${\rm{F}}{{\rm{e}}_3}{{\rm{O}}_4}$

$2{\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}.3{{\rm{H}}_2}{\rm{O}}$

${\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}$

${\rm{CuS}}{{\rm{O}}_4}.5{{\rm{H}}_2}{\rm{O}}$

${\rm{CuS}}{{\rm{O}}_4}.7{{\rm{H}}_2}{\rm{O}}$

${\rm{ZnS}}{{\rm{O}}_4}.7{{\rm{H}}_2}{\rm{O}}$

${\rm{FeS}}{{\rm{O}}_4}.7{{\rm{H}}_2}{\rm{O}}$

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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-139 of 139 questions

121 Easy

121 of 139

Remembering +4 | -1

Green vitriol is formed by

View answer and explanation

Correct option: A

\mathrm{Fe}{\mathrm{S}_2} + {\mathrm{H}_2}\mathrm{O} + {\mathrm{O}_2}

Option A (

\mathrm{Fe}{\mathrm{S}_2} + {\mathrm{H}_2}\mathrm{O} + {\mathrm{O}_2}

) is correct because green vitriol (ferrous sulfate) is formed by the oxidation of iron pyrite in the presence of water and oxygen.

122 Easy

122 of 139

Application +4 | -1

Which of the following pairs has both the ions coloured in aqueous solution?
[Atomic numbers of

{Sc}={2 1}, {T i}={2 2}, {N i}={2 8}

{C u}=29

and

{M n}=25

]

View answer and explanation

Correct option: D

{Mn}^{2+}, {Ti}^{3+}

Option D (

{Mn}^{2+}, {Ti}^{3+}

) is correct because both ions have unpaired electrons, allowing for d-d transitions and thus color in aqueous solution.

123 Easy

123 of 139

Application +4 | -1

Which of the following in its oxidation state shows the paramagnetism?

View answer and explanation

Correct option: A

\mathrm{Tb}(\mathrm{IV})

The correct answer is A (

\mathrm{Tb}(\mathrm{IV})

) because

\mathrm{Tb}^{4+}

has unpaired electrons in its electronic configuration, making it paramagnetic.

124 Easy

124 of 139

Remembering +4 | -1

When

{MnO}_2

is fused with potassium hydroxide in presence of

{KNO}_3

, the deep green compound obtained is

View answer and explanation

Correct option: B

{K}_2 {MnO}_4

Option B (

{K}_2 {MnO}_4

) is correct because when

MnO_2

is fused with potassium hydroxide in the presence of

KNO_3

, potassium manganate (

K_2MnO_4

), a deep green compound, is formed.

125 Easy

125 of 139

Understanding +4 | -1

Which product is obtained during reaction of

{MnO}_4^{-}

with

{I}^{-}

in faintly alkaline condition?

View answer and explanation

Correct option: B

{IO}_3^{-}

Option B (

{IO}_3^{-}

) is correct because in a faintly alkaline condition, permanganate oxidizes iodide to iodate.

126 Easy

126 of 139

Application +4 | -1

In chromite ore, the oxidation number of iron and chromium are respectively.

View answer and explanation

Correct option: D

+ 2, + 3

Option D (+2, +3) is correct because in chromite ore (FeCr2O4), iron exists as FeO (oxidation state +2) and chromium as Cr2O3 (oxidation state +3).

127 Easy

127 of 139

Application +4 | -1

Among the following the compound that is both paramagnetic and coloured is

View answer and explanation

Correct option: C

\mathrm{VOS}{\mathrm{O}_4}

Option C (

\mathrm{VOS}{\mathrm{O}_4}

) is correct because it contains vanadium in a +4 oxidation state, which has an unpaired electron, making it both paramagnetic and colored.

128 Easy

128 of 139

Analyzing +4 | -1

Which of the following statements are correct?

(A) The

\mathrm{M}^{3+} / \mathrm{M}^{2+}

reduction potential for iron is greater than manganese.

(B) The higher oxidation states of first row

d

-block elements get stabilized by oxide ion

(C) Aqueous solution of

\mathrm{Cr}^{2+}

can liberate hydrogen from dilute acid

(D) Magnetic moment of

\mathrm{V}^{2+}

is observed between

4.4-5.2 \mathrm{BM}

Choose the correct answer from the options given below:

View answer and explanation

Correct option: A

(B), (C) only

Option A ((B), (C) only) is correct because the higher oxidation states of first row d-block elements are stabilized by oxide ions, and aqueous solutions of Cr

{}^{2+}

can liberate hydrogen from dilute acid.

