Skip to main content
Back to CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Your Progress

0 / 184 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 61-90 of 184 questions

Preparing practice and saved progress…

61 Easy
61 of 184
Understanding +4 | -1
The consequence of high screening effect of inner electrons of the nucleus for an element “X” is
View answer and explanation
Correct option: A
A decrease in the ionization potential
Option A (A decrease in the ionization potential) is correct because a high screening effect reduces the effective nuclear charge experienced by the outer electrons, making them easier to remove.
62 Easy
62 of 184
Application +4 | -1
A dipositive ion has number of e−{e^ - } equal to 24 and mass number 56, the number of neutrons present is
View answer and explanation
Correct option: C
30
Option C (30) is correct because the number of neutrons is calculated by subtracting the atomic number (number of protons) from the mass number, and the atomic number is equal to the number of electrons plus the charge of the ion.
63 Easy
63 of 184
Analyzing +4 | -1
On which of the following Dobereiner's Triad law is not applicable?
View answer and explanation
Correct option: C
F,Cl,Br{F}, {Cl}, {Br}
Option C (F,Cl,Br{F}, {Cl}, {Br}) is correct because the atomic mass of chlorine is not the arithmetic mean of the atomic masses of fluorine and bromine.
64 Easy
64 of 184
Remembering +4 | -1
The atomic number of element Unp is
View answer and explanation
Correct option: A
105
Option A (105) is correct because Unp represents Unnilpentium, where Un = 1, nil = 0, and pent = 5, thus the atomic number is 105.
65 Easy
65 of 184
Remembering +4 | -1
IUPAC name of element having atomic number 108 is
View answer and explanation
Correct option: A
Unniloctium
Option A (Unniloctium) is correct because the IUPAC name for element 108 is Unniloctium, derived from the numerical roots for 1, 0, and 8.
66 Easy
66 of 184
Remembering +4 | -1
The electronic structure (n−1)d1−10ns0−2(n-1) d^{1-10} n s^{0-2} is characteristic of
View answer and explanation
Correct option: D
transition elements
Option D (transition elements) is correct because the electronic configuration (n−1)d1−10ns0−2(n-1) d^{1-10} n s^{0-2} is the general electronic configuration of transition elements.
67 Easy
67 of 184
Analyzing +4 | -1
The electronic configurations of four elements are :

