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JEE • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 592 questions

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241 Medium
241 of 592
Remembering +4 | -1
The total number of nodes in a subshell are given by
View answer and explanation
Correct option: C
n−l−1{n}-l-1
Option C (n−l−1{n}-l-1) is correct because the total number of nodes in a subshell is the sum of radial and angular nodes, where radial nodes are n−l−1{n}-l-1.
242 Easy
242 of 592
Understanding +4 | -1
The quantum number values for the designation 3d3 d are
View answer and explanation
Correct option: D
n=3,l=2n=3, l=2
Option D (n=3,l=2n=3, l=2) is correct because for a 3d orbital, the principal quantum number (n) is 3, and the azimuthal quantum number (l) is 2 (d corresponds to l=2).
243 Hard
243 of 592
Application +4 | -1
A photon of 300 nm is absorbed by a gas which then
re-emits two photons. One re-emitted photon has
wavelength of 496 nm. Wavelength of other re-emitted
photon is
View answer and explanation
Correct option: C
759 nm
Option C (759 nm) is correct because the energy of the absorbed photon must equal the sum of the energies of the two re-emitted photons.
244 Medium
244 of 592
Analyzing +4 | -1
Which of the following is correctly matched?
View answer and explanation
Correct option: A
Momentum of H atom when electrons return from n=2 to n=1: 3Rh4\frac{{3Rh}}{4}
Option A is correctly matched because the momentum of the H atom equals the momentum of the emitted photon when the electron transitions from n=2 to n=1, which is calculated to be 3Rh4\frac{{3Rh}}{{4}}.
245 Medium
245 of 592
Understanding +4 | -1
For a d – electron, the orbital angular momentum is
View answer and explanation
Correct option: A
6 ℏ\sqrt 6 \,\hbar
Option A (6 ℏ\sqrt 6 \,\hbar) is correct because the orbital angular momentum for a d-electron (l=2) is given by l(l+1)ℏ=2(2+1)ℏ=6ℏ\sqrt{l(l+1)}\hbar = \sqrt{2(2+1)}\hbar = \sqrt{6}\hbar.
246 Hard
246 of 592
Application +4 | -1
An electron and a proton are accelerated through a potential VV. If PeP_{\mathrm{e}} and PpP_{\mathrm{p}} are their momentum, then PP:PeP_{\mathrm{P}}: P_{\mathrm{e}} ratio is approximately equal to
View answer and explanation
Correct option: D
43:143: 1
Option D (43:1) is correct because the ratio of momenta is proportional to the square root of the mass ratio, which is approximately the square root of 1836, resulting in approximately 43:1.
247 Easy
247 of 592
Understanding +4 | -1
S-II: Electrons may be considered as particles and waves.

