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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 254 questions

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181 Medium
181 of 254
Analyzing +4 | -1
Which of the following has highest 3rd3^{\text {rd}} ionization energy?
View answer and explanation
Correct option: A
Mn\mathrm{Mn}
Option A (Mn) is correct because Mn has the highest 3rd ionization energy due to its stable d5 configuration after losing two electrons.
182 Medium
182 of 254
Understanding +4 | -1
Cerium (Z = 58) is an important member of the lanthanides. Which of the following statements about cerium is incorrect?
View answer and explanation
Correct option: C
The +4 oxidation state of cerium is not known in solutions.
The correct answer is C (The +4 oxidation state of cerium is not known in solutions) because Ce(IV) is a strong oxidizing agent and exists in solutions.
183 Medium
183 of 254
Remembering +4 | -1
German silver alloy contains
View answer and explanation
Correct option: D
Zinc, nickel and copper
Option D (Zinc, nickel and copper) is correct because German silver is an alloy primarily composed of zinc, nickel, and copper.
184 Medium
184 of 254
Understanding +4 | -1
Acidified K2Cr2O7{K}_2 {Cr}_2 {O}_7 solution turns green when Na2SO3{Na}_2 {SO}_3 is added to it. This is due to the formation of:
View answer and explanation
Correct option: A
Cr2(SO4)3{Cr}_2\left({SO}_4\right)_3
Option A (Cr2(SO4)3{Cr}_2\left({SO}_4\right)_3) is correct because K2Cr2O7{K}_2 {Cr}_2 {O}_7 is reduced to Cr3+{Cr}^{3+} which forms Cr2(SO4)3{Cr}_2\left({SO}_4\right)_3 in the presence of sulfate ions.
185 Medium
185 of 254
Analyzing +4 | -1
When a certain compound XX (used in laboratory for analysis) is added to copper sulphate solution a yellow-brown precipitate is obtained which turns white on addition of excess of Na2 S2O3\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3 solution.On addition to Ag+\mathrm{Ag}^{+}ion solution, a yellow curdy precipitate is obtained which is insoluble in NH4OH\mathrm{NH}_4 \mathrm{OH}. The XX is
View answer and explanation
Correct option: C
KI\mathrm{KI}
Option C (KI) is correct because KI reacts with copper sulfate to form a yellow-brown precipitate that turns white with excess Na2S2O3, and it forms a yellow curdy precipitate with Ag+ that is insoluble in NH4OH.
186 Medium
186 of 254
Remembering +4 | -1
KMnO4{KMnO}_4 is added to KOH{KOH}, which of the following colour is observed?
View answer and explanation
Correct option: D
Green
Option D (Green) is correct because KMnO4KMnO_4 in a basic medium (KOHKOH) is reduced to MnO42−MnO_4^{2-}, which is green in color.
187 Medium
187 of 254
Remembering +4 | -1
Blueprint papers have a coating of:
View answer and explanation
Correct option: A
Mixture of potassium ferricyanide and ammonium ferric citrate or ferric oxalate
Option A (Mixture of potassium ferricyanide and ammonium ferric citrate or ferric oxalate) is correct because blueprint paper is coated with a mixture of these compounds which react upon exposure to UV light to form Prussian blue.
188 Medium
188 of 254
Analyzing +4 | -1
What happens when a molten mixture of K2FeO4\mathrm{K}_2 \mathrm{FeO}_4 and K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 is acidified?
View answer and explanation
Correct option: D
FeO42−\mathrm{FeO}_4{ }^{2-} is reduced to Fe3+\mathrm{Fe}^{3+} liberating O2\mathrm{O}_2
Option D is correct because in acidic conditions, FeO42−FeO_4^{2-} is unstable and gets reduced to Fe3+Fe^{3+} liberating oxygen gas.
189 Medium
189 of 254
Understanding +4 | -1
Among FeSO4⋅7H2O(A),CuSO4⋅5H2O(B)\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}(A), \mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}(B), ZnSO4⋅7H2O(C),MnSO4⋅4H2O(D)\mathrm{ZnSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}(C), \mathrm{MnSO}_4 \cdot 4 \mathrm{H}_2 \mathrm{O}(D) isomorphous salts are
View answer and explanation
Correct option: A
AA and CC
Option A (AA and CC) is correct because FeSO4⋅7H2O\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O} and ZnSO4⋅7H2O\mathrm{ZnSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O} have similar crystalline form and chemical composition, making them isomorphous.
190 Medium
190 of 254
Remembering +4 | -1
Consider the following statements.

