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JEE • MATHEMATICS • COMPLEX NUMBERS
Complex numbers practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 871-900 of 979 questions
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871
Easy
871 of 979
Application
+4 | -1
The argument of is
View answer and explanation
Correct option: A
Option A () is correct because after simplifying the complex number, its argument falls in the second quadrant with a reference angle of .
872
Medium
872 of 979
Analyzing
+4 | -1
Two conjugate complex numbers and represent two adjacent vertices of a polygon of sides, whose centre is origin. If then ratio of the areas of the circles inscribed and circumscribed the polygon is
View answer and explanation
Correct option: C
Option C () is correct because it represents the square of the cosine of , which is the ratio of the inscribed to circumscribed circle areas.
873
Medium
873 of 979
Application
+4 | -1
If is a complex number in the Argand plane, then the equation represents
View answer and explanation
Correct option: D
A circle
The correct answer is D (A circle) because the simplified equation results in the equation of a circle.
874
Easy
874 of 979
Analyzing
+4 | -1
If the number is real and positive, then is
View answer and explanation
Correct option: C
Option C () is correct because the expression is real and positive only when is of the form , where is an integer.
875
Easy
875 of 979
Application
+4 | -1
If and , then equals
View answer and explanation
Correct option: A
Option C () is incorrect. The correct answer is not among the options provided. The correct solution involves equating real and imaginary parts and solving for z, which results in z = 1/(2) + i/2.
876
Easy
876 of 979
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: A
0
Option A (0) is correct because taking the modulus of both sides of the equation and solving for n results in n = 0.
877
Easy
877 of 979
Application
+4 | -1
If is a complex cube root of unity, then the value of is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the sum of consecutive powers of omega () where the powers differ by 1, and are multiples of 3, is always 0.
878
Easy
878 of 979
Application
+4 | -1
If is a positive integer, then is equal to
View answer and explanation
Correct option: C
Option C () is correct because by converting the complex numbers to polar form and applying De Moivre's theorem, the expression simplifies to .
879
Medium
879 of 979
Application
+4 | -1
If , then is equal to:
View answer and explanation
Correct option: D
-1
Option D (-1) is correct because substituting into the expression and simplifying using properties of complex numbers and cube roots of unity leads to -1.
880
Easy
880 of 979
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: B
Option B () is correct because it is the simplified form of the given expression after substituting and using Euler's formula.
881
Easy
881 of 979
Application
+4 | -1
If , then greatest possible value of is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the maximum value of occurs when z is farthest from 7 on the circle, which leads to a value of 2.
882
Medium
882 of 979
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
, for some integer
Option C (, for some integer ) is correct because the argument of a product of complex numbers is the sum of their arguments.
883
Easy
883 of 979
Application
+4 | -1
A particle starts from the point . It moves first horizontally away from origin by 5 units and then vertically away from origin by 3 units to reach a point . From , the particle moves units in the direction of the vector and then it moves through an angle in anti-clockwise direction on a circle with centre at origin, to reach a point , then the point is given by
View answer and explanation
Correct option: D
Option D (-6+7 i) is correct because it represents the final position of the particle after all the described movements.
884
Hard
884 of 979
Application
+4 | -1
If and are two real numbers, then (where ) is equal to
View answer and explanation
Correct option: C
1
Option C (1) is correct because after simplification using trigonometric identities and Euler's formula, the expression equals 1.
885
Easy
885 of 979
Understanding
+4 | -1
If , then one of the values of is
View answer and explanation
Correct option: A
0
Option A (0) is correct because if , then and have the same argument, so .
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886
Easy
886 of 979
Application
+4 | -1
If is a non-real root of , then is equal to
View answer and explanation
Correct option: B
Option B (-1) is correct because after simplifying the powers of z using the fact that z7 = -1, the expression reduces to -1.
887
Easy
887 of 979
Application
+4 | -1
If , then radius of the circle is
View answer and explanation
Correct option: C
Option C () is correct because the equation of the circle can be derived from the given modulus condition, and the radius can be found from the equation of the circle.
888
Medium
888 of 979
Application
+4 | -1
For complex numbers , and , we write if and . Let be a complex number such that , then
View answer and explanation
Correct option: C
Option C () is correct because, given , the real and imaginary parts of are both non-positive.
889
Medium
889 of 979
Application
+4 | -1
If the roots of unity are then is equal to
View answer and explanation
Correct option: B
-1
Option B (-1) is correct because the sum of the squares of the non-real fifth roots of unity is -1.
890
Easy
890 of 979
Application
+4 | -1
If are distinct complex numbers with , then value of equals
View answer and explanation
Correct option: A
1
Option A (1) is correct because the expression simplifies to 1 using the property that and .
891
Medium
891 of 979
Application
+4 | -1
Let and be th roots of unity which subtend a right angle at the origin. Then must be of the form
View answer and explanation
Correct option: D
Option D () is correct because the angle between the nth roots of unity must be a right angle, implying that n is a multiple of 4.
892
Medium
892 of 979
Application
+4 | -1
For any two complex numbers and and any real numbers and , is equal to
View answer and explanation
Correct option: B
Option B () is correct because expanding and simplifying the expression leads to this result.
893
Medium
893 of 979
Application
+4 | -1
Let then is equal to
View answer and explanation
Correct option: C
Option C () is correct because substituting and (where is a cube root of unity) and expanding the product leads to the given expression.
894
Easy
894 of 979
Application
+4 | -1
If is a cube root of unity and , then equals to
View answer and explanation
Correct option: A
Option A ((1,1)) is correct because simplifying the expression (1+ω)7 using the properties of cube roots of unity leads to 1+ω, thus A=1 and B=1.
895
Easy
895 of 979
Application
+4 | -1
If the cube roots of unity are , then the roots of the equation are
View answer and explanation
Correct option: C
Option D () is correct because by substituting into the equation, we can solve for y and then find the roots in terms of .
896
Medium
896 of 979
Application
+4 | -1
Locus of point so that , and are collinear, is
View answer and explanation
Correct option: B
a circle
Option B (a circle) is correct because the condition for collinearity leads to an equation that represents a circle in the complex plane.
897
Medium
897 of 979
Application
+4 | -1
Let be the roots of , then the equation whose roots are is
View answer and explanation
Correct option: B
Option B () is correct because the roots can be expressed using Euler's formula, and raising them to the power of n results in a new equation with coefficients involving cos(nφ).
898
Easy
898 of 979
Application
+4 | -1
If then belongs to the interval
View answer and explanation
Correct option: B
Option B ([2,∞)) is the correct interval because solving the inequality leads to x being greater than or equal to 2.
899
Easy
899 of 979
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
The correct answer is C () because, after substituting and simplifying using the properties of complex cube roots of unity, the expression equals .
900
Easy
900 of 979
Application
+4 | -1
The area of the triangle whose vertices are and , where and are complex cube roots of unity, is
View answer and explanation
Correct option: D
Option D () is correct because it is the area of the triangle calculated using the determinant formula with the given vertices.
Revision notes and key takeaways
Review COMPLEX NUMBERS in your textbook or class notes, then use this set to check your understanding.
Showing 871-900 of 979 questions
