Skip to main content
Back to CIRCLES

Your Progress

0 / 189 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • CIRCLES

Circles practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 151-180 of 189 questions

Preparing practice and saved progress…

151 Medium
151 of 189
Application +4 | -1
For all values of aa, equation of a diameter of the circle x2+y2–2ax+2ay+a2=0x^2 + y^2– 2ax+2ay+ a^2 = 0 is
View answer and explanation
Correct option: D
x–y=2ax – y = 2a.
The correct answer is D (x–y=2ax – y = 2a) because the center of the circle lies on this line, making it a diameter.
152 Medium
152 of 189
Application +4 | -1
If the chord y=mx+1y=m x+1 of the circle x2+y2=1x^{2}+y^{2}=1 subtends an angle of measure 45∘45^{\circ} at the major segment of the circle then value of mm is
View answer and explanation
Correct option: C
−1±2-1 \pm \sqrt{2}
Option C (−1±2-1 \pm \sqrt{2}) is correct because it represents the values of m for which the given chord subtends an angle of 45 degrees at the major segment of the circle.
153 Medium
153 of 189
Application +4 | -1
The point on the circle x2+y2=a2x^2+y^2=a^2 in first quadrant, so that tangent drawn at this point make a triangle of area a2a^2 with the coordinate axes, is
View answer and explanation
Correct option: B
(a2,a2)\left(\frac{a}{\sqrt{2}}, \frac{a}{\sqrt{2}}\right)
Option B ((a2,a2)\left(\frac{{a}}{{\sqrt{{2}}}}, \frac{{a}}{{\sqrt{{2}}}}\right)) is correct because the area of the triangle formed by the tangent and the axes is a2a^2, which leads to θ=π4\theta = \frac{{\pi}}{{4}}.
154 Medium
154 of 189
Application +4 | -1
If y=2xy=2 x is a chord of the circle x2+y2−10x=0x^2+y^2-10 x=0, then the equation of a circle with this chord as diameter, is x2+y2−ax−by=0x^2+y^2-a x-b y=0. Sum of aa and bb is
View answer and explanation
Correct option: A
6
Option A (6) is correct because the sum of a and b in the circle's equation is 6, derived from the chord and circle intersection.
155 Medium
155 of 189
Application +4 | -1
If a conic passes through (1,0)(1,0) and satisfies differential equation (1+y2)dx−xydy=0\left(1+y^2\right) d x-x y d y=0. Then the equation of circle which is touching this conic at (2,1)(\sqrt{2}, 1) and passing through one of its foci is:
View answer and explanation
Correct option: A
x2+y2−32x−y+4=0x^2+y^2-3 \sqrt{2} x-y+4=0
The correct answer is x2+y2−32x−y+4=0x^2+y^2-3 \sqrt{2} x-y+4=0 because it represents the equation of the circle that touches the conic at the given point and passes through one of its foci.
156 Medium
156 of 189
Analyzing +4 | -1
If the chord of contact of tangents from a point on the circle x2+y2=r12{x^2} + {y^2} = r_1^2 to the circle x2+y2=r22{x^2} + {y^2} = r_2^2 touches the circle x2+y2=r32{x^2} + {y^2} = r_3^2, then r,,r2,r3{r_,},{r_2},{r_3} are in
View answer and explanation
Correct option: C
GP
Option C (GP) is correct because the radii r1,r2,r3{r_1},{r_2},{r_3} are in geometric progression.
157 Medium
157 of 189
Application +4 | -1
Consider the circles x2+y2=9x^2+y^2=9 and x2+y2−10x+9=0x^2+y^2-10 x+9=0, then find the length of the common chord of circle is
View answer and explanation
Correct option: C
245\frac{24}{5}
Option C (245\frac{{24}}{{5}}) is correct because the length of the common chord is calculated using the radical axis and the distance from the center to the radical axis.
158 Medium
158 of 189
Analyzing +4 | -1
If a line, y=mx+cy = mx + c is a tangent to the circle, (x−3)2+y2=1{(x - 3)^2} + {y^2} = 1 and it is perpendicular to a line L1,{L_1}, where L1{L_1} is the tangent to the circle, x2+y2=1{x^2} + {y^2} = 1 at the point (12, 12)\left( {\frac{1}{{\sqrt 2 }},\,\frac{1}{{\sqrt 2 }}} \right); then
