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JEE • MATHEMATICS • DEFINITE INTEGRATION

Definite integration practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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541 Medium
541 of 995
Analyzing +4 | -1
Let I1=∫12  11  +  x2  dx{I_1} = \int \limits_1^2 \,\,\frac{1}{{\sqrt {1\,\, + \,\,{x^2}} }}\,\,dx and I2=∫12  1x  dx{I_2} = \int \limits_1^2 \,\,\frac{1}{x}\,\,dx. Then
View answer and explanation
Correct option: B
I2>I1{I_2} > {I_1}
Option B (I2 > I1) is correct because for x in [1, 2], 1/√(1+x²) < 1/x, implying that the integral I2 is greater than I1.
542 Easy
542 of 995
Application +4 | -1
Area enclosed by the parabola ay=3(a2−x2)a y=3\left(a^2-x^2\right) and xx-axis is
View answer and explanation
Correct option: A
4a2sq4 a^2 \mathrm{sq}, unit
Option A (4a24 a^2 sq, unit) is correct because it represents the area enclosed by the parabola and the x-axis, calculated by integrating the function between its roots.
543 Easy
543 of 995
Application +4 | -1
∫0π/22 cos⁡  θ3 (sin⁡  θ  +  cos⁡  θ)  dθ\int \nolimits_0^{\pi /2} \frac{{2\,\sqrt {\cos \,\,\theta } }}{{3\,(\sqrt {\sin \,\,\theta } \,\, + \,\,\sqrt {\cos \,\,\theta )} }}\,\,d\mathrm{\theta } is equal to
View answer and explanation
Correct option: A
π6\frac{\pi }{6}
Option A (π6\frac{\pi}{6}) is correct because using the property of definite integrals and adding the two forms of the integral simplifies the expression, leading to the result.
544 Medium
544 of 995
Analyzing +4 | -1
The value of the integral ∫0π  log⁡  (1  +  cos⁡  x)  dx\int \limits_0^\pi \,\,\log \,\,\left( {1\,\, + \,\,\cos \,\,x} \right)\,\,dx is
View answer and explanation
Correct option: B
− π  log⁡  2- \,\pi \,\,\log \,\,2
Option B (−πlog⁡,2- \pi \log \\,2) is correct because the integral is solved using trigonometric identities and properties of logarithms and definite integrals.
545 Easy
545 of 995
Application +4 | -1
∫01  dxx+1−x2\int \nolimits_0^1 \,\,\frac{{dx}}{{x + \sqrt {1 - {x^2}} }} is equal to
View answer and explanation
Correct option: D
π/4\pi /4
Option D (π/4\pi /4) is correct because the integral can be solved using trigonometric substitution and properties of definite integrals.
546 Easy
546 of 995
Application +4 | -1
The value of the integral ∫π/6π/311+tan⁡xdx,\int\limits_{{\pi / 6}}^{\pi / 3} \frac{1}{1+\sqrt{\tan x}} d x, is
View answer and explanation
Correct option: C
π12\frac{\pi}{12}
Option C is correct because by using the property ∫abf(x)dx=∫abf(a+b−x)dx\int_a^b f(x) dx = \int_a^b f(a+b-x) dx, the integral simplifies to b−a2\frac{b-a}{2}.
547 Easy
547 of 995
Analyzing +4 | -1
The value of ∫02πxsin⁡8xsin⁡8x+cos⁡8xdx\int_0^{2\pi } {\frac{{x{{\sin }^8}x}}{{{{\sin }^8}x + {{\cos }^8}x}}dx} is equal to
View answer and explanation
Correct option: D
π2{\pi ^2}
Option D (π2{\pi ^2}) is correct because it is the value of the definite integral after applying properties of definite integrals to simplify it.
548 Medium
548 of 995
Analyzing +4 | -1
Let f(x)=∣x−2∣f(x)=|x-2| and g(x)=f(f(x)),x∈[0,4]g(x)=f(f(x)), x \in[0,4]. Then ∫03(g(x)−f(x))dx\int\limits_{0}^3(g(x)-f(x)) d x is equal to:
View answer and explanation
Correct option: A
1
Option A (1) is correct because evaluating the definite integral of g(x)-f(x) from 0 to 3 gives a result of 1.
