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JEE • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 592 questions

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31 Medium
31 of 592
Application +4 | -1
What is the wavelength in nm\mathrm{nm} of the spectral line associated with a transition from n=3n=3 to n=2n=2 for the Li2+\mathrm{Li}^{2+} ion?
View answer and explanation
Correct option: C
73
Option C (73) is correct because it is the wavelength calculated using the Rydberg formula for the given transition in the Li2+\mathrm{Li}^{2+} ion.
32 Easy
32 of 592
Understanding +4 | -1
The energy of the electron in a hydrogen atom has a negative sign because
View answer and explanation
Correct option: A
the energy of the electron in the atom is lower than the energy of a free electron at rest
Option A (the energy of the electron in the atom is lower than the energy of a free electron at rest) is correct because the negative sign indicates that the electron is in a bound state, requiring energy to be removed from the atom.
33 Hard
33 of 592
Application +4 | -1
The momentum of a photon of frequency 5×1017s−15 \times {10^{17}}{\mathrm{s}^{ - 1}} is nearly:
View answer and explanation
Correct option: A
1.1×10−24  kg  m  s−11.1 \times {10^{ - 24}}\mathrm{\;kg\;m\;}{\mathrm{s}^{ - 1}}
Option A (1.1×10−24  kg  m  s−11.1 \times {10^{ - 24}}\mathrm{\;kg\;m\;}{\mathrm{s}^{ - 1}}) is correct because the momentum of a photon is calculated using the formula p=h/λ=hv/cp = h/\lambda = hv/c.
34 Easy
34 of 592
Remembering +4 | -1
Electromagnetic radiation with minimum wavelength is
View answer and explanation
Correct option: C
X-ray
Option C (X-ray) is correct because X-rays have the shortest wavelength among the given electromagnetic radiations.
35 Hard
35 of 592
Application +4 | -1
The velocity of particle AA is 0.1 ms−10.1 {~ms}^{-1} and that of particle BB is 0.05 ms−10.05 {~ms}^{-1}. If the mass of particle BB is five times that of particle A{A}, then the ratio of de-Broglie wavelengths associated with the particles A{A} and B{B} is
View answer and explanation
Correct option: D
5:25: 2
Option D (5:25: 2) is the correct answer because it is the ratio of de-Broglie wavelengths calculated using the given velocities and masses of particles A and B.
36 Easy
36 of 592
Remembering +4 | -1
Which of the following scientists explained his model on the basis of centrifugal force?
View answer and explanation
Correct option: D
Rutherford
Option D (Rutherford) is correct because Rutherford's model of the atom proposed that electrons orbit the nucleus, with the centrifugal force balancing the electrostatic force of attraction.
37 Hard
37 of 592
Application +4 | -1
The uncertainties in the velocities of two particles A and B are 0.05 and 0.02 ms−1\mathrm{m}{\mathrm{s}^{ - 1}} respecively. The mass of B is five times to that of mass A. What is the ratio of uncertainties (ΔxAΔxB)\left( {\frac{{\Delta {x_A}}}{{\Delta {x_B}}}} \right) in their positions?
View answer and explanation
Correct option: A
2
Option A (2) is correct because the ratio of uncertainties in position is inversely proportional to the product of mass and uncertainty in velocity.
38 Medium
38 of 592
Analyzing +4 | -1
Which of the following electronic transitions requires for the greatest quantity of energy be absorbed by a H-atom?
View answer and explanation
Correct option: D
n=1n=1 to n=∞n=\infty
Option D (n=1n=1 to n=∞n=\infty) is correct because the energy difference is the greatest when the electron is completely removed from the atom.
39 Medium
39 of 592
Analyzing +4 | -1
Assertion: All p-orbitals have only one planar node.

