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JEE • CHEMISTRY • Equilibrium

Equilibrium practice · Mixed difficulty

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601 Hard
601 of 680
Analyzing +4 | -1
A volume of 1.0 L1.0 \mathrm{~L} of solution which was in equilibrium with solid mixture of AgCl{AgCl} and Ag2CrO4{Ag}_2 {CrO}_4 was found to contain 1×10−41 \times 10^{-4} moles of Ag+{Ag}^{+} ions, 1.0×10−61.0 \times 10^{-6} moles of Cl−{Cl}^{-} ions and 8.0×10−48.0 \times 10^{-4} moles of CrO42−{CrO}_4{ }^{2-} ions. The Ag+{Ag}^{+} ions are added slowly to the above mixture (keeping the volume constant) till 8.0×10−78.0 \times 10^{-7} moles of AgCl{AgCl} got precipitated. How many moles of Ag2CrO4{Ag}_2 {CrO}_4 were precipitated simultaneously?
View answer and explanation
Correct option: A
7.68×10−47.68 \times 10^{-4}
Option A (7.68×10−47.68 \times 10^{-4}) is correct because it calculates the amount of Ag2CrO4Ag_2CrO_4 precipitated based on the change in chloride concentration and the solubility product constants.
602 Medium
602 of 680
Application +4 | -1
The number of H+{H^ + } ions present in 1 ml of a solution having PH=13{P^H} = 13 is
View answer and explanation
Correct option: C
6.02×1076.02 \times {10^{7}}
Option C (6.02×1076.02 \times {10^{7}}) is correct because it calculates the number of H+ ions from pH and converts concentration to number of ions in 1 ml.
603 Medium
603 of 680
Analyzing +4 | -1
At 30∘C30^{\circ} \mathrm{C}, the solubility of Ag2CO3( Ksp=8×10−2){Ag}_2{CO}_3\left({~K}_{\mathrm{sp}}=8 \times 10^{-2}\right) will be maximum in -
View answer and explanation
Correct option: D
0.05 M NH30.05\, \mathrm{M~} {NH}_3
Option D (0.05 M NH30.05\, \mathrm{M~} {NH}_3) is correct because the solubility of Ag2CO3{Ag}_2{CO}_3 increases in NH3{NH}_3 due to the formation of a complex ion, while it decreases in Na2CO3{Na}_2{CO}_3 and AgNO3{AgNO}_3 due to the common ion effect.
604 Medium
604 of 680
Analyzing +4 | -1
Assertion (A): The degree of dissociation of CH3COOH\mathrm{CH}_3 \mathrm{COOH} is more in a solution which is basic than in water.

Reason (R): Ka\mathrm{K}_{\mathrm{a}} of CH3COOH\mathrm{CH}_3 \mathrm{COOH} increases in basic solution.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C ((A) is true but (R) is false) is correct because the degree of dissociation increases in a basic solution, but the Ka value remains constant as it's a characteristic of the acid.
605 Medium
605 of 680
Application +4 | -1
When 0.5 mole of N2O4\mathrm{N}_2 \mathrm{O}_4 is placed in a 4.00 L4.00 \mathrm{~L} reaction vessel and heated at 405 K,79.3%405 \mathrm{~K}, 79.3 \% of the N2O4\mathrm{N}_2 \mathrm{O}_4 decomposes to NO2\mathrm{NO}_2. Calculate value of KP\mathrm{K}_{\mathrm{P}} at 405 K405 \mathrm{~K}, for the reaction : N2O4( g)⇌2NO2( g)\mathrm{N}_2 \mathrm{O}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2(\mathrm{~g}).
View answer and explanation
Correct option: A
50
The correct answer is A (50) because Kp is calculated using the equilibrium constant Kc and the ideal gas constant R, along with the temperature and change in moles.
606 Hard
606 of 680
Analyzing +4 | -1
Given below are two statements: One is labelled as Assertion A and the other labelled as Reason R.
Assertion A: During the boiling of water having temporary hardness, Mg(HCO3)2Mg{(HC{O_3})_2} is converted to MgCO3MgC{O_3}.
Reason R The solubility product of Mg(OH)2Mg{(OH)_2} is greater than that of MgCO3MgC{O_3}.
In the light of the above statements, choose the most appropriate answer from the options given below
View answer and explanation
Correct option: D
A is false but R is true.
Option D is correct because the assertion is false (Mg(HCO3)2 converts to Mg(OH)2 during boiling), and the reason is true (Ksp of Mg(OH)2 is greater than that of MgCO3).
607 Medium
607 of 680
Analyzing +4 | -1
What are the product formed when Deuterium is added equilibrium reaction of H2{H}_2 and I2{I}_2 ?