1. The transition metals and their compounds exhibit catalytic property.

II. Transition metals also show paramagnetic behaviour. The correct statement(s) is/are (choose the correct option)
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because transition metals exhibit both catalytic property and paramagnetic behavior.
191 Medium
191 of 254
Remembering +4 | -1
The highest oxidation state exhibited by transition metals is
View answer and explanation
Correct option: B
+8+ 8
Option B (+8+ 8) is correct because Osmium (Os) exhibits the highest oxidation state of +8 in OsO4\mathrm{Os}{\mathrm{O}_4}.
192 Medium
192 of 254
Understanding +4 | -1
When KIKI and CuSO4CuS{O_4} solutions are mixed , it gives
View answer and explanation
Correct option: B
Cu2I2+K2SO4C{u_2}{I_2} + {K_2}S{O_4}
Option B (Cu2I2+K2SO4Cu_2I_2 + K_2SO_4) is correct because when KI and CuSO4CuSO_4 solutions are mixed, Cu2+Cu^{2+} oxidizes I−I^- to I2I_2, which then reacts with more Cu2+Cu^{2+} to form insoluble Cu2I2Cu_2I_2.
193 Medium
193 of 254
Understanding +4 | -1
Europium (Eu) and Terbium (Tb) attain state 4f74 f^7 configuration by exhibiting oxidation states of
View answer and explanation
Correct option: A
#ERROR!
Option C is correct because Europium (Eu) attains a 4f7 configuration by losing two electrons to form Eu+2, and Terbium (Tb) attains a stable state after losing four electrons.
194 Medium
194 of 254
Remembering +4 | -1
Which of the following element is not a member of transition elements?
View answer and explanation
Correct option: C
Ce{Ce}
Option C is correct because Cerium (Ce) belongs to the lanthanide series and is an inner transition element, not a transition element.
195 Medium
195 of 254
Analyzing +4 | -1
The electronic configuration of Cu(II)\mathrm{Cu}(\mathrm{II}) is 3d93 d^9 while that of Cu(I)\mathrm{Cu}(\mathrm{I}) is 3d103 d^{10}. Identify the correct statement.
View answer and explanation
Correct option: B
Cu\mathrm{Cu} (II) is more stable
Option B is correct because Cu(II) is more stable due to its smaller size and higher effective nuclear charge.
196 Medium
196 of 254
Understanding +4 | -1
V2O4{V}_2 {O}_4 when dissolve in acids gives
View answer and explanation
Correct option: C
VO2+{VO}^{2+}
The correct answer is C (VO2+{VO}^{2+}) because V2O4V_2O_4 dissolves in acids to form the vanadyl(IV) ion, VO2+VO^{2+}.
197 Medium
197 of 254
Remembering +4 | -1
The alloy of steel that is used for making automobile parts and utensils is:
View answer and explanation
Correct option: A
Stainless steel
Option A (Stainless steel) is correct because stainless steel is known for its corrosion resistance and is commonly used in automobile parts and utensils.
198 Medium
198 of 254
Understanding +4 | -1
Most of the transition metals are paramagnetic due to the presence of:
View answer and explanation
Correct option: C
Unpaired electrons
Option C (Unpaired electrons) is correct because the presence of unpaired d-electrons in transition metals leads to paramagnetism due to their spin magnetic moments.
199 Medium
199 of 254
Analyzing +4 | -1
Assertion : 1st ionisation potential of mercury is greater than cadmium

Reason : Hg has stable electronic configuration (5d106s2)(5{d^{10}}6{s^2})
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because while both statements are true, the stable electronic configuration is not the primary reason for mercury's higher ionization potential.
200 Medium
200 of 254
Application +4 | -1
When KMnO4{KMnO}_4 acts as an oxidizing agent and ultimately forms MnO42−,MnO2,Mn2O3{MnO}_4^{2-}, {MnO}_2, {Mn}_2 {O}_3 and Mn2+{Mn}^{2+} then the number of electrons transferred in each case respectively are
View answer and explanation
Correct option: A
1,3,4,51,3,4,5
Option A (1,3,4,51,3,4,5) is correct because it accurately represents the number of electrons transferred in each reduction step of KMnO4{KMnO}_4.
201 Medium
201 of 254
Remembering +4 | -1
5f5f-level is successively filled up in:
View answer and explanation
Correct option: B
Actinoids
Option B (Actinoids) is correct because the 5f orbitals are progressively filled in the actinoid series.
202 Medium
202 of 254
Analyzing +4 | -1
Which of the following statement are correct about Zn,Cd{Zn}, {Cd} and Hg{Hg}?