S-II: An electron in an atom may be described as occupying at atomic orbital or by a wave function ψ\psi, which is a solution to the schrodinger wave equation.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because both statements accurately describe the dual nature of electrons and their behavior within atoms.
248 Easy
248 of 592
Analyzing +4 | -1
Which one is wrong statement?
View answer and explanation
Correct option: C
The magnetic quantum number of an electron present in 2nd orbit can be ‘ –2’
The statement that the magnetic quantum number of an electron present in the 2nd orbit can be '-2' is wrong because for n=2, l can be 0 or 1, and ml can range from -l to +l, so it can only be -1, 0, or +1.
249 Medium
249 of 592
Analyzing +4 | -1
Which of the following is not permissible arrangement of electrons in an atom
View answer and explanation
Correct option: A
n=3,  l=2,  m=−3,  s=−12n = 3,\,\,l = 2,\,\,m = - 3,\,\,s = - \frac{1}{2}
Option A is correct because for n=3 and l=2, m can only range from -2 to +2, therefore m=-3 is not permissible.
250 Easy
250 of 592
Understanding +4 | -1
The ratio of speed of γ-rays and X-rays is:
View answer and explanation
Correct option: A
1
Option A (1) is correct because both γ-rays and X-rays are electromagnetic waves and travel at the speed of light in a vacuum, so their speeds are equal.
251 Easy
251 of 592
Remembering +4 | -1
Stark effect refers to the
View answer and explanation
Correct option: A
Splitting up of the lines in an emission spectrum in the presence of an external electrostatic field
Option A (Splitting up of the lines in an emission spectrum in the presence of an external electrostatic field) is correct because the Stark effect is defined as the splitting of spectral lines in the presence of an external electric field.
252 Easy
252 of 592
Understanding +4 | -1
Which of the following is never true for cathode rays?
View answer and explanation
Correct option: B
They are electromagnetic waves.
Option B (They are electromagnetic waves) is correct because cathode rays are streams of electrons, not electromagnetic waves.
253 Medium
253 of 592
Analyzing +4 | -1
Statement I: Fe3+\mathrm{Fe}^{3+} ion is more stable than Fe2+\mathrm{Fe}^{2+} ion in the gaseous state.
Statement II: Fe3+\mathrm{Fe}^{3+} ion has more number of unpaired electrons than Fe2+\mathrm{Fe}^{2+} ion.
View answer and explanation
Correct option: B
Both Statement I and statement II are true
The correct answer is B (Both Statement I and statement II are true) because Fe3+ has a half-filled d orbital configuration, making it more stable, and it has more unpaired electrons than Fe2+.
254 Medium
254 of 592
Understanding +4 | -1
Which of the following orbital have nodal plane in XY-plane?
View answer and explanation
Correct option: D
dyzd_{yz}
Option D (dyzd_{yz}) is correct because the dyzd_{yz} orbital lies in the YZ plane, making the XY plane a nodal plane where the probability of finding an electron is zero.
255 Easy
255 of 592
Application +4 | -1
If radius of second orbit of He+\mathrm{He}^{+}is xnm\mathrm{x} \mathrm{nm} then the radius of the first orbit of Li2+\mathrm{Li}^{2+} will be
View answer and explanation
Correct option: C
x6 nm\frac{x}{6} \mathrm{~nm}
Option C (x6 nm\frac{x}{6} \mathrm{~nm}) is correct because the radius of an orbit is proportional to n²/Z, and the ratio of the radii can be calculated using the given information.
256 Medium
256 of 592
Application +4 | -1
In hydrogen atomic spectrum, a series limit is found at 12186.3 cm−1c{m^{ - 1}}. Then, it belongs to
View answer and explanation
Correct option: C
Paschen series
Option C (Paschen series) is correct because the series limit corresponds to n1=3n_1 = 3, which defines the Paschen series.
257 Easy
257 of 592
Remembering +4 | -1
Which d-orbital does not have four lobes?
View answer and explanation
Correct option: C
dz2{d_{{z^2}}}
Option C (dz2{d_{{z^2}}}) is correct because the dz2{d_{{z^2}}} orbital has two lobes, while all other d-orbitals have four lobes.
258 Medium
258 of 592
Application +4 | -1
The most probable radius (in pm) for finding the electron inHe +{ }^{+}is:
View answer and explanation
Correct option: C
26.526.5
Option C (26.5) is correct because the most probable radius is calculated using the formula a0/Z, where a0 is the Bohr radius (52.9 pm) and Z is the atomic number.
259 Medium
259 of 592
Understanding +4 | -1
Which of the following has the highest value of specific charge?
View answer and explanation
Correct option: D
Electron
Option D (Electron) is correct because the electron has the highest charge-to-mass ratio due to its small mass.
260 Medium
260 of 592
Remembering +4 | -1
The momentum of a photon is p,p, the energy associated with photon is given by:
View answer and explanation
Correct option: B
Ep\frac{E}{p}
Option B (Ep\frac{E}{p}) is correct because the energy of a photon is related to its momentum by the equation E = pc, which gives c = E/p.
261 Medium
261 of 592
Analyzing +4 | -1
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason
R.
Assertion A: Energy of 2s orbital of hydrogen atom is greater than that of 2s orbital of lithium.
Reason R : Energies of the orbitals in the same subshell decrease with increase in the atomic number.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A.
Option A is correct because both the assertion and reason are true, and the reason correctly explains the assertion. The energy of a 2s orbital decreases with increasing atomic number due to the increased nuclear charge.
262 Easy
262 of 592
Application +4 | -1
A transition element X has configuration [Ar]3d5\left[ {\mathrm{Ar}} \right]3{d^5} in its +3 oxidation state. Its atomic number is:
View answer and explanation
Correct option: C
26
Option C (26) is correct because the element with the given electronic configuration in the +3 oxidation state has 26 electrons.
263 Easy
263 of 592
Understanding +4 | -1
Two electrons occupying the same orbital are distinguished by:
View answer and explanation
Correct option: D
Spin quantum number
Option D (Spin quantum number) is correct because the spin quantum number differentiates two electrons occupying the same orbital, as they must have opposite spins (+1/2 and -1/2) according to the Pauli Exclusion Principle.
264 Medium
264 of 592
Application +4 | -1
An electron revolves round Li2+\mathrm{Li}^{2+} nucleus at a distance of 1.587 A∘1.587\,\mathop {\text{A}}\limits^ \circ. The speed of electron should be
View answer and explanation
Correct option: A
2.188×106 m/s2.188 \times 10^6 \mathrm{~m} / \mathrm{s}
Option A (2.188×106m/s2.188 \times 10^6 m/s) is correct because it calculates the speed of the electron using the Bohr model and the given radius for Li²⁺.
265 Easy
265 of 592
Remembering +4 | -1
The minimum energy required to eject an electron from an atom is called :
View answer and explanation
Correct option: D
Work function
Option D (Work function) is correct because the work function is defined as the minimum energy required to eject an electron from an atom.
266 Medium
266 of 592
Application +4 | -1
Number waves in a Bohr orbit of H – atom is 3. Its potential energy would be
View answer and explanation
Correct option: B
−3.02eV- 3.02\mathrm{ }eV
Option B (−3.02eV- 3.02\mathrm{ }eV) is correct because the potential energy is calculated from the total energy of the electron in the given Bohr orbit.
267 Medium
267 of 592
Understanding +4 | -1
Select the correct statements from the following.

