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JEE • CHEMISTRY • SURFACE CHEMISTRY

Surface chemistry practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 83 questions
1 Medium
1 of 83
Understanding +4 | -1
Alumns purify muddy water by
View answer and explanation
Correct option: D
Coagulation
Option D (Coagulation) is correct because alum causes the colloidal particles to clump together and settle down, purifying the water.
2 Medium
2 of 83
Understanding +4 | -1
Negatively charged sol is formed in peptisation of
View answer and explanation
Correct option: C
SnO2{SnO}_2 by NaOH{NaOH}
Option C (SnO2{SnO}_2 by NaOH{NaOH}) is correct because when SnO2{SnO}_2 is peptized by NaOH{NaOH}, the SnO32−SnO_3^{2-} ions are adsorbed on the surface of the SnO2{SnO}_2 particles, forming a negatively charged sol.
3 Medium
3 of 83
Understanding +4 | -1
The sol given below with negatively charge colloidal particles is
View answer and explanation
Correct option: C
AgNO3AgN{O_3} added to KlKl solution
Option C (AgNO3AgN{O_3} added to KlKl solution) is correct because the iodide ions get adsorbed on the surface of AgIAgI forming negatively charged colloids.
4 Medium
4 of 83
Remembering +4 | -1
A curve showing the variation of pressure with temperature for a given amount of adsorption is called
View answer and explanation
Correct option: C
Adsorption isoster
Option C (Adsorption isoster) is correct because an adsorption isoster represents the variation of pressure with temperature at a constant amount of adsorption.
5 Medium
5 of 83
Understanding +4 | -1
The isoelectric-point of a colloidally dispersed material is the pH\mathrm{pH} value at which
View answer and explanation
Correct option: B
the dispersed phase does not migrate in an electric field
Option B (the dispersed phase does not migrate in an electric field) is correct because the isoelectric point is the pH at which the net charge of the colloidal particles is zero, so they don't move in an electric field.
6 Medium
6 of 83
Understanding +4 | -1
The cause of Brownian movement is
View answer and explanation
Correct option: C
The impact of molecules of the dispersion medium on the colloidal particles.
Option C (The impact of molecules of the dispersion medium on the colloidal particles) is correct because Brownian movement is caused by the random collisions of the molecules of the dispersion medium with the colloidal particles.
7 Medium
7 of 83
Remembering +4 | -1
Which of the following can reduce decomposition of H2O2\mathrm{H}_{2} \mathrm{O}_{2} on exposure to light
View answer and explanation
Correct option: A
Urea
Option A (Urea) is correct because urea acts as a negative catalyst, retarding the decomposition of hydrogen peroxide (H2O2H_2O_2) into water and oxygen upon exposure to light.
8 Medium
8 of 83
Understanding +4 | -1
Assertion : Alcohols are dehydrated to hydrocarbons in the presence of acidic zeolites.

