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JEE • MATHEMATICS • CIRCLES
Circles practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 301-330 of 480 questions
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301
Easy
301 of 480
Application
+4 | -1
If a chord of the circle makes equal intercepts of length on the coordinate axes, then
View answer and explanation
Correct option: A
The correct answer is because the length of the perpendicular from the center to the chord must be less than the radius.
302
Easy
302 of 480
Analyzing
+4 | -1
Centre of circle whose normal’s are , is
View answer and explanation
Correct option: A
Option A is correct because the center of the circle is the intersection point of its normals.
303
Easy
303 of 480
Analyzing
+4 | -1
Centre of circle whose normals are, , is
View answer and explanation
Correct option: A
Option A is correct because the normals of a circle pass through its center, and the intersection of the given normals gives the center.
304
Easy
304 of 480
Application
+4 | -1
the centre of the hyperbola . The tangents at any point on this hyperbola meets the straight lines and in the points and respectively. Then
View answer and explanation
Correct option: A
Option A () is correct because the product of the distances CQ and CR simplifies to using the equation of the tangent to the hyperbola.
305
Easy
305 of 480
Analyzing
+4 | -1
The number of common tangents to the circles one of which passes through the origin and cuts off intercepts 2 from each of the axes and the other circle has the segment joining the origin and the point as a diameter, is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the distance between the centers of the two circles is equal to the difference of their radii, indicating they touch internally, hence one common tangent.
306
Easy
306 of 480
Application
+4 | -1
If a tangent to the circle intersects the coordinate axes at distinct points and , then the locus of the mid-point of is
View answer and explanation
Correct option: C
Option C () is correct because it represents the locus of the midpoint of the line segment PQ, where P and Q are the points where the tangent to the circle intersects the coordinate axes.
307
Easy
307 of 480
Application
+4 | -1
Two diameters of the circle are along the lines and . Then, the value of is
View answer and explanation
Correct option: A
Option A () is correct because it is the product of the constants and obtained by substituting the center of the circle into the diameter equations.
308
Easy
308 of 480
Analyzing
+4 | -1
The equation of the circumcircle of an equilateral triangle is and one vertex of the triangle is . The equation of the incircle of the triangle, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the equation of the incircle of the equilateral triangle, derived using the relationship between circumcenter, incenter, circumradius, and inradius.
309
Easy
309 of 480
Application
+4 | -1
The line 2x -y + 1 = 0 is a tangent to the circle at the point (2, 5) and the center of the circle lies on x –2y = 4. Then the radius of the circle is
View answer and explanation
Correct option: A
Option A () is correct because it is the distance between the center of the circle and the point of tangency, calculated using the given conditions.
310
Easy
310 of 480
Application
+4 | -1
The equation to the chord of the circle whose middle point is is
View answer and explanation
Correct option: C
Option D () is correct because the equation of the chord with a given midpoint (1, -2) is found using the formula T = S', where T is the equation of the tangent-like expression and S' is the value of the circle equation at the midpoint.
311
Easy
311 of 480
Application
+4 | -1
The centre of a circle passing through the points and touching the circle is
View answer and explanation
Correct option: D
Option D, , is correct because the center of the circle passing through (0,0) and (1,0) and touching satisfies the given conditions.
312
Easy
312 of 480
Application
+4 | -1
The equation of the circle with centre and radius 2 is . The value of is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the value of m in the circle's equation is 4, derived from the center and radius.
313
Easy
313 of 480
Application
+4 | -1
The equation of a circle which touches the line at and having as a normal, is
View answer and explanation
Correct option: A
Option A () is correct because it represents the equation of a circle that touches the line y=x at (1,1) and has y=x-3 as a normal.
314
Easy
314 of 480
Application
+4 | -1
The equation of the circle passing through the point and having two diameters along the pair of lines , is
View answer and explanation
Correct option: C
Option C () is correct because it represents the circle passing through the given point and having diameters along the given pair of lines.
315
Easy
315 of 480
Application
+4 | -1
The lines and are diameters of a circle having area as 154 sq.units. Then the equation of the circle is
View answer and explanation
Correct option: D
.
Option D () is correct because it represents the equation of the circle with the given area and diameters, found by determining the center and radius.
