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JEE • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 118 questions
31 Medium
31 of 118
Analyzing +4 | -1
An organic compound C5H11X{\mathrm{C}_5}{\mathrm{H}_{11}}X on dehydrohalogenation gives pentene-2 only. What is halide?
View answer and explanation
Correct option: A
CH3CH2CHXCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH}X\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}
Option A (CH3CH2CHXCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH}X\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}) is correct because 3-halopentane will only give pent-2-ene upon dehydrohalogenation due to the symmetrical nature of the molecule.
32 Medium
32 of 118
Remembering +4 | -1
Which fraction of coal-tar is rich in arene?
View answer and explanation
Correct option: A
Light oil
Option A (Light oil) is correct because light oil from coal tar distillation is rich in arenes like benzene, toluene, and xylene.
33 Medium
33 of 118
Understanding +4 | -1
C – H bond energy is about101 kcal/mol for methane, ethane and other alkanes but is only77 kcal/mol for C – H bond of CH3\mathrm{C}{\mathrm{H}_3} in toluene. This is because
View answer and explanation
Correct option: C
Of resonance among the structures of benzyl radical in toluene
Option C is correct because the benzyl radical formed after removing a hydrogen atom from toluene is stabilized by resonance, which lowers the C-H bond energy.
34 Medium
34 of 118
Remembering +4 | -1
The molecule benzene can undergo a chemical reaction known as nitration.The carry out this
reaction there is need for the presence of two concentrated acids. Nitric acid is one, but
what is the other?
View answer and explanation
Correct option: B
Sulphuric acid
Option B (Sulphuric acid) is correct because the nitration of benzene requires a mixture of concentrated nitric acid and concentrated sulfuric acid, where sulfuric acid acts as a catalyst to generate the nitronium ion (NO2+NO_2^+).
35 Medium
35 of 118
Analyzing +4 | -1
Assertion :-Ethyne and its derivatives give white precipate with ammonical silver nitrate solution.

