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JEE • CHEMISTRY • CHEMICAL KINETICS

Chemical kinetics practice · Mixed difficulty

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181 Medium
181 of 301
Analyzing +4 | -1
For the reaction X⟶Y+Z\mathrm{X \longrightarrow Y+Z} the following were obtained.

Time09001800Conc. of X50.719.67.61\begin{array}{cccccccccccccccccccc} {{\text{Time}}}&0&{900}&{1800} \\ {{\text{Conc}}{\text{. of X}}}&{50.7}&{19.6}&{7.61} \end{array}

Find the order of the reaction.
View answer and explanation
Correct option: A
1.05×10−3 S−11.05 \times 10^{-3} \mathrm{~S}^{-1}
Option A (1.05×10−3 S−11.05 \times 10^{-3} \mathrm{~S}^{-1}) is correct because the rate constant calculated at different time intervals remains approximately constant, indicating a first-order reaction.
182 Medium
182 of 301
Application +4 | -1
For a reaction the initial rate is given as: R0=k[A]02[B]0R_0=k[A]_0^2[B]_0 by what factor, the initial rate of reaction will increase if initial concentration of AA is taken 1.5 times and of BB is tripled?
View answer and explanation
Correct option: C
6.756.75
Option D (6.756.75) is correct because the new rate is 6.75 times the original rate when the concentration of A is multiplied by 1.5 and B is tripled.
183 Easy
183 of 301
Application +4 | -1
For a first order reaction k=100  s−1.k = 100\;{\mathrm{s}^{ - 1}}\mathrm{.} The time for completion of 50% reaction is
View answer and explanation
Correct option: C
7 mili-second
Option C (7 mili-second) is correct because it is the approximate half-life calculated for a first-order reaction with the given rate constant.
184 Hard
184 of 301
Application +4 | -1
The slope of Arrhenius plot (ln⁡ k v/s1T)\left( {\ln \,k\,\mathrm{v/s}\frac{1}{T}} \right) of first order reaction is −5×103K.- 5 \times {10^3}K. The value of Ea{E_a} of the reaction is.
Choose the correct option for your answer.
[Given R=8.314JK−1mol−1R = 8.314\mathrm{ J}{\mathrm{K}^{ - 1}}\mathrm{ mo}{\mathrm{l}^{ - 1}}]
View answer and explanation
Correct option: C
41.5 KJ mol−141.5\,\mathrm{KJ}\,\mathrm{mo}{\mathrm{l}^{ - 1}}
Option C (41.5 kJ/mol) is correct because it is the activation energy calculated from the slope of the Arrhenius plot.
185 Medium
185 of 301
Analyzing +4 | -1
Assertion (A):Threshold energy of a reaction is dependent of temperature.

Reason (R):The energy of activation decreases with increase in temperature.
View answer and explanation
Correct option: D
Both A and R are correct but R is not correct explanation of A
Option D is correct because both Assertion and Reason are true statements, but the Reason does not explain the Assertion.
186 Easy
186 of 301
Understanding +4 | -1
The rate of reaction increases with temperature due to
View answer and explanation
Correct option: C
Increase in collision frequency
Option C (Increase in collision frequency) is correct because increasing the temperature increases the kinetic energy of the molecules, leading to more frequent and effective collisions.
187 Medium
187 of 301
Understanding +4 | -1
Consider the following statements.

a. For zero order reaction t1/2t_{1 / 2} is directly proportional to the initial concentration of the reactants.

b. Inversion of cane sugar is an example of pseudo first order reaction.

c. Decomposition of gaseous ammonia on a hot platinum surface is a zero order reaction at high pressure.

The correct statement are
View answer and explanation
Correct option: D
a, b & c
Option C (Each carbon atom in diamond is chemically bonded to a greater number of neighbouring carbon atoms) is correct because diamond has a tetrahedral structure with strong covalent bonds in all directions, while graphite has a layered structure with weaker van der Waals forces between layers.
188 Easy
188 of 301
Remembering +4 | -1
Half-life period of second order reaction is
View answer and explanation
Correct option: C
Inversely proportional to initial concentration of reactants
Option C (Inversely proportional to initial concentration of reactants) is correct because the half-life of a second-order reaction is inversely proportional to the initial concentration of the reactants.
189 Medium
189 of 301
Application +4 | -1
A first order reaction is half-completed in 45 min45 \mathrm{~min}. How long does it need for 99.9%99.9 \% of the reaction to be completed?
View answer and explanation
Correct option: D
7.5 h7.5 \mathrm{~h}
The correct answer is D (7.5 h) because the time required for a first-order reaction to complete a certain percentage is directly proportional to the half-life.
190 Easy
190 of 301
Remembering +4 | -1
Rate of reaction depends upon
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the rate of a reaction depends on temperature, catalyst, and concentration.
191 Easy
191 of 301
Understanding +4 | -1
Which of the following statements are correct?

