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JEE • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 426 questions

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301 Hard
301 of 426
Understanding +4 | -1
The pair of elements having approximately equal ionisation potential is
View answer and explanation
Correct option: A
Al, Ga
Option A (Al, Ga) is correct because the ionization potential of Ga is similar to Al due to poor shielding by the d-electrons in Ga.
302 Medium
302 of 426
Understanding +4 | -1
The statement that is not correct for the periodic classification of elements is
View answer and explanation
Correct option: D
For transition elements the dd-sub shells are filled with electrons monotonically with increase in atomic number
Option D is correct because the filling of d-subshells in transition elements is not always monotonic due to electron-electron repulsion and stability of half-filled and fully-filled configurations.
303 Easy
303 of 426
Understanding +4 | -1
The second ionisation enthalpies of elements are always higher than their first ionisation enthalpies because
View answer and explanation
Correct option: D
The cation is smaller than its parent atom
Option D (The cation is smaller than its parent atom) is correct because removing an electron increases the effective nuclear charge, causing the remaining electrons to be pulled closer to the nucleus, thus decreasing the size.
304 Medium
304 of 426
Understanding +4 | -1
The first ionisation enthalpy of NaNa is 5.1 eV, the value of electron gain enthalpy of Na+N{a^ + } will be
View answer and explanation
Correct option: C
- 5.1 eV
Option C (- 5.1 eV) is correct because the electron gain enthalpy of Na+Na^+ is the negative of the ionization enthalpy of Na.
305 Medium
305 of 426
Analyzing +4 | -1
The incorrect statement among the following is
View answer and explanation
Correct option: A
density increases across the period from left to right while decreases down the group.
Option A is the incorrect statement. Density generally increases across a period and also increases down a group due to increasing atomic mass outweighing the increase in atomic size.
306 Medium
306 of 426
Understanding +4 | -1
The element with Z = 120 (not yet discovered) will be an/a
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Correct option: C
Alkaline earth metal
Option C (Alkaline earth metal) is correct because element with Z = 120 will have electronic configuration [noble gas]ns², similar to alkaline earth metals.
307 Medium
307 of 426
Understanding +4 | -1
The tendency towards formation of coloured ions is the maximum in:
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Correct option: B
d-block elements
The correct answer is B (d-block elements) because d-block elements exhibit a high tendency to form colored ions due to d-d transitions.
308 Medium
308 of 426
Understanding +4 | -1
The factor not affecting the ionization enthalpy is
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Correct option: C
Type of bonding in the crystalline lattice
Option C (Type of bonding in the crystalline lattice) is correct because ionization enthalpy primarily depends on atomic size, nuclear charge, and the type of electron being removed, not the crystalline lattice structure.
309 Easy
309 of 426
Remembering +4 | -1
What would be the IUPAC name for the element with atomic number 115
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Correct option: C
UuP
Option C (UuP) is correct because the IUPAC nomenclature rules dictate that the element with atomic number 115 is named Ununpentium, abbreviated as Uup, which is now Moscovium (Mc). However, in the options, UuP is given.
310 Easy
310 of 426
Understanding +4 | -1
Which of the following arrangements represents the increasing order of ionic radii of the given species, O−2,  S2−,  N3−,  P3−{O^{ - 2}},\,\,{S^{2 - }},\,\,{N^{3 - }},\,\,{P^{3 - }}
View answer and explanation
Correct option: A
O2−<N3−<S2−<P3−{O^{2 - }} < {N^{3 - }} < {S^{2 - }} < {P^{3 - }}
Option A (O2−<N3−<S2−<P3−{O^{2 - }} < {N^{3 - }} < {S^{2 - }} < {P^{3 - }}) is correct because ionic radii increase down a group and for isoelectronic species, radii decrease with increasing nuclear charge.