Reason :- Alkynes gives white ppt with ammonical silver nitrate solution due to nucleophilic substitution reaction.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
The correct answer is D (If both Assertion & Reason are false) because alkynes react with ammoniacal silver nitrate via an acid-base reaction, not nucleophilic substitution, and only terminal alkynes give a precipitate.
36 Medium
36 of 118
Analyzing +4 | -1
Select the incorrect statement regarding A
CH3−C≡CH+H2OAC{H_3} - C \equiv CH + {H_2}OA
View answer and explanation
Correct option: D
Reduces Tollen’s reagent
The correct answer is D (Reduces Tollen’s reagent) because acetone does not have an aldehyde group and cannot reduce Tollen's reagent.
37 Medium
37 of 118
Understanding +4 | -1
All alkyl halides undergo reduction process except
View answer and explanation
Correct option: A
fluorides
Option A (fluorides) is correct because alkyl fluorides are generally unreactive in reduction reactions due to the strong carbon-fluorine bond.
38 Medium
38 of 118
Remembering +4 | -1
Number of conformations possible in cyclohexane will be
View answer and explanation
Correct option: D
Infinite
Option D (Infinite) is correct because cyclohexane can undergo continuous conformational changes due to rotation around its C-C single bonds, leading to an infinite number of possible conformations.
39 Medium
39 of 118
Understanding +4 | -1
The alkane with highest boiling point is
View answer and explanation
Correct option: D
n - pentane
Option D (n - pentane) is correct because boiling point increases with increasing molecular weight and straight-chain structure.
40 Medium
40 of 118
Application +4 | -1
Addition of Br2\mathrm{B}{\mathrm{r}_2} on cis−butene−2cis -{\kern 1pt} {\kern 1pt} \mathrm{butene} - 2 gives :
View answer and explanation
Correct option: A
A racemic mixture of 2,3-dibromobutane
Option A (A racemic mixture of 2,3-dibromobutane) is correct because the addition of Br2 to cis-butene-2 results in anti-addition, leading to a racemic mixture.
41 Medium
41 of 118
Understanding +4 | -1
Select the organic compounds aliphatic in nature but burn with smoky flame :
View answer and explanation
Correct option: D
Both (a) and (b)
Option D (Both (a) and (b)) is correct because both carbon tetrachloride (CCl4\mathrm{CCl_4}) and chloroform (CHCl3\mathrm{CHCl_3}) are aliphatic compounds that burn with a smoky flame due to incomplete combustion.
42 Medium
42 of 118
Analyzing +4 | -1
The compound that will react most readily with gaseous bromine has the formula:
View answer and explanation
Correct option: D
C4H10{C_4}{H_{10}}
Option A (C2H4) is correct because alkenes react most readily with bromine due to the presence of a pi bond, which is more reactive than sigma bonds in alkanes.
43 Medium
43 of 118
Understanding +4 | -1
Acetylenic hydrogens are acidic because
View answer and explanation
Correct option: A
Sigma electron density of C−H\mathrm{C}-\mathrm{H} bond in acetylene is nearer to carbon, which has 50%s50 \% s-character
Option A is correct because the sigma electron density of the C-H bond in acetylene is closer to the carbon, which has 50% s-character, making the hydrogen relatively acidic.
44 Medium
44 of 118
Analyzing +4 | -1
Compound 'X' on treatment with O3\mathrm{O}_3 followed by Zn/H2O\mathrm{Zn} / \mathrm{H}_2 \mathrm{O} gives methanal and cyclohexyl methanal. The compound 'X' is:
View answer and explanation
Correct option: D
3-cyclohexyl-1-propene
Option D (3-cyclohexyl-1-propene) is correct because its ozonolysis followed by reductive workup yields methanal and cyclohexyl methanal.
45 Medium
45 of 118
Analyzing +4 | -1
The olefin which on ozonolysis gives CH3CH2CHO  and  CH3CHO\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CHO}\;and\;\mathrm{C}{\mathrm{H}_3}\mathrm{CHO} is:
View answer and explanation
Correct option: D
2-pentene
Option D (2-pentene) is correct because ozonolysis of 2-pentene yields propanal (CH3CH2CHO) and acetaldehyde (CH3CHO).
46 Medium
46 of 118
Analyzing +4 | -1
Assertion :- In the following reaction CH2 = CH2+NaNH2→CH2=C−HNa++NH3{\text{C}}{{\text{H}}_2}{\text{ = C}}{{\text{H}}_{\text{2}}} + {\text{NaN}}{{\text{H}}_{\text{2}}} \to {\text{C}}{{\text{H}}_{\text{2}}} = \mathop {\text{C}}\limits^ - {\text{H}}\mathop {{\text{Na}}}\limits^ + + {\text{N}}{{\text{H}}_{\text{3}}}
reaction is always in forward direction
Reason :-Ethene is stronger acid than ammonia.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because ethene is a weaker acid than ammonia, and the reaction is not always in the forward direction.
47 Medium
47 of 118
Understanding +4 | -1
Butyne-2 contains:
View answer and explanation
Correct option: D
Both sps p and sp3s p^3 hybridised carbon atoms
Option D (Both sps p and sp3s p^3 hybridised carbon atoms) is correct because Butyne-2 has two spsp hybridized carbons (the ones in the triple bond) and two sp3sp^3 hybridized carbons (the methyl groups).
48 Medium
48 of 118
Understanding +4 | -1
Which of the following compounds will show cis-trans isomerism?
View answer and explanation
Correct option: C
C6H5CH=CH−CH3\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3
Option C (C6H5CH=CH−CH3\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3) is correct because for cis-trans isomerism to occur, each carbon of the double bond must have two different groups attached to it.
49 Medium
49 of 118
Analyzing +4 | -1
Which of the following statement is incorrect regarding nitration of aromatic compounds?