549 Easy
549 of 995
Application +4 | -1
Area bounded by the curve xy−3x−2y−10=0,xx y-3 x-2 y-10=0, x-axis and the lines x=3,x=4x=3, x=4 is
View answer and explanation
Correct option: C
16log⁡2+316 \log 2+3
Option C (16log⁡2+316 \log 2+3) is correct because it represents the definite integral of the given function between the specified limits, calculated after proper simplification.
550 Easy
550 of 995
Application +4 | -1
The value of integral ∫04  ∣ x  −  1 ∣  dx    is\int \nolimits_0^4 \,\,\left| {\,x\,\, - \,\,1\,} \right|\,\,dx\;\,\,\mathrm{is} is
View answer and explanation
Correct option: B
5\mathrm{5}
Option B (5\mathrm{5}) is correct because the integral of the absolute value function is evaluated by splitting the integral at the point where the function changes sign.
551 Easy
551 of 995
Analyzing +4 | -1
The value of ∫π3π2(2+3sin⁡x)sin⁡x(1+cos⁡x)dx\int\limits_{\frac{\pi}{3}}^{\frac{\pi}{2}} \frac{(2+3 \sin x)}{\sin x(1+\cos x)} d x is equal to
View answer and explanation
Correct option: D
103−3+log⁡e3\frac{10}{3}-\sqrt{3}+\log _{e} \sqrt{3}
Option D (103−3+log⁡e3\frac{10}{3}-\sqrt{3}+\log _{e} \sqrt{3}) is correct because the integral is solved by partial fraction decomposition and trigonometric substitution.
552 Medium
552 of 995
Application +4 | -1
∫1e1+log⁡10xxdx=\int\limits_{1}^e \frac{1+\log _{10} x}{x} d x=
View answer and explanation
Correct option: C
12log⁡10e+1\frac{1}{2} \log _{10} e+1
Option C is correct because the integral can be split into two parts and evaluated, resulting in 12log⁡10e+1\frac{1}{2} \log_{10} e + 1.
553 Easy
553 of 995
Application +4 | -1
The area, enclosed by the curves y=sin⁡x+cos⁡x  and  y=∣cos⁡x−sin⁡x∣y = \sin x + \cos x\mathrm{ }\,\,\mathrm{and}\,\,\mathrm{ }y = |\cos x - \sin x| and the lines x=0,  x=π2,x = 0,\,\,x = \frac{\pi }{2}, is
View answer and explanation
Correct option: A
22(2−1)2\sqrt 2 (\sqrt 2 - 1)
Option A (22(2−1)2\sqrt 2 (\sqrt 2 - 1)) is correct because it represents the area between the curves, calculated by integrating the difference of the functions over the given interval.
554 Hard
554 of 995
Application +4 | -1
∫1435−1  x+2x2+2x−3  dx\int \limits_1^{\frac{{4\sqrt 3 }}{5} - 1} \,\,\frac{{x + 2}}{{\sqrt {{x^2} + 2x - 3} }}\,\,dx equals to
View answer and explanation
Correct option: B
2 33  +  12  log⁡  3\frac{{2\,\sqrt 3 }}{3}\,\, + \,\,\frac{1}{2}\,\,\log \,\,3
Option B (2 33  +  12  log⁡ 3\frac{{2\,\sqrt 3 }}{3}\,\,+\,\,\frac{1}{2}\,\,\log \,3) is correct because it is the result of evaluating the definite integral after proper substitution and simplification.
555 Easy
555 of 995
Application +4 | -1
If ff and gg are continuous functions on [0,π][0, \pi] satisfying f(x)+f(π−x)=1=g(x)+g(π−x),f(x)+f(\pi-x)=1=g(x)+g(\pi-x), \quad then ∫0π{f(x)+g(x)}dx\int_0^\pi\{f(x)+g(x)\} d x is equal to
View answer and explanation
Correct option: A
π\pi
Option A (π\pi) is correct because it uses the given functional equations to simplify the integral.
