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JEE • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Mixed difficulty

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Showing 421-426 of 426 questions

421 Medium

421 of 426

Application +4 | -1

The values of electronegativity of atom A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A-B bond is

View answer and explanation

Correct option: D

0.736

Option D (0.736) is correct because the percentage of ionic character is estimated based on the electronegativity difference between the two atoms.

422 Medium

422 of 426

Understanding +4 | -1

What is the correct order of ionisation energy

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Correct option: A

B > Al < Ga > In < Tl

Option D (

B > Al < Ga < In < Tl

) is correct because ionization energy generally decreases down a group, but there are exceptions due to the filling of d and f orbitals.

423 Hard

423 of 426

Understanding +4 | -1

The basic character of

\mathrm{MgO}, \mathrm{BaO}, \mathrm{Na}_2 \mathrm{O}

and

\mathrm{FeO}

follow the order

View answer and explanation

Correct option: C

\mathrm{FeO} < \mathrm{MgO} < \mathrm{BaO} < \mathrm{Na}_2 \mathrm{O}

Option C is correct because basic character increases down a group and decreases across a period, with Na2O being the most basic and FeO the least.

424 Medium

424 of 426

Analyzing +4 | -1

The three successive ionisation energies of an element are

Z, 25 Z

and

36 Z

. The element probably belongs to

View answer and explanation

Correct option: B

Group 1

Option B (Group 1) is correct because there is a large jump in ionization energy after the removal of one electron, indicating that the element has one valence electron.

425 Medium

425 of 426

Analyzing +4 | -1

What is the correct order of I.E

View answer and explanation

Correct option: A

K < Cu < C{u^ + } < {K^ + }

Option A (

K < Cu < C{u^ + } < {K^ + }

) is correct because ionization energy increases as electrons are removed and noble gas configurations are more stable.

426 Medium

426 of 426

Analyzing +4 | -1

Which represents alkali metal based on

(I{E_1})

and

(I{E_2})

values.

View answer and explanation

Correct option: C

\begin{array}{cccccccccccccccccccc} {}&{(I{E_1})}&{(I{E_2})} \\ {\text{Z}}&{195}&{500} \end{array}

The correct answer is C because alkali metals have a significantly lower first ionization energy compared to the second due to the stable noble gas configuration after losing one electron.

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Review CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES in your textbook or class notes, then use this set to check your understanding.

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