I. The rate of nitration of benzene decreases at 323-333 K.

II. The rate of nitration of toluene is greater than that of benzene.

III. The rate of nitration of chlorobenzene is greater than that of benzene.

IV. Nitration is an electrophilic substitution reaction. Choose the incorrect statement.
View answer and explanation
Correct option: B
Both I and III
Option B (Both I and III) is correct because the rate of nitration of benzene increases with temperature, and the rate of nitration of chlorobenzene is lower than that of benzene due to the -I effect of chlorine.
50 Medium
50 of 118
Remembering +4 | -1
2-Hexyne can be converted into trans-2-hexene
by the action of:
View answer and explanation
Correct option: B
Na in liq. NH3\mathrm{NH}_3
Option B (Na in liq. NH3\mathrm{NH}_3) is correct because sodium in liquid ammonia reduces alkynes to trans-alkenes.
51 Medium
51 of 118
Understanding +4 | -1
The alkane that gives only one mono-chloro product on chlorination with Cl2C{l_2} in presence of diffused sunlight is
View answer and explanation
Correct option: B
Ethane
Option B (Ethane) is correct because ethane (CH3−CH3C{H_3} - C{H_3}) has only one type of hydrogen atom, leading to only one monochloro product upon chlorination.
52 Medium
52 of 118
Understanding +4 | -1
Pure methane can be produced by
View answer and explanation
Correct option: C
Soda lime decarboxylation
Option C (Soda lime decarboxylation) is correct because it's the only method listed that directly produces methane from sodium acetate.
53 Medium
53 of 118
Understanding +4 | -1
Statement I : The boiling point of alkanes increases steadily with increase in size of chain
Statement II : Greater the length of the chain, greater is the surface area and hence, larger the vander Waal's attractive forces
View answer and explanation
Correct option: C
Both statements are true
Option C is correct because both statements are true regarding the boiling point of alkanes and the influence of chain length on van der Waals forces.
54 Medium
54 of 118
Remembering +4 | -1
CH≡CH→Cu2Cl2NH4Clproduct\mathrm{CH} \equiv \mathrm{CH} \xrightarrow[\mathrm{Cu}_2 \mathrm{Cl}_2]{\mathrm{NH}_4 \mathrm{Cl}} \text{product}

Product is:
View answer and explanation
Correct option: A
Cu−C≡C−Cu\mathrm{Cu}-\mathrm{C} \equiv \mathrm{C}-\mathrm{Cu}
Option A (Cu−C≡C−Cu\mathrm{Cu}-\mathrm{C} \equiv \mathrm{C}-\mathrm{Cu}) is correct because the reaction of acetylene with Cu2Cl2\mathrm{Cu}_2 \mathrm{Cl}_2 in NH4Cl\mathrm{NH}_4 \mathrm{Cl} forms copper acetylide.
55 Medium
55 of 118
Analyzing +4 | -1
The alkyne which gives pyruvic acid (CH3COCOOH)\left( {\mathrm{C}{\mathrm{H}_3}\mathrm{COCOOH}} \right) on oxidation with alk. KMnO4\mathrm{KMn}{\mathrm{O}_4} is:
View answer and explanation
Correct option: B
CH3C≡CH\mathrm{C}{\mathrm{H}_3}\mathrm{C} \equiv \mathrm{CH}
Option B (CH₃C≡CH) is correct because terminal alkynes with a methyl group adjacent to the triple bond yield pyruvic acid upon oxidation with alkaline KMnO₄.
56 Medium
56 of 118
Analyzing +4 | -1
Assertion (A): In the electrophilic substitution of aryl halides, the incoming electrophile gets attached to the meta position.

Reason (R): Aryl halides are moderately deactivating.
View answer and explanation
Correct option: D
R is correct; A is incorrect
Option D is correct because aryl halides are ortho/para directing due to resonance, not meta directing, and the reason that aryl halides are moderately deactivating is correct.
57 Medium
57 of 118
Analyzing +4 | -1
(A): Ethene is more reactive than ethane
(R): C=C\mathrm{C}=\mathrm{C} bond energy in ethene is more than that in ethane
View answer and explanation
Correct option: B
Both A and R are correct, R is not the correct explanation of A
Option B (Both A and R are correct, R is not the correct explanation of A) is correct because ethene is indeed more reactive than ethane, but the reason is due to the presence of the pi bond, not the overall bond energy.
58 Medium
58 of 118
Understanding +4 | -1
Propyne does not react with
View answer and explanation
Correct option: D
NaOH
Option D (NaOH) is correct because propyne, being a weak acid, does not react with a strong base like NaOH as the reverse reaction is favored.
59 Medium
59 of 118
Understanding +4 | -1
CH2=CH2+Br2⟶CCl4\mathrm{CH}_2=\mathrm{CH}_2+\mathrm{Br}_2 \stackrel{\mathrm{CCl}_4}{\longrightarrow} Product (A). Product A is:
View answer and explanation
Correct option: A
1, 2-Dibromoethane
Option A is correct because the addition of bromine to ethene results in the formation of 1,2-dibromoethane through a vicinal dibromination reaction.
60 Medium
60 of 118
Application +4 | -1
Amount of Br2\mathrm{B}{\mathrm{r}_2} required to react with 5 g pentene to form monobromo derivative is:
View answer and explanation
Correct option: B
11.43  g11.43\mathrm{ }\;g
Option B (11.43  g11.43\mathrm{ }\;g) is correct because it is calculated based on the stoichiometry of the reaction between pentene and bromine.
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