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JEE • MATHEMATICS • 3D GEOMETRY SYSTEM

3d geometry system practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 140 questions

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61 Easy
61 of 140
Application +4 | -1
A variable line through the point (15,15)\left( {\frac{1}{5},\frac{1}{5}} \right) cuts the coordinate axes in the points
AA and BB. If the point PP divides ABAB internally in the ratio 3:1, then the locus of PP is
View answer and explanation
Correct option: B
y+3x=20xyy + 3x = 20xy
Option B (y+3x=20xyy + 3x = 20xy) is correct because by finding the equation of a line passing through (1/5, 1/5) and using the section formula to express the coordinates of point P in terms of the intercepts, the locus of P can be derived as y+3x=20xyy + 3x = 20xy.
62 Easy
62 of 140
Application +4 | -1
The xyx y-plane divides the line joining the points (−1,3,4)(2,−5,6)(-1,3,4)(2,-5,6)
View answer and explanation
Correct option: B
externally in the ratio 2:32: 3
Option B is correct because the xy-plane divides the line externally in the ratio found by setting the z-coordinate of the division point to zero.
63 Easy
63 of 140
Understanding +4 | -1
The number of straight lines that are equally inclined to three dimensional coordinate axes, is
View answer and explanation
Correct option: B
4
Option D (8) is correct because there are four possible sets of direction cosines with equal inclination to the three axes, considering both positive and negative values.
64 Easy
64 of 140
Application +4 | -1
A point P moves on the line 2x−3y+4=02x - 3y + 4 = 0. If Q(1, 4) and R(3, -2) are fixed points, then the locus of the centroid of ΔPQR\Delta PQR is a line
View answer and explanation
Correct option: A
with slope 23\frac{2}{3}
Option A (Both P(3) and P(5) are true) is correct because substituting n=3 and n=5 into the expression yields prime numbers.
65 Medium
65 of 140
Application +4 | -1
If the line joining A(1,3,4)A(1,3,4) and BB is divided by the point (−2,3,5)(-2,3,5) in the ratio 1:31: 3, then BB is
View answer and explanation
Correct option: A
(−11,3,8)(-11,3,8)
Option A ((-11,3,8)) is correct because it is found by using the section formula to determine the coordinates of point B.
66 Easy
66 of 140
Application +4 | -1
If the three points (0, 1), (0,  −1)\left( {0,\; - 1} \right) and (x,  0)\left( {x,\;0} \right) are vertices of an equilateral triangle, then the values of xx are
View answer and explanation
Correct option: B
3,  −3\sqrt 3 ,\; - \sqrt 3
Option B (√3, -√3) is correct because the distance between each pair of points must be equal for an equilateral triangle.
67 Medium
67 of 140
Application +4 | -1
The shortest distance (S.D) between lines x−33=y−8−1=z−31\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1} and x+3−3−y+72=z−64\frac{x+3}{-3}-\frac{y+7}{2}=\frac{z-6}{4} is
View answer and explanation
Correct option: A
3303 \sqrt{30}
Option A (3303 \sqrt{30}) is correct because it represents the shortest distance between the two given lines, calculated by finding a common perpendicular.
68 Easy
68 of 140
Application +4 | -1
The equation of the plane through the points (2,3,1)(2,3,1) and (4,−5,3)(4,-5,3) and parallel to xx-axis is
View answer and explanation
Correct option: C
y+4z−7=0y+4 z-7=0
Option C (y+4z−7=0y+4z-7=0) is correct because it represents the equation of the plane passing through the given points and parallel to the x-axis.
69 Medium
69 of 140
Application +4 | -1
The line x−23=y−32=z−4−4\frac{x-2}{3}=\frac{y-3}{2}=\frac{z-4}{-4} intervals the curve xy=k2,z=0xx y=k^2, z=0 \mathrm{x} then k=k=
View answer and explanation
Correct option: B
±5\pm 5
Option B (±5\pm 5) is correct because substituting the parametric form of the line into the curve equation yields k = ±5\pm 5.
70 Easy
70 of 140
Application +4 | -1
If projection of a line on x,yx, y and zz axis are 6,2 and 3 respectively, then direction cosines of the line are
View answer and explanation
Correct option: A
⟨67,27,37⟩\left\langle\frac{6}{7}, \frac{2}{7}, \frac{3}{7}\right\rangle
Option A is correct because the direction cosines are found by dividing the projections by the magnitude of the vector.
71 Easy
71 of 140
Application +4 | -1
The locus of a point which divides the line segment joining the point (0,−1)\left( {0, - 1} \right) and a point on the parabola, x2=4y,{x^2} = 4y, internally in the ratio 1 : 2, is
View answer and explanation
Correct option: C
9x2−12y=89{x^2} - 12y = 8
Option C (9x2−12y=89{x^2} - 12y = 8) is correct because it represents the locus of the point that divides the line segment in the given ratio.
