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JEE • CHEMISTRY • THERMODYNAMICS
Thermodynamics practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 391-420 of 500 questions
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391
Hard
391 of 500
Application
+4 | -1
Enthalpy of vaporisation for water is 186.5 kJ . The entropy change during vaorisation is …kJ .
View answer and explanation
Correct option: A
0.5
Option A (0.5) is correct because the entropy change is calculated by dividing the enthalpy of vaporization by the temperature.
392
Easy
392 of 500
Understanding
+4 | -1
Which of the following is/are state function?
View answer and explanation
Correct option: C
Energy
Option C (Energy) is the state function because its value depends only on the initial and final states of the system, not on the path taken.
393
Easy
393 of 500
Understanding
+4 | -1
Assertion (A): Work is a path function which is expressed in joule.
Reason (R): Work appears only at the boundary of the system.
Reason (R): Work appears only at the boundary of the system.
View answer and explanation
Correct option: B
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
Option B (Both (A) & (R) are true but the (R) is not the correct explanation of the (A)) is correct because both statements are true, but the reason doesn't explain why work is a path function.
394
Medium
394 of 500
Analyzing
+4 | -1
Statement I: Heat evolved in the neutralization of either 1 mole of or 1 mole of with is same.
Statement II: Both and are strong acids.
Statement II: Both and are strong acids.
View answer and explanation
Correct option: D
If Statement I is INCORRECT, but Statement II is CORRECT
Option D is correct because the heat evolved in the neutralization of 1 mole of with is different from that of 1 mole of because is a dibasic acid, while is a monobasic acid.
395
Medium
395 of 500
Understanding
+4 | -1
Among the following the set of parameters that represents path functions, is
(A) (B) (C) (D)
(A) (B) (C) (D)
View answer and explanation
Correct option: D
(B) and (C)
Option D ((B) and (C)) is correct because heat () and work () are path functions, meaning their values depend on the path taken during a process.
396
Easy
396 of 500
Analyzing
+4 | -1
The difference between electron gain enthalpies will be maximum between:
View answer and explanation
Correct option: C
and
Option C ( and ) is correct because the electron gain enthalpy of Ne is positive (noble gas) and that of Cl is highly negative, resulting in the maximum difference.
397
Medium
397 of 500
Remembering
+4 | -1
Identify the correct statement regarding entropy
View answer and explanation
Correct option: C
At absolute zero of temperature, entropy of a perfectly crystalline substance is taken to be zero
Option C (At absolute zero of temperature, entropy of a perfectly crystalline substance is taken to be zero) is correct because the Third Law of Thermodynamics states that the entropy of a perfectly crystalline substance at absolute zero (0 K) is zero.
398
Medium
398 of 500
Application
+4 | -1
The heat of combustion of and are and respectively. The heat of formation of methane is
View answer and explanation
Correct option: C
Option C (-80 kcal) is correct because it correctly applies Hess's Law to calculate the heat of formation.
399
Medium
399 of 500
Application
+4 | -1
The entropy change for vaporisation of liquid water to steam at 100℃ is…Given that heat of vaporisation is
View answer and explanation
Correct option: A
109.38
Option A (109.38) is correct because the entropy change is calculated by dividing the heat of vaporization by the temperature in Kelvin.
400
Medium
400 of 500
Remembering
+4 | -1
Specific heat is defined as:
View answer and explanation
Correct option: A
Heat capacity/g
Option A (Heat capacity/g) is correct because specific heat is defined as the amount of heat required to raise the temperature of 1 gram of a substance by 1 degree Celsius.
401
Hard
401 of 500
Analyzing
+4 | -1
Calculate proton affinity of from the following data.
Ionization energy of
E.A. of
Lattice energy of
Ionization energy of
E.A. of
Lattice energy of
View answer and explanation
Correct option: B
The correct answer is B (-718 kJ/mol) because it is the calculated proton affinity of NH3(g) using the given thermochemical data and Hess's Law.
402
Medium
402 of 500
Remembering
+4 | -1
The enthalpy of a monoatomic gas at Kelvin is:
View answer and explanation
Correct option: D
Option D () is correct because the enthalpy of a monoatomic gas is given by H = E + PV = .
403
Medium
403 of 500
Application
+4 | -1
At 1 mole of butane upon heating forms and . The work done is
View answer and explanation
Correct option: B
atm
Option B () is correct because it involves calculating the work done using the change in the number of moles of gas and the ideal gas constant.
404
Medium
404 of 500
Application
+4 | -1
The enthalpy of neutralisation of and is and enthalpy of neutralisation of with strong base is . The enthalpy of ionisation of will be
View answer and explanation
Correct option: C
Option C () is correct because it is calculated by considering the enthalpy of neutralization of a weak acid with a weak base and a weak acid with a strong base.
405
Hard
405 of 500
Application
+4 | -1
For the complete combustion of ethanol, the amount of heat produced as measured in bomb calorimeter, is at . Assuming ideality the enthalpy of combustion, for the reaction will be
()
()
View answer and explanation
Correct option: A
Option A () is correct because it accounts for the change in the number of moles of gas using the relationship between \ and \.
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406
Medium
406 of 500
Application
+4 | -1
Given that ;
, the standard molar enthalpy of formation in of is
, the standard molar enthalpy of formation in of is
View answer and explanation
Correct option: D
-46
Option D (-46) is correct because the standard molar enthalpy of formation is half of the given reaction enthalpy since 2 moles of NH3 are formed.
