Back to BIOMOLECULES

Your Progress

0 / 159 Answered

Correct

Incorrect

Accuracy

JEE • CHEMISTRY • BIOMOLECULES

Biomolecules practice · Medium

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

Showing 31-60 of 159 questions

31 Medium

31 of 159

Remembering +4 | -1

The enzyme which hydrolyses triglycerides to fatty acids and glycerol is called

View answer and explanation

Correct option: B

Lipase

Option B (Lipase) is correct because lipases are enzymes that specifically catalyze the hydrolysis of triglycerides into fatty acids and glycerol.

32 Medium

32 of 159

Understanding +4 | -1

Number of possible isomers of glucose is:

View answer and explanation

Correct option: C

Option C (16) is correct because glucose has 4 chiral carbons, so the number of stereoisomers is 2⁴ = 16.

33 Medium

33 of 159

Remembering +4 | -1

Houskeeping proteins are found in

View answer and explanation

Correct option: D

All of the above

Option D (All of the above) is correct because housekeeping proteins, essential for basic cellular functions, are found in various organelles including the endoplasmic reticulum, cytoskeleton, and Golgi complex.

34 Medium

34 of 159

Remembering +4 | -1

The number of disulphide linkage present in insulin are

View answer and explanation

Correct option: B

Option B (2) is correct because insulin contains two disulphide linkages between its A and B chains.

35 Medium

35 of 159

Remembering +4 | -1

Iodine value related to

View answer and explanation

Correct option: A

Fats and oils

Option A (Fats and oils) is correct because the iodine value is a measure of the degree of unsaturation in fats and oils.

36 Medium

36 of 159

Understanding +4 | -1

Before cellular respiration, amino acid undergo the process of :

View answer and explanation

Correct option: C

deamination

The correct answer is deamination because amino acids must undergo deamination to remove the amino group before entering cellular respiration.

37 Medium

37 of 159

Understanding +4 | -1

A polysaccharide is composed only of

\beta

D

-glucose units which are joined by glycosidic linkage between

\mathrm{C}-1

of one glucose unit and

\mathrm{C}-4

of the next glucose unit. Name the polysaccharide.

View answer and explanation

Correct option: B

Cellulose

Option B is correct because cellulose is a polysaccharide composed of

\beta

-D-glucose units linked by glycosidic linkages between C-1 and C-4.

38 Medium

38 of 159

Remembering +4 | -1

\alpha

and

\beta

-glucose are called as

View answer and explanation

Correct option: B

Anomers

Option B (Anomers) is correct because alpha and beta glucose are cyclic stereoisomers that differ only in the configuration at the anomeric carbon (C1).

39 Medium

39 of 159

Understanding +4 | -1

Which of the following statements is/are correct about proteins?

View answer and explanation

Correct option: D

All of the above

Option D is correct. Proteins are the basis of structure and function of life, required for growth and maintenance, and are polymers of alpha-amino acids, making all statements correct.

40 Medium

40 of 159

Remembering +4 | -1

Choose correct statement about archidonic acid

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because arachidonic acid is a polyunsaturated omega-6 fatty acid, helps in membrane formation, and is abundant in the brain.

41 Medium

41 of 159

Analyzing +4 | -1

Pick out the one which doesn’t belong to the family?

View answer and explanation

Correct option: B

Cellulose

Option B (Cellulose) is correct because it is a polysaccharide (carbohydrate), while the other options are enzymes.

42 Medium

42 of 159

Remembering +4 | -1

Which one of the following is the reagent used to identify glucose?

View answer and explanation

Correct option: C

Ammoniacal silver nitrate

Option C (Ammoniacal silver nitrate) is correct because glucose, having an aldehyde group, reduces Tollen's reagent (ammoniacal silver nitrate) to metallic silver, forming a silver mirror.

43 Medium

43 of 159

Remembering +4 | -1

Which one is not a constituent of nucleic acid?

View answer and explanation

Correct option: B

Guanidine

Option B (Guanidine) is correct because guanidine is not a constituent of nucleic acids; guanine is, but guanidine is a different compound.

44 Medium

44 of 159

Remembering +4 | -1

Fructose present in honey is

View answer and explanation

Correct option: A

Laevorotatory

Option A (Laevorotatory) is correct because fructose, a sugar found in honey, rotates plane-polarized light to the left, hence it is laevorotatory.

45 Medium

45 of 159

Remembering +4 | -1

Deficiency of vitamin D causes

View answer and explanation

Correct option: A

Rickets

Option A (Rickets) is correct because a deficiency in vitamin D leads to rickets, a condition affecting bone development.

Explore Other Chapters in CHEMISTRY

View All →

P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

46 Medium

46 of 159

Remembering +4 | -1

Which of the following indicates to 'regions of ordered structure within a protein'.

View answer and explanation

Correct option: B

Secondary structure

Option B (Secondary structure) is correct because the secondary structure of a protein refers to the local ordered structures like alpha-helices and beta-sheets.

47 Medium

47 of 159

Remembering +4 | -1

The secondary structure of a protein refers to

View answer and explanation

Correct option: B

\alpha

-helical backbone

Option B (

\alpha

-helical backbone) is correct because the secondary structure of a protein often refers to the

\alpha

-helical or

\beta

-pleated sheet conformations of the polypeptide backbone.