72 Easy
72 of 140
Application +4 | -1
The equation of the plane that passes through (2,−3,1)(2,-3,1) and is perpendicular to the line joining the points (3(3, 4,−1)4,-1) and (2,−1,5)(2,-1,5) is
View answer and explanation
Correct option: A
x+5y−6z+19=0x+5 y-6 z+19=0
Option A (x+5y−6z+19=0x+5y-6z+19=0) is correct because it is the equation of the plane passing through the given point and perpendicular to the line joining the other two points.
73 Easy
73 of 140
Application +4 | -1
The equation of the plane through (2,3,4)(2,3,4) and parallel to the plane x+2y+4z=5x+2 y+4 z=5 is
View answer and explanation
Correct option: A
x+2y+4z=24x+2 y+4 z=24
Option A (x+2y+4z=24x+2 y+4 z=24) is correct because it represents a plane parallel to the given plane and passing through the specified point.
74 Medium
74 of 140
Application +4 | -1
The ratio in which ZXZ X-plane divides the line segment ABA B joining the points A(4,2,3)A(4,2,3) and B(−2,4,5)B(-2,4,5) is equal to
View answer and explanation
Correct option: B
1:21: 2, externally
Option B (1:21: 2, externally) is correct because the ZX-plane divides the line segment in the ratio −y1:y2-y_1 : y_2, which is negative, indicating external division.
75 Hard
75 of 140
Application +4 | -1
The distance between the planes r⋅(2i^−j^+3k^)=4{r} \cdot(2 \hat{i}-\hat{j}+3 \hat{k})=4 and r⋅(6i^−3j^+9k^)+13=0{r} \cdot(6 \hat{i}-3 \hat{j}+9 \hat{k})+13=0 is
View answer and explanation
Correct option: C
25314\frac{25}{3 \sqrt{14}}
Option C (25314\frac{25}{3 \sqrt{14}}) is the correct distance between the two parallel planes after normalizing the second plane's equation and applying the distance formula.
76 Medium
76 of 140
Analyzing +4 | -1
If ABCDA B C D is a tetrahedron such that each △ABC,△ABD\triangle A B C, \triangle A B D and △ACD\triangle A C D has a right angle at AA. If ar⁡(△ABC)=k1\operatorname{ar}(\triangle A B C)=k_1, ar⁡(△ABD)=k2,ar⁡(△BCD)=k3\operatorname{ar}(\triangle A B D)=k_2, \operatorname{ar}(\triangle B C D)=k_3, then ar⁡(△ACD)\operatorname{ar}(\triangle A C D) is
View answer and explanation
Correct option: C
∣k12+k22−k32∣\sqrt{\left|k_1^2+k_2^2-k_3^2\right|}
The correct answer is C (12) because it is the value of 6(a+b+c) after finding the relationship between a, b, and c from the coplanarity conditions.
77 Medium
77 of 140
Application +4 | -1
The ratio in which the line joining (1,2,3)(1,2,3) and (−3,4,−5)(-3,4,-5) is divided by XYX Y-plane, is
View answer and explanation
Correct option: B
3:53: 5
Option B (3: 5) is correct because the XY-plane divides the line joining (1,2,3) and (-3,4,-5) in the ratio k:1, where the z-coordinate of the point of division is 0, giving k=35k = \frac{{3}}{{5}}, so the ratio is 3:5.
78 Easy
78 of 140
Analyzing +4 | -1
In a three dimensional co-ordinate system, P,QP, Q and RR are images of a point A(a,b,c)A(a, b, c) in the xy,yzx y, y z and zxz x planes, respectively. If GG is the centroid of triangle PQRP Q R, then area of triangle AOGA O G is ( OO is the origin)
View answer and explanation
Correct option: A
0
Option A (0) is correct because the centroid G lies on the line OA, making the area of triangle AOG zero.
79 Easy
79 of 140
Application +4 | -1
Chord AB{AB} is a diameter of the sphere ∣r−2i^−j^+6k^∣|{r}-2 \hat{i}-\hat{j}+6 \hat{k}| =18=\sqrt{18}. If the coordinates of A{A} are (3,2,−2)(3,2,-2), then the coordinates B{B} are
View answer and explanation
Correct option: B
(1,0,−10)(1,0,-10)
Option B ((1,0,-10)) is correct because it represents the coordinates of point B, which is diametrically opposite to point A on the sphere.
