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JEE • CHEMISTRY • Equilibrium

Equilibrium practice · Mixed difficulty

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121 Easy
121 of 680
Understanding +4 | -1
Which of these is a Lewis acid?
View answer and explanation
Correct option: A
AlCl3\mathrm{AlC}{\mathrm{l}_3}
Option A (AlCl3\mathrm{AlC}{\mathrm{l}_3}) is correct because aluminum chloride is electron deficient and can accept a lone pair of electrons.
122 Medium
122 of 680
Analyzing +4 | -1
The equilibrium constants for the reaction A2⇌2A\mathrm{A}_2 \rightleftharpoons2 \mathrm{A} at 500 K500 \mathrm{~K} and 1000 K1000 \mathrm{~K} are 1×10−101 \times 10^{-10} and 1×10−5,1 \times 10^{-5}, respectively. The reaction is
View answer and explanation
Correct option: D
Endothermic
Option D (Endothermic) is correct because the equilibrium constant increases with increasing temperature, indicating an endothermic reaction.
123 Medium
123 of 680
Application +4 | -1
Number of H+{\mathrm{H}^ + } ions present in 10  mL10\;mL of a solution of pH  =  3pH\; = \;3 is:
View answer and explanation
Correct option: B
6.02×10186.02 \times {10^{18}}
Option B (6.02×10186.02 \times {10^{18}}) is correct because it accurately calculates the number of H+ ions based on the pH and volume of the solution.
124 Hard
124 of 680
Application +4 | -1
The percentage error in H+\mathrm{H}^{+}concentration provided by 10−8 M HCl10^{-8} \mathrm{~M} \mathrm{~HCl} if ionisation of water is not neglected is :
View answer and explanation
Correct option: C
5%5 \%
Option A (3%3 \%) is correct because the percentage error in H⁺ concentration is calculated by considering the autoionization of water.
125 Easy
125 of 680
Analyzing +4 | -1
Among BMe3,BF3,BCl3  and  B2H6\mathrm{BM}{\mathrm{e}_3},\mathrm{B}{\mathrm{F}_3},\mathrm{BC}{\mathrm{l}_3}\;\mathrm{and}\;{\mathrm{B}_2}{\mathrm{H}_6} which one will be the best Lewis acid?
View answer and explanation
Correct option: A
BCl3\mathrm{BC}{\mathrm{l}_3}
Option A (BCl3\mathrm{BC}{\mathrm{l}_3}) is the best Lewis acid because it has the least pπ−pπp\pi - p\pi back bonding due to the larger size of Cl compared to F, making it more electron deficient.
126 Hard
126 of 680
Application +4 | -1
A weak acid HX(Ka=1×10−5)\mathrm{H}X\left( {{K_a} = 1 \times {{10}^{ - 5}}} \right) on reaction with NaOH\mathrm{NaOH} gives NaX\mathrm{Na}X. For 0.1  M0.1\;M aqueous solution of NaX\mathrm{Na}X, the %\% hydrolysis is:
View answer and explanation
Correct option: B
0.01%0.01\%
Option B (0.01%0.01\%) is correct because it is calculated by finding the hydrolysis constant and then the percentage of hydrolysis.
127 Medium
127 of 680
Analyzing +4 | -1
Solid BaF2\mathrm{BaF}_2 is added to a solution containing 0.1 mole of Na2C2O4\mathrm{Na}_2 \mathrm{C}_2 \mathrm{O}_4 solution (1 L)(1 \mathrm{~L}) until equilibrium is reached. If the KspK_{\mathrm{sp}} of BaF2\mathrm{BaF}_2 and BaC2O4\mathrm{BaC}_2 \mathrm{O}_4 is 10−610^{-6} mol3 L−3\mathrm{mol}^3 \mathrm{~L}^{-3} and 10−10 mol2 L−2,10^{-10} \mathrm{~mol}^2 \mathrm{~L}^{-2}, respectively, then find the equilibrium concentration of Ba2+\mathrm{Ba}^{2+} in the solution. Assume that addition of BaF2\mathrm{BaF}_2 does not cause any change in volume.
View answer and explanation
Correct option: C
2.5×10−5M2.5 \times 10^{-5} \mathrm{M}
Option C is correct because the equilibrium concentration of Ba2+\mathrm{Ba}^{2+} is calculated using the solubility product of BaF2\mathrm{BaF}_2 and the fluoride ion concentration derived from the reaction with oxalate.
