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JEE • CHEMISTRY • Equilibrium
Equilibrium practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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451
Medium
451 of 680
Application
+4 | -1
The of mixture having and is
View answer and explanation
Correct option: A
Option A (8.7) is correct because the pH of the buffer solution is calculated using the Henderson-Hasselbalch equation for a basic buffer.
452
Easy
452 of 680
Remembering
+4 | -1
The indicator used in the titration of sodium carbonate with sulphuric acid is
View answer and explanation
Correct option: C
Methyl orange
Option C (Methyl orange) is correct because methyl orange is a suitable indicator for titrations involving a strong acid and a weak base.
453
Medium
453 of 680
Application
+4 | -1
What is the pH of a neutral solution at where equals
View answer and explanation
Correct option: C
6.8
Option C (6.8) is correct because it accurately calculates the pH of a neutral solution at 37°C using the given Kw value.
454
Easy
454 of 680
Understanding
+4 | -1
According to Le-Chatelier principle, adding heat a solid and liquid in equilibrium will cause the
View answer and explanation
Correct option: A
Amount of solid to decrease
Option A (Amount of solid to decrease) is correct because the fusion of a solid is an endothermic process, and adding heat favors the forward reaction (solid to liquid), thus decreasing the amount of solid.
455
Medium
455 of 680
Analyzing
+4 | -1
Which statement is wrong about ?
View answer and explanation
Correct option: B
Adding , solution of and pH will be seven
Option B is wrong because a mixture of a weak acid (CH3COOH) and a strong base (NaOH) will result in a pH greater than 7 at equivalence point.
456
Medium
456 of 680
Analyzing
+4 | -1
Statement (S): The in is .
Explanation(E): The is obtained from and ; the later furnishes less than due to common ion effect.
Explanation(E): The is obtained from and ; the later furnishes less than due to common ion effect.
View answer and explanation
Correct option: C
Both S and E are correct and E is correct explanation for S
The correct answer is C because both the statement and the explanation are correct, and the explanation correctly justifies why the [H+] in 10-8 N HCl is slightly higher than 10-7 M due to the contribution from water.
457
Medium
457 of 680
Application
+4 | -1
If the solubility of is Its solubility product is
View answer and explanation
Correct option: C
Option C () is correct because the solubility product for a salt of type is given by , where S is the solubility.
458
Medium
458 of 680
Application
+4 | -1
The of What concentration of ion in aqueous solution will just fail to give a precipitate of with a solution in which
View answer and explanation
Correct option: D
Option D () is correct because it represents the maximum silver ion concentration that will not cause precipitation of given the chromate concentration and .
459
Medium
459 of 680
Analyzing
+4 | -1
Statement I : For the reaction,
If we start with 1 mole each of A, B and C in 5 L flask, then at equilibrium, molar concentration of A and B increases and that of B decreases
Statement II : Reaction quotient with given quantity of A, B and C, hence reaction is reversed.
If we start with 1 mole each of A, B and C in 5 L flask, then at equilibrium, molar concentration of A and B increases and that of B decreases
Statement II : Reaction quotient with given quantity of A, B and C, hence reaction is reversed.
View answer and explanation
Correct option: C
Both Statements are true
Both statements are true. Statement I is true because the reaction will shift to reach equilibrium. Statement II is true because Q > Kc, indicating the reaction will proceed in reverse.
460
Hard
460 of 680
Analyzing
+4 | -1
The correct increasing order of solubility of the following substances in is
(Atomic masses:
(Atomic masses:
View answer and explanation
Correct option: C
Option C () is correct because it represents the increasing order of solubility based on the calculated solubility from the given Ksp values.
461
Easy
461 of 680
Application
+4 | -1
For the reaction, If the value of equilibrium constant is then the equilibrium constant for the reaction, will be
View answer and explanation
Correct option: B
Option B () is correct because reversing the reaction and halving the stoichiometric coefficients results in taking the reciprocal of the square root of the original equilibrium constant.
462
Medium
462 of 680
Application
+4 | -1
A saturated solution prepared by dissolved in water, has M. What is the of ?
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the solubility product expression for , where .
463
Medium
463 of 680
Understanding
+4 | -1
The total number of different kind of buffers obtained during the titration of with are:
View answer and explanation
Correct option: A
3
Option A (3) is correct because during the titration of with NaOH, three buffer regions are formed corresponding to the three acidic protons.
464
Hard
464 of 680
Analyzing
+4 | -1
The value of solutions of and is in the order
View answer and explanation
Correct option: C
V II III I IV
Option C is correct because it correctly orders the pH values of the given solutions from most acidic to most basic.
465
Easy
465 of 680
Application
+4 | -1
In the reaction, , is that part of which dissociates, then the number of moles at equilibrium will be
View answer and explanation
Correct option: C
The correct answer is C () because it accurately calculates the total number of moles at equilibrium based on the dissociation of N2O4.
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466
Medium
466 of 680
Understanding
+4 | -1
The total number of different kind of buffers obtained during the titration of with are:
View answer and explanation
Correct option: A
3
Option A (3) is correct because three different buffer solutions can be formed during the titration of H3PO4 with NaOH.
467
Medium
467 of 680
Analyzing
+4 | -1
STATEMENT I : of a aqueous solution of acetic acid remains unchanged on the addition of sodium acetate.