556 Easy
556 of 995
Application +4 | -1
ddx  (∫f(x)g(x)  ϕ  (t)  dt)\frac{d}{{dx}}\,\,\left( {\int \limits_{f\left( x \right)}^{g\left( x \right)} \,\,\phi \,\,\left( t \right)\,\,dt} \right) is equal to
View answer and explanation
Correct option: C
g′(x)  ϕ( g  (x))  −  f′(x)  ϕ( f  (x))g'\left( x \right)\,\,\phi \left( {\,g\,\,\left( x \right)} \right)\,\, - \,\,f'\left( x \right)\,\,\phi \left( {\,f\,\,\left( x \right)} \right)
Option C (g′(x)  ϕ( g  (x)) − f′(x)  ϕ( f  (x))g'(x)\,\,\phi (\,g\,\,( x ) )\, - \,f'(x)\,\,\phi (\,f\,\,( x ) )) is correct because it directly applies the Leibniz rule for differentiating an integral with variable limits.
557 Easy
557 of 995
Application +4 | -1
Value of xx satisfying ∫log⁡2xdxex−1=π6\int\limits_{{\log 2}}^x \frac{d x}{\sqrt{e^x-1}}=\frac{\pi}{6} is
View answer and explanation
Correct option: C
2log⁡22 \log 2
Option C (2log⁡22 \log 2) is correct because solving the integral equation ∫log⁡2xdxex−1=π6\int_{\log 2}^x \frac{{dx}}{{\sqrt{{e^x-1}}}} = \frac{{\pi}}{{6}} leads to x=log⁡4=2log⁡2x = \log 4 = 2 \log 2.
558 Easy
558 of 995
Application +4 | -1
If [.] stands for the greatest integer function, then ∫12[3x]dx\int\limits_{1}^2[3 x] d x is equal to
View answer and explanation
Correct option: B
4
Option B (4) is correct because the integral is evaluated by breaking it into intervals where the greatest integer function has a constant value.
559 Medium
559 of 995
Application +4 | -1
∫02x3(x2+1)3/2dx\int\limits_{0}^2 \frac{x^3}{\left(x^2+1\right)^{3 / 2}} d x is equal to
View answer and explanation
Correct option: D
None of these
The correct answer is D (None of these) because the calculated value of the integral does not match any of the given options.
560 Easy
560 of 995
Analyzing +4 | -1
If I1=∫ee2dxlog⁡xI_1=\int\limits_{e}^{e^2} \frac{d x}{\log x} and I2=∫12exxdxI_2=\int\limits_{1}^2 \frac{e^x}{x} d x, then
View answer and explanation
Correct option: A
I1=I2I_1=I_2
Option A (I1=I2I_1=I_2) is correct because by substituting log⁡x=t\log x = t in I1I_1, we obtain the same integral as I2I_2.
561 Easy
561 of 995
Analyzing +4 | -1
In=∫0π/4  tan⁡n  x  dx{I_n} = \int \nolimits_0^{\pi /4} \,\,{\tan ^n}\,\,x\,\,dx, then lim⁡n→∞n  [In  +  In+2]\lim\limits_{n \to \infty } n\,\,\left[ {{I_n}\,\, + \,\,{I_{n + 2}}} \right] is equal to
View answer and explanation
Correct option: B
1\mathrm{1}
Option B (1\mathrm{1}) is correct because the limit is evaluated by simplifying the integral and applying the limit definition.
562 Easy
562 of 995
Application +4 | -1
The value of ∫1/ee  ∣log⁡  x∣x2  dx\int \limits_{1/e}^e \,\,\frac{{|\log \,\,x|}}{{{x^2}}}\,\,dx, is
View answer and explanation
Correct option: C
2  (1  −  1e)2\,\,\left( {1\,\, - \,\,\frac{1}{e}} \right)
Option C, 2  (1  −  1e)2\,\,\left( {1\,\, - \,\,\frac{1}{e}} \right), is the correct answer because it is the result of evaluating the definite integral with the absolute value of the logarithm.
563 Easy
563 of 995
Application +4 | -1
The value of the integral ∫−11  [x2+{x}]  dx\int \limits_{ - 1}^1 \,\,\left[ {{x^2} + \left\{ x \right\}} \right]\,\,dx, where [⋅]\left[ \cdot \right] and {⋅}\left\{ \cdot \right\} denote respectively the greatest integer function and fractional part function, is equal to
View answer and explanation
Correct option: B
5−52\frac{{5 - \sqrt 5 }}{2}
Option B (5−52\frac{{5 - \sqrt 5 }}{2}) is correct because evaluating the integral of the greatest integer function and fractional part function over the given limits results in this value.