128 Medium
128 of 680
Application +4 | -1
3.2 moles of hydrogen iodide were heated in a sealed bulb at 444∘C444^\circ C till the equilibrium state was reached. Its degree of dissociation at this temperature was found to be 22%.22\% . The number of moles of hydrogen iodide present at equilibrium are
View answer and explanation
Correct option: B
2.496
Option B (2.496) is correct because it is the number of moles of HI remaining at equilibrium after dissociation.
129 Hard
129 of 680
Application +4 | -1
Consider the following equilibrium at 25∘C25^{\circ} \mathrm{C} CuSO4.5H2O(s)⇌CuSO4.3H2O(s)+2H2O(g)\mathrm{CuSO}_4.5 \mathrm{H}_2 \mathrm{O}{(\mathrm{s})} \rightleftharpoons \mathrm{CuSO}_4.3 \mathrm{H}_2 \mathrm{O}{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}{(\mathrm{g})} If this reaction takes place at two cities A\mathrm{A} and B\mathrm{B} having relative humidity 60%60 \% and 80%80 \% respectively. The vapour pressure of water at 25∘C25^{\circ} \mathrm{C} is 20 mm Hg20 \mathrm{~mm} \mathrm{~Hg} and KP\mathrm{K}_{\mathrm{P}} for the above reaction is 4×10−2(atm)24 \times 10^{-2}(\mathrm{atm})^2 at 25∘C25^{\circ} \mathrm{C} then CuSO4.5H2O\mathrm{CuSO}_4.5 \mathrm{H}_2 \mathrm{O} acts as efflorescent in which city?
View answer and explanation
Correct option: A
At A only
Option A (At A only) is correct because CuSO4.5H2O acts as efflorescent when the partial pressure of water vapor in the atmosphere is less than the equilibrium vapor pressure, which is the case in city A.
130 Hard
130 of 680
Application +4 | -1
For the reaction H2( g)+CO2( g)⇌CO(g)+H2O(g)\mathrm{H}_2(\mathrm{~g})+\mathrm{CO}_2(\mathrm{~g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g}), If the initial concentration of [H2]=[CO2]\left[\mathrm{H}_2\right]=\left[\mathrm{CO}_2\right] and  x mol/L\mathrm{~x} \mathrm{~mol} / \mathrm{L} of hydrogen is consumed at equilibrium, the correct expression of kpk_{\mathrm{p}} is
View answer and explanation
Correct option: C
x21−x2\frac{x^2}{1-x^2}
Option C (x21−x2\frac{x^2}{1-x^2}) is correct because it is the correct expression for Kp based on the equilibrium concentrations of the reactants and products.
131 Hard
131 of 680
Application +4 | -1
20%20 \% of N2O4\mathrm{N}_2 \mathrm{O}_4 molecules are dissociated in a sample of gas at 27∘C27^{\circ} \mathrm{C} and 760 torn. Calculate the density of the equilibrium mixture.
View answer and explanation
Correct option: A
3.11 g litre−13.11 \mathrm{~g} \mathrm{~litre}^{-1}
Option A (3.11 g litre−13.11 \mathrm{~g} \mathrm{~litre}^{-1}) is correct because it is calculated using the ideal gas law and the concept of degree of dissociation to find the density of the equilibrium mixture.
132 Medium
132 of 680
Analyzing +4 | -1
Which oxide of nitrogen is the most stable?
View answer and explanation
Correct option: A
2NO2(g) ⇌ N2(g)+2O2(g);K=6.7×1016mol   litre−12N{O_2}(g)\, \rightleftharpoons \,{N_2}(g) + 2{O_2}(g);K = 6.7 \times {10^{16}}{\text{mol}}\,\,\,{\text{litr}}{{\text{e}}^{ - 1}}
Option A (2NO2(g) ⇌ N2(g)+2O2(g);K=6.7×1016mol   litre−12N{O_2}(g)\, \rightleftharpoons \,{N_2}(g) + 2{O_2}(g);K = 6.7 \times {10^{16}}{\text{mol}}\,\,\,{\text{litr}}{{\text{e}}^{ - 1}}) is correct because the lower the value of K, the more stable the oxide of nitrogen.
133 Easy
133 of 680
Application +4 | -1
What is the minimum pH\mathrm{pH} necessary to cause a precipitate of Pb(OH)2( Ksp=1.2×10−5){Pb}({OH})_2\left({~K}_{{sp}}=1.2 \times 10^{-5}\right) to form in a 0.12 M  PbCl20.12\, \mathrm{M}\,\, {PbCl}_2 solution ?
View answer and explanation
Correct option: C
12
Option C (12) is correct because it is the minimum pH required to precipitate Pb(OH)₂ from a 0.12 M PbCl₂ solution, calculated using the Ksp value.
