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JEE • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 451-480 of 592 questions

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451 Easy
451 of 592
Remembering +4 | -1
Spin angular momentum for electron
View answer and explanation
Correct option: A
S(s+1)h2π\sqrt {S(s + 1)} \frac{h}{{2\pi }}
Option A (S(s+1)h2π\sqrt {S(s + 1)} \frac{h}{{2\pi }}) is correct because this is the formula for the spin angular momentum of an electron.
452 Medium
452 of 592
Application +4 | -1
A dye emits 50%50 \% of the absorbed energy as fluorescence. If the number of quanta absorbed and emitted out is in the ratio 1:21: 2 and it absorbs the radiation of wavelength ' xx ' A∘\mathop {\text{A}}\limits^ \circ, then the wavelength of the emitted radiation will be
View answer and explanation
Correct option: C
4x A∘4 x\,\mathop {\text{A}}\limits^ \circ
Option C (4x A∘4 x\,\mathop {\text{A}}\limits^ \circ) is correct because the emitted wavelength is four times the absorbed wavelength, derived from the energy and quantum ratio relationship.
453 Easy
453 of 592
Remembering +4 | -1
The principle, which gives a way to fill the electrons in the available energy level is:
View answer and explanation
Correct option: C
Aufbau principle
Option C (Aufbau principle) is correct because the Aufbau principle dictates the filling of electrons in available energy levels.
454 Easy
454 of 592
Remembering +4 | -1
The number of electrons in the nucleus of C12{C^{12}} is
View answer and explanation
Correct option: C
0
Option C (0) is correct because the nucleus of an atom contains protons and neutrons, but not electrons.
455 Medium
455 of 592
Understanding +4 | -1
Which are in the ascending order of wavelength?
View answer and explanation
Correct option: B
Lyman limit, Balmer limit, Paschen limit in the hydrogen spectrum
Option B is correct because the wavelengths of the Lyman, Balmer, and Paschen limits increase in that order, corresponding to the ultraviolet, visible, and infrared regions, respectively.
456 Medium
456 of 592
Application +4 | -1
Calculate the wave number for the shortest wavelength transition in the Balmer series of atomic hydrogen.
View answer and explanation
Correct option: A
27419.25 cm−127419.25 \mathrm{~cm}^{-1}
Option A (27419.25 cm−127419.25 \mathrm{~cm}^{-1}) is correct because the shortest wavelength corresponds to the largest energy transition, which in the Balmer series is from infinity to n=2.
457 Hard
457 of 592
Application +4 | -1
Binding energy of hydrogen atom is 13.6 eV. The binding energy of a singly ionised helium atom is:
View answer and explanation
Correct option: C
54.4 eV
Option C (54.4 eV) is correct because the binding energy of a singly ionized helium atom is four times that of a hydrogen atom due to the increased nuclear charge (Z=2).
458 Medium
458 of 592
Application +4 | -1
Which of the followings sets of quantum numbers represents the highest energy of an atom?
View answer and explanation
Correct option: B
n=3,l=2,m=1,s=+12n = 3,l = 2,m = 1,s = + \frac{1}{2}
The correct answer is B (n=3,l=2,m=1,s=+12n = 3, l = 2, m = 1, s = + \frac{1}{2}) because it represents the highest energy level based on the n+ln + l rule.
459 Easy
459 of 592
Understanding +4 | -1
Which one is not in agreement with Bohr's model of the atom?
View answer and explanation
Correct option: D
Heisenberg’s uncertainty principle
Option D (Heisenberg’s uncertainty principle) is correct because Bohr's model violates the Heisenberg uncertainty principle by defining both position and momentum of an electron simultaneously.
460 Easy
460 of 592
Application +4 | -1
A metallic ion M2+{M^{2 + }} ion has a electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus are
View answer and explanation
Correct option: A
30
Option A (30) is correct because the number of neutrons is the difference between the mass number and the atomic number.
