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Find the heat of formation of .
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JEE • CHEMISTRY • THERMODYNAMICS
Thermodynamics practice · Medium
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211
Medium
211 of 329
Application
+4 | -1
For a perfectly crystalline solid , where is constant. If is , molar entropy at is :
View answer and explanation
Correct option: C
Option C () is correct because it is calculated by integrating from 0 to 20 K, using the given relationship .
212
Medium
212 of 329
Analyzing
+4 | -1
Consider the following conversions:
(i)
(ii)
(iii)
(iv)
That according to given information the incorrect statements is:
(i)
(ii)
(iii)
(iv)
That according to given information the incorrect statements is:
View answer and explanation
Correct option: D
and are negative whereas and are positive
Option D is correct because the first electron gain enthalpy for O, F, and Cl are negative, but the second electron gain enthalpy for oxygen is positive due to electron-electron repulsion.
213
Medium
213 of 329
Analyzing
+4 | -1
An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If is the initial temperature and is the final temperature, which of the following statements is correct?
View answer and explanation
Correct option: A
Option A ((Tf)irrev > (Tf)rev) is correct because in an irreversible adiabatic expansion, less work is done, resulting in a smaller decrease in internal energy and a higher final temperature compared to a reversible process.
214
Medium
214 of 329
Application
+4 | -1
A gas is allowed to expand in an insulated container against a constant external pressure of 4 atm from the initial volume of 1.8 L to a final volume of 5.2 L. The change in internal energy of the gas is
View answer and explanation
Correct option: C
–1.38 kJ
Option C (–1.38 kJ) is correct because the change in internal energy is equal to the work done in an adiabatic process, calculated as -Pext * ΔV.
215
Medium
215 of 329
Application
+4 | -1
is expanded reversibly at temperature from to then find out and (in cal)
View answer and explanation
Correct option: A
Option A (-483.63 cal, 483.63 cal) is correct because the process is isothermal and reversible, allowing for the calculation of work and heat using the appropriate formulas.
216
Medium
216 of 329
Application
+4 | -1
Two moles of an ideal gas undergo reversible isothermal expansion from to at . The change in entropy is: ]
View answer and explanation
Correct option: D
Option D () is correct because it is calculated using the formula for entropy change in a reversible isothermal expansion: .
217
Medium
217 of 329
Understanding
+4 | -1
The enthalpy change is negative for :
View answer and explanation
Correct option: A
Option A is correct because the hydration of ions is an exothermic process, releasing energy and resulting in a negative enthalpy change.
218
Medium
218 of 329
Analyzing
+4 | -1
Assertion :- Catalyst changes Gibbs free energy of system.
Reason :- Catalyst changes preexpotential factor of a chemical reaction.
Reason :- Catalyst changes preexpotential factor of a chemical reaction.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because a catalyst does not change the Gibbs free energy of the system, and it changes the activation energy, not the pre-exponential factor.
219
Medium
219 of 329
Remembering
+4 | -1
In the exothermic reaction, the enthalpy of
reaction is always:
reaction is always:
View answer and explanation
Correct option: C
negative
Option C (negative) is correct because exothermic reactions release heat, meaning the enthalpy change (ΔH) is negative.
220
Medium
220 of 329
Application
+4 | -1
10 moles of an ideal gas compressed from to reversibly at constant temperature of . The entropy change during the process is ( Universal gas constant)
View answer and explanation
Correct option: D
Option D () is correct because the entropy change for an isothermal reversible compression is calculated using ΔS = nRln(V2/V1).
221
Medium
221 of 329
Understanding
+4 | -1
Identify the correct statement for change of Gibb’s energy for a system () at constant temperature and pressure:
View answer and explanation
Correct option: D
If =0, the system has attained equilibrium
Option D is correct because at equilibrium, the change in Gibb's free energy is zero, indicating no further net change in the system.
222
Medium
222 of 329
Analyzing
+4 | -1
When equivalent of strong acid reacts with strong base, the heat released is When equivalent is completely neutralized against strong base, is released. When equivalent is completely neutralized against strong acid, heat is released. What is the enthalpy change when 1 mole of is completely neutralized by
View answer and explanation
Correct option: D
The correct answer is D (-19 kcal) because the enthalpy change is calculated by considering the enthalpy of ionization for both the acid and the base and subtracting them from the total heat released during neutralization.
223
Medium
223 of 329
Analyzing
+4 | -1
Find the heat of formation of .
View answer and explanation
Correct option: A
-102 k cal
Option A (-102 k cal) is correct because it is calculated by manipulating the given equations to arrive at the formation of KOH.
224
Medium
224 of 329
Application
+4 | -1
The bond dissociation energies for and
are 242.3, 151 and 211.3 kJ/mol
respectively. The enthalpy of sublimation of
iodine is 62.8 kJ/mol. What is the standard
enthalpy of formation of
are 242.3, 151 and 211.3 kJ/mol
respectively. The enthalpy of sublimation of
iodine is 62.8 kJ/mol. What is the standard
enthalpy of formation of
View answer and explanation
Correct option: C
-16.8 kJ/mol
Option C (-16.8 kJ/mol) is correct because it is the standard enthalpy of formation calculated using the given bond dissociation energies and enthalpy of sublimation.
225
Medium
225 of 329
Understanding
+4 | -1
Which of the following statements is incorrect?