View answer and explanation
Correct option: D
c2+6c+7=0{c^2} + 6c + 7 = 0
Option D (c2+6c+7=0{c^2} + 6c + 7 = 0) is correct because it represents the equation derived from the tangency condition of the line to the given circle.
159 Medium
159 of 189
Application +4 | -1
The line joining (5,0)(5,0) to (10cos⁡θ,10sin⁡θ)(10 \cos \theta, 10 \sin \theta) is divided internally in the ratio 2:32: 3 at PP. If θ\theta varies, then the locus of PP is
View answer and explanation
Correct option: B
A circle
Option B (A circle) is correct because the locus of point P is a circle derived from the section formula and trigonometric identities.
160 Medium
160 of 189
Application +4 | -1
How many common tangents can be drawn to the following circles x2+y2=6xx^2+y^2=6 x and x2+y2+6x+2y+1=0?x^2+y^2+6 x+2 y+1=0?
View answer and explanation
Correct option: A
4
Option A (4) is correct because the distance between the centers of the circles is greater than the sum of their radii, allowing for four common tangents.
161 Medium
161 of 189
Application +4 | -1
Let O(0, 0)O(0,\,0) and A(0, 1)A(0,\,1) be two fixed points, then the locus of a point PP such that the perimeter of ΔAOP\Delta AOP is 4, is
View answer and explanation
Correct option: C
9x2+8y2−8y=16 9{x^2} + 8{y^2} - 8y = 16\,
Option C (9x2+8y2−8y=169{x^2} + 8{y^2} - 8y = 16) is correct because it represents the locus of point P satisfying the given perimeter condition.
162 Medium
162 of 189
Application +4 | -1
Locus of mid point of the chords of contact of x2+y2=2x^2+y^2=2 from the points on the line 3x+4y=103 x+4 y=10 is a circle with centre PP. If OO is the origin then OPO P is equal to:
View answer and explanation
Correct option: D
12\frac{1}{2}
Option D (12\frac{{1}}{{2}}) is correct because it represents the distance from the origin to the center of the circle formed by the locus of the midpoint of the chords of contact.
163 Medium
163 of 189
Application +4 | -1
The locus of a point which moves such that the sum of the squares of its distance from three vertices of a triangle is constant is a/an
View answer and explanation
Correct option: A
Circle
Option A (Circle) is correct because the locus equation simplifies to the standard form of a circle, where the coefficients of x2x^2 and y2y^2 are equal and there is no xyxy term.
164 Medium
164 of 189
Application +4 | -1
Four distinct points (2k,3k),(1,0),(0,1)(2 k, 3 k),(1,0),(0,1) and (0,0)(0,0) lie on a circle for kk equal to:
View answer and explanation
Correct option: C
513\frac{5}{13}
Option C is correct because it involves finding the equation of a circle passing through three points and then using the fourth point to solve for k.
165 Medium
165 of 189
Application +4 | -1
The locus of the centre of a circle of radius 2 which rolls on the outside of the circle, is x2+y2+3x−6y−9=0{x^2} + {y^2} + 3x - 6y - 9 = 0 is
View answer and explanation
Correct option: B
x2+y2+3x−6y−31=0{x^2} + {y^2} + 3x - 6y - 31 = 0
Option B (x2+y2+3x−6y−31=0{x^2} + {y^2} + 3x - 6y - 31 = 0) is correct because it represents the locus of the center of the rolling circle, considering the sum of the radii.
166 Medium
166 of 189
Application +4 | -1
Find the equation of the normal to the circle x2+y2−5x+2yx^2+y^2-5 x+2 y −48=0-48=0 at the point (5,6)(5,6).
View answer and explanation
Correct option: A
14x−5y−40=014 x-5 y-40=0
Option A (14x−5y−40=014 x-5 y-40=0) is correct because it represents the equation of the normal to the circle at the given point (5,6), which is perpendicular to the tangent at that point.