461 Hard
461 of 592
Analyzing +4 | -1
Which of the following energy change is less than third balmer transition in He+\mathrm{He}^{+} ion:
View answer and explanation
Correct option: B
Third separation energy of Li+2\mathrm{Li}^{+2} ion
Option B (Third separation energy of Li+2\mathrm{Li}^{+2} ion) is correct because it has the lowest energy change compared to the third Balmer transition in He+\mathrm{He}^{+} ion.
462 Easy
462 of 592
Analyzing +4 | -1
Which among the following species have the same number of electrons in its outermost as well as penultimate shell?
View answer and explanation
Correct option: D
Ca2+\mathrm{C}{\mathrm{a}^{2 + }}
Option D (Ca2+\mathrm{C}{\mathrm{a}^{2 + }}) is correct because it has 8 electrons in both its outermost and penultimate shells.
463 Medium
463 of 592
Application +4 | -1
How many sets of four quantum number are possible for the electrons present in He2−?\mathrm{H}{\mathrm{e}^{2 - }}?
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Correct option: A
4
Option A (4) is correct because He2−\mathrm{H}{\mathrm{e}^{2 - }} has four electrons, and each electron can have a unique set of four quantum numbers according to Pauli's exclusion principle.
464 Easy
464 of 592
Understanding +4 | -1
Heisenberg's uncertainity principle is applicable to
View answer and explanation
Correct option: D
Any moving object
Option D (Any moving object) is correct because Heisenberg's uncertainty principle applies to all moving objects, not just atoms, electrons, or nuclei.
465 Medium
465 of 592
Analyzing +4 | -1
Which of the following has maximum energy
View answer and explanation
Correct option: C
An electron moving with velocity of light
Option C (An electron moving with velocity of light) has maximum energy because the kinetic energy of an electron moving at the speed of light is significantly higher than the energy of a photon with a wavelength of 10 nm or a frequency of 10 Hz.
466 Easy
466 of 592
Remembering +4 | -1
Electrons are filled in energy orbitals, in increasing order of energy." This statement is related to
View answer and explanation
Correct option: D
Aufbau principle
Option D (Aufbau principle) is correct because the Aufbau principle states that electrons fill atomic orbitals in order of increasing energy.
467 Medium
467 of 592
Application +4 | -1
The radius of hydrogen atom in the ground state is 0.53A00.53{A^0}. The radius of Li2+L{i^{2 + }} ion (atomic number =3) in a similar state is
View answer and explanation
Correct option: A
0.176 Å
Option A (0.176 Å) is correct because the radius of Li2+Li^{2+} is calculated using the formula rn=r0×n2Z{r_n} = \frac{{{r_0} \times {n^2}}}{Z}.
468 Hard
468 of 592
Application +4 | -1
Calculate the velocity of an electron having wavelength of 0.15 nm Mass of an electron is 9.109×10−28g9.109 \times {10^{ - 28}}g. (h=6.626×10−27 erg−s)\left( {h = 6.626 \times {{10}^{ - 27}}\,erg - s} \right)
View answer and explanation
Correct option: C
4.84×108cm.s−14.84 \times {10^8}\mathrm{cm}.{\mathrm{s}^{ - 1}}
Option C (4.84×108cm.s−14.84 \times {10^8}\mathrm{cm}.{\mathrm{s}^{ - 1}}) is correct because it is the velocity of the electron calculated using the de Broglie wavelength equation.
469 Easy
469 of 592
Understanding +4 | -1
The outer electronic structure 3s23p53 s^2 3 p^5 is possessed by
View answer and explanation
Correct option: A
Cl{Cl}
Option A (Cl{Cl}) is correct because its electronic configuration ends with 3s23p53s^2 3p^5.
470 Medium
470 of 592
Remembering +4 | -1
The presence of charge particles in the atoms was first confirmed by
View answer and explanation
Correct option: C
Faraday
Option C (Faraday) is correct because Faraday's experiments on electrolysis provided the first concrete evidence of charged particles within atoms.
471 Easy
471 of 592
Understanding +4 | -1
In potassium the order of energy level for 19th electron is:
