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JEE • MATHEMATICS • COMPLEX NUMBERS
Complex numbers practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 391-420 of 979 questions
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391
Medium
391 of 979
Application
+4 | -1
If , where , , are real, then
View answer and explanation
Correct option: A
Option A () is correct because substituting z=i into the binomial expansion and comparing magnitudes leads to this result.
392
Easy
392 of 979
Application
+4 | -1
If , then the position of the first significant figure of is
View answer and explanation
Correct option: B
17
Option B (17) is correct because the position of the first significant figure is determined by the characteristic of the logarithm of the number.
393
Easy
393 of 979
Understanding
+4 | -1
Reflection of the line in the real axis is
View answer and explanation
Correct option: A
Option A () is correct because reflecting a complex number in the real axis means taking its conjugate, which transforms the equation accordingly.
394
Easy
394 of 979
Application
+4 | -1
The complex number in polar form can be written as
View answer and explanation
Correct option: B
Option B is correct because the complex number can be expressed in polar form as .
395
Hard
395 of 979
Application
+4 | -1
The maximum distance from the origin of coordinates to the point satisfying the equation is
View answer and explanation
Correct option: C
Option C is correct because it represents the maximum distance derived by maximizing the modulus of the complex number and solving the resulting quadratic equation.
396
Easy
396 of 979
Application
+4 | -1
If the real part of is 4, then the locus of the point representing in the complex plane is
View answer and explanation
Correct option: A
a circle
Option A (a circle) is correct because the locus of the point representing z is a circle, derived from the given condition on the real part of the complex expression.
397
Easy
397 of 979
Application
+4 | -1
Let be two complex numbers such that and is purely real, then is equal to
View answer and explanation
Correct option: C
1
Option C (1) is correct because if z_2/z_1 is purely real, the magnitude of the given expression simplifies to 1.
398
Medium
398 of 979
Application
+4 | -1
If , satisfies the equation , then is equal to :
View answer and explanation
Correct option: C
1
The correct answer is C (1) because by taking the modulus of the given equation, we find that |z| = 1, and therefore |z2| = 1.
399
Easy
399 of 979
Understanding
+4 | -1
A point which represents a complex number moves such that , then its locus is
View answer and explanation
Correct option: D
Perpendicular bisector of line joining and
Option A () is correct because it represents the equation of a circle in the complex plane with center z0 and radius r.
400
Easy
400 of 979
Analyzing
+4 | -1
For , let and . Then the number of elements in the set is
View answer and explanation
Correct option: B
Option B () is correct because the intersection of the two circles is empty for an infinite number of values of n.
401
Easy
401 of 979
Application
+4 | -1
The modulus of is:
View answer and explanation
Correct option: A
2
Option A (2) is correct because simplifying the expression and then finding its modulus results in 2.
402
Easy
402 of 979
Application
+4 | -1
The value of is
View answer and explanation
Correct option: D
Option D () is correct because after applying De Moivre's theorem and simplifying, the expression equals .
403
Easy
403 of 979
Application
+4 | -1
Let then , (where is the matrix obtained by taking conjugate of each element of ) is equal to
View answer and explanation
Correct option: A
256
Option A (256) is correct because the determinant of Z * conjugate(Z) is the square of the magnitude of the determinant of Z.
404
Easy
404 of 979
Application
+4 | -1
If is equal to
View answer and explanation
Correct option: B
Option B () is correct because after rationalizing the denominator and equating real and imaginary parts, simplifies to .
405
Medium
405 of 979
Application
+4 | -1
If and for any two complex numbers and , then we say
Let be a complex number with . Then
Let be a complex number with . Then
View answer and explanation
Correct option: C
Option C () is correct because given the condition 1 ∩ z, it follows that the real and imaginary parts of are non-positive, implying it is \"less than or equal to\" 0.