STATEMENT II : Dissociation of acetic acid is increased by the addition of sodium acetate due to common ion effect.
STATEMENT II : Dissociation of acetic acid is increased by the addition of sodium acetate due to common ion effect.
View answer and explanation
Correct option: B
Statement I, II are incorrect
Option B (Statement I, II are incorrect) is correct because the pH changes due to the common ion effect, and the dissociation of acetic acid decreases.
468
Hard
468 of 680
Application
+4 | -1
A gaseous phase reaction taking place in flask at is given, .
Starting with 1 mole and 3 moles , equilibrium mixture required of . Thus, is
Starting with 1 mole and 3 moles , equilibrium mixture required of . Thus, is
View answer and explanation
Correct option: C
0.029
Option C (0.029) is correct because the equilibrium constant Kc is calculated based on the stoichiometry of the reaction and the amount of ammonia produced, which is determined by the titration with sulfuric acid.
469
Medium
469 of 680
Application
+4 | -1
An aqueous solution contains ions at equal concentrations. The solubility product of in water at are , respectively. Indicate which of these ions will be precipitated first and last when sulphide concentration is progressively increased from zero?
View answer and explanation
Correct option: D
Option D () is correct because PbS, having the lowest solubility product, will precipitate first, and NiS, with the highest solubility product, will precipitate last.
470
Medium
470 of 680
Analyzing
+4 | -1
Assertion : Mixture of and is an example of acidic buffer.
Reason: Acidic buffer contains equimolar mixture of a weak acid and its salt with weak base.
Reason: Acidic buffer contains equimolar mixture of a weak acid and its salt with weak base.
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because an acidic buffer requires a weak acid and a salt of that weak acid with a strong base, not a weak base.
471
Medium
471 of 680
Analyzing
+4 | -1
The solubility of is Calculate the solubility product of from this information and from the fact that when is added slowly to a solution containing equimolar concentration of and no precipitate of is formed until of has been precipitated as
View answer and explanation
Correct option: C
Option C () is correct because it is calculated using the solubility of CaCO3 and the relative precipitation of BaCO3 compared to CaCO3.
472
Medium
472 of 680
Application
+4 | -1
of an acidic buffer is 7 and is 5 then the ratio of is:-
View answer and explanation
Correct option: B
100
Option B (100) is correct because it is the ratio of [salt]/[acid] calculated using the Henderson-Hasselbalch equation for an acidic buffer.
473
Medium
473 of 680
Application
+4 | -1
A 0.2 molar solution of formic acid is ionised, its ionisation constant is
View answer and explanation
Correct option: B
The correct answer is B () because the ionization constant is calculated using the degree of ionization and the initial concentration of the formic acid.
474
Medium
474 of 680
Analyzing
+4 | -1
Assertion :- For the reaction at equilibrium state and equilibrium constant is
Reason :- Given reaction is exothermic.
Reason :- Given reaction is exothermic.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because the assertion is true (equilibrium state is given), but the reason is false (the reaction's equilibrium constant doesn't imply it's exothermic).
475
Medium
475 of 680
Analyzing
+4 | -1
Statement I : For the equilibrium is doubled if volume of the vessel is reduced to half its initial volume.
Statement II : Decrease in volume proportionately decrease the concentrations of both reactants & products.
Statement II : Decrease in volume proportionately decrease the concentrations of both reactants & products.
View answer and explanation
Correct option: B
Statement I, II are incorrect
Option B is correct because the equilibrium constant depends only on temperature and is independent of volume changes for reactions with .
476
Medium
476 of 680
Application
+4 | -1
The values of of and are and respectively at . If the mixture of these two is washed with water, what is the concentration of ions in water?
View answer and explanation
Correct option: A
Option A () is correct because it involves calculating the total calcium ion concentration by considering the solubility product constants of both calcium carbonate and calcium oxalate.
477
Medium
477 of 680
Application
+4 | -1
The pH of an aqueous solution having hydroxide ion concentration as is
View answer and explanation
Correct option: B
9
Option B (9) is correct because pH is calculated from pOH using the relationship pH + pOH = 14, where pOH is derived from the hydroxide ion concentration.
478
Medium
478 of 680
Application
+4 | -1
Find change in of water when of is added to of at .
View answer and explanation
Correct option: A
2
Option A (2) is correct because the addition of KOH to water increases the pH from 7 to 9, resulting in a change of 2 pH units.
479
Hard
479 of 680
Application
+4 | -1
Hydrolysis of sucrose gives
sucrose + Glucose + Fructose
Equilibrium constant for the reaction is at 300 K. calculate at 300 K
sucrose + Glucose + Fructose
Equilibrium constant for the reaction is at 300 K. calculate at 300 K
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the formula .
480
Medium
480 of 680
Analyzing
+4 | -1
Which statement is false? (Assume complete dissociation in each case)
View answer and explanation
Correct option: D
In a 0.001 M solution of the concentration of mol/L
Option D (In a 0.001 M solution of the concentration of mol/L) is false because in a 0.001 M NaOH solution, the is M, not M.
Revision notes and key takeaways
Review Equilibrium in your textbook or class notes, then use this set to check your understanding.
Showing 451-480 of 680 questions
