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JEE • CHEMISTRY • BIOMOLECULES

Biomolecules practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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271 Hard

271 of 315

Remembering +4 | -1

What does '

D

' and

(+)

signifies in

D-(+)

-glucose?

View answer and explanation

Correct option: B

D represents configuration and

(+)

represents the dextrorotatory nature of molecule

Option B (D represents configuration and (+) represents the dextrorotatory nature of molecule) is correct because 'D' indicates the configuration at the chiral carbon farthest from the aldehyde or ketone group, and '(+)' indicates that the molecule rotates plane-polarized light clockwise (dextrorotatory).

272 Medium

272 of 315

Remembering +4 | -1

The disaccharide held together by a glycosidic linkage between C1 of

\alpha \mathrm{ - D}

-glucose and C2 of

\beta \mathrm{ - D}

-fructose is

View answer and explanation

Correct option: A

Sucrose

Option A (Sucrose) is correct because sucrose is formed by a glycosidic linkage between C1 of

\alpha\mathrm{ - D}

-glucose and C2 of

\beta\mathrm{ - D}

-fructose.

273 Easy

273 of 315

Understanding +4 | -1

Which molecule possess the general formula of carbohydrates, but is not a carbohydrate?

View answer and explanation

Correct option: C

Acetic acid

Option C (Acetic acid) is correct because acetic acid has the general formula of carbohydrates (

{\mathrm{C}}_n({\mathrm{H}}_2{\mathrm{O}})_n

) but is not a carbohydrate.

274 Medium

274 of 315

Understanding +4 | -1

Which one group of biological molecule are micro and macromolecule respectively?

View answer and explanation

Correct option: B

Lipids, RNA and proteins

Option C (Lipids and polysaccharides) is correct because lipids are generally considered micromolecules, while polysaccharides are macromolecules.

275 Medium

275 of 315

Understanding +4 | -1

Which of the statements about "Denaturation" given below are correct ?

(A) Denaturation of proteins causes loss of secondary and tertiary structures of the protein.

(B) Denturation leads to the conversion of double strand of DNA into single strand.

(C) Denaturation affects primary structure which gets distorted.

Options :

View answer and explanation

Correct option: C

(A) and (B)

Option C ((A) and (B)) is correct because denaturation disrupts secondary and tertiary structures and can convert double-stranded DNA to single-stranded DNA.

276 Easy

276 of 315

Remembering +4 | -1

Which of the following vitamins contains isoprene unit?

View answer and explanation

Correct option: A

Option A (A) is correct because Vitamin A's structure contains isoprene units, which are repeating 5-carbon branched units.

277 Medium

277 of 315

Remembering +4 | -1

Chemically amylose is a with

200-1000

\alpha

-D-(+)-glucose units held by glycosidic linkage

View answer and explanation

Correct option: C

long unbranched chain,

\mathrm{Cl}-\mathrm{C} 4

Option C (long unbranched chain,

\mathrm{Cl}-\mathrm{C} 4

) is correct because amylose is a linear polymer of glucose units linked by

\alpha

-1,4-glycosidic bonds.

278 Easy

278 of 315

Remembering +4 | -1

Carbohydrates containing more than 10 simple units of sugar are called:

View answer and explanation

Correct option: D

Polysaccharides

Option D (Polysaccharides) is correct because polysaccharides are carbohydrates containing more than 10 simple sugar units.

279 Easy

279 of 315

Remembering +4 | -1

Which base is present in RNA but not in DNA?

View answer and explanation

Correct option: A

Uracil

Option A (Uracil) is correct because Uracil is a nitrogenous base found in RNA but not in DNA, where it is replaced by Thymine.

280 Medium

280 of 315

Understanding +4 | -1

Glucose reacts with acetyl chloride to form penta acetyl glucose, it indicates presence of:

View answer and explanation

Correct option: D

Five ─OH groups

Option D is correct because the formation of penta-acetyl glucose indicates the presence of five hydroxyl (-OH) groups in the glucose molecule, each reacting with acetyl chloride.

281 Easy

281 of 315

Remembering +4 | -1

The secondary structure of a protein refers to

View answer and explanation

Correct option: A

\alpha

-helical backbone

Option A (

\alpha

-helical backbone) is correct because the secondary structure of a protein primarily refers to the local folding patterns like alpha-helices and beta-sheets.

282 Medium

282 of 315

Remembering +4 | -1

Which of the following bases is not present in DNA?

View answer and explanation

Correct option: B

Uracil

Option B (Uracil) is correct because Uracil is a nitrogenous base found in RNA, not DNA. DNA contains Thymine instead of Uracil.

283 Medium

283 of 315

Analyzing +4 | -1

Assertion (A): Glucose does not form the hydrogen bisulphite addition product.

Reason (R): Glucose is not so reactive to form the product with

\mathrm{NaHSO}_3

View answer and explanation

Correct option: C

\mathrm{A}

is correct but

\mathrm{R}

is incorrect.

Option C is correct because glucose exists predominantly in a cyclic form, making the aldehyde group less available for reaction with NaHSO3.

284 Easy

284 of 315

Remembering +4 | -1

Which enzyme hydrolyses triglyceride to fatty acids and glycerol?

