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JEE • CHEMISTRY • Equilibrium

Equilibrium practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 161 questions
31 Easy
31 of 161
Understanding +4 | -1
Which of the following pairs constitutes a buffer?
View answer and explanation
Correct option: D
HNO2{HNO}_2 and NaNO2{NaNO}_2
Option D (HNO2{HNO}_2 and NaNO2{NaNO}_2) is correct because it consists of a weak acid (HNO2{HNO}_2) and its conjugate base (NaNO2{NaNO}_2).
32 Easy
32 of 161
Understanding +4 | -1
When sodium acetate is added to an aqueous solution of acetic acid :
View answer and explanation
Correct option: B
The pH{pH} of the solution increases
Option B (The pH of the solution increases) is correct because the addition of sodium acetate suppresses the dissociation of acetic acid due to the common ion effect, decreasing [H+] and increasing pH.
33 Easy
33 of 161
Analyzing +4 | -1
Which of the following salts will give highest PH{P^H} in water
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Correct option: C
Na2CO3N{a_2}C{O_3}
The correct answer is C (Na2CO3N{a_2}C{O_3}) because it is a salt of a strong base (NaOH) and a weak acid (H2CO3H_2CO_3), resulting in a higher pH due to hydrolysis.
34 Easy
34 of 161
Understanding +4 | -1
The reaction 3Fe(s)+4H2O(l)⇋FeSO4(s)+4H2(g)3Fe(s) + 4{H_2}O(l)\underset{{}}{\overset{{}}{\leftrightharpoons}}FeS{O_4}(s) + 4{H_2}(g) is reversible if it is carried out
View answer and explanation
Correct option: D
In a closed vessel
Option D is correct because for a reaction to be reversible, it must be carried out in a closed vessel to prevent the escape of gaseous products, allowing the reverse reaction to occur.
35 Easy
35 of 161
Understanding +4 | -1
Which of these is a Lewis acid?
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Correct option: A
AlCl3\mathrm{AlC}{\mathrm{l}_3}
Option A (AlCl3\mathrm{AlC}{\mathrm{l}_3}) is correct because aluminum chloride is electron deficient and can accept a lone pair of electrons.
36 Easy
36 of 161
Analyzing +4 | -1
Among BMe3,BF3,BCl3  and  B2H6\mathrm{BM}{\mathrm{e}_3},\mathrm{B}{\mathrm{F}_3},\mathrm{BC}{\mathrm{l}_3}\;\mathrm{and}\;{\mathrm{B}_2}{\mathrm{H}_6} which one will be the best Lewis acid?
View answer and explanation
Correct option: A
BCl3\mathrm{BC}{\mathrm{l}_3}
Option A (BCl3\mathrm{BC}{\mathrm{l}_3}) is the best Lewis acid because it has the least pπ−pπp\pi - p\pi back bonding due to the larger size of Cl compared to F, making it more electron deficient.
37 Easy
37 of 161
Application +4 | -1
What is the minimum pH\mathrm{pH} necessary to cause a precipitate of Pb(OH)2( Ksp=1.2×10−5){Pb}({OH})_2\left({~K}_{{sp}}=1.2 \times 10^{-5}\right) to form in a 0.12 M  PbCl20.12\, \mathrm{M}\,\, {PbCl}_2 solution ?
View answer and explanation
Correct option: C
12
Option C (12) is correct because it is the minimum pH required to precipitate Pb(OH)₂ from a 0.12 M PbCl₂ solution, calculated using the Ksp value.
38 Easy
38 of 161
Analyzing +4 | -1
STATEMENT-1 : The endothermic reactions are favoured at lower temperature and the exothermic reactions are favoured at higher temperature.