407
Medium
407 of 500
Analyzing
+4 | -1
Butane exists in various conformations in nature. At any given instant, the probability that a given butane molecule is in anti, gauche, eclipsed and fully eclipsed conformation is and respectively. If the molar enthalpy of combustion of natural butane is at then calculate the enthalpy of combustion of butane if all the butane molecules are in gauche conformation. The potential energy of gauche form is higher than anti form but it is less than eclipsed form and less than fully eclipsed form.
View answer and explanation
Correct option: C
Option C (-691 kcal/mol) is correct because it calculates the enthalpy of combustion for the gauche conformation based on the given probabilities and energy differences.
408
Medium
408 of 500
Understanding
+4 | -1
According to the first law of thermodynamics which of the following quantities represents change in a state function?
View answer and explanation
Correct option: D
Option D () is correct because, according to the first law of thermodynamics, the change in internal energy, a state function, is equal to the sum of heat and work.
409
Medium
409 of 500
Application
+4 | -1
1 mol of an ideal gas expanded reversibly from 10 L to 100 L at Work done involved in the process is
View answer and explanation
Correct option: B
-5.74 kJ
Option B (-5.74 kJ) is correct because the work done in a reversible isothermal expansion is calculated using the formula W = -2.303 nRT log(V2/V1).
410
Medium
410 of 500
Remembering
+4 | -1
A process in which no heat change takes place is called.
View answer and explanation
Correct option: B
An adiabatic process
Option B (An adiabatic process) is correct because an adiabatic process is defined as a thermodynamic process in which there is no heat exchange between the system and its surroundings (ΔQ = 0).
411
Medium
411 of 500
Application
+4 | -1
The enthalpy changes for the following processes are listed below :
Given that the standard states for iodine and chlorine are and , the standard enthalpy of formation for is :
Given that the standard states for iodine and chlorine are and , the standard enthalpy of formation for is :
View answer and explanation
Correct option: A
Option A (+16.8 kJ mol⁻¹) is correct because it is calculated using Hess's Law and the given enthalpy changes.
412
Easy
412 of 500
Understanding
+4 | -1
The standard heat of combustion of solid boron is :
View answer and explanation
Correct option: D
Option B () is correct because the standard heat of combustion of solid boron is half the standard heat of formation of B2O3.
413
Medium
413 of 500
Application
+4 | -1
The heat of formations of and are and respectively. The heat of combustion of carbon monoxide will be
View answer and explanation
Correct option: D
Option D (-67.6 kcal) is correct because it is the result of subtracting the heat of formation of CO from that of CO2.
414
Medium
414 of 500
Application
+4 | -1
Consider a reversible isontropic expansion of 1.0 mole of an ideal monoatomic gas from to . If the initial pressure was , final pressure is
View answer and explanation
Correct option: A
1.474 bar
Option A (1.474 bar) is correct because it is calculated using the isentropic process formula relating pressure and temperature.
415
Medium
415 of 500
Application
+4 | -1
If the bond energies of and are 433,192 and mol respectively the for the reaction is:
View answer and explanation
Correct option: C
Option C (-103 kJ) is correct because it calculates the enthalpy change of the reaction using bond energies of reactants and products.
416
Medium
416 of 500
Understanding
+4 | -1
Which of the following on combustion gives
maximum energy?
maximum energy?
View answer and explanation
Correct option: D
Butane
Option D (Butane) is correct because, for alkanes, the heat of combustion increases with the number of carbon atoms.
417
Medium
417 of 500
Understanding
+4 | -1
A process which is unfavourable with respect to enthalpy,
but favourable with respect to entropy
but favourable with respect to entropy
View answer and explanation
Correct option: B
could occur at high temperatures, but not at low
temperatures
temperatures
Option B is correct because a process unfavorable in enthalpy but favorable in entropy can occur at high temperatures where the entropy term dominates the Gibbs free energy equation.
418
Medium
418 of 500
Understanding
+4 | -1
Heat absorbed at constant volume is measured in a calorimeter in which steel vessel is immersed to ensure that
View answer and explanation
Correct option: C
No heat is lost to the surrounding
Option C is correct because a calorimeter is designed to prevent heat exchange with the surroundings, ensuring accurate measurement of heat absorbed at constant volume.
419
Medium
419 of 500
Analyzing
+4 | -1
Assertion (A): The dissolution of in water is endothermic but it dissolves in water.
Reason (R): On dissolution of , entropy increases.
Reason (R): On dissolution of , entropy increases.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct; Reason is not the correct explanation of Assertion
Option B (Both Assertion and Reason are correct; Reason is not the correct explanation of Assertion) is correct because while NH4Cl dissolution is endothermic and dissolves in water, the driving force is entropy increase, not a direct consequence of endothermicity.
420
Medium
420 of 500
Remembering
+4 | -1
The molar heat capacity, of an ideal gas whose energy is that of translational motion only is
View answer and explanation
Correct option: B
Option B () is correct because for an ideal gas with only translational motion, Cv = (3/2)R, which equals 12.47 J/mol·K.
Revision notes and key takeaways
Review THERMODYNAMICS in your textbook or class notes, then use this set to check your understanding.
Showing 391-420 of 500 questions