View answer and explanation
Correct option: B
4s<3d
Option B (4s<3d) is correct because the (n+l) rule dictates that the 4s orbital is filled before the 3d orbital due to its lower energy.
472 Easy
472 of 592
Understanding +4 | -1
For which species, Bohr's theory does not apply:
View answer and explanation
Correct option: B
Be
Option B (Be) is correct because Bohr's theory is only applicable to single-electron systems, and Be has more than one electron.
473 Easy
473 of 592
Remembering +4 | -1
Which is the correct relationship between wavelength and momentum of particles ?
View answer and explanation
Correct option: A
λ=hp\lambda=\frac{h}{p}
Option A (λ=hp\lambda=\frac{h}{p}) is correct because it represents the de Broglie wavelength equation, relating wavelength and momentum.
474 Easy
474 of 592
Application +4 | -1
Chlorophyll present in green leaves of plants absorbs light at 4.620×1014Hz4.620 \times {10^{14}}Hz. Calculate the wavelength of radiation in nm.
View answer and explanation
Correct option: A
649.4
Option A (649.4) is correct because the wavelength is calculated using the formula λ=c/f\lambda = c/f, where c is the speed of light and f is the frequency.
475 Easy
475 of 592
Application +4 | -1
If the K.E of a particle is reduced to half, de Broglie wavelength becomes
View answer and explanation
Correct option: D
2\sqrt 2 times
Option D (2\sqrt 2 times) is correct because de Broglie wavelength is inversely proportional to the square root of kinetic energy.
476 Medium
476 of 592
Application +4 | -1
Time period of a wave is 5×10−3s5 \times {10^{ - 3}}s, what is the frequency?
View answer and explanation
Correct option: B
2×102s−12 \times {10^2}{\mathrm{s}^{ - 1}}
Option B (2×102s−12 \times {10^2}{\mathrm{s}^{ - 1}}) is correct because frequency is the inverse of the time period.
477 Easy
477 of 592
Application +4 | -1
The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value of the first excited state for electron in Bohr orbit of hydrogen is:
View answer and explanation
Correct option: A
– 3.4 eV
Option A (– 3.4 eV) is correct because it represents the energy of the electron in the first excited state (n=2) of the hydrogen atom.
478 Medium
478 of 592
Application +4 | -1
A photon of light of wavelength 6000 Å has energy EE. What will be the wavelength of photon of a light which has energy of photon 4E4 E ?
View answer and explanation
Correct option: A
1500 Å
Option A (1500 Å) is correct because energy and wavelength are inversely proportional, so if the energy is quadrupled, the wavelength is reduced to one-fourth.
479 Medium
479 of 592
Remembering +4 | -1
Select the incorrect option among the following
View answer and explanation
Correct option: A
e/m\mathrm{e} / \mathrm{m} ratio of proton is 1.758820×1011Cg−11.758820 \times 10^{11} \mathrm{C} \mathrm{g}^{-1}
Option A (e/m\mathrm{e} / \mathrm{m} ratio of proton is 1.758820×1011Cg−11.758820 \times 10^{11} \mathrm{C} \mathrm{g}^{-1}) is correct because the given value is the e/m ratio for an electron, not a proton. The e/m ratio for a proton is much smaller.
480 Medium
480 of 592
Understanding +4 | -1
Which of the following statements concerning the quantum numbers are correct?

(i) Angular quantum number determines the threedimensional shape of the orbital.

(ii) The principal quantum number determines the orientation and energy of the orbital.

(iii) Magnetic quantum number determines the size of the orbital.

(iv) Spin quantum number of an electron determines the orientation of the spin of electron relative to the chosen axis.

The correct set of option is
View answer and explanation
Correct option: B
(i) and (iv)
Option B is correct because the angular quantum number determines the shape of the orbital, and the spin quantum number determines the orientation of the electron's spin.
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