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JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 118 questions

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31 Easy

31 of 118

Understanding +4 | -1

In which of the following species hyper conjugation is possible?

View answer and explanation

Correct option: B

{C_6}{H_5} - C{H_3}

Option B (

{C_6}{H_5} - C{H_3}

) is correct because it has an alpha carbon with respect to the benzene ring, and that alpha carbon has at least one hydrogen atom.

32 Easy

32 of 118

Understanding +4 | -1

Interaction b/w

{\pi}

. bond

\&

lone pair

l-s

on adjacent atoms

View answer and explanation

Correct option: A

Resonance

Option A (Resonance) is correct because resonance involves the interaction between a

\pi

bond and a lone pair on adjacent atoms.

33 Easy

33 of 118

Remembering +4 | -1

Thin layer chromatography is a type of _______

View answer and explanation

Correct option: A

Adsorption chromatography

Option A (Adsorption chromatography) is correct because thin layer chromatography separates substances based on their adsorption onto a solid stationary phase.

34 Easy

34 of 118

Understanding +4 | -1

How to obtain Glacial acetic acid from its solution

View answer and explanation

Correct option: B

Crystallizing, separating and melting acetic acid

Option B (Crystallizing, separating and melting acetic acid) is correct because it's the most effective method to obtain highly pure glacial acetic acid.

35 Easy

35 of 118

Analyzing +4 | -1

Which of the following is strongest nucleophile

View answer and explanation

Correct option: C

C{N^ - }

Option C is correct because CN- is the strongest nucleophile among the given options due to its higher polarizability and negative charge.

36 Easy

36 of 118

Understanding +4 | -1

Given below are two statements:

Statement I: When two or more compounds differ in the position of substituent atom or functional group on the carbon skeleton, they are called functional isomers.

Statement II: Two or more compounds having the same molecular formula but different functional groups are called position isomers.

In the light of the above statements, choose the most appropriate answer from the options given below:

View answer and explanation

Correct option: A

Both Statement I and Statement II are incorrect

The correct answer is A (Both Statement I and Statement II are incorrect) because the definitions of functional and position isomers are swapped in the statements.

37 Easy

37 of 118

Remembering +4 | -1

Terpentine oil can be purified by:

View answer and explanation

Correct option: C

Steam distillation

Option C (Steam distillation) is correct because terpentine oil is steam volatile and can be separated from non-volatile impurities using this method.

38 Easy

38 of 118

Remembering +4 | -1

The property by virtue of which a compound can turn the plane of polarization of light is known as :

View answer and explanation

Correct option: C

Optical activity

Option C (Optical activity) is correct because optical activity is the property of a compound to rotate the plane of polarized light.

39 Easy

39 of 118

Understanding +4 | -1

Ethoxy ethane and methoxy propane are :

View answer and explanation

Correct option: D

Metamers

Option D (Metamers) is correct because ethoxy ethane and methoxy propane have the same molecular formula but different alkyl groups attached to the ether functional group.

40 Easy

40 of 118

Remembering +4 | -1

The correct decreasing order of priority for the functional groups of organic compounds in the IUPAC system of nomenclature is

View answer and explanation

Correct option: A

- \mathrm{COOH},\mathrm{\;} - \mathrm{S}{\mathrm{O}_3}\mathrm{H},\mathrm{\;} - \mathrm{CON}{\mathrm{H}_2}, - \mathrm{CHO}

Option A (

- \mathrm{COOH},\mathrm{\;} - \mathrm{S}{\mathrm{O}_3}\mathrm{H},\mathrm{\;} - \mathrm{CON}{\mathrm{H}_2}, - \mathrm{CHO}

) is correct because it represents the correct decreasing order of priority for the listed functional groups according to IUPAC nomenclature rules.

41 Easy

41 of 118

Application +4 | -1

The IUPAC name of the compound,
is

C{H_3}\,CH = CHC \equiv CH

View answer and explanation

Correct option: B

Pent – 3 – en – 1- yne

Option B (Pent – 3 – en – 1- yne) is correct because it follows the IUPAC naming rules, prioritizing the alkyne functional group and numbering the carbon chain accordingly.

42 Easy

42 of 118

Analyzing +4 | -1

Which among the following has maximum stability

View answer and explanation

Correct option: A

C{H_2} = \mathrm{ }CH\mathrm{ }\mathop C\limits^ \bullet {H_2}

Option A (

C{H_2} = \mathrm{ }CH\mathrm{ }\mathop C\limits^ \bullet {H_2}

) is correct because allylic free radicals are more stable than primary, secondary, or tertiary free radicals due to resonance stabilization.

43 Easy

43 of 118

Remembering +4 | -1

Electrophiles are :

View answer and explanation

Correct option: A

Electron loving species

Option A (Electron loving species) is correct because electrophiles are electron-deficient species that are attracted to electron-rich areas.

44 Easy

44 of 118

Remembering +4 | -1

Rotation of plane polarized light can be measured by :

View answer and explanation

Correct option: C

Polarimeter

The correct answer is C (Polarimeter) because a polarimeter is an instrument used to measure the angle of rotation of plane-polarized light by an optically active substance.

45 Easy

45 of 118

Remembering +4 | -1

The optical isomers, which are not enantiomers, are called

View answer and explanation

Correct option: B

Diastereomer

Option B (Diastereomer) is correct because diastereomers are stereoisomers that are not mirror images of each other.

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46 Easy

46 of 118

Understanding +4 | -1

In the hydrocarbon .

