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JEE • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 269 questions

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61 Easy
61 of 269
Application +4 | -1
If an alkane has number of carbon atoms equal to n,n, then the
number of moles of oxygen required for its complete
combustion is:
View answer and explanation
Correct option: A
3n+12\frac{3n+1}{2}
Option A (3n+12\frac{3n+1}{2}) is correct because it represents the stoichiometric coefficient of oxygen in the balanced combustion equation for an alkane.
62 Medium
62 of 269
Understanding +4 | -1
Which of the following groups deactivates the benzene ring towards electrophilic substitution reaction?
View answer and explanation
Correct option: B
−NO2-{NO}_2
Option B (−NO2-{NO}_2) is correct because the nitro group is an electron-withdrawing group that deactivates the benzene ring towards electrophilic substitution due to its -M effect.
63 Easy
63 of 269
Remembering +4 | -1
Baeyer’s reagent is used in the laboratory for:
View answer and explanation
Correct option: A
Detection of double bonds
Option A (Detection of double bonds) is correct because Baeyer's reagent (cold, dilute alkaline KMnO4) oxidizes alkenes, causing the purple color to disappear.
64 Medium
64 of 269
Application +4 | -1
CH3−C≡CH→HgSO4H2SO4A→IsomerisationCH3−C∣∣O−CH3C{H_3} - C \equiv CH\xrightarrow[{HgS{O_4}}]{{{H_2}S{O_4}}}A\xrightarrow[{}]{{{\text{Isomerisation}}}}C{H_3} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} {||} \\ O \end{array}} - C{H_3}
Structure of AA and type of isomerism in the above reactions respectively.
View answer and explanation
Correct option: C
Prop-1-en-2-ol, Tautomerism
Option C (Prop-1-en-2-ol, Tautomerism) is correct because the intermediate A is prop-1-en-2-ol, which then undergoes tautomerism to form acetone.
65 Easy
65 of 269
Remembering +4 | -1
The synthetic gas is:
View answer and explanation
Correct option: C
CO+3H2\mathrm{CO} + 3{\mathrm{H}_2}
The correct answer is C (CO+3H2\mathrm{CO} + 3{\mathrm{H}_2}) because synthetic gas, also known as syngas, is a mixture primarily composed of carbon monoxide (CO) and hydrogen (H2H_2). The ratio can vary, but the option closest to the typical composition is CO + 3H2.
66 Medium
66 of 269
Remembering +4 | -1
Conformation of ethane in which hydrogen atoms attached to two carbon atoms are closest to each other is known as
View answer and explanation
Correct option: A
eclipsed
The correct answer is A (eclipsed) because in the eclipsed conformation, the hydrogen atoms on adjacent carbon atoms are as close as possible.
67 Medium
67 of 269
Understanding +4 | -1
Bromination of toluene gives
View answer and explanation
Correct option: C
Mixture of o\mathrm{o} and p\mathrm{p} substituted product
Option C is correct because the methyl group (−CH3\mathrm{-CH}_3) in toluene is an ortho- and para-directing group, leading to a mixture of ortho- and para-substituted products.
68 Medium
68 of 269
Analyzing +4 | -1
An organic compound C5H11X{\mathrm{C}_5}{\mathrm{H}_{11}}X on dehydrohalogenation gives pentene-2 only. What is halide?
View answer and explanation
Correct option: A
CH3CH2CHXCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH}X\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}
Option A (CH3CH2CHXCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH}X\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}) is correct because 3-halopentane will only give pent-2-ene upon dehydrohalogenation due to the symmetrical nature of the molecule.
69 Easy
69 of 269
Remembering +4 | -1
Paraffin wax is:
View answer and explanation
Correct option: D
Saturated hydrocarbon
Option D (Saturated hydrocarbon) is correct because paraffin wax consists of alkanes, which are saturated hydrocarbons.
70 Medium
70 of 269
Remembering +4 | -1
Which fraction of coal-tar is rich in arene?
View answer and explanation
Correct option: A
Light oil
Option A (Light oil) is correct because light oil from coal tar distillation is rich in arenes like benzene, toluene, and xylene.
71 Medium
71 of 269
Understanding +4 | -1
C – H bond energy is about101 kcal/mol for methane, ethane and other alkanes but is only77 kcal/mol for C – H bond of CH3\mathrm{C}{\mathrm{H}_3} in toluene. This is because
View answer and explanation
Correct option: C
Of resonance among the structures of benzyl radical in toluene
Option C is correct because the benzyl radical formed after removing a hydrogen atom from toluene is stabilized by resonance, which lowers the C-H bond energy.
72 Easy
72 of 269
Remembering +4 | -1
The general formula of a cycloalkane is
View answer and explanation
Correct option: B
CnH2n{\mathrm{C}_n}{\mathrm{H}_{2n}}
Option B (CnH2n{\mathrm{C}_n}{\mathrm{H}_{2n}}) is correct because it represents the general formula for cycloalkanes, which have a ring structure and thus two fewer hydrogen atoms than alkanes.
73 Medium
73 of 269
Remembering +4 | -1
The molecule benzene can undergo a chemical reaction known as nitration.The carry out this
reaction there is need for the presence of two concentrated acids. Nitric acid is one, but
what is the other?
View answer and explanation
Correct option: B
Sulphuric acid
Option B (Sulphuric acid) is correct because the nitration of benzene requires a mixture of concentrated nitric acid and concentrated sulfuric acid, where sulfuric acid acts as a catalyst to generate the nitronium ion (NO2+NO_2^+).