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406
Easy
406 of 979
Application
+4 | -1
If then
View answer and explanation
Correct option: A
Option A () is correct because by expressing x and y in terms of θ and then calculating , it can be shown that .
407
Medium
407 of 979
Analyzing
+4 | -1
If are positive and are in AP, then roots of the quadratic equation are complex for
View answer and explanation
Correct option: B
Option B is correct because the condition for complex roots of the quadratic equation, given that p, q, and r are in AP, leads to the inequality .
408
Easy
408 of 979
Application
+4 | -1
is
View answer and explanation
Correct option: C
Option C (-1) is correct because the series simplifies to a geometric series with a common ratio of -1, and the sum is -1.
409
Easy
409 of 979
Application
+4 | -1
The modulus and amplitude of are respectively
View answer and explanation
Correct option: B
256 and
Option B (256 and ) is correct because can be simplified using De Moivre's theorem, resulting in a modulus of 256 and an argument of .
410
Easy
410 of 979
Application
+4 | -1
If , then is
View answer and explanation
Correct option: B
1
Option B (1) is correct because when you multiply the logarithms together, the terms cancel out, leaving a result of 1.
411
Easy
411 of 979
Analyzing
+4 | -1
Let be two complex numbers such that then
View answer and explanation
Correct option: C
Option C (arg z₁ = π/4) is correct because by using the given relationships between z₁ and z₂ and their arguments, we can solve for arg z₁.
412
Easy
412 of 979
Understanding
+4 | -1
Consider the following statements.
I. Additive inverse of is equal to .
II. If and are two complex numbers, then represents a complex number which is sum of and additive inverse of .
III. Simplest form of is
Choose the correct option.
I. Additive inverse of is equal to .
II. If and are two complex numbers, then represents a complex number which is sum of and additive inverse of .
III. Simplest form of is
Choose the correct option.
View answer and explanation
Correct option: C
I, II and III are correct
Option C is correct because all three statements are correct. Statement I correctly identifies the additive inverse, Statement II describes complex number subtraction, and Statement III simplifies the given expression correctly.
413
Easy
413 of 979
Understanding
+4 | -1
The inequality is true when
View answer and explanation
Correct option: B
Option B () is correct because inequalities are only defined for real numbers, thus the imaginary parts must be zero, and the real parts must satisfy the inequality.
414
Easy
414 of 979
Application
+4 | -1
If is a complex cube root of unity, then is equal to
View answer and explanation
Correct option: A
Option A () is correct because simplifying the expression inside the sine function using properties of complex cube roots of unity leads to .
415
Easy
415 of 979
Application
+4 | -1
The locus of point satisfying , where is a non-zero real number, is
View answer and explanation
Correct option: B
A circle
Option B (A circle) is correct because the equation simplifies to the equation of a circle.
416
Easy
416 of 979
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because after rationalizing the denominator and separating real and imaginary parts, the expression simplifies to 1.
417
Easy
417 of 979
Application
+4 | -1
If are the cube roots of unity, then is equal to
View answer and explanation
Correct option: A
0
Option A (0) is correct because the determinant simplifies to 0 using the properties of cube roots of unity, where .
418
Easy
418 of 979
Application
+4 | -1
If , then is equal to The value of '' is
View answer and explanation
Correct option: A
0
Option A (0) is correct because simplifying the expression results in 3 + 0i, so the value of 'b' is 0.
419
Medium
419 of 979
Application
+4 | -1
is equal to
View answer and explanation
Correct option: B
1
The expression is equal to 1 because it simplifies to 1 using trigonometric identities and Euler's formula.
420
Easy
420 of 979
Application
+4 | -1
If , where , then equals to
View answer and explanation
Correct option: B
Option B (z) is correct because by substituting the given value of z and simplifying using properties of complex numbers and cube roots of unity, the expression simplifies to z.
Revision notes and key takeaways
Review COMPLEX NUMBERS in your textbook or class notes, then use this set to check your understanding.
Showing 391-420 of 979 questions