View answer and explanation

Correct option: C

Lipase

Option C (Lipase) is correct because lipase is the enzyme that specifically hydrolyzes triglycerides into fatty acids and glycerol.

285 Medium

285 of 315

Remembering +4 | -1

The change in optical rotation of a freshly prepared solution of glucose with time is called ______.

View answer and explanation

Correct option: C

Mutarotation

Option C (Mutarotation) is correct because mutarotation describes the change in optical rotation of a freshly prepared glucose solution over time as it equilibrates between its alpha and beta anomers.

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286 Medium

286 of 315

Remembering +4 | -1

Starch can be used as an indicator for the detection of the traces of:

View answer and explanation

Correct option: C

Iodine in aqueous solution

The correct answer is C (Iodine in aqueous solution) because starch forms a deep blue complex with iodine, which is used as an indicator for the presence of iodine.

287 Medium

287 of 315

Analyzing +4 | -1

Assertion (A): A solution of sucrose on hydrolysis becomes laevorotatory from dextrorotatory.

Reason (R): Sucrose on hydrolysis gives more number of glucose units due to which sign of rotation is changed.

View answer and explanation

Correct option: C

Assertion (A) is true, but Reason (R) is false

Option C (Assertion (A) is true, but Reason (R) is false) is correct because sucrose does become levorotatory upon hydrolysis, but this is due to fructose's higher negative rotation, not the number of glucose units.

288 Easy

288 of 315

Remembering +4 | -1

Which one of the following is an ester?

View answer and explanation

Correct option: A

Coconut oil

Option A (Coconut oil) is correct because coconut oil is an ester of glycerol and fatty acids.

289 Medium

289 of 315

Remembering +4 | -1

Which of the following sets of bases is present both in DNA and in RNA?

View answer and explanation

Correct option: B

Adenine, guanine, cytosine

Option B (Adenine, guanine, cytosine) is correct because these three bases are present in both DNA and RNA.

290 Medium

290 of 315

Understanding +4 | -1

Assertion:- Sucrose is dextrorotatory but its aqueous solution is laevorotatory.

Reason:- Dextro rotation of glucose is less than laevorotation of fructose.

View answer and explanation

Correct option: A

If both assertion & reason true & the reason is a correct explanation of the assertion

Option A (If both assertion & reason true & the reason is a correct explanation of the assertion) is correct because sucrose is initially dextrorotatory, but after hydrolysis, the resulting solution is laevorotatory due to the greater laevorotation of fructose compared to the dextrorotation of glucose.

291 Medium

291 of 315

Remembering +4 | -1

Which of the following is not an example of fibrous protein?

View answer and explanation

Correct option: B

Albumin

Option B (Albumin) is correct because Albumin is a globular protein, while Keratin, Collagen, and Myosin are fibrous proteins.

292 Easy

292 of 315

Remembering +4 | -1

Globular proteins are present in:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because globular proteins, characterized by their spherical shape and solubility in water, are found in blood, eggs, and milk.

293 Easy

293 of 315

Understanding +4 | -1

Which of the following is not a classification of proteins?

View answer and explanation

Correct option: B

Antibiotics

Option B is correct because antibiotics are drugs synthesized to inhibit or kill bacteria, and are not classified as proteins.

294 Easy

294 of 315

Remembering +4 | -1

Which of the following enzymes hydrolysis starch to glucose?

View answer and explanation

Correct option: A

Amylase

Option A (Amylase) is correct because amylase is the enzyme that specifically breaks down starch into glucose molecules through hydrolysis.

295 Medium

295 of 315

Remembering +4 | -1

A fatty acid with no double bond and high melting point are A saturated fatty acid is

View answer and explanation

Correct option: A

Saturated in nature

Option A (Saturated in nature) is correct because fatty acids with no double bonds are saturated and tend to have higher melting points due to efficient packing.

296 Medium

296 of 315

Remembering +4 | -1

Gene is a segment of

View answer and explanation

Correct option: A

DNA

Option A (DNA) is correct because a gene is a specific segment of DNA that codes for a particular protein or polypeptide.

297 Hard

297 of 315

Remembering +4 | -1

Purines possess nitrogen at

View answer and explanation

Correct option: C

1, 3, 7 and 9 position

Option C (1, 3, 7 and 9 position) is correct because the purine ring system has nitrogen atoms at positions 1, 3, 7, and 9.

298 Easy

298 of 315

Understanding +4 | -1

How glucose is related with fructose?

View answer and explanation

Correct option: A

Functional group isomerism

Option A (Functional group isomerism) is correct because glucose (an aldohexose) and fructose (a ketohexose) differ in their functional groups (aldehyde vs. ketone).

299 Medium

299 of 315

Understanding +4 | -1

Glucose does not

View answer and explanation

Correct option: C

Give Schiff’s test

Option C (Give Schiff’s test) is correct because glucose does not give Schiff's test due to the cyclic hemiacetal form being predominant.

300 Easy

300 of 315

Remembering +4 | -1

Nucleic acid are polymers of

View answer and explanation

Correct option: D

Nucleotides

Option D (Nucleotides) is correct because nucleic acids (DNA and RNA) are polymers made up of nucleotide monomers.

Revision notes and key takeaways

Review BIOMOLECULES in your textbook or class notes, then use this set to check your understanding.

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Biomolecules practice · Mixed difficulty

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