134 Easy
134 of 680
Analyzing +4 | -1
STATEMENT-1 : The endothermic reactions are favoured at lower temperature and the exothermic reactions are favoured at higher temperature.

STATEMENT-2 : When a system in equilibrium is disturbed by changing the temperature, it will tend to adjust itself so as to overcome the effect of change
View answer and explanation
Correct option: D
If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Option D is correct because statement 1 is false as endothermic reactions are favored at higher temperatures, and statement 2 is true, reflecting Le Chatelier's principle.
135 Medium
135 of 680
Application +4 | -1
For a weak electrolyte α1\alpha_1 and α2\alpha_2 are in ratio of 1:21: 2, for a given concentration ka1=2×10−4k_{\mathrm{a}_1}=2 \times 10^{-4}. What will be value of ka2\mathrm{k}_{\mathrm{a}_2} ?
View answer and explanation
Correct option: A
8×10−48 \times 10^{-4}
Option A (8×10−48 \times 10^{-4}) is correct because the degree of dissociation is proportional to the square root of the acid dissociation constant.
136 Medium
136 of 680
Application +4 | -1
Buffer capacity of a buffer solution is x, the volume of 1M added to 100 ml of this solution if the change of PH{P^H} by 1 is
View answer and explanation
Correct option: C
100x ml100x\,ml
Option C (100x ml100x\,ml) is correct because buffer capacity is defined as the number of moles of acid or base required to change the pH of 1 liter of solution by 1, and the calculation uses this definition to find the volume of 1M NaOH needed.
137 Hard
137 of 680
Application +4 | -1
An aqueous solution contains an unknown concentration of Ba2+.B{a^{2 + }}. When 50 mL of a 1 M solution of Na2SO4N{a_2}S{O_4} is added, BaSO4BaS{O_4} just begins to precipitate. The final volume is 500 mL. The solubility product of BaSO4BaS{O_4} is 1×10−101 \times {10^{ - 10}}. What is the original concentration of Ba2+?B{a^{2 + }}?
View answer and explanation
Correct option: C
1.1×10−9M1.1 \times {10^{ - 9}}M
Option C (1) is correct because after finding the roots and substituting them into the expression, the result simplifies to 1.
138 Easy
138 of 680
Application +4 | -1
In 100  mL\mathrm{100}\;\mathrm{mL} of an aqueous HCl\mathrm{HCl} of pH  1.0,  900  mL\mathrm{pH}\;1.0,\;900\;\mathrm{mL} of distilled water is added, the pH of the resultant solution becomes:
View answer and explanation
Correct option: B
2.0\mathrm{2}\mathrm{.0}
Option B (2.0) is correct because diluting the HCl solution decreases the concentration of H+ ions, resulting in a pH increase from 1.0 to 2.0.
139 Medium
139 of 680
Application +4 | -1
Which may be added to one litre of water to act as a buffer?
View answer and explanation
Correct option: D
One mole of HC2H3O2\mathrm{H}{\mathrm{C}_2}{\mathrm{H}_3}{\mathrm{O}_2} and 0.50.5 mole of NaOH\mathrm{NaOH}
Option D (One mole of HC2H3O2\mathrm{H}{\mathrm{C}_2}{\mathrm{H}_3}{\mathrm{O}_2} and 0.50.5 mole of NaOH\mathrm{NaOH}) is correct because it results in a mixture of a weak acid and its conjugate base, which is a buffer solution.
140 Medium
140 of 680
Application +4 | -1
The equivalent conductance of M32\frac{M}{{32}} solution of a weak monobasic acid is 8.0  mhos  cm28.0\;\mathrm{mhos}\;\mathrm{c}{\mathrm{m}^2} and at infinite dilution is 400  mhos  cm2.400\;\mathrm{mhos}\;\mathrm{c}{\mathrm{m}^2}. The dissociation constant of this acid is:
View answer and explanation
Correct option: B
1.25×10−51.25 \times {10^{ - 5}}
Option B (1.25×10−51.25 \times {10^{ - 5}}) is correct because it is calculated using the formula for the dissociation constant of a weak acid, Ka=cα2K_a = c\alpha^2, where α\alpha is the degree of dissociation.
141 Medium
141 of 680
Application +4 | -1
For the reaction C(s)+CO2(g)2  CO(g)C(s) + C{O_2}(g)2\,\,CO(g) the partial pressure of CO2C{O_2} and are 2.0 and 4.0 atm resp, at equilibrium. The Kp{K_p} for the reaction is
View answer and explanation
Correct option: C
3.03.0
Option D (32.0) is incorrect. The correct answer is 8.0. The equilibrium constant Kp is calculated by taking the ratio of the square of the partial pressure of CO to the partial pressure of CO2.
