Skip to main content
Back to DEFINITE INTEGRATION

Your Progress

0 / 791 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • DEFINITE INTEGRATION

Definite integration practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 631-660 of 791 questions

Preparing practice and saved progress…

631 Easy
631 of 791
Application +4 | -1
The value of ∫π/4π/2cot⁡θcosec⁡2θdθ\int\limits_{{\pi / 4}}^{\pi / 2} \cot \theta \operatorname{cosec}^2 \theta \mathrm{d} \theta is
View answer and explanation
Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct. The integral is solved by using a simple substitution to simplify the expression and then evaluating the resulting integral.
632 Easy
632 of 791
Analyzing +4 | -1
The value of the integral ∫−aa  xex21+x2  dx\int \nolimits_{ - a}^a \,\,\frac{{x{e^x}^2}}{{1 + {x^2}}}\,\,dx is
View answer and explanation
Correct option: B
0
Option B (0) is correct because the integrand is an odd function, and the integral is evaluated over a symmetric interval.
633 Easy
633 of 791
Application +4 | -1
The value of ∫0π/2ex2ex2+e(π2−x)2dx\int\limits_{0}^{\pi / 2} \frac{e^{x^2}}{e^{x^2}+e^{\left(\frac{\pi}{2}-x\right)^2}} d x is
View answer and explanation
Correct option: A
π/4\pi / 4
Option A (π/4\pi / 4) is correct because by using the property of definite integrals ∫0af(x)dx=∫0af(a−x)dx\int_0^a f(x) dx = \int_0^a f(a-x) dx, the integral simplifies to π/4\pi/4.
634 Easy
634 of 791
Understanding +4 | -1
If I=∫0π/4sin⁡2xdxI=\int\limits_{0}^{\pi / 4} \sin ^2 x d x and J=∫0π/4cos⁡2xdxJ=\int\limits_{0}^{\pi / 4} \cos ^2 x d x, then I=I=
View answer and explanation
Correct option: A
π4−J\frac{\pi}{4}-J
Option C is correct because the integrals of sin²(x) and cos²(x) from 0 to π/4 are related by I + J = π/4.
635 Easy
635 of 791
Application +4 | -1
∫0π/2  dx1+  tan⁡3  x\int \nolimits_0^{\pi /2} \,\,\frac{{dx}}{{1 + \,\,{{\tan }^3}\,\,x}} is equal to
View answer and explanation
Correct option: C
π4\frac{\pi }{4}
Option C (π4\frac{\pi }{4}) is correct because the integral is evaluated using properties of definite integrals and trigonometric identities.
636 Easy
636 of 791
Application +4 | -1
∫π/3π/2xsin⁡(π[x]−x)dx\int\limits_{{\pi / 3}}^{\pi / 2} x \sin (\pi[x]-x) d x is equal to :
View answer and explanation
Correct option: B
1−32+π61-\frac{\sqrt{3}}{2}+\frac{\pi}{6}
Option B (1−32+π61-\frac{\sqrt{3}}{2}+\frac{\pi}{6}) is correct because in the interval [π3,π2][\frac{\pi}{3}, \frac{\pi}{2}], [x]=1[x] = 1, so the integral simplifies and can be evaluated using integration by parts.
637 Easy
637 of 791
Application +4 | -1
\lim \limits_\limits {n \rightarrow \infty} \frac{1+2^4+3^4+\ldots n^4}{n^5}-\lim \limits_{{n \rightarrow \infty}} \frac{1+2^3+3^3+\ldots n^3}{n^5}\lim \limits_\limits {n \rightarrow \infty} \frac{1+2^4+3^4+\ldots n^4}{n^5}-\lim \limits_{{n \rightarrow \infty}} \frac{1+2^3+3^3+\ldots n^3}{n^5}
View answer and explanation
Correct option: A
