When excess of ${\rm{SnC}}{{\rm{l}}_2}$ is added to a solution of ${\rm{HgC}}{{\rm{l}}_2}$, a white ppt. turning to grey is obtained. This grey colour is due to the formation of:

${\rm{H}}{{\rm{g}}_2}{\rm{C}}{{\rm{l}}_2}$

Which is obtained when ${\rm{S}}{{\rm{O}}_2}$ is bubbled through a solution of ${\rm{CuC}}{{\rm{l}}_2}$?

${\rm{C}}{{\rm{u}}_2}{\rm{C}}{{\rm{l}}_2}$

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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Medium

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Showing 61-90 of 254 questions

61 Medium

61 of 254

Application +4 | -1

A transition element X has the configuration

\left[ {\mathrm{Ar}} \right]{d^4}

in its +3 oxidation state. Its atomic number is

View answer and explanation

Correct option: A

Option A (25) is correct because the atomic number is calculated by adding the electrons in the [Ar] core and the d⁴ configuration in the +3 oxidation state, then adding back the 3 electrons lost during ionization.

62 Medium

62 of 254

Understanding +4 | -1

Which one amongst the following are good
oxidizing agents?

A.

{Sm}^{2+}

{Ce}^{2+}

{Ce}^{4+}

{Tb}^{4+}

Choose the most appropriate answer from the
options given below.

View answer and explanation

Correct option: D

C and D only

Option D (C and D only) is correct because

Ce^{4+}

and

Tb^{4+}

are strong oxidizing agents as they tend to gain electrons to achieve the more stable +3 oxidation state.

63 Medium

63 of 254

Understanding +4 | -1

It is always advisable not to cover egg yolk or mustard with silver cutlery because:

View answer and explanation

Correct option: B

Silver reacts with sulphur of egg yolk forming black

\mathrm{A}{\mathrm{g}_2}\mathrm{S}

Option B (Silver reacts with sulphur of egg yolk forming black

\mathrm{A}{\mathrm{g}_2}\mathrm{S}

) is correct because egg yolk and mustard contain sulfur compounds that react with silver to form silver sulfide, which is black.

64 Medium

64 of 254

Application +4 | -1

Which of the following ions has the maximum magnetic moment?

View answer and explanation

Correct option: A

{Mn}^{+2}

Option A (

{Mn}^{+2}

) is correct because it has the maximum number of unpaired electrons, leading to the highest magnetic moment.

65 Medium

65 of 254

Remembering +4 | -1

Which of the following is not a characteristic of transition elements?

View answer and explanation

Correct option: D

Natural radioactivity

Option D (Natural radioactivity) is correct because natural radioactivity is a property of unstable nuclei, not a general characteristic of transition elements.

66 Medium

66 of 254

Remembering +4 | -1

The principle characteristic of interstitial compounds formed by transition elements is

View answer and explanation

Correct option: A

They retain metallic conductivity

Option A (They retain metallic conductivity) is correct because interstitial compounds of transition metals retain metallic conductivity due to the presence of metallic bonding.

67 Medium

67 of 254

Application +4 | -1

Which of the following ions has a magnetic moment of 5.93 BM?

(At. no. V=23, Cr=24, Mn=25, Fe=26)

View answer and explanation

Correct option: A

\mathrm{M}{\mathrm{n}^{2 + }}

Option A (

\mathrm{M}{\mathrm{n}^{2 + }}

) is correct because it has 5 unpaired electrons, resulting in a magnetic moment of approximately 5.93 BM.

68 Medium

68 of 254

Remembering +4 | -1

Which is known as purple of Cassius?

View answer and explanation

Correct option: B

Colloidal gold solution

Option B (Colloidal gold solution) is correct because Purple of Cassius is the trade name for gold sol in water.

69 Medium

69 of 254

Analyzing +4 | -1

Among the following, the species that is both paramagnetic and coloured is

View answer and explanation

Correct option: A

\left[\mathrm{MnO}_4\right]^{2-}

Option A (

\left[\mathrm{MnO}_4\right]^{2-}

) is both paramagnetic and colored because it has one unpaired electron and undergoes d-d transition.