Reason: The number of radial nodes depends on the principal quantum number only.
View answer and explanation
Correct option: C
If A is true but R is false
The correct answer is C (If A is true but R is false) because all p-orbitals have one planar node, but the number of radial nodes depends on both the principal quantum number and the azimuthal quantum number.
40 Medium
40 of 592
Application +4 | -1
The radius of which of the following orbit is same as that of first Bohr’s orbit of Hydrogen atom
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Correct option: D
Be+3(n=2)B{e^{ + 3}}\left( {n = 2} \right)
Option D (Be+3(n=2)Be^{+3}(n=2)) is correct because the radius of its second orbit is the same as the first Bohr's orbit of Hydrogen atom, calculated using the formula r = 0.529 * (n2/Z).
41 Easy
41 of 592
Remembering +4 | -1
The number of waves in an orbit are
View answer and explanation
Correct option: B
nn
Option B (nn) is correct because the number of waves in an orbit is equal to the principal quantum number, nn.
42 Easy
42 of 592
Remembering +4 | -1
When the azimuthal quantum number has a value of l=1l=1, the shape of the orbital is:
View answer and explanation
Correct option: C
dumb-bell
Option C (dumb-bell) is correct because when the azimuthal quantum number l = 1, it corresponds to a p-orbital, which has a dumb-bell shape.
43 Easy
43 of 592
Remembering +4 | -1
The electron possesses wave properties was shown experimentally by:
View answer and explanation
Correct option: C
Davission and germer
Option C (Davission and germer) is correct because the Davisson-Germer experiment demonstrated the wave nature of electrons through diffraction patterns.
44 Medium
44 of 592
Understanding +4 | -1
As ‘n’ value increases de-broglie’s wavelength of electron
View answer and explanation
Correct option: B
Increases
Option B is correct because as 'n' (principal quantum number) increases, the de Broglie wavelength of an electron increases, as the momentum decreases with increasing energy levels.
45 Easy
45 of 592
Understanding +4 | -1
For which of the following species, Bohr’s theory doesn’t apply
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Correct option: D
Na+N{a^ + }
Option D is correct because Bohr's theory is only applicable to hydrogen-like species (species with only one electron), and Na+ has more than one electron.
46 Medium
46 of 592
Analyzing +4 | -1
Assertion :- A spectral line will be seen for a 2px–2py2p_x – 2p_y transition.

Reason :- Only Balmer lines are observed in the visible region.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (4,2) is correct because the molecule has 3 chiral centers, leading to a maximum of 8 stereoisomers, but due to symmetry, there are only 4 stereoisomers with 2 meso forms.
47 Easy
47 of 592
Understanding +4 | -1
In order to designate an orbital n in an atom, the number of quantum number required are:
View answer and explanation
Correct option: C
3
Option C (3) is correct because three quantum numbers (n, l, and m) are required to define an orbital in an atom.
48 Medium
48 of 592
Application +4 | -1
Thewavelength of a 150 g150 \mathrm{~g} rubber ball moving with a velocity of 50 ms−150 {~ms}^{-1} is :
View answer and explanation
Correct option: D
8.83×10−33 cm8.83 \times 10^{-33} {~cm}
Option D (8.83×10−33 cm8.83 \times 10^{-33} {~cm}) is correct because it is calculated using the de Broglie wavelength formula with the given mass and velocity.
49 Hard
49 of 592
Remembering +4 | -1
The probability of finding out an electron at a point within an atom is proportional to the
View answer and explanation
Correct option: A
Square of the orbital wave function i.e., ψ2\psi^2
Option B (Na) is correct because Sodium (Na) is the most abundant alkali metal found in combined state due to its high reactivity and presence in various minerals and salts.
50 Easy
50 of 592
Remembering +4 | -1
Millikan performed an experiment method to determine which of the following?
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Correct option: B
Charge of the electron
Option B (Charge of the electron) is correct because Millikan's oil drop experiment was designed to measure the elementary electric charge.
51 Easy
51 of 592
Analyzing +4 | -1
Statement (S): Electronic configuration of 23V3+{ }_{23} \mathrm{V}^{3+} ion is [Ar]183d2[\mathrm{Ar}]^{18} 3 d^2 and not [Ar]183d04s2.[\mathrm{Ar}]^{18} 3 d^0 4 s^2.