1. Order of a reaction can be known from experimental result and not from the stoichiometry of reaction

2. Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction

3. Overall order of reaction,

Am+Bn→ABx  is  (m+n){A^m} + {B^n} \to A{B_x}\;is\;\left( {m + n} \right)

4. Molecularity of a reaction refers to

(i) Molecularity of each of the elementary steps (slow steps) in a multistep reaction

(ii) Molecularity of that particular step in a single step reaction

Select the correct answer by using the codes given below
View answer and explanation
Correct option: D
1, 2 and 4
Option A (1, 3 and 4) is incorrect. The correct answer is that statements 1 and 4 are correct, but statement 3 is incorrect because the overall order of a reaction is not always simply the sum of the exponents in the rate law.
192 Hard
192 of 301
Analyzing +4 | -1
For a homogeneous gaseous reaction A⟶3B\mathrm{A} \longrightarrow 3 \mathrm{B}, if pressure after time t\mathrm{t} was Pt\mathrm{P}_{\mathrm{t}} and after completion of reaction, pressure was P∞\mathrm{P}_{\infty} then select correct relation
View answer and explanation
Correct option: D
k=1tln⁡(2P∞3(P∞−Pt))\mathrm{k}=\frac{1}{\mathrm{t}} \ln \left(\frac{2 \mathrm{P}_{\infty}}{3\left(\mathrm{P}_{\infty}-\mathrm{P}_\mathrm{t}\right)}\right)
Option D (k=1tln⁡(2P∞3(P∞−Pt))\mathrm{k}=\frac{1}{\mathrm{t}} \ln \left(\frac{2 \mathrm{P}_{\infty}}{3\left(\mathrm{P}_{\infty}-\mathrm{P}_\mathrm{t}\right)}\right)) is correct because it is derived from the integrated rate law for a first-order reaction, considering the stoichiometry and pressure changes.
193 Medium
193 of 301
Understanding +4 | -1
Which is correct relation in between dcdt,dndt  and  dPdt,\frac{{dc}}{{dt}},\frac{{dn}}{{dt}}\;and\;\frac{{dP}}{{dt}}, where c,n  and  pc,n\;and\;p, represent concentration, mole and pressure terms for gaseous phase reactant A(g)→productsA\left( \mathrm{g} \right) \to products?
View answer and explanation
Correct option: A
−dcdt=−1Vdndt=−1RTdPdt- \frac{{dc}}{{dt}} = - \frac{1}{V}\frac{{dn}}{{dt}} = - \frac{1}{{RT}}\frac{{dP}}{{dt}}
Option A (−dcdt=−1Vdndt=−1RTdPdt- \frac{{dc}}{{dt}} = - \frac{1}{V}\frac{{dn}}{{dt}} = - \frac{1}{{RT}}\frac{{dP}}{{dt}}) is correct because it correctly relates the rate of change of concentration, moles, and pressure for a gaseous reactant.
194 Easy
194 of 301
Understanding +4 | -1
For zero order reaction the integrated rate equation is
View answer and explanation
Correct option: C
[A]=−kt+[A]0\left[ A \right] = - kt + {\left[ A \right]_0}
Option C is correct because the integrated rate law for a zero-order reaction is given by [A] = -kt + [A]0.
195 Easy
195 of 301
Understanding +4 | -1
An increase in the concentration of reactants of a reaction leads to change in
View answer and explanation
Correct option: D
Collision frequency
The correct answer is D. Increasing reactant concentration increases the number of collisions between reactant molecules.
196 Medium
196 of 301
Application +4 | -1
For the two gaseous reactions, following data are given,

