, then value of integral
is
is
View answer and explanation
Correct option: D
Option D () is correct because the integrand is an odd function integrated over a symmetric interval.
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586
Medium
586 of 596
Analyzing
+4 | -1
If , then equals
View answer and explanation
Correct option: C
Option C () is correct because after differentiating and substituting, the value of is found to be .
587
Medium
587 of 596
Analyzing
+4 | -1
Let , then
View answer and explanation
Correct option: B
Option B () is correct because it follows from the derivation of the difference between consecutive terms of and its relation to .
588
Medium
588 of 596
Application
+4 | -1
The value of integral is
View answer and explanation
Correct option: B
Option B () is correct because the integral is solved by simplifying the expression and using trigonometric substitution.
589
Medium
589 of 596
Analyzing
+4 | -1
Let be the number of integral values of , which satisfy the equation
.
Let where and are unit vectors and angle between and is
Let the value of definite integral equals , then the value of is equal to
.
Let where and are unit vectors and angle between and is
Let the value of definite integral equals , then the value of is equal to
View answer and explanation
Correct option: C
The correct answer is C (17/2). This value is obtained by solving trigonometric equations, vector algebra, and definite integrals, then summing the results.
590
Medium
590 of 596
Application
+4 | -1
If , then
View answer and explanation
Correct option: C
2
Option C (2) is correct. The integral is evaluated by splitting the integral and recognizing that one part is an odd function.
591
Medium
591 of 596
Application
+4 | -1
The area bounded by the curve and the -axis, is
View answer and explanation
Correct option: C
sq. unit
Option C ( sq. unit) is correct because the area bounded by the curve and the x-axis is found by integrating the function from 0 to 4, which results in .
592
Medium
592 of 596
Application
+4 | -1
The value of the definite integral lies in the interval . Then smallest such interval is
View answer and explanation
Correct option: A
Option A ([0, ]) is correct because the integral's value lies within this interval, determined by bounding the integrand.
593
Medium
593 of 596
Analyzing
+4 | -1
equals:
View answer and explanation
Correct option: C
Option C () is correct because after evaluating the integral by splitting the interval and using the greatest integer function, the result simplifies to .
594
Medium
594 of 596
Application
+4 | -1
(where [.] denotes greatest integer function and . denotes fractional part of function) is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the integral of [x]{x} from 0 to 5 can be broken down into intervals where [x] is constant, and the sum of these integrals equals 5.
595
Medium
595 of 596
Analyzing
+4 | -1
If , then is equal to
View answer and explanation
Correct option: A
Option A is correct because after differentiating the given equation twice and simplifying, is equal to .
596
Medium
596 of 596
Application
+4 | -1
If , then value of is
View answer and explanation
Correct option: B
Option B () is correct because after expanding and integrating, the coefficients of x and the logarithm term match these values.
Revision notes and key takeaways
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