48 Medium

48 of 159

Understanding +4 | -1

Select the incorrect statement from the following.

View answer and explanation

Correct option: D

Cellulose is a branched chain polysaccharide made up of only

\alpha

-glucose units.

Option D (Cellulose is a branched chain polysaccharide made up of only

\alpha

-glucose units) is correct because cellulose is a straight-chain polysaccharide made up of

\beta

-glucose units, not branched and not

\alpha

-glucose.

49 Medium

49 of 159

Understanding +4 | -1

The detergency of a substance can be increased by addition of :

View answer and explanation

Correct option: D

All of the above

Option D (All of the above) is correct because the detergency of a substance can be enhanced by adding another detergent, builders like sodium tripolyphosphate, or other additives.

50 Medium

50 of 159

Remembering +4 | -1

The central dogma of molecular genetics states that the genetic information flows from

View answer and explanation

Correct option: D

DNA

\to

RNA

\to

Proteins

Option D (DNA

\to

RNA

\to

Proteins) is correct because the central dogma of molecular biology states that genetic information flows from DNA to RNA to proteins.

51 Medium

51 of 159

Remembering +4 | -1

Kwashiorkar is caused by the deficiency of

View answer and explanation

Correct option: D

essential amino acids

Option D (essential amino acids) is correct because Kwashiorkor is a nutritional disorder caused by a deficiency of essential amino acids in the diet.

52 Medium

52 of 159

Remembering +4 | -1

Fertility preventing steroid is

View answer and explanation

Correct option: A

Diosgenin

Option A (Diosgenin) is correct because diosgenin is a steroid sapogenin used in the synthesis of steroidal hormones, including those used in fertility control.

53 Medium

53 of 159

Understanding +4 | -1

Which of the following carbohydrate does not correspond to the general formula

\mathrm{C}_x\left(\mathrm{H}_2 \mathrm{O}\right)_y

View answer and explanation

Correct option: B

2-Deoxyribose

Option B (2-Deoxyribose) is correct because its formula is

\mathrm{C}_5\mathrm{H}_{10}\mathrm{O}_4

, which does not fit the general formula

\mathrm{C}_x(\mathrm{H}_2\mathrm{O})_y

54 Medium

54 of 159

Remembering +4 | -1

C-2 epimer of D-Glucose is

View answer and explanation

Correct option: C

D-Mannose

Option C (D-Mannose) is correct because D-Mannose is the C-2 epimer of D-Glucose, meaning they differ in configuration only at the C-2 carbon.

55 Medium

55 of 159

Remembering +4 | -1

An amine hormone is

View answer and explanation

Correct option: B

Adrenaline

Option B (Adrenaline) is correct because adrenaline is an amine hormone derived from the amino acid tyrosine, while the other options are steroid hormones.

56 Medium

56 of 159

Remembering +4 | -1

In DNA, C joins with ____ base by _____ hydrogen bonds.

View answer and explanation

Correct option: B

G, 3

Option B (G, 3) is correct because in DNA, cytosine (C) always pairs with guanine (G) through three hydrogen bonds.

57 Medium

57 of 159

Analyzing +4 | -1

Assertion (A): Sucrose is laevorotatory.

Reason (R): Sucrose on hydrolysis gives dextrorotatory glucose

\left(+52.5^{\circ}\right)

and laevorotation of fructose

\left(-92.4^{\circ}\right)

View answer and explanation

Correct option: D

(A) is incorrect but (R) is correct

Option D is correct because sucrose is dextrorotatory, but after hydrolysis, the resulting mixture is laevorotatory due to the higher laevorotation of fructose.

58 Medium

58 of 159

Remembering +4 | -1

Which one is the complimentary base in RNA strand to the adenine base in DNA during protein synthesis?

View answer and explanation

Correct option: D

Cytosine

Option C (Uracil) is correct because in RNA, uracil (U) base pairs with adenine (A), while in DNA, thymine (T) base pairs with adenine (A).

59 Medium

59 of 159

Understanding +4 | -1

Which among the following is not essential amino acid but optically active?

View answer and explanation

Correct option: B

Asparagine

Option B (Asparagine) is correct because asparagine is not an essential amino acid, but it is optically active due to the chiral carbon atom.

60 Medium

60 of 159

Analyzing +4 | -1

Periodic acid splits glucose and fructose into formaldehyde and formic acid, ratio of moles of formic acid
in glucose and fructose is

View answer and explanation

Correct option: B

5:3

Option B (

5:3

) is correct because periodic acid (

HIO_4

) oxidation of glucose yields 5 moles of formic acid, while fructose yields 3 moles of formic acid.

Revision notes and key takeaways

Review BIOMOLECULES in your textbook or class notes, then use this set to check your understanding.

Showing 31-60 of 159 questions

Continue Your Practice

📚 Switch Set (MEDIUM)

Chapter Sets

ALL 315 MCQs EASY 141 MCQs HARD 15 MCQs MEDIUM 159 MCQs

0 /159

0✓ 0✗

0% Accuracy