STATEMENT-2 : When a system in equilibrium is disturbed by changing the temperature, it will tend to adjust itself so as to overcome the effect of change
View answer and explanation
Correct option: D
If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Option D is correct because statement 1 is false as endothermic reactions are favored at higher temperatures, and statement 2 is true, reflecting Le Chatelier's principle.
39 Easy
39 of 161
Application +4 | -1
In 100  mL\mathrm{100}\;\mathrm{mL} of an aqueous HCl\mathrm{HCl} of pH  1.0,  900  mL\mathrm{pH}\;1.0,\;900\;\mathrm{mL} of distilled water is added, the pH of the resultant solution becomes:
View answer and explanation
Correct option: B
2.0\mathrm{2}\mathrm{.0}
Option B (2.0) is correct because diluting the HCl solution decreases the concentration of H+ ions, resulting in a pH increase from 1.0 to 2.0.
40 Easy
40 of 161
Application +4 | -1
Solution prepared by dissolving equal number of mole of HOCl  (Ka=3.2×10−8)\mathrm{HOCl}\;\left( {{K_a} = 3.2 \times {{10}^{ - 8}}} \right) and NaOCl\mathrm{NaOCl} is a buffer of pH:
View answer and explanation
Correct option: B
3.23.2
Option A (3.23.2) is correct because when the concentration of the acid and its conjugate base are equal, the pH equals the pKa of the acid.
41 Easy
41 of 161
Understanding +4 | -1
Which one of the molecular hydride acts as Lewis acid?
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Correct option: C
B2H6{\mathrm{B}_2}{\mathrm{H}_6}
Option C (B2H6{\mathrm{B}_2}{\mathrm{H}_6}) is correct because diborane is an electron-deficient compound and acts as a Lewis acid by accepting electron pairs.
42 Easy
42 of 161
Remembering +4 | -1
Which of the following mixture is a buffer solution?
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Correct option: D
NH4OH+NH4Cl\mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}
Option D (NH4OH+NH4Cl\mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}) is correct because a buffer solution consists of a weak acid/base and its conjugate salt, and this option represents a weak base (ammonium hydroxide) and its salt (ammonium chloride).
43 Easy
43 of 161
Remembering +4 | -1
Which of the following is Lewis acid?
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Correct option: B
H+{H}^{+}
Option B (H+{H}^{+}) is correct because Lewis acids are electron-deficient species, and H+{H}^{+} can accept an electron pair.
44 Easy
44 of 161
Understanding +4 | -1
For an equilibrium H2O(s)⇌H2O(l)\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightleftharpoons \mathrm{H}_2 \mathrm{O}(\mathrm{l}) which of the following statements is true:
View answer and explanation
Correct option: B
More of ice melts if pressure on the system is increased
The correct answer is B (More of ice melts if pressure on the system is increased) because increasing pressure favors the liquid phase, which has a smaller volume than the solid phase.
45 Easy
45 of 161
Analyzing +4 | -1
Assertion : pH{pH} of hydrochloric acid solution is less than that of acetic acid solution of the same concentration.

Reason : In equimolar solutions, the number of titrable protons present in hydrochloric acid is less than that persent in acetic acid.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Hydrochloric acid (HCl) is a strong acid and completely dissociates in solution, resulting in a lower pH compared to acetic acid (CH3COOH), which is a weak acid. The number of titratable protons is not less in HCl. Therefore, the assertion is true, but the reason is false, making option C the correct answer.
46 Easy
46 of 161
Analyzing +4 | -1
The equilibrium constants of the following are.

N2+3H2⇋2NH3K1{\mathrm{N}_2} + 3{\mathrm{H}_\mathrm{2}}\leftrightharpoons2\mathrm{N}{\mathrm{H}_3}\mathrm{ }{\mathrm{K}_1}

N2+O2⇋2NOK2{\mathrm{N}_\mathrm{2}}\mathrm{ + }{\mathrm{O}_\mathrm{2}}\leftrightharpoons\mathrm{2NO }{\mathrm{K}_2}

H2+12O2→H2OK3{\mathrm{H}_\mathrm{2}}\mathrm{ + }\frac{\mathrm{1}}{\mathrm{2}}{\mathrm{O}_\mathrm{2}} \to {\mathrm{H}_\mathrm{2}}\mathrm{O }{\mathrm{K}_3}