167 Medium
167 of 189
Application +4 | -1
The distance between the chords of contact of the tangent to the circle x2+y2+2gx+2fy+c=0{x^2} + {y^2} + 2gx + 2fy + c = 0 from the origin and the point (g,f),\left( {g,f} \right), is
View answer and explanation
Correct option: D
g2+f2−c2g2+f2\frac{{{g^2} + {f^2} - c}}{{2\sqrt {{g^2} + {f^2}} }}
The correct answer is g2+f2−c2g2+f2\frac{{{g^2} + {f^2} - c}}{{2\sqrt {{g^2} + {f^2}} }} because it represents the distance between the chords of contact, calculated using the formula for the distance between parallel lines.
168 Medium
168 of 189
Application +4 | -1
The pole of the line 3x+5y+17=03 x+5 y+17=0 with respect to the circle x2+y2+4x+6y+9=0x^2+y^2+4 x+6 y+9=0 is
View answer and explanation
Correct option: A
(1,2)(1,2)
Option A ((1,2)) is correct because it represents the pole of the given line with respect to the given circle.
169 Medium
169 of 189
Analyzing +4 | -1
If three distinct point A,B,CA, B, C are given in the 2-dimensional coordinate plane such that the ratio of the distance of each one of them from the point (1,0)(1,0) to the distance from (−1,0)(-1,0) is equal to 12\frac{1}{2}, then the circumcentre of the triangle ABCA B C is at the point:
View answer and explanation
Correct option: B
(5/3,0)(5 / 3,0)
Option B ((5/3,0)(5 / 3,0)) is correct because it represents the circumcenter of the triangle formed by points satisfying the given distance ratio condition.
170 Medium
170 of 189
Application +4 | -1
The lines 5x+12y−10=05 x+12 y-10=0 and 5x−12y−40=05 x-12 y-40=0 touch a circle of radius 3 units. If the centre of circle lies in the first quadrant, then the coordinates of centre is
View answer and explanation
Correct option: C
(5,2)(5,2)
Option C ((5,2)) is correct because it satisfies the condition that the distance from the center to both lines is equal to the radius, and the center lies in the first quadrant.
171 Medium
171 of 189
Analyzing +4 | -1
The point of the straight line y=2x+11y = 2x + 11 which is nearest to the circle 16(x2+y2)+32x−8y−50=0,16\left( {{x^2} + {y^2}} \right) + 32x - 8y - 50 = 0, is
View answer and explanation
Correct option: B
(−9/2,2)\left( { - 9/2,2} \right)
Option B ((−9/2,2)\left( { - 9/2,2} \right)) is correct because it is the point on the line nearest to the circle.
172 Medium
172 of 189
Analyzing +4 | -1
If the line xcos⁡θ+ysin⁡θ=2x \cos \theta+y \sin \theta=2 is the equation of a transverse common tangent to the circles x2+y2=4x^2+y^2=4 and x2+y2−63x−6y+20=0x^2+y^2-6 \sqrt{3} x-6 y+20=0, then the value of θ\theta is
View answer and explanation
Correct option: D
π6\frac{\pi}{6}
Option D (π6\frac{\pi}{6}) is correct because the equation of the common tangent can be found by using the condition C1C2=r1+r2C_1C_2 = r_1 + r_2 and then comparing with the given equation.
173 Medium
173 of 189
Analyzing +4 | -1
If the point (−5+λ2,−3+λ2)\left( { - 5 + \frac{\lambda }{{\sqrt 2 }}, - 3 + \frac{\lambda }{{\sqrt 2 }}} \right) is an interior point of the larger segment of the circle x2+y2=16{x^2} + {y^2} = 16 cut off by the line x+y=2,x + y = 2, then
View answer and explanation
Correct option: B
λ∈(42−14,52)\lambda \in \left( {4\sqrt 2 - \sqrt {14} ,5\sqrt 2 } \right)
Option B (λ∈(42−14,52)\lambda \in \left( {4\sqrt 2 - \sqrt {14} ,5\sqrt 2 } \right)) is correct because it satisfies both conditions: the point lies inside the circle and on the correct side of the line.
174 Medium
174 of 189
Application +4 | -1