A. They exhibit high enthalpy of atomization as the dd-subshell is full.

B. Zn{Zn} and Cd{Cd} do not show variable oxidation state while Hg{Hg} shows +I and +II.

C. Compounds of Zn,Cd{Zn}, {Cd} and Hg{Hg} are paramagnetic in nature.

D. Zn,Cd{Zn}, {Cd} and Hg{Hg} are called soft metals.

Choose the most appropriate from the options given below:
View answer and explanation
Correct option: A
B, D only
Option A (B, D only) is correct because Zinc, Cadmium, and Mercury do not have high enthalpy of atomization and their compounds are diamagnetic.
203 Medium
203 of 254
Remembering +4 | -1
Which of the following is correct?
View answer and explanation
Correct option: C
Gun metal: Cu  +  Zn  +  Sn\mathrm{Cu\;} + \mathrm{\;Zn\;} + \mathrm{\;Sn}
Option C (Gun metal: Cu  +  Zn  +  Sn\mathrm{Cu\;} + \mathrm{\;Zn\;} + \mathrm{\;Sn}) is correct because gun metal is an alloy of copper, zinc, and tin.
204 Medium
204 of 254
Remembering +4 | -1
Copper becomes green when exposed to moist air for a long period. This is due to
View answer and explanation
Correct option: B
the formation of a layer of basic carbonate of copper on the surface of copper.
Option B (the formation of a layer of basic carbonate of copper on the surface of copper) is correct because copper reacts with carbon dioxide and moisture in the air to form a green layer of basic copper carbonate.
205 Medium
205 of 254
Analyzing +4 | -1
In context with the transition elements, which of the following statements is incorrect?
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Correct option: B
In the highest oxidation state, the transition metal shows basic character and form cationic complexes.
Option B is correct because in the highest oxidation state, transition metals tend to form acidic oxides and oxoanions, not basic compounds or cationic complexes.
206 Medium
206 of 254
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : In aqueous solutions Cr2+\mathrm{Cr}^{2+} is reducing while Mn3+\mathrm{Mn}^{3+} is oxidising in nature.

Reason (R) : Extra stability to half filled electronic configuration is observed than incompletely filled electronic configuration.

In the light of the above statement, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because Cr2+ is reducing due to its tendency to form the stable half-filled t2g3 configuration of Cr3+, while Mn3+ is oxidizing due to the formation of the stable d5 configuration of Mn2+.
207 Medium
207 of 254
Understanding +4 | -1
Assertion (A) : Chromium can be used as a protective and non-corrosive plating on other metals.

Reason (R): Due to atmospheric oxidation, chemically a inert layer of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 is formed.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B is correct because both the assertion and the reason are true, but the reason doesn't fully explain why chromium is used as a protective plating.
208 Medium
208 of 254
Remembering +4 | -1
Which of the following is philosopher’s wool?
View answer and explanation
Correct option: A
ZnO\mathrm{ZnO}
Option A (ZnO\mathrm{ZnO}) is correct because zinc oxide (ZnO\mathrm{ZnO}) is known as philosopher's wool due to its appearance.
209 Medium
209 of 254
Remembering +4 | -1
Which of the following does not react with oxygen directly?
View answer and explanation
Correct option: C
PtPt
Option C (PtPt) is correct because Platinum (PtPt) is a noble metal and does not readily react with oxygen directly.
210 Medium
210 of 254
Understanding +4 | -1
Assertion: Higher oxidation states in transition metals are more covalent than lower oxidation states.

Reason: Higher oxidation states involve more d-electrons than lower oxidation states.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion) is correct because higher oxidation states lead to greater polarization and thus more covalent character.
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