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JEE • MATHEMATICS • BINOMIAL THEOREM

Binomial theorem practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 451-468 of 468 questions
451 Medium
451 of 468
Application +4 | -1
If (1+x)n=∑r=0ncrxr(1+x)^n=\sum\limits_{{r=0}}^n c_r x^r, then ∑r=0200crr+1=\sum\limits_{{r=0}}^{200} \frac{c_r}{r+1}=
View answer and explanation
Correct option: D
2201−1201\frac{2^{201}-1}{201}
Option D (2201−1201\frac{{2^{201}-1}}{{201}}) is correct because it is derived from integrating the binomial expansion and evaluating the sum.
452 Medium
452 of 468
Application +4 | -1
If ' nn ' is positive integer and three consecutive coefficient in the expansion of (1+x)n(1+x)^n are in the ratio 6:33:1106: 33: 110, then nn is equal to :
View answer and explanation
Correct option: C
12
Option C (12) is correct because solving the ratio of consecutive coefficients in the binomial expansion leads to n=12.
453 Medium
453 of 468
Analyzing +4 | -1
The value of ∑r=0       r≤sn∑s=1nnCssCr\sum\limits_{\mathop {r = 0}\limits_{\,\,\,\,\,\,\,r \le s} }^n {\sum\limits_{s = 1}^n {^n} {C_s}^s{C_r}} is
View answer and explanation
Correct option: A
3n−13^n-1
Option A (3n−13^n-1) is correct because the double summation simplifies to a binomial expansion minus the first term.
454 Medium
454 of 468
Application +4 | -1
If in the expansion of (1+x)m(1−x)n(1+x)^m(1-x)^n, the coefficients of xx and x2x^2 are 3 and -6 respectively, then mm is
View answer and explanation
Correct option: C
12
Option C (12) is correct because solving the system of equations derived from the coefficients of x and x² yields m=12.
455 Medium
455 of 468
Application +4 | -1
The greatest term in the expansion of (2x+5y)13(2 x+5 y)^{13} when x=10x=10 and y=2y=2
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated greatest term does not match any of the provided options.
456 Medium
456 of 468
Application +4 | -1
Middle term in the expansion of (x2+1x2+2)n\left(x^2+\frac{1}{x^2}+2\right)^n is
View answer and explanation
Correct option: B
(2n)!(n!)2\frac{(2 n) !}{(n !)^2}
Option B ((2n)!(n!)2\frac{{(2 n) !}}{{(n !)^2}}) is correct because the middle term of the simplified binomial expansion is found using the binomial coefficient 2nCn{}^{2n}C_n.
457 Medium
457 of 468
Application +4 | -1
The greatest term (numerically) in the expansion of (3−5x)15(3-5 x)^{15}, when x=15x=\frac{1}{5} is
View answer and explanation
Correct option: C
15C3×312{ }^{15} C_3 \times 3^{12}
Option C (15C3×312{ }^{15} C_3 \times 3^{12}) is correct because it represents the numerically greatest term in the expansion, calculated by comparing consecutive terms and finding the largest.
458 Medium
458 of 468
Analyzing +4 | -1
10 th term of (3−174+32)20\left(3-\sqrt{\frac{17}{4}+3 \sqrt{2}}\right)^{20} is
View answer and explanation
Correct option: A
An irrational number
Option A (An irrational number) is correct because the 10th term of the binomial expansion contains a term with 2\sqrt{2} raised to an odd power, making it irrational.
459 Medium
459 of 468
Application +4 | -1
The coefficient of a8b6c4a^8 b^6 c^4 in the expansion of (a+b+c)18(a+b+c)^{18} is
View answer and explanation
Correct option: A
18C14⋅14C8{ }^{18} C_{14} \cdot{ }^{14} C_8
Option A (18C14⋅14C8{ }^{18} C_{14} \cdot{ }^{14} C_8) is correct because it represents the multinomial coefficient for the given term in the expansion.
460 Medium
460 of 468
Application +4 | -1
If m,n,rm,n,r are positive integers such that r<m,n,r < m,n, then   mCr+  mCr−1  nC1+  mCr−2  nC2+…+  mC1  nCr−1+  nCr{\;^m}{C_r} + {\;^m}{C_{r - 1}}{\;^n}{C_1} + {\;^m}{C_{r - 2}}{\;^n}{C_2} + \ldots + {\;^m}{C_1}{\;^n}{C_{r - 1}} + {\;^n}{C_r} equals
View answer and explanation
Correct option: B
  m+nCr{\;^{m + n}}{C_r}
Option B (  m+nCr{\;^{m + n}}{C_r}) is correct because the given expression represents the coefficient of xrx^r in the expansion of (1+x)m(1+x)n(1+x)^m(1+x)^n, which simplifies to (1+x)m+n(1+x)^{m+n}.