311 Medium
311 of 426
Understanding +4 | -1
The first ionisation enthalpy values of third period element, Na,Mg\mathrm{Na}, \mathrm{Mg} an Si\mathrm{Si} are respectively 496,737496,737 and 786 kJ mol−1786 \mathrm{~kJ} \mathrm{~mol}^{-1}. The first ΔiH\Delta_\mathrm{i} \mathrm{H} value for Al\mathrm{Al} will be close to
View answer and explanation
Correct option: B
575 kJ mol−1575 \mathrm{~kJ} \mathrm{~mol}^{-1}
Option B (575 kJ mol−1575 \text{{ kJ mol}}^{-1}) is correct because aluminum's first ionization enthalpy is lower than magnesium's due to effective shielding of the 3p electron.
312 Easy
312 of 426
Analyzing +4 | -1
In which of the following options, the order of arrangement does not agree with the variation of property indicated against it
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Correct option: B
I<Br<Cl<FI < Br < Cl < F (increasing E.A)
Option B is correct because the electron affinity trend is generally increasing across a period and decreasing down a group, but chlorine has a higher electron affinity than fluorine due to its larger size and weaker electron-electron repulsion.
313 Medium
313 of 426
Understanding +4 | -1
Which of the following statement is incorrect?
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Correct option: D
Increase in electronegativity down a group is accompanied by a decrease in non-metallic properties
Option D (Increase in electronegativity down a group is accompanied by a decrease in non-metallic properties) is correct because electronegativity generally decreases down a group, which also leads to a decrease in non-metallic properties.
314 Medium
314 of 426
Understanding +4 | -1
The molecular formula of chloride of Eka-Aluminium and Eka-Silicon respectively are
View answer and explanation
Correct option: D
GaCl3{GaCl}_3 and GeCl4{GeCl}_4
Option D (GaCl3{GaCl}_3 and GeCl4{GeCl}_4) is correct because Eka-Aluminium corresponds to Gallium (Ga) and Eka-Silicon corresponds to Germanium (Ge), and their respective chlorides are GaCl3{GaCl}_3 and GeCl4{GeCl}_4.
315 Medium
315 of 426
Remembering +4 | -1
The magnitude of screening effect depends upon the number of
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Correct option: A
Inner electrons
Option A (Inner electrons) is correct because the screening effect, also known as the shielding effect, is primarily determined by the number of inner electrons between the nucleus and the valence electrons.
316 Medium
316 of 426
Analyzing +4 | -1
Assertion : Atomic size along a period decreases.

Reason : Zeff.Z_{\text {eff.}} in a period decreases.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because atomic size decreases along a period due to increasing effective nuclear charge, but the reason states that effective nuclear charge decreases, which is false.
317 Medium
317 of 426
Analyzing +4 | -1
Given below are two statements:
Statement I: The correct order of first ionization enthalpy values of Li,Na,F\mathrm{Li}, \mathrm{Na}, \mathrm{F} and Cl\mathrm{Cl} is Na<Li<Cl<F\mathrm{Na} < \mathrm{Li} < \mathrm{Cl} < \mathrm{F}.
Statement II: The correct order of negative electron gain enthalpy values of Li,Na,F\mathrm{Li}, \mathrm{Na}, \mathrm{F} and Cl\mathrm{Cl} is Na<Li<F<Cl\mathrm{Na} < \mathrm{Li} < \mathrm{F} < \mathrm{Cl}
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: A
Both Statement I and Statement II are true
Option A (Both Statement I and Statement II are true) is correct because the ionization enthalpy and electron gain enthalpy orders are accurate based on periodic trends and specific electronic configurations.
318 Easy
318 of 426
Remembering +4 | -1
The number of naturally occurring p- block elements that are diamagnetic is
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Correct option: C
5
Option C (5) is correct because the naturally occurring diamagnetic p-block elements are Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn).
319 Easy
319 of 426
Remembering +4 | -1
The outer electronic configuration of transition element is
View answer and explanation
Correct option: A
(n−1)d1−10  ns0−2\left( {n - 1} \right){d^{1 - 10}}\,\,n{s^{0 - 2}}
Option A ((n−1)d1−10 ns0−2\left( {n - 1} \right){d^{1 - 10}}\,n{s^{0 - 2}}) correctly represents the outer electronic configuration of transition elements.