(i) [Xe]6s1[{Xe}] 6 s^1

(ii) [Xe]4f145d16s2[{Xe}] 4 f^{14} 5 d^1 6 s^2

(iii) [Ar]4s24p5[{Ar}] 4 s^2 4 p^5

(iv) [Ar]3d74s2[{Ar}] 3 d^7 4 s^2

Which one of the following statements about these elements is not correct?
View answer and explanation
Correct option: B
(ii) is a d-block element
Option B ((ii) is a d-block element) is not correct because element (ii) is a lanthanide (f-block) element, specifically the last member of the lanthanide series.
68 Easy
68 of 184
Understanding +4 | -1
The correct order of electronegativity of N, O, F and P is
View answer and explanation
Correct option: A
F>O>N>P\mathrm{F > O > N > P}
Option A (F>O>N>P\mathrm{F > O > N > P}) is correct because electronegativity increases across a period and decreases down a group in the periodic table.
69 Easy
69 of 184
Analyzing +4 | -1
The element having greatest difference between its first and second ionisation energy, is
View answer and explanation
Correct option: D
KK
Option D (K) is correct because Potassium (K) has a large difference between its first and second ionization energies due to its electronic configuration.
70 Easy
70 of 184
Remembering +4 | -1
......... is measured as the radius of an atom's core which is in contact with the core of an adjacent atom in a bonded situation.
View answer and explanation
Correct option: C
Covalent radius
Option C (Covalent radius) is correct because the covalent radius is defined as half the distance between the nuclei of two covalently bonded atoms.
71 Easy
71 of 184
Remembering +4 | -1
Which of the following is a transition element?
View answer and explanation
Correct option: C
NiNi
Option C (NiNi) is correct because Nickel is a transition element, characterized by having partially filled d-orbitals in its electronic configuration.
72 Easy
72 of 184
Understanding +4 | -1
Which of the following set of elements cannot be a triad
View answer and explanation
Correct option: B
B, Al, Ga
Option B is correct because B, Al, and Ga do not form a triad as the atomic weight of Al is not the arithmetic mean of the atomic weights of B and Ga.
73 Easy
73 of 184
Understanding +4 | -1
Correct statements among the following is /are:-
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the statements regarding electron gain enthalpy, electronegativity, and amphoteric oxides are true.
74 Easy
74 of 184
Remembering +4 | -1
The number of elements which can be accommodated in the present set-up of the long form of the periodic table is:
View answer and explanation
Correct option: B
118
The correct answer is B (118) because the current long form of the periodic table accommodates 118 elements, from Hydrogen (atomic number 1) to Oganesson (atomic number 118).
75 Easy
75 of 184
Understanding +4 | -1
The element with electronic configuration 1s22s22p63s21{s^2}2{s^2}2{p^6}3{s^2} is
View answer and explanation
Correct option: C
an alkaline earth metal
Option C (an alkaline earth metal) is correct because the electronic configuration 1s22s22p63s21s^22s^22p^63s^2 indicates two valence electrons, which is characteristic of alkaline earth metals.
76 Easy
76 of 184
Understanding +4 | -1
Which of the following is the correct order of electron gain enthalpy
View answer and explanation
Correct option: A
P>O>S>FP > O > S > F
Option C (F > S > P > O) is correct because electron gain enthalpy generally increases across a period and decreases down a group, with exceptions due to electron-electron repulsion.
77 Easy
77 of 184
Remembering +4 | -1
Which important property did Mendeleev use to classify the elements in his periodic table?
View answer and explanation
Correct option: A
Atomic weight
Option A (Atomic weight) is correct because Mendeleev used atomic weight to classify elements.
78 Easy
78 of 184
Understanding +4 | -1
If the ionisation potential is IE, electron affinity is EA and electronegativity is X, which of the following relation is correct
View answer and explanation
Correct option: A
X=IE+EA2X = \frac{{IE + EA}}{2}
Option A is correct because Mulliken's electronegativity (X) is defined as the average of the ionization energy (IE) and electron affinity (EA): X=IE+EA2X = \frac{{IE + EA}}{2}.
79 Easy
79 of 184
Understanding +4 | -1
When an electron is removed from an atom, its energy
View answer and explanation
Correct option: A
Increase
Option A (Increase) is correct because removing an electron requires energy input, thus increasing the energy of the resulting ion.
80 Easy
80 of 184
Remembering +4 | -1
Which among the following is a representative element?
View answer and explanation
Correct option: A
Se\mathrm{Se}
Option A (Se\mathrm{Se}) is correct because Selenium (Se) is a p-block element and s-block and p-block elements are classified as representative elements.
81 Easy
81 of 184
Understanding +4 | -1
Observe the following statement VIII. The physical and chemical properties of elements are periodic functions of their electronic configuration. IX. Electronegativity of fluorine is less than the electronegativity of chlorine. X. Electropositive nature decreases from top to bottom in a group. The correct answer is
View answer and explanation
Correct option: B
Only I is correct
Option B (Only I is correct) is the correct answer because only the first statement regarding the periodic function of electronic configuration is accurate.
82 Easy
82 of 184
Understanding +4 | -1
The first ionisation potential is maximum for :
View answer and explanation
Correct option: D
Hydrogen
Option D is correct because hydrogen has the highest ionization potential due to its small size and the strong attraction between the nucleus and its single electron.
83 Easy
83 of 184
Understanding +4 | -1
Which group of the periodic table contains all the three (gas, liquid and solid) type of element :
View answer and explanation
Correct option: D
Both 1 and 2
Option D (Both 1 and 2) is correct because both Group 1 (alkali metals) and Group 17 (halogens) contain elements that exist as gases, liquids, and solids at room temperature and pressure.
84 Easy
84 of 184
Application +4 | -1
Maximum number of orbitals in 3rd 3^{\text {rd }} excited state of Li+2=xL i^{+2}=x. Electronegativity (Pauling scale) of most electronegative element =y=y. Then find value of (xy)\left(\frac{x}{y}\right).
View answer and explanation
Correct option: A
4
Option A (4) is correct because the maximum number of orbitals in the 3rd excited state is 16, and the electronegativity of Fluorine is 4.0, so 16/4 = 4.
85 Easy
85 of 184
Understanding +4 | -1
Which of the following is arranged in decreasing order of size?
View answer and explanation
Correct option: B
O2−>Mg2+>Al3+\mathrm{O}^{2-} > \mathrm{Mg}^{2+} > \mathrm{Al}^{3+}
Option B (O2−>Mg2+>Al3+\mathrm{O}^{2-} > \mathrm{Mg}^{2+} > \mathrm{Al}^{3+}) is correct because for isoelectronic species, the ionic radius decreases with increasing nuclear charge (atomic number).
86 Easy
86 of 184
Remembering +4 | -1
Which of the following electronic configuration in the outermost shell is characteristic of alkali metals
View answer and explanation
Correct option: C
(n−1)s2p6ns1 (n - 1){s^2}{p^6}n{s^1}\,
Option C ((n−1)s2p6ns1 (n - 1){s^2}{p^6}n{s^1}\,) is correct because alkali metals have one electron in their outermost shell, represented as ns1ns^1.
87 Easy
87 of 184
Analyzing +4 | -1
Correct order of second I . P is
View answer and explanation
Correct option: C
O > F > N > C
Option C (O > F > N > C) is the correct order of the second ionization potential because after the first ionization, oxygen attains a half-filled stable configuration, requiring more energy for the second ionization.
88 Easy
88 of 184
Analyzing +4 | -1
Assertion: In a period on going left to right Ionisation energy decrease.
Reason: In a period on moving left to right nuclear charge outweighs the shielding.
View answer and explanation
Correct option: B
Assertion is wrong and reason is true
Option B (Assertion is wrong and reason is true) is correct because ionization energy generally increases across a period, and the effective nuclear charge increases.
89 Easy
89 of 184
Remembering +4 | -1
The stable oxidation state of thallium, a IIIAII{I_A} ______ group element is
View answer and explanation
Correct option: A
+1+ 1
Option A (+1+ 1) is correct because thallium, being a group IIIAII{I_A} element, exhibits both +1 and +3 oxidation states, but +1 is more stable due to the inert pair effect.
90 Easy
90 of 184
Remembering +4 | -1
The elements which are characterized by the outer shell configurations ns1−2n{s^{1 - 2}} to np1−5n{p^{1 - 5}} are collectively called
View answer and explanation
Correct option: B
Representative elements
Option B (Representative elements) is correct because elements with outer shell configurations ns1−2ns^{1-2} to np1−5np^{1-5} are known as representative or main group elements.
Revision notes and key takeaways

Review CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 184 questions

Your practice

0 / 184 answered · 184 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.