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JEE • MATHEMATICS • BINOMIAL THEOREM

Binomial theorem practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 931-951 of 951 questions
931 Easy
931 of 951
Application +4 | -1
The coefficient of x4{x^4} in the expansion of (1+x+x2+x3)11,{\left( {1 + x + {x^2} + {x^3}} \right)^{11}}, is
View answer and explanation
Correct option: C
990
Option C (990) is correct because it is the sum of the products of binomial coefficients that contribute to the x4 term in the expansion.
932 Medium
932 of 951
Application +4 | -1
Middle term in the expansion of (x2+1x2+2)n\left(x^2+\frac{1}{x^2}+2\right)^n is
View answer and explanation
Correct option: B
(2n)!(n!)2\frac{(2 n) !}{(n !)^2}
Option B ((2n)!(n!)2\frac{{(2 n) !}}{{(n !)^2}}) is correct because the middle term of the simplified binomial expansion is found using the binomial coefficient 2nCn{}^{2n}C_n.
933 Easy
933 of 951
Application +4 | -1
If the fourth term in the expansion of {x(1log⁡x+1)+x1/12}6{\left\{ {\sqrt {{x^{\left( {\frac{1}{{\log x + 1}}} \right)}}} + {x^{1/12}}} \right\}^6} is equal to 200 and x>1,x > 1,, then xx is equal to
View answer and explanation
Correct option: B
10
Option B (10) is correct because the value of x is found by setting the fourth term in the given expansion equal to 200 and solving the resulting equation for x, given that x > 1.
934 Easy
934 of 951
Application +4 | -1
If   nC12=  nC6{\;^n}{C_{12}} = {\;^n}{C_6}, then   nC2{\;^n}{C_2} is equal to
View answer and explanation
Correct option: B
153
Option B (153) is correct. Using the property that if nCx=nCy^nC_x = ^nC_y, then either x=y or x+y=n, we can find n and then calculate nC2^nC_2.
935 Medium
935 of 951
Application +4 | -1
The greatest term (numerically) in the expansion of (3−5x)15(3-5 x)^{15}, when x=15x=\frac{1}{5} is
View answer and explanation
Correct option: C
15C3×312{ }^{15} C_3 \times 3^{12}
Option C (15C3×312{ }^{15} C_3 \times 3^{12}) is correct because it represents the numerically greatest term in the expansion, calculated by comparing consecutive terms and finding the largest.
936 Medium
936 of 951
Analyzing +4 | -1
10 th term of (3−174+32)20\left(3-\sqrt{\frac{17}{4}+3 \sqrt{2}}\right)^{20} is
View answer and explanation
Correct option: A
An irrational number
Option A (An irrational number) is correct because the 10th term of the binomial expansion contains a term with 2\sqrt{2} raised to an odd power, making it irrational.
937 Easy
937 of 951
Analyzing +4 | -1
The total number of terms in the expansion of (x+a)200+(x−a)200(x+a)^{200}+(x-a)^{200} after simplification is
View answer and explanation
Correct option: A
101
Option A (101) is correct because after simplification, only the even-powered terms remain, resulting in 101 terms.
938 Easy
938 of 951
Application +4 | -1
If the fourth term in the expansion of (x+xlog⁡2x)7{(x + {x^{{{\log }_2}x}})^7} is 4480, then the value of x, Where x∈Nx \in \mathrm{N} is equal to
View answer and explanation
Correct option: A
2
Option A (2) is correct because substituting x = 2 into the binomial expansion and solving the resulting equation yields a consistent result.
939 Medium
939 of 951
Application +4 | -1
The coefficient of a8b6c4a^8 b^6 c^4 in the expansion of (a+b+c)18(a+b+c)^{18} is
View answer and explanation
Correct option: A
18C14⋅14C8{ }^{18} C_{14} \cdot{ }^{14} C_8
Option A (18C14⋅14C8{ }^{18} C_{14} \cdot{ }^{14} C_8) is correct because it represents the multinomial coefficient for the given term in the expansion.
940 Medium
940 of 951
Application +4 | -1
If m,n,rm,n,r are positive integers such that r<m,n,r < m,n, then   mCr+  mCr−1  nC1+  mCr−2  nC2+…+  mC1  nCr−1+  nCr{\;^m}{C_r} + {\;^m}{C_{r - 1}}{\;^n}{C_1} + {\;^m}{C_{r - 2}}{\;^n}{C_2} + \ldots + {\;^m}{C_1}{\;^n}{C_{r - 1}} + {\;^n}{C_r} equals
View answer and explanation
Correct option: B
  m+nCr{\;^{m + n}}{C_r}
Option B (  m+nCr{\;^{m + n}}{C_r}) is correct because the given expression represents the coefficient of xrx^r in the expansion of (1+x)m(1+x)n(1+x)^m(1+x)^n, which simplifies to (1+x)m+n(1+x)^{m+n}.
941 Medium
941 of 951
Application +4 | -1
If n−  1Cr=(k2−3)  nCr+1,n - {\;^1}{C_r} = \left( {{k^2} - 3} \right){\;^n}{C_{r + 1}}, then k∈k \in
View answer and explanation
Correct option: D
(3,2]\left( {\sqrt 3 ,2} \right]
Option D ((3,2]\left( {\sqrt 3 ,2} \right]) is correct because it satisfies the condition 0<k2−3≤10 < k^2 - 3 \le 1 derived from the properties of binomial coefficients.
