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JEE • CHEMISTRY • PRACTICAL CHEMISTRY
Practical chemistry practice · Medium
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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 31-60 of 84 questions
31
Medium
31 of 84
Understanding
+4 | -1
An inorganic salt on reaction with dil. gives colourless gas, which turns lime water milky. The anion present in the salt is
View answer and explanation
Correct option: A
Option A is correct because carbonate ions react with dilute HCl to produce carbon dioxide, which turns lime water milky.
32
Medium
32 of 84
Remembering
+4 | -1
Which sulphide is soluble in
View answer and explanation
Correct option: B
Option B () is correct because Arsenic trisulfide () is soluble in ammonium carbonate due to the formation of soluble complex ions.
33
Medium
33 of 84
Analyzing
+4 | -1
A white powder when strongly heated gives off brown fumes. A solution of this powder gives a yellow precipitate with a solution of When a solution of barium chloride is added to a solution of powder, a white precipitate results. This white powder may be
View answer and explanation
Correct option: D
The correct answer is D () because it decomposes to give brown fumes of , forms a yellow precipitate with KI (AgI), and reacts with barium chloride to form a white precipitate of AgCl.
34
Medium
34 of 84
Understanding
+4 | -1
Which is maximum hydrated:
View answer and explanation
Correct option: D
Option D () is correct because the hydration energy is proportional to the charge density of the cation, and has the highest charge density among the given options.
35
Medium
35 of 84
Remembering
+4 | -1
Starch iodide paper is used to test for the presence of :
A. iodide ion
B. oxidising agent
C. reducing agent
D. iodine
A. iodide ion
B. oxidising agent
C. reducing agent
D. iodine
View answer and explanation
Correct option: D
Oxidising agent
Option D (Oxidising agent) is correct because starch iodide paper is used to detect the presence of oxidizing agents, which oxidize iodide ions to iodine, forming a blue-violet complex with starch.
36
Medium
36 of 84
Remembering
+4 | -1
Of the following sulphides which one is insoluble in dil. acids but soluble in alkalies.
View answer and explanation
Correct option: D
Option D is correct. is insoluble in dilute acids but soluble in alkalies, forming thioantimonate(III) and antimonite(III) ions.
37
Medium
37 of 84
Remembering
+4 | -1
All of the following can be used as primary standards in acid-base titrations EXCEPT:
View answer and explanation
Correct option: D
Sodium hydroxide
Option D (Sodium hydroxide) is correct because NaOH is hygroscopic and absorbs moisture from the air, making it difficult to obtain in a pure, stable form for accurate standardization.
38
Medium
38 of 84
Remembering
+4 | -1
Mark the correct statement:
View answer and explanation
Correct option: D
All the above statement are correct
Option D (All the above statement are correct) is correct because each statement accurately describes the precipitation of basic radicals in qualitative analysis.
39
Medium
39 of 84
Remembering
+4 | -1
A black sulphide is formed by the action of on
View answer and explanation
Correct option: A
Cupric chloride
Option A (Cupric chloride) is correct because cupric chloride reacts with hydrogen sulfide to form copper sulfide, which is a black precipitate.
40
Medium
40 of 84
Understanding
+4 | -1
In (III) group of basic radical analysis, is added before group reagent This is due to
View answer and explanation
Correct option: D
Decrease the degree of ionisation of group reagent
Option D () is correct because alcohols are more acidic than terminal alkynes, benzene, and alkanes due to the electronegativity of oxygen.
41
Medium
41 of 84
Analyzing
+4 | -1
The ion that cannot be precipitated by both and is
View answer and explanation
Correct option: C
Option C () is correct because is precipitated only by , not by .
42
Medium
42 of 84
Remembering
+4 | -1
Which of the following will not produce a precipitate with solution
View answer and explanation
Correct option: A
Option A () is correct because silver fluoride () is soluble in water and does not form a precipitate with solution.
43
Medium
43 of 84
Remembering
+4 | -1
A colourless salt gives violet colour in bunsen flame, it may be
View answer and explanation
Correct option: D
Option D () is correct because potassium ions () impart a violet color to the Bunsen flame.
44
Medium
44 of 84
Remembering
+4 | -1
Which of the following sulphate is insoluble in water?
View answer and explanation
Correct option: C
Option C () is correct because lead sulfate is known to be insoluble in water due to the strong lattice energy.
45
Medium
45 of 84
Analyzing
+4 | -1
Addition of excess of ammonium chloride ammonia buffer to a solution containing nitrates of and will precipitate hydroxides of
View answer and explanation
Correct option: A
The correct answer is A because Al and Bi hydroxides have lower solubility products and will precipitate out in the presence of the ammonium chloride/ammonia buffer, while Mg and Zn hydroxides require higher pH for precipitation.
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46
Medium
46 of 84
Remembering
+4 | -1
Which is not dissolved by dil
View answer and explanation
Correct option: D
Option D () is correct because barium sulfate is insoluble in dilute hydrochloric acid.