A tangent is drawn to the circle 2(x2+y2)−3x+4y=02\left( {{x^2} + {y^2}} \right) - 3x + 4y = 0 and it touches the circle at point AA. If the tangent passes through the point P(2,1)P\left( {2,1} \right) then PA=PA =
View answer and explanation
Correct option: B
2
Option B (2) is correct because it is the length of the tangent calculated using the formula for the length of a tangent from a point to a circle.
175 Medium
175 of 189
Application +4 | -1
The area of a circle and the area of a regular polygon of nn sides and of perimeter equal to that of the circle are in the ratio
View answer and explanation
Correct option: A
tan⁡πn:πn\tan \frac{\pi}{n}: \frac{\pi}{n}
Option A (tan(π/n):π/n) is correct because it represents the ratio of the area of a circle to the area of a regular polygon with the same perimeter.
176 Medium
176 of 189
Application +4 | -1
A cone is made from a circular sheet of radius 3\sqrt{3} by cutting out a sector and gluing the cut edges of the remaining piece together. The maximum volume attainable for the cone is
View answer and explanation
Correct option: C
2π/32 \pi / 3
Option C (2π/32 \pi / 3) is correct because it represents the maximum volume attainable for the cone formed from the circular sheet.
177 Medium
177 of 189
Application +4 | -1
The angle between the pair of tangents from the point (1,12)\left(1, \frac{1}{2}\right) to the circle x2+y2+4x+2y−4=0x^2+y^2+4 x+2 y-4=0, is
View answer and explanation
Correct option: B
sin⁡−1(45)\sin ^{-1}\left(\frac{4}{5}\right)
Option B (sin⁡−1(45)\sin ^{-1}(\frac{{4}}{{5}})) is correct because it represents the angle between the pair of tangents from the given point to the given circle, calculated using the formula involving the radius and distance from the center.
178 Medium
178 of 189
Application +4 | -1
The range of values of aa such that the angle θ\theta between the pair of tangents drawn from (a,  0)\left( {a,\;0} \right) to the circle x2+y2=1{x^2} + {y^2} = 1 satisfies π2<θ<π\frac{\pi }{2} < \theta < \pi, is
View answer and explanation
Correct option: D
(−2,  −1)∪(1,  2)\left( { - \sqrt 2 ,\; - 1} \right) \cup \left( {1,\;\sqrt 2 } \right)
Option D (−2,  −1)∪(1,  2)\left( { - \sqrt 2 ,\; - 1} \right) \cup \left( {1,\;\sqrt 2 } \right) is correct because it represents the range of 'a' for which the angle between the tangents from (a,0) to the circle is between π2\frac{\pi}{2} and π\pi.
179 Medium
179 of 189
Analyzing +4 | -1
If y+3x=0y+3 x=0 is the equation of a chord of the circle, x2+y2−30x=0x^{2}+y^{2}-30 x=0, then the equation of the circle with this chord as diameter is :
View answer and explanation
Correct option: D
x2+y2−3x+9y=0x^{2}+y^{2}-3 x+9 y=0
Option D (x2+y2−3x+9y=0x^{2}+y^{2}-3 x+9 y=0) is correct because it represents the circle with the given chord as a diameter, found by determining the intersection points of the line and circle.
180 Medium
180 of 189
Analyzing +4 | -1
Tangent to circle x2+y2=5x^2+y^2=5 at (1,−2)(1,-2), also touches the circle x2+y2−8x+6y+20=0x^2+y^2-8 x+6 y+20=0. The coordinates of the corresponding point of contact is
View answer and explanation
Correct option: B
(3,−1)(3,-1)
Option B ((3,-1)) is correct. By finding the equation of the tangent to the first circle and substituting it into the equation of the second circle, we can solve for the point of contact.
Revision notes and key takeaways

Review CIRCLES in your textbook or class notes, then use this set to check your understanding.

Showing 151-180 of 189 questions

Your practice

0 / 189 answered · 189 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.