70 Medium

70 of 254

Remembering +4 | -1

d

-block elements generally form:

View answer and explanation

Correct option: C

Interstitial hydrides

Option C (Interstitial hydrides) is correct because d-block elements form metallic hydrides where hydrogen atoms occupy the interstitial sites in the metal lattice.

71 Medium

71 of 254

Remembering +4 | -1

In the extraction of Fe from

\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3}

, the reducing agent used is

View answer and explanation

Correct option: A

Option A (C) is correct because carbon (in the form of coke) is used as the reducing agent in the extraction of iron from iron oxide.

72 Medium

72 of 254

Analyzing +4 | -1

S-I:

{Cr}^{2+}

is a stronger reducing agent than

{Fe}^{2+}

.

S-II: In aqueous medium,

d^3

is more stable than

d^5

configuration.

View answer and explanation

Correct option: A

Statement-I & statement-II are correct

Option A is correct because both statements are true: Cr²⁺ is a stronger reducing agent than Fe²⁺, and in aqueous medium, d³ is more stable than d⁵ configuration.

73 Medium

73 of 254

Remembering +4 | -1

Most abundant transition element is:

View answer and explanation

Correct option: A

Option A (Fe) is correct because Iron (Fe) is the most abundant transition element in the Earth's crust.

74 Medium

74 of 254

Remembering +4 | -1

Which is not ferromagnetic?

View answer and explanation

Correct option: D

Option D (V) is correct because Vanadium (V) is not ferromagnetic, while Iron (Fe), Cobalt (Co), and Nickel (Ni) are well-known ferromagnetic materials.

75 Medium

75 of 254

Understanding +4 | -1

When excess of

\mathrm{SnC}{\mathrm{l}_2}

is added to a solution of

\mathrm{HgC}{\mathrm{l}_2}

, a white ppt. turning to grey is obtained. This grey colour is due to the formation of:

View answer and explanation

Correct option: D

\mathrm{H}{\mathrm{g}_2}

Option D (

\mathrm{H}{\mathrm{g}_2}

) is correct because the grey color observed is due to the formation of metallic mercury (

\mathrm{Hg}

) via reduction of

\mathrm{HgC}{\mathrm{l}_2}

by excess

\mathrm{SnC}{\mathrm{l}_2}

Explore Other Chapters in CHEMISTRY

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P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

76 Medium

76 of 254

Analyzing +4 | -1

Wrong match of the following is

View answer and explanation

Correct option: C

{K}_2{Cr}_2{O}_7

can disproportionate in acidic medium

Option C (

{K}_2{Cr}_2{O}_7

can disproportionate in acidic medium) is the wrong match because

{K}_2{Cr}_2{O}_7

cannot disproportionate as chromium is already in its highest oxidation state (+6).

77 Medium

77 of 254

Understanding +4 | -1

Which is obtained when

\mathrm{S}{\mathrm{O}_2}

is bubbled through a solution of

\mathrm{CuC}{\mathrm{l}_2}

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{u}_2}\mathrm{C}{\mathrm{l}_2}

Option B (

\mathrm{C}{\mathrm{u}_2}\mathrm{C}{\mathrm{l}_2}

) is correct because sulfur dioxide reduces cupric chloride to cuprous chloride in the presence of water.

78 Medium

78 of 254

Understanding +4 | -1

Most basic lanthanoids hydroxide among the following is

View answer and explanation

Correct option: A

\mathrm{Eu}(\mathrm{OH})_3

Option A (

\mathrm{Eu}(\mathrm{OH})_3

) is the most basic lanthanoid hydroxide because basicity decreases with increasing atomic number across the lanthanoid series.

79 Medium

79 of 254

Remembering +4 | -1

Yellow mercury (II) oxide is obtained when

View answer and explanation

Correct option: B

\mathrm{HgC}{\mathrm{l}_2}

is treated with NaOH solution

Option B (

\mathrm{HgC}{\mathrm{l}_2}

is treated with NaOH solution ) is correct because the reaction of mercury(II) chloride with sodium hydroxide produces yellow mercury(II) oxide.