The equilibrium constant (K)(K) of the reaction

2NH3+52O2⇆K2NO+3H2O,2\mathrm{N}{\mathrm{H}_3}\mathrm{ + }\frac{5}{2}{\mathrm{O}_2}\overset K \leftrightarrows \mathrm{2NO + 3}{\mathrm{H}_2}\mathrm{O,} will be
View answer and explanation
Correct option: C
K2K33/K1{K_2}K_3^3/{K_1}
Option C is correct. The equilibrium constant K is calculated by combining the given reactions to match the target reaction and then multiplying/dividing the corresponding equilibrium constants.
47 Easy
47 of 161
Remembering +4 | -1
The pH of solution, whose hydrogen ion concentration is one mole per litre, will be:
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because the pH is calculated as the negative logarithm of the hydrogen ion concentration, and the negative logarithm of 1 is 0.
48 Easy
48 of 161
Application +4 | -1
The rate constant for forward reaction and backward reaction of hydrolysis of ester are 1.1×10−2{1.1 \times {{10}^{ - 2}}} and 1.5×10−3{1.5 \times {{10}^{ - 3}}} per minute respectively. Equilibrium constant for the reaction is

CH3COOC2H5+H2O  ⇋  CH3COOH+C2H5OH\mathrm{C}{\mathrm{H}_3}\mathrm{COO}{\mathrm{C}_2}{\mathrm{H}_5} + {\mathrm{H}_2}\mathrm{O}\;\leftrightharpoons\;\mathrm{C}{\mathrm{H}_3}\mathrm{COOH} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}
View answer and explanation
Correct option: B
7.337.33
Option B (7.33) is correct because the equilibrium constant is the ratio of the forward rate constant to the backward rate constant.
49 Easy
49 of 161
Understanding +4 | -1
Which of the following is a Bronsted acid as well as Bronsted base:
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Correct option: B
H2O{\mathrm{H}_2}\mathrm{O}
Option B (H2O{\mathrm{H}_2}\mathrm{O}) is correct because water can act as both a proton donor (acid) and a proton acceptor (base).
50 Easy
50 of 161
Understanding +4 | -1
Unit of equilibrium constant for the reversible reaction H2+I2⇌{H}_2+{I}_2 \rightleftharpoons 2HI2 {HI} is
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Correct option: D
None of these
Option D (None of these) is correct because for the reaction H2+I2⇌2HI{H}_2+{I}_2 \rightleftharpoons 2 {HI}, the change in the number of moles is zero, so the equilibrium constant is dimensionless.
51 Easy
51 of 161
Application +4 | -1
pH of a 0.0001  M  HCl0.0001\;\mathrm{ }M\;\mathrm{ }HCl solution is
View answer and explanation
Correct option: A
4.04.0
Option A (4.0) is correct because the pH is calculated directly from the hydrogen ion concentration: pH = -log[H+].
52 Easy
52 of 161
Understanding +4 | -1
If acetic acid is mixed with sodium acetate then H+{\mathrm{H}^ + } ion concentration will
View answer and explanation
Correct option: B
Decrease
Option B (Decrease) is correct because adding sodium acetate, a common ion, to acetic acid will shift the equilibrium to the left, decreasing the hydrogen ion concentration due to the common ion effect.
53 Easy
53 of 161
Analyzing +4 | -1
Assertion(A) BF3{BF}_3 is a Lewis acid as well as Bronsted-Lowry acid.