942 Easy
942 of 951
Application +4 | -1
The sum of the coefficients of all the integral powers of xx in the expansion of (1+2x)40(1+2 \sqrt{x})^{40} is
View answer and explanation
Correct option: D
12(340+1)\frac{1}{2}\left(3^{40}+1\right)
Option D (12(340+1)\frac{1}{2}\left(3^{40}+1\right)) is correct because it represents the sum of the coefficients of all integral powers of x in the expansion of (1+2x)40(1+2 \sqrt{x})^{40}.
943 Easy
943 of 951
Application +4 | -1
If ∣x∣<12\left| x \right| < \frac{1}{2}, then the coefficient of xr{x^r} in the expansion of 1+2x(1−2x)2\frac{{1 + 2x}}{{{{\left( {1 - 2x} \right)}^2}}}, is
View answer and explanation
Correct option: D
(2r+1)2r\left( {2r + 1} \right){2^r}
Option D ((2r+1)2r(2r + 1){2^r}) is correct because it represents the coefficient of xr{x^r} after expanding and simplifying the given expression.
944 Hard
944 of 951
Application +4 | -1
If the sum of the coefficients in the expansion of (α  x2−2x+1)35{\left( {\alpha \;{x^2} - 2x + 1} \right)^{35}} is equal to the sum of the coefficient in the expansion of (x−α  y)35,{\left( {x - \alpha \;y} \right)^{35}}, then α=\alpha =
View answer and explanation
Correct option: B
1
Option B (1) is correct because setting the sum of coefficients equal in both expressions leads to the equation (α\alpha - 1)35 = -(α\alpha - 1)35, which is only true when α\alpha = 1.
945 Medium
945 of 951
Analyzing +4 | -1
The value of ∑r=0n(−2)r(nCrr+2Cr)\sum\limits_{{r=0}}^n(-2)^r\left(\frac{{ }^n C_r}{{ }^{r+2} C_r}\right) is
View answer and explanation
Correct option: C
1n+1,n\frac{1}{n+1}, n is even
Option C (1(n+1)\frac{{1}}{{(n+1)}}, n is even) is correct because after simplifying the summation, the expression reduces to this form when n is even.
946 Medium
946 of 951
Application +4 | -1
In the expansion of (1+3x+2x2)6{(1 + 3x + 2{x^2})^6} the coefficient of x11{x^{11}} is
View answer and explanation
Correct option: D
576
The correct answer is D (576) because it is the coefficient of x11{x^{11}} obtained from the multinomial expansion of the given expression.
947 Medium
947 of 951
Application +4 | -1
The coefficient of x4x^4 in the expansion of (1+5x+9x2+13x3+17x4+…..)(1+x2)11\left(1+5 x+9 x^2+13 x^3+17 x^4+\ldots ..\right)\left(1+x^2\right)^{11} is equal to
View answer and explanation
Correct option: D
171
Option D (171) is correct because it calculates the coefficient of x4 by multiplying the series and considering terms that result in x4.
948 Medium
948 of 951
Application +4 | -1
The coefficient of x2x^2 in the expansion of (1+x+x2)10\left(1+x+x^2\right)^{10} is
View answer and explanation
Correct option: C
11C2{ }^{11} C_2
Option C (11C2{ }^{11} C_2) is correct because the coefficient of x2 is found by simplifying the expression and applying the binomial theorem.
949 Medium
949 of 951
Application +4 | -1
The 10 th term in the expansion of (x−1)11(x-1)^{11} (in decreasing powers of xx ) is
View answer and explanation
Correct option: D
−11C9x2-{ }^{11} C_9 x^2
Option D (-{ }^{11} C_9 x2) is correct because it is the 10th term in the expansion of (x-1)11 using the binomial theorem.
950 Medium
950 of 951
Application +4 | -1
If (1+x)n=C0+C1x+C2x2+…+Cnxn,n∈N(1+x)^n=C_0+C_1 x+C_2 x^2+\ldots+C_n x^n, n \in N, then for 2≤m≤n2 \leq m \leq n, C0−C1+C2−C3+…+(−1)m−1Cm−1C_0-C_1+C_2-C_3+\ldots+(-1)^{m-1} C_{m-1} is equal to
View answer and explanation
Correct option: A
(−1)m−1⋅n−1Cm−1(-1)^{m-1} \cdot{ }^{n-1} C_{m-1}
Option A ((-1)(m-1) * { }^{n-1} C_{m-1}) is correct because it is derived by equating coefficients of x(m-1) in the expansion of (1-x)^n(1-x)(-1).
951 Medium
951 of 951
Application +4 | -1
The value of 50C4+∑r=1656−rC3{ }^{50} C_4+\sum\limits_{{r=1}}^6{ }^{56-r} C_3 is
View answer and explanation
Correct option: A
56C4{ }^{56} \mathrm{C}_4
Option A (56C4{ }^{56} C_4) is correct because the summation can be simplified using the identity nCr+nCr−1=n+1Cr{ }^n C_r + { }^n C_{r-1} = { }^{n+1} C_r repeatedly.
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