A. Atoms of all elements are composed of two fundamental particles.

B. The mass of the electron is 9.10939×10−31 kg9.10939 \times 10^{-31} \mathrm{~kg}.

C. All the isotopes of a given element show same chemical properties.

D. Protons and electrons are collectively known as nucleons.

E. Dalton's atomic theory, regarded the atom as an ultimate particles of matter.

Choose the correct answer from the options given below.
View answer and explanation
Correct option: B
B, C and E only
Option A (4) is correct because each boron atom in diborane (B2H6B_2H_6) is sp3sp^3 hybridized, involving four orbitals.
268 Medium
268 of 592
Application +4 | -1
The de Broglie wavelength associated with a ball of mass 200 g200 {~g} and moving at a speed of 5 m/h5 {~m} / {h}, is of the order of (h=6.625×10−34Js\left({h}=6.625 \times 10^{-34} {Js}\right. )
View answer and explanation
Correct option: C
10−25 m10^{-25} {~m}
Option C (10−25 m10^{-25} {~m}) is correct because it calculates the de Broglie wavelength using the formula λ=hmv\lambda = \frac{{h}}{{mv}} with appropriate unit conversions.
269 Medium
269 of 592
Remembering +4 | -1
The radii of an atom and atomic nucleus is of the order of
View answer and explanation
Correct option: C
10−10 m10^{-10} \mathrm{~m} and 10−15 m10^{-15} \mathrm{~m}
Option C (10−10 m10^{-10} \mathrm{~m} and 10−15 m10^{-15} \mathrm{~m}) is correct because it represents the approximate order of magnitude for the radii of an atom and its nucleus, respectively.
270 Medium
270 of 592
Application +4 | -1
The wavelength of a spectral line emitted by hydrogen atom in the Lyman series is 1615Rcm\frac{{16}}{{15R}}\mathrm{cm}. What is the value of n2{n_2}?(R=Rydberg constant)
View answer and explanation
Correct option: C
4
Option C (4) is correct because it is derived from the Rydberg formula for the Lyman series.
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