Explanation (E): V3+\mathrm{V}^{3+} ion is diamagnetic in nature.
View answer and explanation
Correct option: A
S is correct but E is wrong
Option A is correct because V3+ has the electronic configuration [Ar]3d2, and it is paramagnetic, not diamagnetic.
52 Medium
52 of 592
Analyzing +4 | -1
Which of the following is not iso electronic with H2S?{H}_2 {S}?
View answer and explanation
Correct option: B
Oxide ion
Option B (Oxide ion) is not isoelectronic with H2S{H}_2 {S} because oxide ion has 10 electrons, while H2S{H}_2 {S} has 18 electrons.
53 Easy
53 of 592
Remembering +4 | -1
How many neutrons are present in tritium nucleus?
View answer and explanation
Correct option: A
2
Option A (2) is correct because tritium, being an isotope of hydrogen with a mass number of 3, has 1 proton and therefore 2 neutrons (3 - 1 = 2).
54 Medium
54 of 592
Remembering +4 | -1
The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?
View answer and explanation
Correct option: A
−1.76×108-1.76 \times 10^8 coulombs/g
Option A (−1.76×108-1.76 \times 10^8 coulombs/g) is correct because it represents the experimentally determined charge-to-mass ratio of an electron.
55 Easy
55 of 592
Application +4 | -1
Calculate number of electron for which n=4n=4 and S=+12{S}=+\frac{1}{2}
View answer and explanation
Correct option: A
16
Option A (16) is correct because for n=4, there are 16 electrons with spin +1/2, considering all the possible subshells (4s, 4p, 4d, and 4f).
56 Medium
56 of 592
Understanding +4 | -1
For hydrogen atom, the correct order of energy of orbitals is
View answer and explanation
Correct option: D
4f=4d=4p>3d=3p=3s
Option D (4f=4d=4p>3d=3p=3s) is correct because for a hydrogen atom, energy depends only on the principal quantum number (n).
57 Medium
57 of 592
Understanding +4 | -1
Consider the following statements:

I. The speed of light does not depends upon the nature of the medium through which it passes.

II. The beam of light is deviated or refracted from its original path as it passes from one medium to another.

III. When a ray of white light is passed through a prism, the wave with shorter wavelength bends more than the one with a longer wavelength.

Choose the correct statements and select the correct option.
View answer and explanation
Correct option: B
II and III
Option B (II and III) is correct because the speed of light depends on the medium, light refracts when passing between media, and shorter wavelengths bend more in a prism.
58 Easy
58 of 592
Remembering +4 | -1
Which of the following phenomenon is responsible for the television pictures?
View answer and explanation
Correct option: B
Fluorescence
Option B (Fluorescence) is correct because television pictures are produced due to the phenomenon of fluorescence, where substances emit light upon excitation by electrons.
59 Easy
59 of 592
Understanding +4 | -1
Assertion: The maximum number of eletrons in p & d subshells are 6 and 10 respectively.

Reason: The maximum number of electrons in the shell with prinicpal quantum number nn is equal to 2n22 n^2.
View answer and explanation
Correct option: B
If both A and R are true but R is not the correct explanation of A
Option B (If both A and R are true but R is not the correct explanation of A) is correct because both the assertion and reason are true statements, but the reason does not explain the assertion.
60 Easy
60 of 592
Remembering +4 | -1
Spin angular momentum of electron is given by
View answer and explanation
Correct option: A
34hπ\frac{{\sqrt 3 }}{4}\frac{h}{\pi }
Option A (34hπ\frac{{\sqrt 3 }}{4}\frac{h}{\pi }) is correct because the spin angular momentum is calculated using the formula h2πs(s+1)\frac{h}{{2\pi }}\sqrt {s(s + 1)}, where s = 1/2 for an electron.
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