Reason : Zeolites are porous catalysts.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
Option B is correct because both the assertion and the reason are correct, but the reason does not explain the assertion. Zeolites are porous catalysts, but the dehydration of alcohols to hydrocarbons is due to their acidic nature.
9 Medium
9 of 83
Remembering +4 | -1
The atoms present in cationic detergent can be
View answer and explanation
Correct option: C
C,H,N{C}, {H}, {N}
Option C (C,H,N{C}, {H}, {N}) is correct because cationic detergents typically contain a long hydrocarbon chain and a positively charged nitrogen atom.
10 Medium
10 of 83
Application +4 | -1
Particles of a sol migrate towards cathode under influence of electric field. Which of the following has least flocculation value for coagulation of above mentioned sol?
View answer and explanation
Correct option: A
K4[Fe(CN)6]\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]
Option A (K4[Fe(CN)6]\mathrm{K}_4[\mathrm{Fe}(\mathrm{CN})_6]) is correct because it has the highest charge anion, thus the least flocculation value for a positively charged sol.
11 Medium
11 of 83
Understanding +4 | -1
Among the following, the INCORRECT statement about colloids is :
View answer and explanation
Correct option: D
The osmotic pressure of a colloidal solution is of higher order than the true solution at the same concentration.
Option D is correct because the osmotic pressure of a colloidal solution is lower than that of a true solution at the same concentration due to the larger size and fewer number of colloidal particles.
12 Medium
12 of 83
Understanding +4 | -1
A freshly prepared Fe(OH)3\mathrm{Fe}(\mathrm{OH})_3 precipitate is peptised by adding FeCl3\mathrm{FeCl}_3 solution. The charge on the colloidal particles is due to the preferential adsorption of :
View answer and explanation
Correct option: B
Fe+3\mathrm{Fe}^{+3} ions
Option B is correct because during peptization of Fe(OH)3\mathrm{Fe(OH)}_3 with FeCl3\mathrm{FeCl}_3, the Fe3+\mathrm{Fe}^{3+} ions are preferentially adsorbed onto the precipitate, giving the colloidal particles a positive charge.
13 Medium
13 of 83
Application +4 | -1
On adding AgNO3AgN{O_3} solution to KIKI solution, a negatively charged colloidal solution will be formed in which of the following conditions?
View answer and explanation
Correct option: D
100mlof0.1M   AgNO3+100mlof0.15M KI          100\mathrm{ }ml\mathrm{ of }0.1\mathrm{ }M\;\,AgN{O_3} + \mathrm{ 10}0\mathrm{ }ml\mathrm{ of }0.15\mathrm{ }M\,KI\;\;\;\;\;
Option D (100mlof0.1M   AgNO3+100mlof0.15M KI100\mathrm{ }ml\mathrm{ of }0.1\mathrm{ }M\;\,AgN{O_3} + \mathrm{ 10}0\mathrm{ }ml\mathrm{ of }0.15\mathrm{ }M\,KI) is correct because excess KI will adsorb I−I^- ions, forming a negatively charged colloidal solution.
14 Medium
14 of 83
Understanding +4 | -1
Correct set of example of given type of colloid is
View answer and explanation
Correct option: C
Gel : Cheese
Option C (Gel : Cheese) is correct because cheese is a well-known example of a gel colloid.
15 Medium
15 of 83
Understanding +4 | -1
The Tyndall effect is observed only when following conditions are satisfied

1. The diameter of the dispersed particles is much smaller than the wavelength of the light used

2. The diameter of the dispersed particle is not much smaller than the wavelength of the light used

3. The refractive indices of the dispersed phase and dispersion medium are almost similar in magnitude

4. The refractive indices of the dispersed phase and dispersion medium differ greatly in magnitude
View answer and explanation
Correct option: B
2 and 4
Option B (2 and 4) is correct because the Tyndall effect requires the dispersed particle size to be comparable to the wavelength of light and a significant difference in refractive indices between the dispersed phase and the medium.

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16 Medium
16 of 83
Remembering +4 | -1
Sulphur colloid is prepared by
View answer and explanation
Correct option: B
Oxidation
Option D (Reduction) is incorrect. Option B (Oxidation) is correct because sulphur colloid can be prepared by oxidizing H2S with bromine.
17 Medium
17 of 83
Remembering +4 | -1
Positive sol among the following is
View answer and explanation
Correct option: A
Fe(OH)3{Fe}({OH})_3 sol
Option A (Fe(OH)3{Fe}({OH})_3 sol) is correct because Fe(OH)3{Fe}({OH})_3 sol is a positively charged sol, while AuAu, Cu{Cu}, and As2 S3{As}_2{~S}_3 sols are negatively charged.
18 Medium
18 of 83
Understanding +4 | -1
For As2 S3\mathrm{As}_2 \mathrm{~S}_3 colloids, which of the following ion will have highest coagulating power?
View answer and explanation
Correct option: D
Al3+\mathrm{Al}^{3+}
Option D (Al3+\mathrm{Al}^{3+}) is correct because, according to the Hardy-Schulze rule, ions with higher charges have greater coagulating power for colloids with opposite charges.
19 Medium
19 of 83
Remembering +4 | -1
Butter is a colloidal solution of
View answer and explanation
Correct option: B
Liquid-solid
Option B (Liquid-solid) is correct because in butter, the dispersed phase is liquid (water/fat globules) and the dispersion medium is solid (milk solids).
20 Medium
20 of 83
Understanding +4 | -1
On which of the following properties does the coagulating power of an ion depend ?
View answer and explanation
Correct option: C
Both magnitude and sign of the charge on the ion
Option C (Both magnitude and sign of the charge on the ion) is correct because the coagulating power of an ion depends on both its charge and its sign, as per the Hardy-Schulze rule.
21 Medium
21 of 83
Understanding +4 | -1
S-I: Catalyst is more effective in the powdered state.