15\frac{1}{5}
Option A (15\frac{1}{5}) is correct because the limit is evaluated by converting the sums to integrals and subtracting.
638 Easy
638 of 791
Application +4 | -1
∫0π/2  x  sin⁡  x  dx\int \nolimits_0^{\pi /2} \,\,x\,\,\sin \,\,x\,\,dx is equal to
View answer and explanation
Correct option: B
1\mathrm{1}
Option B (1) is correct because it is the result of integrating x*sin(x) by parts over the interval [0, pi/2].
639 Easy
639 of 791
Application +4 | -1
If k=∫01et1+tdtk=\int_0^1 \frac{e^t}{1+t} d t, then ∫01etlog⁡e(1+t)dt\int_0^1 e^t \log _e(1+t) d t is equal to
View answer and explanation
Correct option: C
eln⁡2−ke \ln 2-k
The correct answer is C (eln⁡2−ke \ln 2-k) because after applying integration by parts, the integral is expressed in terms of k, resulting in eln⁡2−ke \ln 2 - k.
640 Easy
640 of 791
Analyzing +4 | -1
The value of ∫π/43π/4  x1  +  sin⁡  x  dx\int \limits_{\pi /4}^{3\pi /4} \,\,\frac{x}{{1\,\, + \,\,\sin \,\,x}}\,\,dx is equal to
View answer and explanation
Correct option: A
(2−1)π\left( {\sqrt 2 - 1} \right)\pi
Option A ((2−1)π\sqrt 2 - 1)\pi) is correct because the integral can be solved by using the property ∫abf(x)dx=∫abf(a+b−x)dx\int_a^b f(x) dx = \int_a^b f(a+b-x) dx and then simplifying the resulting expression.
641 Easy
641 of 791
Analyzing +4 | -1
The value of the integral ∫−11x7−3x5+7x3−xcos⁡2xdx\int\limits_{{-1}}^1 \frac{x^7-3 x^5+7 x^3-x}{\cos ^2 x} d x is
View answer and explanation
Correct option: B
0
Option B (0) is correct because the integrand is an odd function integrated over a symmetric interval.
642 Easy
642 of 791
Application +4 | -1
Let a be a positive real number such that ∫0aex−[x]dx=10e−9 \int_\mathrm{0}^\mathrm{a} {{\mathrm{e}^{x - \left[ x \right]}}dx} \mathrm{ = 10e - 9}\,, where [x] is the greatest integer less than or equal to x. Then, a is equal to
View answer and explanation
Correct option: B
10+loge2\mathrm{10 + lo}{\mathrm{g}_e}2
Option B is correct because the integral can be solved by splitting it into intervals of length 1, utilizing the property of the greatest integer function, and then solving for 'a'.
643 Easy
643 of 791
Application +4 | -1
Solve ∫0π/2dx(a2cos⁡2x+b2sin⁡2x)2\int\limits_{0}^{\pi / 2} \frac{d x}{\left(a^2 \cos ^2 x+b^2 \sin ^2 x\right)^2}
View answer and explanation
Correct option: B
π4(a2+b2a3b3)\frac{\pi}{4}\left(\frac{a^2+b^2}{a^3 b^3}\right)
Option B (π4(a2+b2a3b3)\frac{\pi}{4}\left(\frac{a^2+b^2}{a^3 b^3}\right)) is correct because the integral can be solved using trigonometric substitution and partial fractions.
644 Easy
644 of 791
Application +4 | -1
∫23  dxx2−x\int \nolimits_2^3 \,\,\frac{{dx}}{{{x^2} - x}} is equal to
View answer and explanation
Correct option: C
log⁡  (43)\log \,\,\left( {\frac{4}{3}} \right)
Option C is correct because the integral of 1/(x2 - x) from 2 to 3 is solved using partial fraction decomposition, resulting in log(4/3).
645 Easy
645 of 791
Application +4 | -1