320 Medium
320 of 426
Understanding +4 | -1
Which pair of ions are isoelectronic?
View answer and explanation
Correct option: D
Na+\mathrm{Na}^{+}and Mg2+\mathrm{Mg}^{2+}
Option D (Na+\mathrm{Na}^{+}and Mg2+\mathrm{Mg}^{2+}) is correct because both ions have 10 electrons, making them isoelectronic.
321 Medium
321 of 426
Understanding +4 | -1
Which of the following obeys triad law :
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Correct option: D
Both (1) and (3)
Option D (Both (1) and (3)) is correct because both Li, Na, K and Be, Mg, Ca follow Dobereiner's Triad Law where the atomic mass of the middle element is approximately the average of the other two.
322 Medium
322 of 426
Understanding +4 | -1
Considering the elements F,   Cl,   OF,\,\,\,Cl,\,\,\,O and NN the correct order of their chemical reactivity in terms of oxidizing property is
View answer and explanation
Correct option: B
F>O>Cl>NF > O > Cl > N
Option B (F>O>Cl>NF > O > Cl > N) is correct because oxidizing power generally increases across a period and decreases down a group, with some exceptions due to factors like electron affinity and hydration enthalpy.
323 Easy
323 of 426
Understanding +4 | -1
Which one of the following elements has lower value of ionisation energy?
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Correct option: B
Rb\mathrm{Rb}
Option B (Rb) is correct because ionization energy decreases down the group, and Rb is located furthest down Group 1 compared to the other options.
324 Easy
324 of 426
Understanding +4 | -1
Periodic classification of elements is used to examine the
View answer and explanation
Correct option: C
Both (1) and (2)
Option C is correct because the periodic classification is used to examine both the physical and chemical properties of elements.
325 Medium
325 of 426
Remembering +4 | -1
Out of the four blocks in which periodic table is divided, helium belongs to which block?
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Correct option: B
pp-block
Option A (pp-block) is correct because, although helium has its differentiating electron in the s-orbital, it's placed in the p-block due to its noble gas properties.
326 Easy
326 of 426
Understanding +4 | -1
Which of the following oxides is most acidic in nature?
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Correct option: A
BeO
Option A (BeO) is correct because BeO is amphoteric, but among the given alkaline earth metal oxides, it exhibits the most acidic character due to beryllium's smaller size and higher polarizing power.
327 Medium
327 of 426
Understanding +4 | -1
The first ionization potentials (eV)(\mathrm{eV}) of N{N} and O{O} respectively are
View answer and explanation
Correct option: D
11.32,8.2111.32,8.21
Option D (11.32, 8.21) is correct because Nitrogen has a half-filled p-orbital configuration, making it more stable and requiring more energy for ionization than Oxygen.
328 Hard
328 of 426
Analyzing +4 | -1
Out of Ne,  Na+,  O,  NaNe,\,\,N{a^ + },\,\,O,\,\,Na and N,N, the species having maximum and minimum ionization energies respectively are
View answer and explanation
Correct option: C
Na+,  NaN{a^ + },\,\,Na
The correct answer is C (Na+, NaN{a^ + },\,Na) because Na+Na^+ has a higher nuclear charge and smaller size, leading to a higher ionization energy, while Na has the lowest.
329 Medium
329 of 426
Understanding +4 | -1
Identify the correct order of the size of the following
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Correct option: C
Ca2+<K+<Ar<Cl−<S2−{Ca}^{2+} < {K}^{+} < {Ar} < {Cl}^{-} < {S}^{2-}
Option C is correct because it correctly orders the given isoelectronic species based on their nuclear charge, with more positive charge leading to smaller size.
330 Easy
330 of 426
Remembering +4 | -1
Modern periodic table states that the physical and chemical properties of the elements are periodic functions of thier atomic number. This is given by:
View answer and explanation
Correct option: B
Moseley
Option B (Moseley) is correct because Henry Moseley discovered that the physical and chemical properties of elements are periodic functions of their atomic number.
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