129 Easy

129 of 139

Remembering +4 | -1

The formula of azurite is

View answer and explanation

Correct option: B

2\mathrm{CuC}{\mathrm{O}_3}.\mathrm{Cu}{\left( {\mathrm{OH}} \right)_2}

Option B (

2\mathrm{CuC}{\mathrm{O}_3}.\mathrm{Cu}{\left( {\mathrm{OH}} \right)_2}

) is correct because it is the chemical formula for azurite, a copper carbonate hydroxide mineral.

130 Easy

130 of 139

Remembering +4 | -1

Catalyst used in oxo-process is

View answer and explanation

Correct option: D

\left[ {COH{{\left( {CO} \right)}_4}} \right]

Option D ([COH(CO)_4]) is the correct catalyst used in the oxo-process, as it is a known fact in organometallic chemistry.

131 Easy

131 of 139

Remembering +4 | -1

Highest oxidation state exhibited by an actinoid is

View answer and explanation

Correct option: D

Option D (7) is correct because Neptunium (Np) and Plutonium (Pu) can exhibit an oxidation state of +7, which is the highest among the actinoids.

132 Easy

132 of 139

Analyzing +4 | -1

Which of the following compounds has colour but no unpaired electrons?

View answer and explanation

Correct option: A

\mathrm{KMnO}_4

Option A is correct because KMnO4 exhibits color due to charge transfer transitions even though it has no unpaired electrons.

133 Easy

133 of 139

Remembering +4 | -1

Magnetite is:

View answer and explanation

Correct option: C

\mathrm{F}{\mathrm{e}_3}{\mathrm{O}_4}

Option C (

\mathrm{F}{\mathrm{e}_3}{\mathrm{O}_4}

) is correct because it is the chemical formula for Magnetite.

134 Easy

134 of 139

Remembering +4 | -1

Blue vitriol is:

View answer and explanation

Correct option: C

\mathrm{CuS}{\mathrm{O}_4}.5{\mathrm{H}_2}\mathrm{O}

Option C (

\mathrm{CuS}{\mathrm{O}_4}.5{\mathrm{H}_2}\mathrm{O}

) is correct because blue vitriol is the common name for copper(II) sulfate pentahydrate.

135 Easy

135 of 139

Understanding +4 | -1

Copper sulphate is commercially made from copper scrap by:

View answer and explanation

Correct option: B

Action of dilute sulphuric acid and air

Option B (Action of dilute sulphuric acid and air) is correct because copper scrap reacts with dilute sulfuric acid in the presence of air (oxygen) to form copper sulfate.

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136 Easy

136 of 139

Understanding +4 | -1

Which oxide of Mn is acidic in nature?

View answer and explanation

Correct option: B

\mathrm{M}{\mathrm{n}_2}{\mathrm{O}_7}

Option B (

\mathrm{M}{\mathrm{n}_2}{\mathrm{O}_7}

) is correct because Mn2O7 forms HMnO4 (permanganic acid) when dissolved in water, indicating its acidic nature.

137 Easy

137 of 139

Remembering +4 | -1

Gold exhibits the variable oxidation states of:

View answer and explanation

Correct option: B

+ 1,\mathrm{ } + 3

Option B (

+ 1,\mathrm{ } + 3

) is correct because gold commonly exhibits oxidation states of +1 and +3.

138 Easy

138 of 139

Remembering +4 | -1

In 3d-series atomic number

({Z})

varies from

View answer and explanation

Correct option: A

Z=21-30

Option A (

Z=21-30

) is correct because the 3d series starts with Scandium (Z=21) and ends with Zinc (Z=30).

139 Easy

139 of 139

Understanding +4 | -1

Which of the following metals do not react with

\mathrm{HCl}

View answer and explanation

Correct option: B

Silver and gold

Option B is correct. Silver (Ag) and gold (Au) are noble metals and are unreactive with HCl because they have higher reduction potentials than hydrogen.

Revision notes and key takeaways

Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.

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