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JEE • MATHEMATICS • 3D PLANES

3d planes practice · Mixed difficulty

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Application +4 | -1
The angle between the line x−12=y3=z−36\frac{{x - 1}}{2} = \frac{y}{3} = \frac{{z - 3}}{6} and the plane 10x+2y+11z=310x+2y+11z=3, is
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Correct option: A
sin⁡−1(92105){\sin ^{ - 1}}\left( {\frac{{92}}{{105}}} \right)
Option A (sin⁡−1(92105){\sin ^{ - 1}}\left( {\frac{{92}}{{105}}} \right)) is correct because it is the angle between the line and the plane, calculated using the formula involving the dot product of the direction vector of the line and the normal vector of the plane.
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