461 Medium
461 of 468
Application +4 | -1
If n−  1Cr=(k2−3)  nCr+1,n - {\;^1}{C_r} = \left( {{k^2} - 3} \right){\;^n}{C_{r + 1}}, then k∈k \in
View answer and explanation
Correct option: D
(3,2]\left( {\sqrt 3 ,2} \right]
Option D ((3,2]\left( {\sqrt 3 ,2} \right]) is correct because it satisfies the condition 0<k2−3≤10 < k^2 - 3 \le 1 derived from the properties of binomial coefficients.
462 Medium
462 of 468
Analyzing +4 | -1
The value of ∑r=0n(−2)r(nCrr+2Cr)\sum\limits_{{r=0}}^n(-2)^r\left(\frac{{ }^n C_r}{{ }^{r+2} C_r}\right) is
View answer and explanation
Correct option: C
1n+1,n\frac{1}{n+1}, n is even
Option C (1(n+1)\frac{{1}}{{(n+1)}}, n is even) is correct because after simplifying the summation, the expression reduces to this form when n is even.
463 Medium
463 of 468
Application +4 | -1
In the expansion of (1+3x+2x2)6{(1 + 3x + 2{x^2})^6} the coefficient of x11{x^{11}} is
View answer and explanation
Correct option: D
576
The correct answer is D (576) because it is the coefficient of x11{x^{11}} obtained from the multinomial expansion of the given expression.
464 Medium
464 of 468
Application +4 | -1
The coefficient of x4x^4 in the expansion of (1+5x+9x2+13x3+17x4+…..)(1+x2)11\left(1+5 x+9 x^2+13 x^3+17 x^4+\ldots ..\right)\left(1+x^2\right)^{11} is equal to
View answer and explanation
Correct option: D
171
Option D (171) is correct because it calculates the coefficient of x4 by multiplying the series and considering terms that result in x4.
465 Medium
465 of 468
Application +4 | -1
The coefficient of x2x^2 in the expansion of (1+x+x2)10\left(1+x+x^2\right)^{10} is
View answer and explanation
Correct option: C
11C2{ }^{11} C_2
Option C (11C2{ }^{11} C_2) is correct because the coefficient of x2 is found by simplifying the expression and applying the binomial theorem.
466 Medium
466 of 468
Application +4 | -1
The 10 th term in the expansion of (x−1)11(x-1)^{11} (in decreasing powers of xx ) is
View answer and explanation
Correct option: D
−11C9x2-{ }^{11} C_9 x^2
Option D (-{ }^{11} C_9 x2) is correct because it is the 10th term in the expansion of (x-1)11 using the binomial theorem.
467 Medium
467 of 468
Application +4 | -1
If (1+x)n=C0+C1x+C2x2+…+Cnxn,n∈N(1+x)^n=C_0+C_1 x+C_2 x^2+\ldots+C_n x^n, n \in N, then for 2≤m≤n2 \leq m \leq n, C0−C1+C2−C3+…+(−1)m−1Cm−1C_0-C_1+C_2-C_3+\ldots+(-1)^{m-1} C_{m-1} is equal to
View answer and explanation
Correct option: A
(−1)m−1⋅n−1Cm−1(-1)^{m-1} \cdot{ }^{n-1} C_{m-1}
Option A ((-1)(m-1) * { }^{n-1} C_{m-1}) is correct because it is derived by equating coefficients of x(m-1) in the expansion of (1-x)^n(1-x)(-1).
468 Medium
468 of 468
Application +4 | -1
The value of 50C4+∑r=1656−rC3{ }^{50} C_4+\sum\limits_{{r=1}}^6{ }^{56-r} C_3 is
View answer and explanation
Correct option: A
56C4{ }^{56} \mathrm{C}_4
Option A (56C4{ }^{56} C_4) is correct because the summation can be simplified using the identity nCr+nCr−1=n+1Cr{ }^n C_r + { }^n C_{r-1} = { }^{n+1} C_r repeatedly.
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