74 Medium
74 of 269
Analyzing +4 | -1
Assertion :-Ethyne and its derivatives give white precipate with ammonical silver nitrate solution.

Reason :- Alkynes gives white ppt with ammonical silver nitrate solution due to nucleophilic substitution reaction.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
The correct answer is D (If both Assertion & Reason are false) because alkynes react with ammoniacal silver nitrate via an acid-base reaction, not nucleophilic substitution, and only terminal alkynes give a precipitate.
75 Medium
75 of 269
Analyzing +4 | -1
Select the incorrect statement regarding A
CH3−C≡CH+H2OAC{H_3} - C \equiv CH + {H_2}OA
View answer and explanation
Correct option: D
Reduces Tollen’s reagent
The correct answer is D (Reduces Tollen’s reagent) because acetone does not have an aldehyde group and cannot reduce Tollen's reagent.
76 Easy
76 of 269
Understanding +4 | -1
In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei.
View answer and explanation
Correct option: C
6
Option C (6) is correct because in benzene, each π-electron is delocalized over all six carbon nuclei.
77 Easy
77 of 269
Remembering +4 | -1
The energy of π\pi -bond in kcal is about :
View answer and explanation
Correct option: B
50
Option B (50) is correct because the energy of a π\pi-bond is approximately 50 kcal.
78 Easy
78 of 269
Understanding +4 | -1
The test for unsaturation is confirmed by the decolourisation of which of the following?
View answer and explanation
Correct option: C
Bromine water
The correct answer is C (Bromine water) because bromine water is used to test for unsaturation. The disappearance of the bromine color indicates the presence of a double or triple bond.
79 Medium
79 of 269
Understanding +4 | -1
All alkyl halides undergo reduction process except
View answer and explanation
Correct option: A
fluorides
Option A (fluorides) is correct because alkyl fluorides are generally unreactive in reduction reactions due to the strong carbon-fluorine bond.
80 Easy
80 of 269
Remembering +4 | -1
The treatment of calcium carbides with water gives
View answer and explanation
Correct option: B
acetylene
Option B (acetylene) is correct because calcium carbide reacts with water to produce acetylene (C2H2C_2H_2) and calcium hydroxide.
81 Easy
81 of 269
Remembering +4 | -1
o,p−o,p -directing groups are generally:
View answer and explanation
Correct option: A
Activating groups
Option A (Activating groups) is correct because o,p−o,p-directing groups are generally activating groups.
82 Medium
82 of 269
Remembering +4 | -1
Number of conformations possible in cyclohexane will be
View answer and explanation
Correct option: D
Infinite
Option D (Infinite) is correct because cyclohexane can undergo continuous conformational changes due to rotation around its C-C single bonds, leading to an infinite number of possible conformations.
83 Easy
83 of 269
Application +4 | -1
In a mixture of n-hexadecane and α-methylnaphthalene the percentage of the latter is 10.The value of cetane number is:
View answer and explanation
Correct option: B
90
Option B (90) is correct because the cetane number represents the percentage of n-hexadecane in the mixture, which is 100 - 10 = 90.
84 Easy
84 of 269
Understanding +4 | -1
The correct boiling point order for corresponding hydrocarbons is:
View answer and explanation
Correct option: C
Alkyne>alkene>alkane
Option C (Alkyne>alkene>alkane) is correct because alkynes have stronger intermolecular forces due to their linear structure and greater polarizability compared to alkenes and alkanes.
85 Easy
85 of 269
Remembering +4 | -1
Alkanes mainly show reactions involving:
View answer and explanation
Correct option: D
Heat/photochemical substitution
Option D (Heat/photochemical substitution) is correct because alkanes undergo substitution reactions in the presence of heat or light due to their non-polar nature.
86 Easy
86 of 269
Application +4 | -1
A saturated hydrocarbon is shown by CnH10{\mathrm{C}_n}{\mathrm{H}_{10}} The value of carbon atom ′n′'n' in this compound is:
View answer and explanation
Correct option: B
4
Option B (4) is correct because the formula for a saturated hydrocarbon (alkane) is CnH2n+2{\mathrm{C}_n}{\mathrm{H}_{2n + 2}}, and solving 2n+2=102n + 2 = 10 gives n=4n = 4.
87 Medium
87 of 269
Understanding +4 | -1
The alkane with highest boiling point is
View answer and explanation
Correct option: D
n - pentane
Option D (n - pentane) is correct because boiling point increases with increasing molecular weight and straight-chain structure.
88 Easy
88 of 269
Understanding +4 | -1
The C  −C\mathrm{C\;} - \mathrm{C} bond order in benzene is close to:
View answer and explanation
Correct option: A
1.5
Option B (0) is correct because Sc3+ has no unpaired electrons, resulting in a zero magnetic moment.
89 Medium
89 of 269
Application +4 | -1
Addition of Br2\mathrm{B}{\mathrm{r}_2} on cis−butene−2cis -{\kern 1pt} {\kern 1pt} \mathrm{butene} - 2 gives :
View answer and explanation
Correct option: A
A racemic mixture of 2,3-dibromobutane
Option A (A racemic mixture of 2,3-dibromobutane) is correct because the addition of Br2 to cis-butene-2 results in anti-addition, leading to a racemic mixture.
90 Easy
90 of 269
Remembering +4 | -1
The disappearance of the characteristic purple colour of KMnO4{KMnO}_4 in its reaction with an alkene is the test for unsaturation. It is known as
View answer and explanation
Correct option: B
Baeyer test
Option B (Baeyer test) is correct because the disappearance of the purple color of KMnO4 in its reaction with an alkene is known as the Baeyer test, which is used to test for unsaturation.
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