Reason(R) Any species which can accept a lone pair of electrons is a Lewis acid and the species that can lose a proton is Bronsted-Lowry acid.
View answer and explanation
Correct option: D
If (A)(A) is incorrect but (R) is correct.
The correct answer is D (If (A)(A) is incorrect but (R) is correct) because BF3{BF}_3 is a Lewis acid but not a Bronsted-Lowry acid, while the reason correctly defines Lewis and Bronsted-Lowry acids.
54 Easy
54 of 161
Application +4 | -1
Maximum possible pH\mathrm{pH} of a solution of slaked lime is [KSP\left[\mathrm{K}_{\mathrm{SP}}\right. of Ca(OH)2=32×10−6]\left.\mathrm{Ca}(\mathrm{OH})_2=32 \times 10^{-6}\right]:
View answer and explanation
Correct option: D
12.612.6
Option D (12.6) is correct because it is calculated from the solubility product of calcium hydroxide, considering the hydroxide ion concentration and then calculating the pH.
55 Easy
55 of 161
Application +4 | -1
Given the reaction between 2 gases represented by A2{A_2} and B2{B_2} to give the compound AB(g).A{B_{\left( \mathrm{g} \right)}}\mathrm{.}
A2(g)+B2(g)  ⇋  2AB(g){A_{2\left( \mathrm{g} \right)}} + {B_{2\left( \mathrm{g} \right)}}\;\leftrightharpoons\;2A{B_{\left( \mathrm{g} \right)}}
At equilibrium, the concentration
of A2=3.0×10−3  M{A_2} = 3.0 \times {10^{ - 3}}\;\mathrm{M}
of B2=4.2×10−3  M{B_2} = 4.2 \times {10^{ - 3}}\;\mathrm{M}
of AB=2.8×10−3  MAB = 2.8 \times {10^{ - 3}}\;\mathrm{M}
If the reaction takes place in a sealed vessel at 527∘C527^\circ C, then the value of Kc{K_c} will be :
View answer and explanation
Correct option: C
0.620.62
The correct answer is 0.62 (Option C) because it is calculated by substituting the given equilibrium concentrations into the equilibrium constant expression, Kc=[AB]2[A2][B2]{K_c} = \frac{{{{\left[ {AB} \right]}^2}}}{{\left[ {{A_2}} \right]\left[ {{B_2}} \right]}}.
56 Easy
56 of 161
Application +4 | -1
For the reaction N2(g)+O2(g)⇌2NO(g){N}_2(\mathrm{g})+{O}_2(\mathrm{g}) \rightleftharpoons 2 {NO}(\mathrm{g}), the value of KC{K}_{{C}} at 800∘C800^{\circ} \mathrm{C} is 0.1.0.1. What is the value of KP{K}_{{P}} at this temperature?
View answer and explanation
Correct option: D
0.1
Option D (0.1) is correct because for this reaction, Kp equals Kc since the change in moles of gas is zero.
57 Easy
57 of 161
Understanding +4 | -1
On doubling P{P} and V{V} with constant temperature the equilibrium constant will
View answer and explanation
Correct option: A
Remain constant
Option A (Remain constant) is correct because the equilibrium constant (K) is only affected by changes in temperature, not pressure or volume.
58 Easy
58 of 161
Analyzing +4 | -1
Which one of the following statements is not true?
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Correct option: C
The pH of 1×10−8  M  HCl1 \times {10^{ - 8}}\;M\;\mathrm{HCl} is 8
Option C is not true. The pH of 1×10−8  M  HCl1 \times {10^{ - 8}}\;M\;\mathrm{HCl} is not 8 because the solution is acidic. You must also consider the autoionization of water. The pH will be slightly less than 7.
59 Easy
59 of 161
Application +4 | -1
At a given temperature the Kc{K_c} for the reaction, PCl5(g)  ⇋  PCl3(g)+Cl2(g)\mathrm{PC}{\mathrm{l}_5}\left( \mathrm{g} \right)\;\leftrightharpoons\;\mathrm{PC}{\mathrm{l}_3}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right) is 2.4×10−32.4 \times {10^{ - 3}}. At the same temperature, the Kc{K_c} for the reaction

PCl3(g)+Cl2(g)  ⇋  PCl5(g)\mathrm{PC}{\mathrm{l}_3}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right)\;\leftrightharpoons\;\mathrm{PC}{\mathrm{l}_5}\left( \mathrm{g} \right) is :
View answer and explanation
Correct option: C
4.2×10−24.2 \times {10^{ - 2}}
The correct answer is C (4.2×10−24.2 \times {10^{ - 2}}) because the equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the forward reaction.
60 Easy
60 of 161
Understanding +4 | -1
For which reaction Kp � Kc ?
View answer and explanation
Correct option: D
2C(s)+O2(g)→2CO(g)2C\left( s \right)\mathrm{ } + \mathrm{ }{O_2}\left( g \right) \to 2CO\left( g \right)
Option D (2C(s)+O2(g)→2CO(g)2C(s) + O_2(g) \to 2CO(g)) is correct because KpK_p � KcK_c when Δn � 0, and in this reaction, Δn = 2 - 1 = 1.
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