(i) HD{HD}

(ii) DI{DI}

(iii) D2{D}_2

(iv) HI{HI}
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because in a dynamic equilibrium, all possible isotopic combinations can form.
608 Medium
608 of 680
Analyzing +4 | -1
Which of the following statements are correct ?

(i) The extent of dissociation of an acid depends on the strength and polarity of the H−A{H}-{A} bond (where A{A} is an electronegative element.)

(ii) As the strength of H−A{H}-{A} bond increases, the energy required to break the bond decreases.

(iii) As the electronegativity difference between the atoms H{H} and A{A} increases, acidity increases
View answer and explanation
Correct option: C
(i) and (iii)
Option C ((i) and (iii)) is correct because the extent of dissociation depends on the H-A bond strength and polarity, and acidity increases with increasing electronegativity difference.
609 Easy
609 of 680
Understanding +4 | -1
The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to
View answer and explanation
Correct option: B
Dissociation constant of both weak acid and weak base
Option B is correct because the hydrolysis constant Kh{K_h} is inversely proportional to the product of the dissociation constants of the weak acid (Ka{K_a}) and weak base (Kb{K_b}).
610 Hard
610 of 680
Analyzing +4 | -1
At a certain temperature, KPK_{\mathrm{P}} for the dissociation of solid CaCO3\mathrm{CaCO}_3 is 4.5×10−24.5 \times 10^{-2} atm and for the reaction C(s)+CO2(g)⇌2CO(g),\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}), the KPK_{\mathrm{P}} value is 2.0 atm.2.0 \mathrm{~atm}. The pressure of carbon monoxide at this temperature, when solid carbon CaO\mathrm{CaO} and CaCO3\mathrm{CaCO}_3 are mixed together and allowed to attain equilibrium is
View answer and explanation
Correct option: B
0.30 atm0.30 \mathrm{~atm}
Option B (0.30 atm) is correct because it is the partial pressure of CO calculated from the equilibrium constant.
611 Easy
611 of 680
Analyzing +4 | -1
At 30∘C  the  solubility  of Ag2CO3  (Ksp=8×10−12)30^\circ C\;\mathrm{the}\;\mathrm{ solubility}\;\mathrm{ of}\,\mathrm{ A}{\mathrm{g}_2}\mathrm{C}{\mathrm{O}_3}\;\left( {{K_{\mathrm{sp}}} = 8 \times {{10}^{ - 12}}} \right) would be greatest in 1  L1\;L of
View answer and explanation
Correct option: D
0.05  M  NH30.05\;\mathrm{M }\;\mathrm{N}{\mathrm{H}_3}
The correct answer is D (0.05  M  NH30.05\;\mathrm{M }\;\mathrm{N}{\mathrm{H}_3}) because the solubility of Ag2CO3Ag_2CO_3 is greatest in NH3NH_3 due to complex formation, which reduces the concentration of Ag+Ag^+ ions.
612 Medium
612 of 680
Analyzing +4 | -1
For the equilibrium:

(I) C6H5COOH+H2O⇌C6H5COO−+H3O+;K1=6.30×10−5\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}+\mathrm{H}_2 \mathrm{O} \rightleftharpoons \mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{-}+\mathrm{H}_3 \mathrm{O}^{+} ; K_1=6.30 \times 10^{-5}

(II) C6H5COOH+OH−⇌C6H5COO−+H2O;K2=6.30×109\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}+\mathrm{OH}^{-} \rightleftharpoons \mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{-}+\mathrm{H}_2 \mathrm{O} ; K_2=6.30 \times 10^9

(III) H2O+H2O⇌H3O++OH−;K3−?\mathrm{H}_2 \mathrm{O}+\mathrm{H}_2 \mathrm{O} \rightleftharpoons \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{OH}^{-} ; K_3-?