564 Medium
564 of 995
Application +4 | -1
∫−23∣1−x2∣dx=\int\limits_{{-2}}^3\left|1-x^2\right| d x=
View answer and explanation
Correct option: D
283\frac{28}{3}
Option D is correct because by splitting the integral based on the absolute value function's behavior, we can evaluate each part and sum them up to get 283\frac{28}{3}.
565 Easy
565 of 995
Analyzing +4 | -1
∫0π[cot⁡x]dx,\int\limits_{0}^\pi[\cot x] d x, [.] denotes the greatest integer function, is equal to
View answer and explanation
Correct option: D
−π2-\frac{\pi}{2}
Option D (−π2-\frac{\pi}{2}) is correct because the integral evaluates to this value after using the property of definite integrals and the greatest integer function.
566 Medium
566 of 995
Application +4 | -1
∫0π/4  (cos⁡  x  −  sin⁡x)+∫π/45π/4(sin⁡  x  −  cos⁡  x)  dx  +  ∫2ππ/4  (cos⁡  x  −  sin⁡  x)  dx\int \nolimits_0^{\pi /4} \,\,(\cos \,\,x\,\, - \,\,\sin x) + \int \nolimits_{\pi /4}^{5\pi /4} (\sin \,\,x\,\, - \,\,\cos \,\,x)\,\,dx\,\, + \,\,\int \nolimits_{2\pi }^{\pi /4} \,\,(\cos \,\,x\,\, - \,\,\sin \,\,x)\,\,dx is equal to
View answer and explanation
Correct option: D
4 2−24\,\sqrt 2 - 2
Option D (42−24\sqrt 2 - 2) is correct because after evaluating each integral and summing the results, the final value is 42−24\sqrt{2} - 2.
567 Easy
567 of 995
Application +4 | -1
Let In=∫0π/2xncos⁡x dxI_n=\int\limits_{0}^{\pi / 2} x^n \cos x \mathrm{~d} x then I8+56I6I_8+56 I_6 is equal to
View answer and explanation
Correct option: B
(π2)8\left(\frac{\pi}{2}\right)^8
Option B ((π2\frac{π}{2})8) is correct because it uses integration by parts to find a recursive relationship for I_n and then simplifies the expression I_8 + 56I_6.
568 Easy
568 of 995
Application +4 | -1
Let f:R∈Rf: R \in R be a continuous function given by f(x+y)=f(x)+f(y)f(x+y)=f(x)+f(y) for all x,y∈Rx, y \in R.
If ∫02f(x)dx=α\int_0^2 f(x) d x=\alpha, then ∫−22f(x)dx\int_{-2}^2 f(x) d x is equal to
View answer and explanation
Correct option: C
0
The correct answer is C (0) because the given functional equation implies that f(x) is of the form λx\lambda x, making it an odd function, and the integral of an odd function over a symmetric interval is zero.
569 Medium
569 of 995
Application +4 | -1
The value of the integral ∫−1/21/2  {(x+1x−1)2+  (x−1x+1)2−  2}1/2dx\int \limits_{ - 1/2}^{1/2} \,\,{\left\{ {{{\left( {\frac{{x + 1}}{{x - 1}}} \right)}^2} + \,\,{{\left( {\frac{{x - 1}}{{x + 1}}} \right)}^2} - \,\,2} \right\}^{1/2}}dx, is
View answer and explanation
Correct option: C
4  log⁡  (43)4\,\,\log \,\,\left( {\frac{4}{3}} \right)
Option C, 4  log⁡  (43)4\,\,\log \,\,\left( {\frac{4}{3}} \right), is correct because it is the result of simplifying the integrand and evaluating the definite integral.
570 Easy
570 of 995
Analyzing +4 | -1
The value of the integral ∫01ex2dx\int\limits_{0}^1 e^{x^2} d x lies in the interval
View answer and explanation
Correct option: C
(1,e)(1, \mathrm{e})
Option C ((1, e)) is correct because the integral is bounded by the minimum and maximum values of the function within the given interval.
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