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JEE • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-138 of 138 questions
121 Easy
121 of 138
Application +4 | -1
When HCI gas is passed through propene in the presence of benzoyl peroxide, it gives:
View answer and explanation
Correct option: B
2-chloropropane
Option B (2-chloropropane) is correct because in the absence of peroxide, HCl addition to propene follows Markovnikov's rule, where the Cl adds to the more substituted carbon.
122 Easy
122 of 138
Understanding +4 | -1
Which of the following have the least hindered rotation about carbon-carbon bond
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Correct option: A
Ethane
Option A (Ethane) is correct because it has a single bond between the carbon atoms, allowing for free rotation.
123 Easy
123 of 138
Remembering +4 | -1
Which of the following statements is incorrect?
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Correct option: C
It has unpleasant garlic odour
Option C (It has unpleasant garlic odour) is correct because pure acetylene has an ethereal odor, not a garlic odor.
124 Easy
124 of 138
Remembering +4 | -1
In benzene, C−CC - C bond length is 1.39 Ao\mathop \mathrm{A}\limits^\mathrm{o}; the C−HC - H bond length is:
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Correct option: B
1.08
Option B (1.08) is correct because the C-H bond length in benzene is approximately 1.08 Ao\mathop \mathrm{A}\limits^\mathrm{o}.
125 Easy
125 of 138
Remembering +4 | -1
Consider the following reaction, 2CH3−Cl+Na→dry etherCH3−CH3+2NaCl2C{H_3} - Cl + Na\xrightarrow{{\mathrm{dry}\,\mathrm{ether}}}C{H_3} - C{H_3} + 2NaCl
The above reaction is called
View answer and explanation
Correct option: B
Wurtz reaction
Option B (Wurtz reaction) is correct because the reaction of alkyl halides with sodium in dry ether to form alkanes with double the number of carbon atoms is known as the Wurtz reaction.
126 Easy
126 of 138
Understanding +4 | -1
Which of the given species cannot be used in Friedel Craft’s reactions?
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Correct option: D
NaCl{NaCl}
Option D (NaCl{NaCl}) is correct because it is not a Lewis acid and cannot generate the electrophile required for Friedel-Crafts reactions.
127 Easy
127 of 138
Remembering +4 | -1
Out of the following fractions of petroleum the one having the lowest boiling point is:
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Correct option: C
Gasoline
Option C (Gasoline) is correct because gasoline has the lowest boiling point among the given fractions of petroleum.
128 Easy
128 of 138
Application +4 | -1
A saturated hydrocarbon is shown by CnH10{\mathrm{C}_n}{\mathrm{H}_{10}} The value of carbon atom ′n′'n' in this compound is:
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Correct option: B
4
Option B (4) is correct because the formula for a saturated hydrocarbon (alkane) is CnH2n+2{\mathrm{C}_n}{\mathrm{H}_{2n + 2}}, and solving 2n+2=102n + 2 = 10 gives n=4n = 4.
129 Easy
129 of 138
Analyzing +4 | -1
Which one of the following will give only one mono chloro derivative upon halogenation
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Correct option: B
neo pentane
Option B is correct because neopentane has only one type of hydrogen atom (all are primary), leading to only one possible monochloro derivative upon halogenation.
130 Easy
130 of 138
Understanding +4 | -1
The C  −C\mathrm{C\;} - \mathrm{C} bond order in benzene is close to:
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Correct option: A
1.5
Option A (1.5) is correct because the delocalization of pi electrons in benzene results in a bond order between a single and double bond.
131 Easy
131 of 138
Understanding +4 | -1
Which type of overlapping results in the formation of σ\sigma and π\pi-bonds, respectively?
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Correct option: C
Head on and sideways
Option C (Head on and sideways) is correct because sigma bonds are formed by head-on overlapping of atomic orbitals, while pi bonds are formed by sideways or lateral overlapping.
132 Easy
132 of 138
Understanding +4 | -1
Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO3\mathrm{HN}{\mathrm{O}_3} and conc.H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}. In the mixture, nitric acid acts as a/an:
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Correct option: D
Base
Option D (Base) is correct because in the nitration of benzene, nitric acid accepts a proton from sulfuric acid, acting as a base to generate the nitronium ion.
133 Easy
133 of 138
Understanding +4 | -1
Which statement is correct?
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Correct option: D
All are correct
Option D (All are correct) is correct because all the statements about alkanes are factually accurate.
134 Easy
134 of 138
Application +4 | -1
Which is the most suitable reagent among the following distinguish compound (III) from rest of the compounds
(I) CH3−C≡C=CH3C{H_3} - C \equiv C = C{H_3} (II) CH3−CH2−CH2−CH3C{H_3} - C{H_2} - C{H_2} - C{H_3}
(III) CH3−CH2−C≡CHC{H_3} - C{H_2} - C \equiv CH (IV) CH3−CH=CH2C{H_3} - CH = C{H_2}
View answer and explanation
Correct option: D
Ammonical Silver nitrate
Option D (Ammonical Silver nitrate) is correct because it reacts specifically with terminal alkynes due to the presence of acidic hydrogen atoms.
135 Easy
135 of 138
Understanding +4 | -1
n-butane and isobutene, which have same number of hydrogen and carbon atoms in their molecules, boil at different temperatures because:
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Correct option: D
Their atoms are not having the same carbon chain
Option D is correct because n-butane and isobutane have different boiling points due to differences in their molecular structure and carbon chain arrangement, affecting intermolecular forces.
136 Easy
136 of 138
Understanding +4 | -1
The C  −C\mathrm{C\;} - \mathrm{C} bond order in benzene is close to:
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Correct option: A
1.5
Option B (0) is correct because Sc3+ has no unpaired electrons, resulting in a zero magnetic moment.
137 Easy
137 of 138
Understanding +4 | -1
Which of the following statements is true for ethane, ethene and acetylene?
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Correct option: B
Acetylene is the strongest acid and has the shortest C−H\mathrm{C} - \mathrm{H} bond distance
Option B is correct because acetylene is the most acidic and has the shortest C-H bond distance due to the sp hybridization of the carbon atom.
138 Easy
138 of 138
Understanding +4 | -1
Friedel-Craft’s reaction does not occur in case of:
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Correct option: D
pyridine
Option D (pyridine) is correct because pyridine is a deactivated aromatic ring due to the nitrogen atom, and it forms a complex with the Lewis acid catalyst (AlCl3\mathrm{AlCl_3}), preventing Friedel-Crafts reaction.
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