${\rm{H}}{{\rm{g}}_2}{\rm{C}}{{\rm{l}}_2}$

${\rm{H}}{{\rm{g}}_2}{\rm{C}}{{\rm{l}}_2}$ and Hg

${\rm{Hg}} + {\rm{HgC}}{{\rm{l}}_2}$

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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 410 questions

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181 Easy

181 of 410

Remembering +4 | -1

Calomel is:

View answer and explanation

Correct option: D

\mathrm{H}{\mathrm{g}_2}\mathrm{C}{\mathrm{l}_2}

Option D (

\mathrm{H}{\mathrm{g}_2}\mathrm{C}{\mathrm{l}_2}

) is correct because Calomel is the common name for Mercurous chloride, which has the chemical formula

\mathrm{H}{\mathrm{g}_2}\mathrm{C}{\mathrm{l}_2}

182 Easy

182 of 410

Understanding +4 | -1

The properties of Zr and Hf are similar because

View answer and explanation

Correct option: C

Both have similar radii

Option C is correct because Zr and Hf have very similar ionic radii due to the lanthanide contraction, leading to similar chemical properties.

183 Medium

183 of 410

Remembering +4 | -1

The form of iron having the highest carbon content is

View answer and explanation

Correct option: A

Cast iron

Option A (Cast iron) is correct because cast iron has the highest carbon content among the given options, ranging from 2 to 4.5%.

184 Medium

184 of 410

Remembering +4 | -1

Coinage alloy has the composition of:

View answer and explanation

Correct option: A

Ag + Cu + Ni

Option A (Ag + Cu + Ni) is correct because coinage alloys are typically composed of silver, copper, and nickel.

185 Medium

185 of 410

Analyzing +4 | -1

Which of the following metal nitrate can show given change.

{\text{Aqueous solution of metal nitrate}}\xrightarrow[{{\text{N}}{{\text{H}}_{\text{4}}}{\text{OH}}}]{{{\text{Excess}}}}\left( {{\text{No change in colour and no precipitate in test tube}}} \right){\text{ }}

View answer and explanation

Correct option: C

\mathrm{AgNO}_3

Option C (

\mathrm{AgNO}_3

) is correct because silver nitrate forms a soluble complex with excess ammonium hydroxide, resulting in no precipitate or color change.

186 Medium

186 of 410

Remembering +4 | -1

The metal that shows highest and maximum number of oxidation state is:

View answer and explanation

Correct option: B

\mathrm{Mn}

Option B (

\mathrm{Mn}

) is correct because Manganese exhibits the highest number of oxidation states among the given options, ranging from +2 to +7.

187 Easy

187 of 410

Understanding +4 | -1

Which oxide is least stable at room temperature?

View answer and explanation

Correct option: B

\mathrm{A}{\mathrm{g}_2}\mathrm{O}

Option B (

\mathrm{A}{\mathrm{g}_2}\mathrm{O}

) is correct because silver oxide is thermodynamically less stable and decomposes at relatively low temperatures compared to the other oxides.

188 Easy

188 of 410

Understanding +4 | -1

Philosopher’s wool on heating with BaO at 1100

^\circ

C produce

View answer and explanation

Correct option: C

\mathrm{BaZn}{\mathrm{O}_2}

Option C (

\mathrm{BaZn}{\mathrm{O}_2}

) is correct because Philosopher's wool is zinc oxide (ZnO), and it reacts with barium oxide (BaO) at high temperatures to form barium zincate (

\mathrm{BaZn}{\mathrm{O}_2}

189 Hard

189 of 410

Understanding +4 | -1

A blue colouration is not obtained when:

View answer and explanation

Correct option: B

Copper sulphate solution reacts with

{\mathrm{K}_4}[\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

]

Option B (Copper sulphate solution reacts with

{\mathrm{K}_4}[\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

]) is correct because the reaction produces a brown precipitate, not a blue coloration.

190 Medium

190 of 410

Analyzing +4 | -1

For which of the following pairs, magnetic moment is same?

View answer and explanation

Correct option: B

\mathrm{CuCl}_{2}, \mathrm{TiCl}_{3}

Option B (

\mathrm{CuCl}_{2}, \mathrm{TiCl}_{3}

) is correct because both

Cu^{2+}

and

Ti^{3+}

have one unpaired electron, resulting in the same magnetic moment.

191 Medium

191 of 410

Analyzing +4 | -1

Which of the following ions exhibits d-d transition and para magnetism as well?

View answer and explanation

Correct option: C

{\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}

The correct answer is C (

{\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}

) because it exhibits both d-d transition (color) and paramagnetism due to unpaired electrons.

192 Medium

192 of 410

Application +4 | -1

A compound of vanadium chloride has spin only magnetic moment of

1.73 \mathrm{~Bm}

. Its formula is

View answer and explanation

Correct option: C

\mathrm{VCl}_4

Option C (

\mathrm{VCl}_4

) is correct because a magnetic moment of 1.73 Bm corresponds to one unpaired electron, which is consistent with VCl4.

193 Medium

193 of 410

Remembering +4 | -1

Which transition metal is used for the reduction of steam to hydrogen?

View answer and explanation

Correct option: B

Option B (Fe) is correct because iron is used in the Bosch process to convert steam to hydrogen.

194 Medium

194 of 410

Remembering +4 | -1

Among the following substances antiferromagnetic substance is

View answer and explanation

Correct option: A

{MnO}

Option A (

{MnO}

) is correct because Manganese(II) oxide (MnO) is a well-known antiferromagnetic substance.

195 Medium

195 of 410

Analyzing +4 | -1

Which one of the following does not decolourise an acidified

\mathrm{KMn}{\mathrm{O}_4}

solution?