lim⁡n→∞2k+4k+6k+…+(2n)knk+1,k≠−1\lim \limits_{\mathrm{n} \rightarrow \infty} \frac{2^{\mathrm{k}}+4^{\mathrm{k}}+6^{\mathrm{k}}+\ldots+(2 \mathrm{n})^{\mathrm{k}}}{\mathrm{n}^{\mathrm{k}+1}}, \mathrm{k} \neq-1, is equal to
View answer and explanation
Correct option: B
2kk+1\frac{2^{\mathrm{k}}}{\mathrm{k}+1}
Option B (2kk+1\frac{2^{\mathrm{k}}}{\mathrm{k}+1}) is correct because the limit can be expressed as a Riemann sum and then evaluated as a definite integral.
646 Easy
646 of 791
Analyzing +4 | -1
If ∣∫abf(x)dx∣=∫ab∣f(x)∣dx,  a<b,\left| {\int_a^b f (x)dx} \right| = \int_a^b | f(x)|dx,\,\,a < b, then f(x)=0f(x)=0 has
View answer and explanation
Correct option: C
no root in (a,b)(a, b)
Option C (no root in (a,b)(a, b)) is correct because the equality holds only if f(x) does not change sign in the interval (a, b).
647 Easy
647 of 791
Application +4 | -1
The value of ∫01  22x+1  −  52x−110x  dx\int \limits_0^1 \,\,\frac{{{2^{2x + 1}}\,\, - \,\,{5^{2x - 1}}}}{{{{10}^x}}}\,\,dx, is
View answer and explanation
Correct option: B
−35  {2log⁡e  (25)  +  12  log⁡e  (52)}- \frac{3}{5}\,\,\left\{ {\frac{2}{{{{\log }_e}\,\,\left( {\frac{2}{5}} \right)}}\,\, + \,\,\frac{1}{{2\,\,{{\log }_e}\,\,\left( {\frac{5}{2}} \right)}}} \right\}
Option B is correct because after simplifying the integrand and evaluating the definite integral, the result matches the given expression.
648 Easy
648 of 791
Application +4 | -1
Solution of the equation ∫log⁡e2xdtet−1=π6\int\limits_{{\log _e 2}}^x \frac{d t}{\sqrt{e^t-1}}=\frac{\pi}{6} is
View answer and explanation
Correct option: D
log⁡e4\log _e 4
Option D (log_e 4) is correct because after evaluating the integral and solving for x, the result is x = log_e 4.
649 Easy
649 of 791
Analyzing +4 | -1
\lim \limits_\limits{n \rightarrow \infty}\left(\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+\ldots .+\frac{1}{5 n}\right)\lim \limits_\limits{n \rightarrow \infty}\left(\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+\ldots .+\frac{1}{5 n}\right) is equal to:
View answer and explanation
Correct option: D
tan⁡−1(2)\tan ^{-1}(2)
Option D (tan⁡−1(2)\tan^{-1}(2)) is correct because the given limit can be expressed as a Riemann sum, which then converts into a definite integral that evaluates to tan⁡−1(2)\tan^{-1}(2).
650 Easy
650 of 791
Application +4 | -1
The value of ∫0100[tan⁡−1x]dx\int\limits_{0}^{100}\left[\tan ^{-1} x\right] d x, is
View answer and explanation
Correct option: C
100−tan⁡1100-\tan 1
Option C (100−tan⁡1100 - \tan 1) is correct because the integral simplifies to the length of the interval where the greatest integer of tan⁡−1x\tan^{-1} x is 1.
651 Easy
651 of 791
Application +4 | -1
If I(m,   n)=∫01  tm(1+  t)n   dtI\left( {m,\;\,n} \right) = \int \nolimits_0^1 \,\,{t^m}{\left( {1 + \,\,t} \right)^n}\;\,dt, then the expression for I(m,   n)I\left( {m,\;\,n} \right) in terms of I(m+1,    n−1)I\left( {m + 1,\,\,\;n - 1} \right) is