K3K_3 using above equilibria is
View answer and explanation
Correct option: B
1.0×10−141.0 \times 10^{-14}
Option B (1.0×10−141.0 \times 10^{-14}) is correct because K3 is calculated by dividing K1 by K2, which results in 10-14.
613 Hard
613 of 680
Application +4 | -1
SO3(g)\mathrm{SO}_3(g) is partially dissociated into SO2(g)\mathrm{SO}_2(g) and O2(g)\mathrm{O}_2(g) at 900 K900 \mathrm{~K} and 1 atm1 \mathrm{~atm} as:
SO3(g)⇌SO2(g)+12O2(g)\mathrm{SO}_3(g) \rightleftharpoons \mathrm{SO}_2(g)+\frac{1}{2} \mathrm{O}_2(g)

The density of the equilibrium mixture was found to be 0.866 g dm−30.866 \mathrm{~g} \mathrm{~dm}^{-3}. Thus, degree dissociation of SO3( g)\mathrm{SO}_3(\mathrm{~g}). is
View answer and explanation
Correct option: C
0.5
Option C (50%) is correct because the degree of dissociation is calculated using the given density and the equilibrium constant expression.
614 Hard
614 of 680
Analyzing +4 | -1
Equilibrium constants K1{K_1} and K2{K_2}  for the following equilibria are related as :
NO(g)+12O2(g)⇋NO2(g);K1\mathrm{NO}\left( \mathrm{g} \right) + \frac{1}{2}{\mathrm{O}_2}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{N}{\mathrm{O}_2}\left( \mathrm{g} \right);{K_1}
2NO2(g)⇋2NO(g)+O2(g);K22\mathrm{N}{\mathrm{O}_2}\left( \mathrm{g} \right)\leftrightharpoons2\mathrm{NO}\left( \mathrm{g} \right) + {\mathrm{O}_2}\left( \mathrm{g} \right);{K_2}
View answer and explanation
Correct option: A
K2=1K12{K_2} = \frac{1}{{K_1^2}}
The correct answer is A (K2=1K12{K_2} = \frac{1}{{K_1^2}}) because the second reaction is the reverse of the first reaction multiplied by 2, so the equilibrium constant is the inverse squared.
615 Hard
615 of 680
Application +4 | -1
Solid Ca(HCO3)2{Ca}\left({HCO}_3\right)_2 decomposes as
Ca(HCO3)2( s)⇌CaCO3( s)+CO2( g)+H2O(g){Ca}\left({HCO}_3\right)_2({~s}) \rightleftharpoons {CaCO}_3({~s})+{CO}_2({~g})+{H}_2 {O}({g})