A→B;  k1=1010  e−20,000/TA \to B;\;{k_1} = {10^{10}}\;{e^{ - 20,000/T}}

C→D;  k2=1012  e−24,606/TC \to D;\;{k_2} = {10^{12}}\;{e^{ - 24,606/T}}

The temperature at which k1{k_1} becomes equal to k2{k_2} is
View answer and explanation
Correct option: B
1000  K1000\;K
Option B (1000  K1000\;K) is correct because it is the temperature at which the rate constants k1 and k2 are equal, found by equating the given expressions and solving for T.
197 Medium
197 of 301
Analyzing +4 | -1
Statement-1: The reciprocal of time in which 66%66\% of the reactant is converted to product is equal to the rate constant of first order reaction.
Statement-2: The rate constant for first order reaction depends on initial concentration of reactants.
View answer and explanation
Correct option: C
Statement I is true but statement II is false
Option C is correct because Statement I is true, as the reciprocal of the time for 66% conversion in a first-order reaction is related to the rate constant, and Statement II is false, since the rate constant for a first-order reaction is independent of the initial concentration of reactants.
198 Medium
198 of 301
Analyzing +4 | -1
For the reaction, 2NO2(g)+F2(g)⟶2NO2 F(g)2 \mathrm{NO}_2(g)+\mathrm{F}_2(g) \longrightarrow 2 \mathrm{NO}_2 \mathrm{~F}(g)
Steps are

I. NO2(g)+F2(g)⇌k2k1NO2 F2(g)\mathrm{NO}_2(g)+\mathrm{F}_2(g) \stackrel{k_1}{\underset{k_2}{\rightleftharpoons}} \mathrm{NO}_2 \mathrm{~F}_2(g) (Fast)

II. NO2 F2(g)→k3NO2 F(g)+F(g)\mathrm{NO}_2 \mathrm{~F}_2(g) \xrightarrow{k_3} \mathrm{NO}_2 \mathrm{~F}(g)+\mathrm{F}(g) (Slow)

III. F(g)+NO2(g)→k4NO2 F(g)\mathrm{F}(g)+\mathrm{NO}_2(g) \xrightarrow{k_4} \mathrm{NO}_2 \mathrm{~F}(g) (Fast)

Select the correct statement(s).
View answer and explanation
Correct option: B
Rate law is in agreement with slow step
Option B is correct because the rate law is determined by the slow step in the reaction mechanism.
199 Hard
199 of 301
Analyzing +4 | -1
Select the incorrect statement :
View answer and explanation
Correct option: C
For N2+3H2⇌2NH3;\mathrm{N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3; if rate of formation of NH3\mathrm{NH}_3 is 0.001 kg hr,0.001 \mathrm{~kg} \mathrm{~hr}, than rate of consumption of H2\mathrm{H}_2 is 0.0015 kg/hr0.0015 \mathrm{~kg} / \mathrm{hr}
Option C (For N2+3H2⇌2NH3;\mathrm{N}_2+3 \mathrm{H}_2 \rightleftharpoons 2 \mathrm{NH}_3; if rate of formation of NH3\mathrm{NH}_3 is 0.001 kg hr,0.001 \mathrm{~kg} \mathrm{~hr}, than rate of consumption of H2\mathrm{H}_2 is 0.0015 kg/hr0.0015 \mathrm{~kg} / \mathrm{hr}) is incorrect because the rate of consumption of H2{}_2 is not correctly calculated based on the stoichiometry of the reaction and the molar masses.
200 Easy
200 of 301
Understanding +4 | -1
The rate constant for a reaction is 10.8×10−5  mol.L−1.S−110.8 \times {10^{ - 5}}\,\,mol.{L^{ - 1}}.{S^{ - 1}} the reaction obeys
View answer and explanation
Correct option: B
Zero order
Option B (Zero order) is correct because the rate constant's units (mol.L−1.S−1mol.L^{-1}.S^{-1}) match those of a zero-order reaction.
201 Medium
201 of 301
Application +4 | -1
The ratio of the times for 99.9% of the reaction to complete and half of the reaction to complete is
View answer and explanation
Correct option: D
10
Option D (10) is correct because the ratio of times for 99.9% completion to half completion in a first-order reaction is approximately 10.
202 Medium
202 of 301
Application +4 | -1
The rate constant of the reaction A→BA \to B is 0.6×10−30.6 \times {10^{ - 3}} mole per second. If the concentration of A is 5M, then concentration of B after 20 minutes is:
View answer and explanation
Correct option: B
0.72 M\mathrm{0}\mathrm{.72}\,\mathrm{M}
Option B (0.72 M) is correct because, for a zero-order reaction, the concentration of product B is directly proportional to the rate constant and time.
203 Medium
203 of 301
Analyzing +4 | -1
Assertion : If the activation energy of a reaction is zero, temperature will have no effect on the rate constant.