80 Easy
80 of 140
Application +4 | -1
Equation of a line passing through the intersection of the lines 7x−y+2=07 x-y+2=0 and x−3y+6=0x-3 y+6=0 parallel to xx-axis is
View answer and explanation
Correct option: A
y=2y=2
Option A (y=2) is correct because it represents a line parallel to the x-axis passing through the intersection point of the two given lines.
81 Easy
81 of 140
Application +4 | -1
The centroid of a triangle is (2, 7) and two of its vertices are (4, 8) and (−2,  6)\left( { - 2,\;6} \right). The third vertex is
View answer and explanation
Correct option: B
(4, 7)
Option B ((4, 7)) is correct because the centroid coordinates are the average of the vertex coordinates. Solving for the third vertex gives (4, 7).
82 Easy
82 of 140
Application +4 | -1
The centriod of the triangle ABCABC, where A≡(2,3),B≡(8,10)A \equiv \left( {2,3} \right),B \equiv \left( {8,10} \right) and C≡(5,5)C \equiv \left( {5,5} \right) is
View answer and explanation
Correct option: A
(5, 6)
Option A ((5, 6)) is correct because the centroid of a triangle is the average of the coordinates of its vertices.
83 Easy
83 of 140
Application +4 | -1
If lines x−12=y+13=z−14\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4} and x−31=y−k2=z1\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1} intersect, then the value of kk is
View answer and explanation
Correct option: B
92\frac{9}{2}
Option B (92\frac{9}{2}) is correct because it satisfies the condition for the intersection of two lines in 3D space, making the determinant zero.
84 Medium
84 of 140
Analyzing +4 | -1
The points (0,7,10),(−1,6,6)(0,7,10),(-1,6,6) and (−4,9,6)(-4,9,6) form
View answer and explanation
Correct option: A
A right angled isosceles triangle
Option A (A right angled isosceles triangle) is correct because the sides PQ and QR are equal, and PQ2+QR2=PR2PQ^2 + QR^2 = PR^2, satisfying the Pythagorean theorem.
85 Easy
85 of 140
Analyzing +4 | -1
Three distinct points A,  BA,\;B and CC given in the two dimensional coordinate plane such that the ratio of the distance of any one of them from the point (1, 0) to the distance from the point (−1,  0)\left( { - 1,\;0} \right) is equal to 13\frac{1}{3}. Then , the circumcentre of the triangle ABCABC is at the point
View answer and explanation
Correct option: A
(54,  0)\left( {\frac{5}{4},\;0} \right)
Option A ((54,  0)\left( {\frac{{5}}{{4}},\;0} \right)) is correct because the circumcenter of the triangle lies at the center of the circle defined by the given condition.
86 Medium
86 of 140
Remembering +4 | -1
The perpendicular distance of the point P(6,7,8)P(6,7,8) from XYX Y-plane is ____.
View answer and explanation
Correct option: A
8
Option A (8) is correct because the perpendicular distance of a point from the XY-plane is the absolute value of its z-coordinate.
87 Medium
87 of 140
Application +4 | -1
The equation of the plane through the points (2,−1,0)(2,-1,0), (3,−4,5)(3,-4,5) and parallel to the line 2x=3y=4z2 x=3 y=4 z is
View answer and explanation
Correct option: B
29(x−2)−27(y+1)−22z=029(x-2)-27(y+1)-22 z=0
Option B (29(x−2)−27(y+1)−22z=029(x-2)-27(y+1)-22 z=0) is the correct equation of the plane, derived by finding the normal vector and using the point-normal form of a plane equation.
88 Medium
88 of 140
Application +4 | -1
The perpendicular distance of the point (6,5,8)(6, 5, 8) from Y-axis is_________.
View answer and explanation
Correct option: A
10
Option A (10) is correct because the perpendicular distance from the Y-axis is calculated using the x and z coordinates: x2+z2\sqrt{x^2 + z^2}.
89 Easy
89 of 140
Analyzing +4 | -1
Four lines drawn from the vertices of any tetrahedron to the centroid of the opposite faces meet in a point whose distance from each vertex is kk times the distance from each vertex to the opposite face, where kk is
View answer and explanation
Correct option: C
34\frac{3}{4}
Option C (34\frac{3}{4}) is correct because the centroid of a tetrahedron divides the line joining a vertex to the centroid of the opposite face in the ratio 3:1.
90 Easy
90 of 140
Application +4 | -1
If the coordinates of the vertices of a ΔABC\Delta A B C are A(−1,3,2),B(2,3,5)A(-1,3,2), B(2,3,5) and C(3,5,−2)C(3,5,-2), then ∠A\angle A is equal to
View answer and explanation
Correct option: C
90∘90^{\circ}
Option C (90∘90^{\circ}) is correct because the sides of the triangle satisfy the Pythagorean theorem, indicating a right angle at A.
Revision notes and key takeaways

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