If the total pressure is 0.2 bar at 420 K420 {~K}, what is the standard free energy change for the given reaction (ΔrG∘)\left(\Delta_r G^{\circ}\right) ?
View answer and explanation
Correct option: D
16.083 kJ/mol16.083 {~kJ} / {mol}
Option D (16.083 kJ/mol16.083 {~kJ} / {mol}) is correct because it is the standard free energy change calculated using the equilibrium constant derived from the total pressure.
616 Easy
616 of 680
Application +4 | -1
An aqueous solution of 0.1  M  NH4Cl0.1\;M\;\mathrm{N}{\mathrm{H}_4}\mathrm{Cl} will have a pHpH closer to:
View answer and explanation
Correct option: D
5.15.1
Option D (5.1) is correct because NH4ClNH_4Cl is a salt of a weak base and a strong acid, which hydrolyzes to produce an acidic solution, resulting in a pH less than 7.
617 Easy
617 of 680
Application +4 | -1
Kc{K}_{{c}} for the reaction N2( g)+O2( g)⇌2NO(g){N}_2({~g})+{O}_2({~g}) \rightleftharpoons 2 {NO}({g}) at 300 K300 {~K} is 4.0×10−6⋅Kp4.0 \times 10^{-6} \cdot {K}_{{p}} for the abovereaction will be (R=2calmol−1 K−1)\left({R}=2 {calmol}^{-1} {~K}^{-1}\right)
View answer and explanation
Correct option: B
4×10−64 \times 10^{-6}
Option B (4×10−64 \times 10^{-6}) is correct because since Δn = 0, Kp = Kc.
618 Hard
618 of 680
Application +4 | -1
The solubility product of Cr(OH)3Cr{\left( {OH} \right)_3} at 298 K is 6.0×10−316.0 \times {10^{ - 31}}. The concentration of hydroxide ions in a saturated solution of Cr(OH)3Cr{\left( {OH} \right)_3} will be
View answer and explanation
Correct option: B
(18×10−31)1/4{\left( {18 \times {{10}^{ - 31}}} \right)^{1/4}}
The correct answer is (18×10−31)1/4{\left( {18 \times {{10}^{ - 31}}} \right)^{1/4}}. The hydroxide ion concentration is calculated from the solubility product using the appropriate stoichiometric relationship.
619 Medium
619 of 680
Analyzing +4 | -1
20 ml,0.1M20 \mathrm{~ml}, 0.1 \mathrm{M} HA [(Kb)A−=10−10]\left[\left(\mathrm{K}_{\mathrm{b}}\right)_{\mathrm{A}^{-}}=10^{-10}\right] is titrated against 0.2M,NaOH0.2 \mathrm{M}, \mathrm{NaOH}. Select the correct statement :[Given : log⁡2=0.3,log⁡3=0.48\log 2=0.3, \log 3=0.48 ]
View answer and explanation
Correct option: C
Phenolphthalein is suitable indicator for this titration but methyl orange is not suitable
Option C (Phenolphthalein is suitable indicator for this titration but methyl orange is not suitable) is correct because the pH at the equivalence point is greater than 7, making phenolphthalein a suitable indicator.
620 Medium
620 of 680
Application +4 | -1
A dilute solution of HCl\mathrm{HCl} contains [H3O+]=5.4×10−7 mol L−1\left[\mathrm{H}_3 \mathrm{O}^{+}\right]=5.4 \times 10^{-7} \mathrm{~mol} \mathrm{~L}^{-1} at 298 K298 \mathrm{~K}. What is the concentration of hydroxyl ions in this solution?
View answer and explanation
Correct option: B
1.8×10−8 mol L−11.8 \times 10^{-8} \mathrm{~mol} \mathrm{~L}^{-1}
Option B (1.8×10−8 mol L−11.8 \times 10^{-8} \mathrm{~mol} \mathrm{~L}^{-1}) is correct because it is calculated using the ion product of water (KwK_w) and the given hydronium ion concentration.
621 Easy
621 of 680
Understanding +4 | -1
For the Haber’s process for the formation of NH3\mathrm{N}{\mathrm{H}_3} at 298  K\mathrm{298}\;\mathrm{K} is :
N2+3H2  ⇋2NH3;    ΔH=−460    kJ{\mathrm{N}_2} + 3{\mathrm{H}_2}\;\leftrightharpoons2\mathrm{N}{\mathrm{H}_3};\;\;\Delta H = - 460\;\;\mathrm{kJ}
Which of the following is correct?
View answer and explanation
Correct option: A
The condition for equilibrium is GN2+3GH2=2GNH3,{\mathrm{G}_{{\mathrm{N}_2}}} + 3{\mathrm{G}_{{\mathrm{H}_2}}} = 2{\mathrm{G}_{\mathrm{N}{\mathrm{H}_3}}}, where G\mathrm{G} is Gibbs energy per mole of gaseous species measured at that partial pressure
Option A (The condition for equilibrium is GN2+3GH2=2GNH3{\mathrm{G}_{{\mathrm{N}_2}}} + 3{\mathrm{G}_{{\mathrm{H}_2}}} = 2{\mathrm{G}_{\mathrm{N}{\mathrm{H}_3}}}, where G\mathrm{G} is Gibbs energy per mole of gaseous species measured at that partial pressure) is correct because at equilibrium, the change in Gibbs free energy is zero, meaning the Gibbs free energy of the reactants equals the Gibbs free energy of the products.
622 Medium
622 of 680
Application +4 | -1
pHpH of 0.1  M  Na2HPO40.1\;M\;\mathrm{N}{\mathrm{a}_2}\mathrm{HP}{\mathrm{O}_4} and 0.2  M  NaH2PO40.2\;M\;\mathrm{Na}{\mathrm{H}_2}\mathrm{P}{\mathrm{O}_4} solutions are respectively. pKa\mathrm{p}{K_a} for H3PO4{\mathrm{H}_3}\mathrm{P}{\mathrm{O}_4} are 2.12,7.212.12,7.21 and 12.012.0 for respective dissociation to H2PO4−,HPO42−{\mathrm{H}_2}\mathrm{PO}_4^ - ,\mathrm{HPO}_4^{2 - } and PO43−.\mathrm{PO}_4^{3 - }.
View answer and explanation
Correct option: A
4.67,9.614.67,9.61
Option B (9.61, 4.67) is incorrect, the correct order is A (4.67, 9.61). The pH values are calculated using the half-sum of the relevant pKa values.
623 Medium
623 of 680
Application +4 | -1
Morphine (C17H19NO3)\left(\mathrm{C}_{17} \mathrm{H}_{19} \mathrm{NO}_3\right) is administered medically to relieve pain. It is a naturally occurring base or alkaloid. What is the pH\mathrm{pH} of a 0.0025 M0.0025 \mathrm{~M} solution of morphine at 25∘C?25^{\circ} \mathrm{C}? The base-ionization constant KbK_{{b}} is 1.6×10−61.6 \times 10^{-6} at 25∘C.25^{\circ} \mathrm{C}. (log⁡2=0.3)(\log 2=0.3)
View answer and explanation
Correct option: B
9.8
Option B (9.8) is correct because the pH is calculated from the pOH using the base ionization constant.
624 Hard
624 of 680
Analyzing +4 | -1
pH\mathrm{pH} of a saturated solution of silver salt of monobasic acid HA\mathrm{HA} is found to be 9. Select the option(s) which is / are correct. Given : Ka(HA)=10−10\mathrm{K}_{\mathrm{a}}(\mathrm{HA})=10^{-10}
I) Solubility of the silver salt is 1.1×10−5 mol/1.1 \times 10^{-5} \mathrm{~mol} / lit
II) Solubility product of the silver salt is 1.1×10−11 M21.1 \times 10^{-11} \mathrm{~M}^2
III) Concentration of Ag+\mathrm{Ag}^{+} in the solution will be greater than that of A−\mathrm{A}^{-}
View answer and explanation
Correct option: D
I, II &\& III
The correct answer is D (I, II & III) because all three statements regarding the solubility, solubility product, and ion concentrations are correct based on the given information and calculations.
625 Medium
625 of 680
Application +4 | -1
The pH of a 0.1 M solution of NH4OH\mathrm{N}{\mathrm{H}_4}\mathrm{OH} (having Kb=1.0×10−5){K_b} = 1.0 \times {10^{ - 5}}) is equal to
View answer and explanation
Correct option: C
11
Option C (11) is correct because it is the pH calculated from the hydroxide ion concentration of the weak base NH4OH using the given Kb value.
626 Easy
626 of 680
Understanding +4 | -1
What would be the effect on addition of CaCO3\mathrm{CaC}{\mathrm{O}_3} on the equilibrium of CaCO3(s)  ⇋  CaO(s)+CO2(g)\mathrm{CaC}{\mathrm{O}_3}\left( s \right)\;\leftrightharpoons\;\mathrm{CaO}\left( s \right) + \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) in a closed container:
View answer and explanation
Correct option: C
Remains unaffected
Option C (Remains unaffected) is correct because the addition of a solid reactant or product does not change the equilibrium constant, which depends only on the partial pressure of CO2 in this case.
627 Medium
627 of 680
Analyzing +4 | -1
Assertion :- Solubility of AgBr{AgBr} decreases in the presence of sodium bromide.