S-II: In the powdered state surface area is maximum.
View answer and explanation
Correct option: A
Both S-I & S-II are true
Option A (Both S-I & S-II are true) is correct because catalysts are more effective in powdered form due to increased surface area, which is maximized in the powdered state.
22 Medium
22 of 83
Remembering +4 | -1
Colloidal Solution of silver can be prepared by
View answer and explanation
Correct option: C
Bredig’s arc method
Option C (Bredig’s arc method) is correct because Bredig's arc method is specifically used to prepare colloidal solutions of metals like silver, gold, and platinum.
23 Medium
23 of 83
Remembering +4 | -1
Example of macromolecular colloids is
View answer and explanation
Correct option: A
Starch
Option A (Starch) is correct because starch molecules are large and form macromolecular colloids in solution.
24 Medium
24 of 83
Understanding +4 | -1
Measuring Zeta potential is useful in determining which property of colloidal solution ?
View answer and explanation
Correct option: C
Stability of the colloidal particles
Option C (Stability of the colloidal particles) is correct because Zeta potential is directly related to the stability of colloidal solutions.
25 Medium
25 of 83
Understanding +4 | -1
A negatively charged suspension of clay in water needs for precipitation the minimum amount of
View answer and explanation
Correct option: A
AlCl3AlC{l_3}
Option A (AlCl3AlCl_3) is correct because according to Hardy-Schulze rule, greater the valency of the flocculating ion added, greater is its power to cause precipitation.
26 Medium
26 of 83
Understanding +4 | -1
On addition of 1mL solution of 10% NaCl to 10mL gold solution in the presence of 0.025  g0.025\;g of starch, the coagulation is prevented because starch has the following gold numbers
View answer and explanation
Correct option: A
25
Option A (25) is correct because the gold number is defined as the amount of protective colloid in milligrams that prevents coagulation of 10 mL of gold solution by 1 mL of 10% NaCl solution.
27 Medium
27 of 83
Understanding +4 | -1
Assertion: Colloids are heterogeneous mixture.

Reason: The particle size of the dispersed phase is too large for it to form a homogeneous mixture.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A is correct because colloids are indeed heterogeneous mixtures, and the size of the dispersed phase particles prevents them from forming a homogeneous mixture.
28 Medium
28 of 83
Understanding +4 | -1
Assertion: A catalyst is more effective in finely divided form.

Reason: Finely divided form has more surface area.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
Option A is correct because a catalyst's effectiveness increases with surface area, which is maximized in finely divided form.
29 Medium
29 of 83
Analyzing +4 | -1
Which of the following is mismatched?

Dispersed Dispersed Specific

Phase medium name
View answer and explanation
Correct option: D
Gas solid foam
Option D is correct because when the dispersed phase is a gas and the dispersion medium is a solid, the colloid is called a solid foam, not just foam.
30 Medium
30 of 83
Understanding +4 | -1
The most appropriate method of making eggalbumin sol is:
View answer and explanation
Correct option: A
Break an egg carefully and transfer the transparent part of the content to 100 mL100 \mathrm{~mL} of 5%w/V5 \% \mathrm{w} / \mathrm{V} saline solution and stir well.
Option A (Break an egg carefully and transfer the transparent part of the content to 100 mL100 \mathrm{~mL} of 5%w/V5 \% \mathrm{w} / \mathrm{V} saline solution and stir well.) is correct because egg albumin is the transparent part of the egg, and a saline solution helps stabilize the sol.
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