47
Medium
47 of 84
Remembering
+4 | -1
Which of the following give white precipitate when is added to its aqueous solution
View answer and explanation
Correct option: A
Option A () is correct because mercurous ions react with HCl to form a white precipitate of mercurous chloride.
48
Medium
48 of 84
Understanding
+4 | -1
A one litre flask is full of brown bromine vapours. The intensity of brown colour of vapour will not decrease appreciably on adding to the flask some.
View answer and explanation
Correct option: A
Pieces of marble
Option A (Pieces of marble) is correct because marble (calcium carbonate) does not react significantly with bromine vapor, thus not decreasing the color intensity.
49
Medium
49 of 84
Remembering
+4 | -1
Sodium sulphite on heating with dilute liberates a gas which
View answer and explanation
Correct option: B
Turns acidified potassium dichromate paper green
Option B (Turns acidified potassium dichromate paper green) is correct because sulfur dioxide gas () released from the reaction reduces dichromate ions () to chromium ions (), causing the color change.
50
Medium
50 of 84
Remembering
+4 | -1
Disodium hydrogen phoshate is used to test:
View answer and explanation
Correct option: A
Option A () is correct because disodium hydrogen phosphate is used in a test to detect the presence of magnesium ions () in solution, forming a white precipitate of magnesium ammonium phosphate.
51
Medium
51 of 84
Analyzing
+4 | -1
Which one among the following pairs of ions cannot be separated by in dilute
View answer and explanation
Correct option: A
Option A is correct because both Bi3+ and Sn4+ precipitate as sulfides in dilute HCl with H2S, making their separation impossible under these conditions.
52
Medium
52 of 84
Remembering
+4 | -1
The reagent and aqueous will precipitate
View answer and explanation
Correct option: B
Option B () is correct because precipitates as in the presence of and aqueous .
53
Medium
53 of 84
Analyzing
+4 | -1
A mixture of chlorides of copper, cadmium, chromium, iron and aluminium was dissolved in water acidified with and hydrogen sulphide gas was passed for sufficient time. It was filtered, boiled and a few drops of nitric acid were added while boiling. To this solution ammonium chloride and solution hydroxide were added and filtered. The filtrate shall give test for
View answer and explanation
Correct option: B
Sodium and aluminium
Option B (Sodium and aluminium) is correct because after precipitation of CuS and CdS by H2S, and boiling with HNO3, Al3+ forms [Al(OH)4]− in the presence of NH4Cl and NH4OH, which remains in the filtrate along with Na+.
54
Medium
54 of 84
Remembering
+4 | -1
When excess of is added to a solution of a white ppt turning grey is obtained. The grey colour is due to the formation of
View answer and explanation
Correct option: D
Option D () is correct because the grey color is due to the formation of metallic mercury when is reduced by excess .
55
Medium
55 of 84
Understanding
+4 | -1
When adding the indicator to the conical flask,
only two or three drops are added because
(i) too much indicator may make it difficult
to see the colour change at the end-point
(ii) the indicator is corrosive, and adding too
much poses a greater risk
(iii) the indicator may be a weak acid or base
and may interfere with the titration result.
Which of the above statements is/are correct?
only two or three drops are added because
(i) too much indicator may make it difficult
to see the colour change at the end-point
(ii) the indicator is corrosive, and adding too
much poses a greater risk
(iii) the indicator may be a weak acid or base
and may interfere with the titration result.
Which of the above statements is/are correct?
View answer and explanation
Correct option: C
(iii) only
Option C ((iii) only) is correct because indicators are weak acids or bases and can interfere with the titration result if too much is added.
56
Medium
56 of 84
Understanding
+4 | -1
Which of the following doesn’t give a ppt. with silver nitrate solution.
View answer and explanation
Correct option: A
Ethyl bromide
Option A (Ethyl bromide) is correct because ethyl bromide does not readily provide free bromide ions () in solution to react with to form a precipitate.
57
Medium
57 of 84
Remembering
+4 | -1
When crystals are heated with conc. the gas evolved is
View answer and explanation
Correct option: C
Option C () is correct because when crystals are heated with conc. chromyl chloride () gas is evolved.
58
Medium
58 of 84
Remembering
+4 | -1
Identify the test which is not a part of qualitative analysis?
View answer and explanation
Correct option: A
Litmus test
Option A (Litmus test) is correct because the litmus test is used to determine the pH of a solution, while the other tests are used for identifying specific substances in qualitative analysis.
59
Medium
59 of 84
Remembering
+4 | -1
To a metal nitrate, when solution is added, a black precipitate is produced at first, on adding excess of orange solution is produced. Identify the metal ion.
View answer and explanation
Correct option: A
Option A () is correct because forms a black precipitate with KI, which dissolves in excess KI to form an orange solution.
60
Medium
60 of 84
Remembering
+4 | -1
Blue borax bead is obtained with
View answer and explanation
Correct option: B
Cobalt
Option B (Cobalt) is correct because cobalt ions produce a blue color in the borax bead test due to the formation of cobalt(II) metaborate.
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