Reason : Lower the activation energy, faster is the reaction.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B is correct because both the Assertion and Reason are correct statements, but the Reason does not explain the Assertion.
204 Medium
204 of 301
Application +4 | -1
In a reaction: A→B,A \to B, the concentration of ‘AA’ at time 10 s and 20 s is 2.2 mol L−12.2\,{\text{mol}}\,{{\text{L}}^{ - 1}} and 1.1 mol L−1.1.1\,{\text{mol}}\,{{\text{L}}^{ - 1}}.
The average rate of the reaction during the time period is
View answer and explanation
Correct option: C
0.11 mol L−1S−10.11\,{\text{mol}}\,{{\text{L}}^{ - 1}}{{\text{S}}^{ - 1}}
Option C (0.11 mol L−1S−10.11\,{\text{mol}}\,{{\text{L}}^{ - 1}}{{\text{S}}^{ - 1}}) is correct because it is the average rate of the reaction calculated using the change in concentration over the change in time.
205 Hard
205 of 301
Analyzing +4 | -1
Correct statements in the following are

a) In Hg(t)+Cl2(g)→HgCl2(s)\mathrm{Hg}_{(t)}+\mathrm{Cl}_{2(g)} \rightarrow \mathrm{HgCl}_{2(s)}, the rate of disappearance of any of the reactants is same as the rate of appearance of the product

b) In 2HI(g)→H2(g)+I2(g)2 \mathrm{HI}_{(g)} \rightarrow \mathrm{H}_{2(g)}+\mathrm{I}_{2(g)}, the rate of consumption of HI\mathrm{HI} is half of rate of formation of H2\mathrm{H}_2 or I2\mathrm{I}_2

c) In 5Br−(aq)+BrO3−(aq)+6H+(aq)→3Br2(aq)+3H2O(I)\underset{(a q)}{5 \mathrm{Br}^{-}}+\underset{(\mathrm{aq})}{\mathrm{BrO}_3^{-}}+\underset{(\mathrm{aq})}{6 \mathrm{H}^{+}} \rightarrow \underset{(\mathrm{aq})}{3 \mathrm{Br}_2}+3 \mathrm{H}_2 \mathrm{O}(\mathrm{I}), the rate of consumption of Br−(aq)\mathrm{Br}^{-}(\mathrm{aq}) is 1.66 times to the rate of a formation of Br2\mathrm{Br}_2
View answer and explanation
Correct option: C
a, c only correct
Option C is correct because statements a and c are correct regarding the rate of reaction.
206 Medium
206 of 301
Analyzing +4 | -1
Which of the following statements are incorrect?
View answer and explanation
Correct option: B
Rate of the reaction involving the thermal decomposition of acetaldehyde = k[CH3CHO]3/2k{\left[ {\mathrm{C}{\mathrm{H}_3}\mathrm{CHO}} \right]^{3/2}}
Rate of the reaction involving the thermal decomposition of acetaldehyde = k[CH3CHO]3/2k{\left[ {\mathrm{C}{\mathrm{H}_3}\mathrm{CHO}} \right]^{3/2}} is correct because the thermal decomposition of acetaldehyde follows a 3/2 order kinetics.
207 Easy
207 of 301
Remembering +4 | -1
A zero order reaction is one:
View answer and explanation
Correct option: C
Whose rate does not change with time
Option C (Whose rate does not change with time) is correct because a zero-order reaction's rate is independent of reactant concentration and therefore constant.
208 Medium
208 of 301
Analyzing +4 | -1
If in the fermentation of sugar in an enzymatic solution that is 0.12 M, the concentration of the sugar is reduced to 0.06 M in 10 h to 0.03 M in 20 h, what is the order of the reaction:
View answer and explanation
Correct option: A
1
Option A (1) is correct because the half-life is constant, indicating a first-order reaction.
209 Medium
209 of 301
Understanding +4 | -1
Assertion (A):For a free radical combination, K=AK=A.

Reason (R): EaE_a is zero for free radical combination.
View answer and explanation
Correct option: C
Both A and R are correct and R is correct explanation of A
Option C (Both A and R are correct and R is correct explanation of A) is correct because for a free radical combination, the activation energy (EaE_a) is approximately zero, which makes the rate constant (K) equal to the pre-exponential factor (A).
210 Medium
210 of 301
Application +4 | -1
Rate of a chemical reaction becomes 4 times when concentration of reactant is made 4 times. If 50%50 \% of reaction occurs in 1414sec1414 \mathrm{sec}, how long would it take for completion of 75%75 \% reaction?
View answer and explanation
Correct option: B
2828 second
The correct answer is B (2828 second) because the reaction is first order, and 75% completion takes twice the time for 50% completion.
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