View answer and explanation

Correct option: B

\mathrm{FeC}{\mathrm{l}_3}

Option B is correct because

\mathrm{FeC}{\mathrm{l}_3}

is an oxidizing agent itself and cannot be decolorized by acidified

\mathrm{KMn}{\mathrm{O}_4}

solution.

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P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

196 Medium

196 of 410

Remembering +4 | -1

Ruthenium carbonyl is:

View answer and explanation

Correct option: B

\mathrm{Ru}{\left( {\mathrm{CO}} \right)_5}

Option B (

\mathrm{Ru}{\left( {\mathrm{CO}} \right)_5}

) is correct because Ruthenium forms pentacarbonyl with the formula

\mathrm{Ru}{\left( {\mathrm{CO}} \right)_5}

197 Medium

197 of 410

Analyzing +4 | -1

Which of the following is not correct for

\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7

View answer and explanation

Correct option: D

Its colour is yellow

The correct answer is D because the color of K2Cr2O7 is orange, not yellow.

198 Easy

198 of 410

Remembering +4 | -1

The metallic oxide which impart purple colour to pottery is

View answer and explanation

Correct option: D

Manganese oxide

Option D (Manganese oxide) is correct because manganese oxide (

MnO_2

) is known to impart a purple color to pottery.

199 Medium

199 of 410

Remembering +4 | -1

The metal used for making armoured steel for tanks and domestic safes is:

View answer and explanation

Correct option: A

Manganese

Option A (Manganese) is correct because manganese steel is used in making armoured steel due to its high strength and wear resistance.

200 Easy

200 of 410

Remembering +4 | -1

A metal forms a volatile carbonyl compound and this property is taken advantages of its extraction. The metal is:

View answer and explanation

Correct option: B

Nickel

Option B (Nickel) is correct because nickel forms a volatile carbonyl compound,

\mathrm{Ni(CO)_4}

, which is used in the Mond process for nickel extraction.

201 Easy

201 of 410

Remembering +4 | -1

{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

is used as ……. Indicator for

\mathrm{FeS}{\mathrm{O}_4}vs.{\mathrm{K}_2}\mathrm{C}{\mathrm{r}_2}{\mathrm{O}_7}

titrations.

View answer and explanation

Correct option: B

External

Option B (External) is correct because

{\mathrm{K}_3}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}

reacts with

\mathrm{FeS}{\mathrm{O}_4}

internally, so it must be used externally.

202 Medium

202 of 410

Remembering +4 | -1

The process of heating of steel to temperature much below redness and then slowly cooling is called:

View answer and explanation

Correct option: C

Tempering

Option C (Tempering) is correct because tempering involves heating steel to a temperature below redness and then slowly cooling it to reduce brittleness.

203 Medium

203 of 410

Remembering +4 | -1

White colored thiosulphate which changes to black color automatically belongs to the following

d

-block metal.

View answer and explanation

Correct option: D

Silver

Option D (Silver) is correct because silver thiosulphate is white but decomposes to form black silver sulfide in the presence of moisture.

204 Easy

204 of 410

Remembering +4 | -1

An important characteristic property of metals is:

View answer and explanation

Correct option: B

Their ability to conduct electricity

Option B (Their ability to conduct electricity) is correct because the ability to conduct electricity is a fundamental characteristic property of metals.

205 Hard

205 of 410

Analyzing +4 | -1

Assertion :

{\text{E}}{{\text{u}}^{2 + }}\,\& \,{\text{Y}}{{\text{b}}^{{\text{2 + }}}}

are reducing agents for their ions.

Reason: Both ions have stable half - filled configuration.

View answer and explanation

Correct option: C

If Assertion is True but the Reason is False.

The correct answer is C (If Assertion is True but the Reason is False) because while Eu²⁺ and Yb²⁺ are reducing agents, it's due to their tendency to achieve stable f⁷ and f¹⁴ configurations, not just a general half-filled configuration.

206 Medium

206 of 410

Application +4 | -1

The spin only magnetic moment of

\mathrm{Cr}^{3+}

View answer and explanation

Correct option: B

\sqrt{15} \mathrm{BM}

Option B (

\sqrt{15} \mathrm{BM}

) is correct because the spin-only magnetic moment is calculated using the formula

\sqrt{n(n+2)}

, where n is the number of unpaired electrons.

207 Easy

207 of 410

Remembering +4 | -1

Which of the following group of members are known as volatile metals :-

View answer and explanation

Correct option: C

\mathrm{Zn}, \mathrm{Cd}, \mathrm{Hg}

Option C (

\mathrm{Zn}, \mathrm{Cd}, \mathrm{Hg}

) is correct because Zinc, Cadmium, and Mercury are known for their relatively low boiling points, making them volatile metals.

208 Easy

208 of 410

Remembering +4 | -1

Which metal is not used for making coins?

View answer and explanation

Correct option: D

Tungsten

Option D (Tungsten) is correct because it is not typically used for making coins due to its high melting point and difficulty in minting.

209 Hard

209 of 410

Understanding +4 | -1

In chromyl chloride test for confirmation of

{Cl}^{-}

ion, a yellow solution is obtained. Acidification of the solution and addition of amyl alcohol and

10 \% {H}_2 {O}_2

turns organic layer blue indicating formation of chromium pentoxide. The oxidation state of chromium in that is

View answer and explanation

Correct option: A

Option A (6) is correct because the oxidation state of chromium in

CrO_5

is +6, even though it has a peroxo linkage.

210 Easy

210 of 410

Remembering +4 | -1

Highest oxidation state exhibited by an actinoid is

View answer and explanation

Correct option: D

Option D (7) is correct because Neptunium (Np) and Plutonium (Pu) can exhibit an oxidation state of +7.

Revision notes and key takeaways

Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.

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