_{C{H_3}\,\,\, - }^C\,_{CH\,\, = }^5\,_{CH\,\,\, - }^4\,_{C{H_2} - }^3\,_{C\,\,\, \equiv \,}^2\,_{CH}^1

the state of hybridisation of 1, 3 and 5 are in the following sequence

View answer and explanation

Correct option: B

SP,S{P^3},S{P^2}

Option B (

SP,S{P^3},S{P^2}

) is correct because the hybridizations of carbons 1, 3, and 5 are SP, SP3, and SP2 respectively, based on the number of sigma bonds.

47 Easy

47 of 118

Analyzing +4 | -1

Which of the following is a pair of functional isomers?

View answer and explanation

Correct option: B

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{C}{\mathrm{O}_2}\mathrm{H},\mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{O}_2}\mathrm{C}{\mathrm{H}_3}

Option C is correct because carboxylic acids and esters with the same molecular formula are functional isomers, as seen in the pair

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{C}{\mathrm{O}_2}\mathrm{H}

and

\mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{O}_2}\mathrm{C}{\mathrm{H}_3}

48 Easy

48 of 118

Remembering +4 | -1

The isomers observed in alkanes is

View answer and explanation

Correct option: B

Chain isomerism

Option B (Chain isomerism) is correct because alkanes can exhibit chain isomerism due to different arrangements of carbon atoms in the carbon chain.

49 Easy

49 of 118

Understanding +4 | -1

Which of the following species is not electrophilic in nature?

View answer and explanation

Correct option: C

{H_3}\mathop O\limits^ \oplus

The correct answer is C (

{H_3}\mathop O\limits^ \oplus

) because hydronium ion has a lone pair of electrons and a positive charge, making it a nucleophile rather than an electrophile.

50 Easy

50 of 118

Understanding +4 | -1

Lactic acid in which a methyl group, a hydroxyl group, a carboxylic acid group and a hydrogen atom are attached to a central carbon atom shows optical isomerism due to the molecular geometry at the :

View answer and explanation

Correct option: C

Central carbon atom

Option C (Central carbon atom) is correct because the central carbon atom is chiral, meaning it is bonded to four different groups, leading to optical isomerism.

51 Easy

51 of 118

Understanding +4 | -1

Chloroacetic acid is a stronger acid than acetic acid. This can be explained using

View answer and explanation

Correct option: B

- I

effect

Option B (-I effect) is correct because the chlorine atom in chloroacetic acid has a -I effect, which withdraws electron density and stabilizes the conjugate base, making the acid stronger.

52 Easy

52 of 118

Remembering +4 | -1

In the Grignard reaction, which metal forms an organometallic bond?

View answer and explanation

Correct option: C

Magnesium

Option C (Magnesium) is correct because in the Grignard reaction, magnesium metal reacts with an alkyl halide to form an organometallic bond, creating the Grignard reagent.

53 Easy

53 of 118

Remembering +4 | -1

The group named as benzal possesses ……nature.

View answer and explanation

Correct option: B

Bivalent

Option B (Bivalent) is correct because the benzal group,

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{CH}

, has two valencies available for bonding.

54 Easy

54 of 118

Understanding +4 | -1

In which of the following species the central carbon atom is negatively charged?

View answer and explanation

Correct option: B

Carbanion

Option B (Carbanion) is correct because a carbanion is defined as a species where a carbon atom has a negative charge.

55 Easy

55 of 118

Understanding +4 | -1

Ethers are isomeric with

View answer and explanation

Correct option: D

Alcohols

The correct answer is D. Ethers and alcohols have the same general formula (

C_nH_{2n+2}O

) and can be isomers.

56 Easy

56 of 118

Analyzing +4 | -1

Most stable carbanion

View answer and explanation

Correct option: A

\overline C {H_2} - C{H_2} - N{O_2}

Option A (

\overline C {H_2} - C{H_2} - N{O_2}

) is correct because the nitro group (-NO2) is a strong electron-withdrawing group, which stabilizes the carbanion through inductive effect.

57 Easy

57 of 118

Remembering +4 | -1

Lassaigne's test is not used for the detection of the element_______in the organic compound

View answer and explanation

Correct option: D

\mathrm{O}

Option D (O) is correct because Lassaigne's test is specifically designed to detect the presence of nitrogen, sulfur, and halogens (chlorine, bromine, iodine), but not oxygen, in organic compounds.

58 Easy

58 of 118

Remembering +4 | -1

For esters, prefix used in IUPAC nomenclature is

View answer and explanation

Correct option: D

Alkoxycarbonyl

Option D (Alkoxycarbonyl) is correct because alkoxycarbonyl is the prefix used in IUPAC nomenclature for esters when they are substituents.

59 Easy

59 of 118

Analyzing +4 | -1

The correct order of increasing acid strength of the compounds (A)

\mathrm{CH}_3 \mathrm{COOH},

(B)

\mathrm{MeOCH}_2 \mathrm{C O O H},

(C)

\mathrm{CF}_3 \mathrm{COOH},

(D)

\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH}

View answer and explanation

Correct option: C

<

<

<

Option C is correct because the electron-withdrawing groups increase acidity, and electron-donating groups decrease acidity, leading to the order D < A < B < C.

60 Easy

60 of 118

Analyzing +4 | -1

Strongest acid among the following

View answer and explanation

Correct option: C

C{F_3}COOH

Option C (

C{F_3}COOH

) is correct because the presence of three highly electronegative fluorine atoms increases the acidity due to their strong -I effect.

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Review ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES in your textbook or class notes, then use this set to check your understanding.

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Organic chemistry-some basic principles and techniques practice · Easy

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