View answer and explanation
Correct option: A
2nm+1  −  nm+1   I(m+1,   n−1)\frac{{{2^n}}}{{m + 1}}\,\, - \,\,\frac{n}{{m + 1}}\,\;I\left( {m + 1,\;\,n - 1} \right)
Option A (2nm+1 − nm+1   I(m+1,   n−1)\frac{{{2^n}}}{{m + 1}}\, - \,\frac{n}{{m + 1}}\,\;I\left( {m + 1,\;\,n - 1} \right)) is correct because it is derived by integration by parts.
652 Easy
652 of 791
Application +4 | -1
lim⁡n→∞  ∑r=1n  1n  er/n  is\lim\limits_{n \to \infty } \,\,\sum \nolimits_{r = 1}^n \,\,\frac{1}{n}\,\,{e^{r/n}}\,\,\mathrm{is}
View answer and explanation
Correct option: B
e  −  1e\,\, - \,\,1
Option B (e  −  1e\,\, - \,\,1) is correct because the limit of the sum can be expressed as a definite integral and then evaluated.
653 Easy
653 of 791
Understanding +4 | -1
If I1=∫x111+t2dtI_1=\int\limits_{x}^1 \frac{1}{1+t^2} d t and I2=∫1111+t2dtI_2=\int\limits_{1}^1 \frac{1}{1+t^2} d t for x>0x>0, then
View answer and explanation
Correct option: A
I1=I2I_1=I_2
Option A is correct because by substituting t = 1/u in I1, we can show that I1 is equal to I2.
654 Easy
654 of 791
Application +4 | -1
Let [.] denote the greatest integer function, then the value of ∫01.5x[x2]dx\int\limits_{0}^{1.5} x\left[x^2\right] d x, is
View answer and explanation
Correct option: B
34\frac{3}{4}
Option B (34\frac{3}{4}) is correct because the integral is evaluated by breaking it into intervals where the greatest integer function has a constant value.
655 Easy
655 of 791
Application +4 | -1
The value of ∫−115  sgn  ({x})  dx\int \nolimits_{ - 1}^{15} \,\,\mathrm{sgn}\,\,\left( {\left\{ x \right\}} \right)\,\,dx, where { ⋅ }\left\{ {\, \cdot \,} \right\} denotes the fractional part function, is
View answer and explanation
Correct option: B
16\mathrm{16}
Option B (16) is correct because the integral of the sign of the fractional part function over the given interval simplifies to 16.
656 Easy
656 of 791
Application +4 | -1
A particle is moving on the curve with the equation y=2sin⁡−1(3x)y=2 \sin ^{-1}(3 x). When y=π3y=\frac{\pi}{3} the rate of change of " yy " w.r.t time is 2 unit/sec. What is the rate of change of " xx " coordinate of the particle w.r.t time at that instant is unit/sec
View answer and explanation
Correct option: C
112\frac{1}{\sqrt{12}}
Option C (112\frac{{1}}{{\sqrt{{12}}}}) is correct because it is the rate of change of x with respect to time when y = π3\frac{{\pi}}{{3}} and dydt\frac{{dy}}{{dt}} = 2.
657 Easy
657 of 791
Application +4 | -1
If ∫0∞dx(x2+4)(x2+9)=kπ\int\limits_{0}^{\infty} \frac{d x}{\left(x^2+4\right)\left(x^2+9\right)}=k \pi then the value of kk is
View answer and explanation
Correct option: A
1/601 / 60
Option A (1/601 / 60) is correct because the integral is solved using partial fractions and the arctangent integral.
658 Easy
658 of 791
Application +4 | -1
The numbers A,BA, B and CC such that a function of the form f(x)=Ax2+Bx+Cf(x)=A x^2+B x+C satisfies the conditions f′(1)=8,f(2)+f′′(2)=33f^{\prime}(1)=8, f(2)+f^{\prime \prime}(2)=33 and ∫01f(x)dx=7/3\int\limits_{0}^1 f(x) \mathrm{d} x=7 / 3, are
View answer and explanation
Correct option: B
A=7,B=−6,C=3A=7, B=-6, C=3
Option B (A=7,B=−6,C=3A=7, B=-6, C=3) is correct because these values satisfy the given conditions f′(1)=8f'(1)=8, f(2)+f′′(2)=33f(2)+f''(2)=33, and ∫01f(x)dx=7/3\int_0^1 f(x) dx = 7/3.
659 Easy
659 of 791
Analyzing +4 | -1
If [.] denotes the greatest integer function, then the value of ∫13[x2−2x−2]dx\int\limits_{1}^3\left[x^2-2 x-2\right] d x is equal to
View answer and explanation
Correct option: A
−1−2−3-1-\sqrt{2}-\sqrt{3}
Option A (−1−2−3-1-\sqrt{2}-\sqrt{3}) is correct because it is found by evaluating the integral using properties of the greatest integer function.
660 Easy
660 of 791
Application +4 | -1
The equal to integral ∫01log⁡(1−x+1+x)dx\int\limits_{0}^1 \log (\sqrt{1-x}+\sqrt{1+x}) \mathrm{d} x is
View answer and explanation
Correct option: B
12(log⁡2−1+π2)\frac{1}{2}\left(\log 2-1+\frac{\pi}{2}\right)
Option A (12(log⁡2−1+π2)\frac{1}{2}(\log 2-1+\frac{\pi}{2})) is correct because after performing integration by parts and simplifying, the integral evaluates to this expression.
Revision notes and key takeaways

Review DEFINITE INTEGRATION in your textbook or class notes, then use this set to check your understanding.

Showing 631-660 of 791 questions

Your practice

0 / 791 answered · 791 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.