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316
Easy
316 of 480
Application
+4 | -1
The point diametrically opposite to the point on the circle , is
View answer and explanation
Correct option: A
Option A ((-3,-4)) is correct because it is the point diametrically opposite to P(1,0) on the given circle.
317
Easy
317 of 480
Application
+4 | -1
Tangents drawn from the point to the circle are inclined at an angle
View answer and explanation
Correct option: D
Option D () is correct because the point (4,3) lies on the director circle of the given circle.
318
Easy
318 of 480
Application
+4 | -1
If is the angle between the tangents from to the circle , then is equal to
View answer and explanation
Correct option: A
The correct answer is because it represents the angle between the tangents from the given point to the circle.
319
Easy
319 of 480
Application
+4 | -1
The equation of the circle with centre and touching the line is
View answer and explanation
Correct option: C
Option C () is correct because the equation of the circle with center (2,1) and touching the line 3x + 4y = 5 is derived by finding the radius and substituting into the circle equation.
320
Easy
320 of 480
Analyzing
+4 | -1
If the circles and intersect at two distinct points, then
View answer and explanation
Correct option: C
Option C () is correct because it satisfies the condition for two circles to intersect at two distinct points, which is the distance between their centers being between the absolute difference and the sum of their radii.
321
Easy
321 of 480
Application
+4 | -1
The equation of the circle whose centre is and radius 5, is
View answer and explanation
Correct option: B
The correct answer is B () because it represents the equation of a circle with center (2, -3) and radius 5.
322
Easy
322 of 480
Analyzing
+4 | -1
The diameter of the circle having the pair of lines as its normals and having the size just sufficient to contain the circle is
View answer and explanation
Correct option: B
15
Option B (15) is correct because it represents the diameter of the circle, calculated as the distance between the normals plus the diameter of the inner circle.
323
Easy
323 of 480
Application
+4 | -1
The circle passing through the point and touching the -axis at also passes through the point:
View answer and explanation
Correct option: D
Option D ((-4,0)) is correct because the circle equation is found using the given conditions, and substituting (-4,0) into the equation satisfies it.
324
Easy
324 of 480
Analyzing
+4 | -1
Consider where, is a real number, and
Statement I If line is a chord of circle , then line is not always a diameter of circle and
Statement II If line is a diameter of circle , then line is not a chord of circle .
Statement I If line is a chord of circle , then line is not always a diameter of circle and
Statement II If line is a diameter of circle , then line is not a chord of circle .
View answer and explanation
Correct option: C
Statement I is True, statement II is False
Option C (Statement I is True, statement II is False) is correct because if L1 is a chord, L2 may or may not be a diameter, and if L1 is a diameter, L2 cannot be a chord.
325
Easy
325 of 480
Application
+4 | -1
The inverse of the point with respect to the circle , is
View answer and explanation
Correct option: C
The correct answer is D ((0,1)) because finding the foot of the perpendicular from the point (1,2) to the tangent line of the circle at that point gives the inverse point.
326
Easy
326 of 480
Analyzing
+4 | -1
The equation represents
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because completing the square results in a negative radius squared, indicating the equation does not represent a real circle or a pair of straight lines.
327
Easy
327 of 480
Application
+4 | -1
Two tangents are drawn from the origin to a circle with centre at . If the equation of one of the tangents is , the equation of the other tangent is
View answer and explanation
Correct option: C
Option C () is correct because the other tangent from the origin to the circle can be found by using the fact that the perpendicular distance from the center to both tangents is the same.
328
Easy
328 of 480
Application
+4 | -1
If , then the equation will represent
View answer and explanation
Correct option: D
A circle of radius zero
Option D (A circle of radius zero) is correct because the radius of the circle is zero when .
329
Easy
329 of 480
Application
+4 | -1
The area (in square unit) of the circle which touches the lines and is
View answer and explanation
Correct option: D
Option D () is correct because the area of the circle is calculated using the radius, which is half the distance between the two parallel lines.
330
Easy
330 of 480
Analyzing
+4 | -1
If the circles and touch each other, then the equation of their common tangent at the point, where they touch, is given by
View answer and explanation
Correct option: C
Option C () is correct because the equation of the common tangent is found by subtracting the equations of the two circles, which touch each other externally.
Revision notes and key takeaways
Review CIRCLES in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 480 questions