80 Medium

80 of 254

Remembering +4 | -1

A developer used in photography is:

View answer and explanation

Correct option: C

A mild reducing agent

Option C (A mild reducing agent) is correct because photographic developers reduce silver halide to metallic silver.

81 Medium

81 of 254

Remembering +4 | -1

The stainless steel developed in India contains the following special components:

View answer and explanation

Correct option: C

Manganese and chromium

Option C (Manganese and chromium) is correct because stainless steel typically contains chromium for corrosion resistance and manganese for increased strength and toughness.

82 Medium

82 of 254

Understanding +4 | -1

In context of the lanthanoids, which of the following statements is not correct?

View answer and explanation

Correct option: D

A vailability of 4

f

-electrons results in the formation of compounds in +4 state for all members of the series.

Option D (A vailability of 4

f

-electrons results in the formation of compounds in +4 state for all members of the series) is not correct because not all lanthanoids exhibit a stable +4 oxidation state.

83 Medium

83 of 254

Understanding +4 | -1

which of the following does not exist

View answer and explanation

Correct option: A

{\left[ {CC{l_6}} \right]^2}

Option A (

{\left[ {CC{l_6}} \right]^2}^ -

) is correct because carbon cannot expand its octet due to the absence of available d-orbitals.

84 Medium

84 of 254

Understanding +4 | -1

Increasing order of oxidising power is:

View answer and explanation

Correct option: D

All of these

The correct answer is D (All of these) because all the given options represent correct increasing orders of oxidizing power for the specified species.

85 Medium

85 of 254

Remembering +4 | -1

Anhydrous ferric chloride is prepared by

View answer and explanation

Correct option: D

Passing dry

\mathrm{C}{\mathrm{l}_2}

gas over heated iron scrap.

Option D (Passing dry

\mathrm{C}{\mathrm{l}_2}

gas over heated iron scrap) is correct because it directly reacts iron with chlorine gas to form anhydrous ferric chloride.

86 Medium

86 of 254

Analyzing +4 | -1

Which of the following arrangements does not represent the correct order of the property stated against it?

View answer and explanation

Correct option: A

{V^{2 + }} < C{r^{2 + }} < M{n^{2 + }} < F{e^{2 + }}:

paramagnetic behaviour

Option A is correct. The paramagnetic behavior order is incorrect because Fe²⁺ has the same number of unpaired electrons as Cr²⁺, making their paramagnetic behavior similar.

87 Medium

87 of 254

Understanding +4 | -1

Which of the following ions will exhibit colour in aqueous solutions?

View answer and explanation

Correct option: C

{Ti}^{3+}({Z}=22)

Option C (

{Ti}^{3+}({Z}=22)

) is correct because it has one unpaired d-electron, allowing for d-d transitions and thus exhibiting color.

88 Medium

88 of 254

Understanding +4 | -1

The number of ions formed on dissolving one molecule of

\mathrm{FeS}{\mathrm{O}_4}{\left( {\mathrm{N}{\mathrm{H}_4}} \right)_2}\mathrm{S}{\mathrm{O}_4}.6{\mathrm{H}_2}\mathrm{O}

is:

View answer and explanation

Correct option: B

Option D (H3PO3) is correct because PCl3 reacts with water to form phosphorous acid (H3PO3) and HCl.

89 Medium

89 of 254

Remembering +4 | -1

One of the important uses of ferrous sulphate is in the:

View answer and explanation

Correct option: A

Manufacture of blue-black ink

Option A (Manufacture of blue-black ink) is correct because ferrous sulfate is used in the production of iron gall ink, which is a type of blue-black ink.

90 Medium

90 of 254

Understanding +4 | -1

The prussian blue colour obtained in the Lassaigne's test for nitrogen is due to the formation of

View answer and explanation

Correct option: B

Iron (III) hexacyanoferrate (II)

Option B (Iron (III) hexacyanoferrate (II)) is correct because the Prussian blue color in Lassaigne's test is due to the formation of ferric ferrocyanide.

Revision notes and key takeaways

Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.

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