142 Easy
142 of 680
Application +4 | -1
Solution prepared by dissolving equal number of mole of HOCl  (Ka=3.2×10−8)\mathrm{HOCl}\;\left( {{K_a} = 3.2 \times {{10}^{ - 8}}} \right) and NaOCl\mathrm{NaOCl} is a buffer of pH:
View answer and explanation
Correct option: B
3.23.2
Option A (3.23.2) is correct because when the concentration of the acid and its conjugate base are equal, the pH equals the pKa of the acid.
143 Easy
143 of 680
Understanding +4 | -1
Which one of the molecular hydride acts as Lewis acid?
View answer and explanation
Correct option: C
B2H6{\mathrm{B}_2}{\mathrm{H}_6}
Option C (B2H6{\mathrm{B}_2}{\mathrm{H}_6}) is correct because diborane is an electron-deficient compound and acts as a Lewis acid by accepting electron pairs.
144 Easy
144 of 680
Remembering +4 | -1
Which of the following mixture is a buffer solution?
View answer and explanation
Correct option: D
NH4OH+NH4Cl\mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}
Option D (NH4OH+NH4Cl\mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}) is correct because a buffer solution consists of a weak acid/base and its conjugate salt, and this option represents a weak base (ammonium hydroxide) and its salt (ammonium chloride).
145 Easy
145 of 680
Remembering +4 | -1
Which of the following is Lewis acid?
View answer and explanation
Correct option: B
H+{H}^{+}
Option B (H+{H}^{+}) is correct because Lewis acids are electron-deficient species, and H+{H}^{+} can accept an electron pair.
146 Hard
146 of 680
Application +4 | -1
The ionisation constant of an acid, KaK_a is the measure of strength of an acid. The KaK_a values of acetic acid, hypochlorous acid and formic acid are 1.74×10−51.74 \times 10^{-5}, 3.0×10−83.0 \times 10^{-8} and 1.8×10−41.8 \times 10^{-4} respectively. Which of the following order of pH\mathrm{pH} of 0.1 mol dm−30.1 \mathrm{~mol}\,\mathrm{dm}^{-3} solutions of these acids is correct?
View answer and explanation
Correct option: B
Hypochlorous acid >> acetic acid >> formic acid
Option B (Hypochlorous acid >> acetic acid >> formic acid) is correct because pH increases with decreasing Ka value, indicating weaker acidity.
147 Easy
147 of 680
Understanding +4 | -1
For an equilibrium H2O(s)⇌H2O(l)\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightleftharpoons \mathrm{H}_2 \mathrm{O}(\mathrm{l}) which of the following statements is true:
View answer and explanation
Correct option: B
More of ice melts if pressure on the system is increased
The correct answer is B (More of ice melts if pressure on the system is increased) because increasing pressure favors the liquid phase, which has a smaller volume than the solid phase.
148 Easy
148 of 680
Analyzing +4 | -1
Assertion : pH{pH} of hydrochloric acid solution is less than that of acetic acid solution of the same concentration.

Reason : In equimolar solutions, the number of titrable protons present in hydrochloric acid is less than that persent in acetic acid.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Hydrochloric acid (HCl) is a strong acid and completely dissociates in solution, resulting in a lower pH compared to acetic acid (CH3COOH), which is a weak acid. The number of titratable protons is not less in HCl. Therefore, the assertion is true, but the reason is false, making option C the correct answer.
149 Medium
149 of 680
Understanding +4 | -1
STATEMENT-1 : The equilibrium constant of the exothermic reaction at high temperature decreases.

STATEMENT-2 : Since ln⁡K2K1=ΔH∘R[1T1−1T2]\ln \frac{K_2}{K_1}=\frac{\Delta H^{\circ}}{R}\left[\frac{1}{T_1}-\frac{1}{T_2}\right] and for exothermic reaction, ΔH∘=−\Delta H^{\circ}=- ve and thereby; K2K1<1\frac{K_2}{K_1} < 1
View answer and explanation
Correct option: A
If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1
Option A (If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1) is correct because the equilibrium constant of an exothermic reaction decreases at high temperatures, and the provided equation correctly explains this relationship.
150 Medium
150 of 680
Application +4 | -1
The value of the equilibrium constant for the reaction: 2NO+O2⇌2NO22NO + {O_2} \rightleftharpoons 2N{O_2} is 0.25, then the value of equilibrium constant for 2NO2⇌2NO+O22N{O_2} \rightleftharpoons 2NO + {O_2} is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the forward reaction.
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