View answer and explanation
Correct option: C
The standard state of solid iron at is equal to pure iron at 1 bar
Option D (Standard conditions are denoted by adding the superscript 'o' to the symbol ) is incorrect because standard conditions are denoted by adding the superscript '' (nought) to the symbol , not 'o'.
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226
Medium
226 of 329
Understanding
+4 | -1
Which one among the following pairs does not
represent example for intensive property?
represent example for intensive property?
View answer and explanation
Correct option: D
Heat capacity and enthalpy
Option D (Heat capacity and enthalpy) is correct because heat capacity and enthalpy are extensive properties, while the others are intensive.
227
Medium
227 of 329
Remembering
+4 | -1
The change of enthalpy of a chemical reaction is the same whether the reaction takes place in one step or in several steps". This law was presented by
View answer and explanation
Correct option: A
Hess
Option A (Hess) is correct because Hess's Law states that the enthalpy change of a reaction is independent of the pathway.
228
Medium
228 of 329
Remembering
+4 | -1
Which one among the following is the correct option for right relationship between for one mole of ideal gas?
View answer and explanation
Correct option: D
Option D () is correct because the relationship between Cp and Cv for one mole of an ideal gas is given by Mayer's formula: Cp - Cv = R.
229
Medium
229 of 329
Application
+4 | -1
Given that , express the bond energy in .
View answer and explanation
Correct option: C
104
Option C (104) is correct because the H-H bond energy is equivalent to the enthalpy of formation of 2 moles of H atoms from H2, and 436 kJ/mol is approximately 104 kcal/mol.
230
Medium
230 of 329
Analyzing
+4 | -1
For which among the following reactions,
change in entropy is less than zero
change in entropy is less than zero
View answer and explanation
Correct option: B
Dissociation of hydrogen
Option C (Formation of water) is correct because the formation of water from its gaseous elements results in a decrease in entropy.
231
Medium
231 of 329
Application
+4 | -1
In a chemical reaction ∆H=150 kJ and ∆S=100 at 300 K. The ∆G for the reaction is:
View answer and explanation
Correct option: D
120 kJ
Option D (120 kJ) is correct because it is calculated using the Gibbs free energy equation: ∆G = ∆H - T∆S.
232
Medium
232 of 329
Application
+4 | -1
If one mole of an ideal gas is expanded isothermally at until its volume is tripled then is
View answer and explanation
Correct option: D
Option D () is correct because the change in entropy for an isothermal expansion is given by .
233
Medium
233 of 329
Application
+4 | -1
What is the final temperature (in kelvin) of mole monoatomic ideal gas that performs 75 cal of work adiabatically if the initial temperature is ? (use )
View answer and explanation
Correct option: A
250
Option A (250) is correct because it is calculated using the adiabatic process equation and the given work done.
234
Medium
234 of 329
Application
+4 | -1
When a certain amount of ethylene was burnt 6226 kJ heat was evolved. If heat of combustion of ethylene is 1411 kJ, the volume of (at NTP) that entered into the reaction is:
View answer and explanation
Correct option: B
296.5 litre
Option B (296.5 litre) is correct because the volume of O2 is calculated using the stoichiometry of the combustion reaction and the given heat evolved.
235
Medium
235 of 329
Application
+4 | -1
Using bond energy data, calculate heat of formation of isoprene. Given of and .
View answer and explanation
Correct option: A
Option A () is correct because it is the calculated heat of formation of isoprene using the given bond energies.
236
Medium
236 of 329
Application
+4 | -1
decomposes at constant pressure as
at , the heat absorbed during the reaction is .
Calculate & for the reaction
at , the heat absorbed during the reaction is .
Calculate & for the reaction
View answer and explanation
Correct option: A
80 kJ; 77.522 kJ
Option A (80 kJ; 77.522 kJ) is correct because Δ H is equal to the heat absorbed at constant pressure (80 kJ), and Δ U is calculated using the relation Δ H = Δ U + Δ n_g RT.
237
Medium
237 of 329
Understanding
+4 | -1
Which of the following pairs of a chemical reaction is certain to result in a spontaneous reaction?
View answer and explanation
Correct option: C
Exothermic and increasing disorder
Option C is correct because an exothermic reaction (ΔH < 0) with increasing disorder (ΔS > 0) will always result in a negative ΔG, making the reaction spontaneous at all temperatures.
238
Medium
238 of 329
Understanding
+4 | -1
If is the enthalpy change and the change in internal energy accompanying a gaseous reaction then
View answer and explanation
Correct option: D
is less than if the number of moles of gaseous products is less than the number of moles of gaseous reactants.
The correct answer is D ( is less than if the number of moles of gaseous products is less than the number of moles of gaseous reactants) because the relationship between enthalpy and internal energy change depends on the change in the number of gaseous moles.
239
Medium
239 of 329
Understanding
+4 | -1
The standard heat of combustion of a hydrocarbon compound is an/a-
View answer and explanation
Correct option: C
Intensive property
Option A (Extensive property) is incorrect. The standard heat of combustion is an intensive property because it is defined per mole of the substance.
240
Medium
240 of 329
Application
+4 | -1
for the reaction is The bond energies (in ) of and are and respectively. The enthalpy of sublimation of is
View answer and explanation
Correct option: A
The correct answer is because it is calculated using the given enthalpy change, bond energies, and applying Hess's law.
Revision notes and key takeaways
Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 329 questions