Reason :- Sodium bromide undergoes hydrolysis in water.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (Assertion is True but the Reason is False) is correct because the solubility of AgBr decreases in the presence of sodium bromide due to the common ion effect, but sodium bromide does not undergo hydrolysis.
628 Medium
628 of 680
Understanding +4 | -1
The best explanation for the solubility of MnS\mathrm{MnS} in dil.HCl\mathrm{HCl} is that:
View answer and explanation
Correct option: D
Concentration of sulphide ions is lowered by formation of the weak acid H2S{\mathrm{H}_2}\mathrm{S}
The correct answer is D because the solubility of MnS in dilute HCl is due to the formation of the weak acid H2S{\mathrm{H}_2}\mathrm{S}, which lowers the sulfide ion concentration.
629 Easy
629 of 680
Application +4 | -1
For the reaction, CO(g)+Cl2(g)  ⇋  COCl2(g)\mathrm{CO}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right)\;\leftrightharpoons\;\mathrm{COC}{\mathrm{l}_2}\left( \mathrm{g} \right) the value of Kp/Kc{K_p}/{K_c} is equal to :
View answer and explanation
Correct option: D
1RT\frac{1}{{RT}}
Option D (1RT\frac{{1}}{{{{RT}}}}) is correct because it is derived from the relationship between Kp and Kc, considering the change in the number of moles.
630 Hard
630 of 680
Application +4 | -1
The acid ionization constant of Zn2+{Zn}^{2+} is 2.0×10−10.2.0 \times 10^{-10}. What is the pH\mathrm{pH} of 0.001 M0.001 \mathrm{~M} solution of ZnCl2?{ZnCl}_2? (log⁡2=0.3)(\log 2=0.3)
View answer and explanation
Correct option: C
6.35
Option C (6.35) is correct. The pH of the ZnCl2 solution is calculated by considering the hydrolysis of Zn2+ ions and using the given acid ionization constant to find the [H+] concentration.
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